Optimal. Leaf size=115 \[ \frac{2 \sqrt{d x} \text{PolyLog}\left (2,a x^2\right )}{d}+\frac{8 \sqrt{d x} \log \left (1-a x^2\right )}{d}+\frac{16 \tan ^{-1}\left (\frac{\sqrt [4]{a} \sqrt{d x}}{\sqrt{d}}\right )}{\sqrt [4]{a} \sqrt{d}}+\frac{16 \tanh ^{-1}\left (\frac{\sqrt [4]{a} \sqrt{d x}}{\sqrt{d}}\right )}{\sqrt [4]{a} \sqrt{d}}-\frac{32 \sqrt{d x}}{d} \]
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Rubi [A] time = 0.0803542, antiderivative size = 115, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.533, Rules used = {6591, 2455, 16, 321, 329, 212, 208, 205} \[ \frac{2 \sqrt{d x} \text{PolyLog}\left (2,a x^2\right )}{d}+\frac{8 \sqrt{d x} \log \left (1-a x^2\right )}{d}+\frac{16 \tan ^{-1}\left (\frac{\sqrt [4]{a} \sqrt{d x}}{\sqrt{d}}\right )}{\sqrt [4]{a} \sqrt{d}}+\frac{16 \tanh ^{-1}\left (\frac{\sqrt [4]{a} \sqrt{d x}}{\sqrt{d}}\right )}{\sqrt [4]{a} \sqrt{d}}-\frac{32 \sqrt{d x}}{d} \]
Antiderivative was successfully verified.
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Rule 6591
Rule 2455
Rule 16
Rule 321
Rule 329
Rule 212
Rule 208
Rule 205
Rubi steps
\begin{align*} \int \frac{\text{Li}_2\left (a x^2\right )}{\sqrt{d x}} \, dx &=\frac{2 \sqrt{d x} \text{Li}_2\left (a x^2\right )}{d}+4 \int \frac{\log \left (1-a x^2\right )}{\sqrt{d x}} \, dx\\ &=\frac{8 \sqrt{d x} \log \left (1-a x^2\right )}{d}+\frac{2 \sqrt{d x} \text{Li}_2\left (a x^2\right )}{d}+\frac{(16 a) \int \frac{x \sqrt{d x}}{1-a x^2} \, dx}{d}\\ &=\frac{8 \sqrt{d x} \log \left (1-a x^2\right )}{d}+\frac{2 \sqrt{d x} \text{Li}_2\left (a x^2\right )}{d}+\frac{(16 a) \int \frac{(d x)^{3/2}}{1-a x^2} \, dx}{d^2}\\ &=-\frac{32 \sqrt{d x}}{d}+\frac{8 \sqrt{d x} \log \left (1-a x^2\right )}{d}+\frac{2 \sqrt{d x} \text{Li}_2\left (a x^2\right )}{d}+16 \int \frac{1}{\sqrt{d x} \left (1-a x^2\right )} \, dx\\ &=-\frac{32 \sqrt{d x}}{d}+\frac{8 \sqrt{d x} \log \left (1-a x^2\right )}{d}+\frac{2 \sqrt{d x} \text{Li}_2\left (a x^2\right )}{d}+\frac{32 \operatorname{Subst}\left (\int \frac{1}{1-\frac{a x^4}{d^2}} \, dx,x,\sqrt{d x}\right )}{d}\\ &=-\frac{32 \sqrt{d x}}{d}+\frac{8 \sqrt{d x} \log \left (1-a x^2\right )}{d}+\frac{2 \sqrt{d x} \text{Li}_2\left (a x^2\right )}{d}+16 \operatorname{Subst}\left (\int \frac{1}{d-\sqrt{a} x^2} \, dx,x,\sqrt{d x}\right )+16 \operatorname{Subst}\left (\int \frac{1}{d+\sqrt{a} x^2} \, dx,x,\sqrt{d x}\right )\\ &=-\frac{32 \sqrt{d x}}{d}+\frac{16 \tan ^{-1}\left (\frac{\sqrt [4]{a} \sqrt{d x}}{\sqrt{d}}\right )}{\sqrt [4]{a} \sqrt{d}}+\frac{16 \tanh ^{-1}\left (\frac{\sqrt [4]{a} \sqrt{d x}}{\sqrt{d}}\right )}{\sqrt [4]{a} \sqrt{d}}+\frac{8 \sqrt{d x} \log \left (1-a x^2\right )}{d}+\frac{2 \sqrt{d x} \text{Li}_2\left (a x^2\right )}{d}\\ \end{align*}
Mathematica [C] time = 0.0738958, size = 57, normalized size = 0.5 \[ \frac{5 x \text{Gamma}\left (\frac{5}{4}\right ) \left (16 \text{Hypergeometric2F1}\left (\frac{1}{4},1,\frac{5}{4},a x^2\right )+\text{PolyLog}\left (2,a x^2\right )+4 \log \left (1-a x^2\right )-16\right )}{2 \text{Gamma}\left (\frac{9}{4}\right ) \sqrt{d x}} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.053, size = 137, normalized size = 1.2 \begin{align*} 2\,{\frac{\sqrt{dx}{\it polylog} \left ( 2,a{x}^{2} \right ) }{d}}+8\,{\frac{\sqrt{dx}}{d}\ln \left ({\frac{-a{d}^{2}{x}^{2}+{d}^{2}}{{d}^{2}}} \right ) }+16\,{\frac{1}{d}\sqrt [4]{{\frac{{d}^{2}}{a}}}\arctan \left ({\sqrt{dx}{\frac{1}{\sqrt [4]{{\frac{{d}^{2}}{a}}}}}} \right ) }+8\,{\frac{1}{d}\sqrt [4]{{\frac{{d}^{2}}{a}}}\ln \left ({ \left ( \sqrt{dx}+\sqrt [4]{{\frac{{d}^{2}}{a}}} \right ) \left ( \sqrt{dx}-\sqrt [4]{{\frac{{d}^{2}}{a}}} \right ) ^{-1}} \right ) }-32\,{\frac{\sqrt{dx}}{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.88189, size = 408, normalized size = 3.55 \begin{align*} -\frac{2 \,{\left (16 \, d \left (\frac{1}{a d^{2}}\right )^{\frac{1}{4}} \arctan \left (\sqrt{d^{2} \sqrt{\frac{1}{a d^{2}}} + d x} a d \left (\frac{1}{a d^{2}}\right )^{\frac{3}{4}} - \sqrt{d x} a d \left (\frac{1}{a d^{2}}\right )^{\frac{3}{4}}\right ) - 4 \, d \left (\frac{1}{a d^{2}}\right )^{\frac{1}{4}} \log \left (d \left (\frac{1}{a d^{2}}\right )^{\frac{1}{4}} + \sqrt{d x}\right ) + 4 \, d \left (\frac{1}{a d^{2}}\right )^{\frac{1}{4}} \log \left (-d \left (\frac{1}{a d^{2}}\right )^{\frac{1}{4}} + \sqrt{d x}\right ) - \sqrt{d x}{\left ({\rm Li}_2\left (a x^{2}\right ) + 4 \, \log \left (-a x^{2} + 1\right ) - 16\right )}\right )}}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{Li}_{2}\left (a x^{2}\right )}{\sqrt{d x}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\rm Li}_2\left (a x^{2}\right )}{\sqrt{d x}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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