Optimal. Leaf size=102 \[ \frac{2 (d x)^{3/2} \text{PolyLog}(2,a x)}{3 d}+\frac{8 \sqrt{d} \tanh ^{-1}\left (\frac{\sqrt{a} \sqrt{d x}}{\sqrt{d}}\right )}{9 a^{3/2}}-\frac{8 \sqrt{d x}}{9 a}+\frac{4 (d x)^{3/2} \log (1-a x)}{9 d}-\frac{8 (d x)^{3/2}}{27 d} \]
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Rubi [A] time = 0.0530667, antiderivative size = 102, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.385, Rules used = {6591, 2395, 50, 63, 206} \[ \frac{2 (d x)^{3/2} \text{PolyLog}(2,a x)}{3 d}+\frac{8 \sqrt{d} \tanh ^{-1}\left (\frac{\sqrt{a} \sqrt{d x}}{\sqrt{d}}\right )}{9 a^{3/2}}-\frac{8 \sqrt{d x}}{9 a}+\frac{4 (d x)^{3/2} \log (1-a x)}{9 d}-\frac{8 (d x)^{3/2}}{27 d} \]
Antiderivative was successfully verified.
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Rule 6591
Rule 2395
Rule 50
Rule 63
Rule 206
Rubi steps
\begin{align*} \int \sqrt{d x} \text{Li}_2(a x) \, dx &=\frac{2 (d x)^{3/2} \text{Li}_2(a x)}{3 d}+\frac{2}{3} \int \sqrt{d x} \log (1-a x) \, dx\\ &=\frac{4 (d x)^{3/2} \log (1-a x)}{9 d}+\frac{2 (d x)^{3/2} \text{Li}_2(a x)}{3 d}+\frac{(4 a) \int \frac{(d x)^{3/2}}{1-a x} \, dx}{9 d}\\ &=-\frac{8 (d x)^{3/2}}{27 d}+\frac{4 (d x)^{3/2} \log (1-a x)}{9 d}+\frac{2 (d x)^{3/2} \text{Li}_2(a x)}{3 d}+\frac{4}{9} \int \frac{\sqrt{d x}}{1-a x} \, dx\\ &=-\frac{8 \sqrt{d x}}{9 a}-\frac{8 (d x)^{3/2}}{27 d}+\frac{4 (d x)^{3/2} \log (1-a x)}{9 d}+\frac{2 (d x)^{3/2} \text{Li}_2(a x)}{3 d}+\frac{(4 d) \int \frac{1}{\sqrt{d x} (1-a x)} \, dx}{9 a}\\ &=-\frac{8 \sqrt{d x}}{9 a}-\frac{8 (d x)^{3/2}}{27 d}+\frac{4 (d x)^{3/2} \log (1-a x)}{9 d}+\frac{2 (d x)^{3/2} \text{Li}_2(a x)}{3 d}+\frac{8 \operatorname{Subst}\left (\int \frac{1}{1-\frac{a x^2}{d}} \, dx,x,\sqrt{d x}\right )}{9 a}\\ &=-\frac{8 \sqrt{d x}}{9 a}-\frac{8 (d x)^{3/2}}{27 d}+\frac{8 \sqrt{d} \tanh ^{-1}\left (\frac{\sqrt{a} \sqrt{d x}}{\sqrt{d}}\right )}{9 a^{3/2}}+\frac{4 (d x)^{3/2} \log (1-a x)}{9 d}+\frac{2 (d x)^{3/2} \text{Li}_2(a x)}{3 d}\\ \end{align*}
Mathematica [A] time = 0.0816363, size = 75, normalized size = 0.74 \[ \frac{2 \sqrt{d x} \left (9 x^{3/2} \text{PolyLog}(2,a x)+\frac{12 \tanh ^{-1}\left (\sqrt{a} \sqrt{x}\right )}{a^{3/2}}+\frac{2 \sqrt{x} (-2 a x+3 a x \log (1-a x)-6)}{a}\right )}{27 \sqrt{x}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.05, size = 83, normalized size = 0.8 \begin{align*}{\frac{2\,{\it polylog} \left ( 2,ax \right ) }{3\,d} \left ( dx \right ) ^{{\frac{3}{2}}}}+{\frac{4}{9\,d} \left ( dx \right ) ^{{\frac{3}{2}}}\ln \left ({\frac{-adx+d}{d}} \right ) }-{\frac{8}{27\,d} \left ( dx \right ) ^{{\frac{3}{2}}}}-{\frac{8}{9\,a}\sqrt{dx}}+{\frac{8\,d}{9\,a}{\it Artanh} \left ({a\sqrt{dx}{\frac{1}{\sqrt{ad}}}} \right ){\frac{1}{\sqrt{ad}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.56879, size = 362, normalized size = 3.55 \begin{align*} \left [\frac{2 \,{\left ({\left (9 \, a x{\rm Li}_2\left (a x\right ) + 6 \, a x \log \left (-a x + 1\right ) - 4 \, a x - 12\right )} \sqrt{d x} + 6 \, \sqrt{\frac{d}{a}} \log \left (\frac{a d x + 2 \, \sqrt{d x} a \sqrt{\frac{d}{a}} + d}{a x - 1}\right )\right )}}{27 \, a}, \frac{2 \,{\left ({\left (9 \, a x{\rm Li}_2\left (a x\right ) + 6 \, a x \log \left (-a x + 1\right ) - 4 \, a x - 12\right )} \sqrt{d x} - 12 \, \sqrt{-\frac{d}{a}} \arctan \left (\frac{\sqrt{d x} a \sqrt{-\frac{d}{a}}}{d}\right )\right )}}{27 \, a}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{d x}{\rm Li}_2\left (a x\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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