Optimal. Leaf size=111 \[ \frac{b^2 \text{Chi}(a+b x)}{2 a^2}-\frac{b^2 \cosh (a) \text{Chi}(b x)}{2 a^2}-\frac{b^2 \sinh (a) \text{Shi}(b x)}{2 a^2}+\frac{b^2 \sinh (a) \text{Chi}(b x)}{2 a}+\frac{b^2 \cosh (a) \text{Shi}(b x)}{2 a}-\frac{\text{Chi}(a+b x)}{2 x^2}-\frac{b \cosh (a+b x)}{2 a x} \]
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Rubi [A] time = 0.33124, antiderivative size = 111, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 6, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.6, Rules used = {6533, 6742, 3297, 3303, 3298, 3301} \[ \frac{b^2 \text{Chi}(a+b x)}{2 a^2}-\frac{b^2 \cosh (a) \text{Chi}(b x)}{2 a^2}-\frac{b^2 \sinh (a) \text{Shi}(b x)}{2 a^2}+\frac{b^2 \sinh (a) \text{Chi}(b x)}{2 a}+\frac{b^2 \cosh (a) \text{Shi}(b x)}{2 a}-\frac{\text{Chi}(a+b x)}{2 x^2}-\frac{b \cosh (a+b x)}{2 a x} \]
Antiderivative was successfully verified.
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Rule 6533
Rule 6742
Rule 3297
Rule 3303
Rule 3298
Rule 3301
Rubi steps
\begin{align*} \int \frac{\text{Chi}(a+b x)}{x^3} \, dx &=-\frac{\text{Chi}(a+b x)}{2 x^2}+\frac{1}{2} b \int \frac{\cosh (a+b x)}{x^2 (a+b x)} \, dx\\ &=-\frac{\text{Chi}(a+b x)}{2 x^2}+\frac{1}{2} b \int \left (\frac{\cosh (a+b x)}{a x^2}-\frac{b \cosh (a+b x)}{a^2 x}+\frac{b^2 \cosh (a+b x)}{a^2 (a+b x)}\right ) \, dx\\ &=-\frac{\text{Chi}(a+b x)}{2 x^2}+\frac{b \int \frac{\cosh (a+b x)}{x^2} \, dx}{2 a}-\frac{b^2 \int \frac{\cosh (a+b x)}{x} \, dx}{2 a^2}+\frac{b^3 \int \frac{\cosh (a+b x)}{a+b x} \, dx}{2 a^2}\\ &=-\frac{b \cosh (a+b x)}{2 a x}+\frac{b^2 \text{Chi}(a+b x)}{2 a^2}-\frac{\text{Chi}(a+b x)}{2 x^2}+\frac{b^2 \int \frac{\sinh (a+b x)}{x} \, dx}{2 a}-\frac{\left (b^2 \cosh (a)\right ) \int \frac{\cosh (b x)}{x} \, dx}{2 a^2}-\frac{\left (b^2 \sinh (a)\right ) \int \frac{\sinh (b x)}{x} \, dx}{2 a^2}\\ &=-\frac{b \cosh (a+b x)}{2 a x}-\frac{b^2 \cosh (a) \text{Chi}(b x)}{2 a^2}+\frac{b^2 \text{Chi}(a+b x)}{2 a^2}-\frac{\text{Chi}(a+b x)}{2 x^2}-\frac{b^2 \sinh (a) \text{Shi}(b x)}{2 a^2}+\frac{\left (b^2 \cosh (a)\right ) \int \frac{\sinh (b x)}{x} \, dx}{2 a}+\frac{\left (b^2 \sinh (a)\right ) \int \frac{\cosh (b x)}{x} \, dx}{2 a}\\ &=-\frac{b \cosh (a+b x)}{2 a x}-\frac{b^2 \cosh (a) \text{Chi}(b x)}{2 a^2}+\frac{b^2 \text{Chi}(a+b x)}{2 a^2}-\frac{\text{Chi}(a+b x)}{2 x^2}+\frac{b^2 \text{Chi}(b x) \sinh (a)}{2 a}+\frac{b^2 \cosh (a) \text{Shi}(b x)}{2 a}-\frac{b^2 \sinh (a) \text{Shi}(b x)}{2 a^2}\\ \end{align*}
Mathematica [A] time = 0.306355, size = 80, normalized size = 0.72 \[ \frac{\left (b^2 x^2-a^2\right ) \text{Chi}(a+b x)+b^2 x^2 (a \sinh (a)-\cosh (a)) \text{Chi}(b x)+b x (b x (a \cosh (a)-\sinh (a)) \text{Shi}(b x)-a \cosh (a+b x))}{2 a^2 x^2} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.056, size = 0, normalized size = 0. \begin{align*} \int{\frac{{\it Chi} \left ( bx+a \right ) }{{x}^{3}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\rm Chi}\left (b x + a\right )}{x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\operatorname{Chi}\left (b x + a\right )}{x^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{Chi}\left (a + b x\right )}{x^{3}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\rm Chi}\left (b x + a\right )}{x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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