3.42 \(\int \sinh (b x) \text{Shi}(b x) \, dx\)

Optimal. Leaf size=25 \[ \frac{\text{Shi}(b x) \cosh (b x)}{b}-\frac{\text{Shi}(2 b x)}{2 b} \]

[Out]

(Cosh[b*x]*SinhIntegral[b*x])/b - SinhIntegral[2*b*x]/(2*b)

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Rubi [A]  time = 0.0493246, antiderivative size = 25, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 9, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.444, Rules used = {6540, 12, 5448, 3298} \[ \frac{\text{Shi}(b x) \cosh (b x)}{b}-\frac{\text{Shi}(2 b x)}{2 b} \]

Antiderivative was successfully verified.

[In]

Int[Sinh[b*x]*SinhIntegral[b*x],x]

[Out]

(Cosh[b*x]*SinhIntegral[b*x])/b - SinhIntegral[2*b*x]/(2*b)

Rule 6540

Int[Sinh[(a_.) + (b_.)*(x_)]*SinhIntegral[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[(Cosh[a + b*x]*SinhIntegral[c
+ d*x])/b, x] - Dist[d/b, Int[(Cosh[a + b*x]*Sinh[c + d*x])/(c + d*x), x], x] /; FreeQ[{a, b, c, d}, x]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 5448

Int[Cosh[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sinh[(a_.) + (b_.)*(x_)]^(n_.), x_Symbol] :> Int
[ExpandTrigReduce[(c + d*x)^m, Sinh[a + b*x]^n*Cosh[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n,
0] && IGtQ[p, 0]

Rule 3298

Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[(I*SinhIntegral[(c*f*fz)
/d + f*fz*x])/d, x] /; FreeQ[{c, d, e, f, fz}, x] && EqQ[d*e - c*f*fz*I, 0]

Rubi steps

\begin{align*} \int \sinh (b x) \text{Shi}(b x) \, dx &=\frac{\cosh (b x) \text{Shi}(b x)}{b}-\int \frac{\cosh (b x) \sinh (b x)}{b x} \, dx\\ &=\frac{\cosh (b x) \text{Shi}(b x)}{b}-\frac{\int \frac{\cosh (b x) \sinh (b x)}{x} \, dx}{b}\\ &=\frac{\cosh (b x) \text{Shi}(b x)}{b}-\frac{\int \frac{\sinh (2 b x)}{2 x} \, dx}{b}\\ &=\frac{\cosh (b x) \text{Shi}(b x)}{b}-\frac{\int \frac{\sinh (2 b x)}{x} \, dx}{2 b}\\ &=\frac{\cosh (b x) \text{Shi}(b x)}{b}-\frac{\text{Shi}(2 b x)}{2 b}\\ \end{align*}

Mathematica [A]  time = 0.0098559, size = 25, normalized size = 1. \[ \frac{\text{Shi}(b x) \cosh (b x)}{b}-\frac{\text{Shi}(2 b x)}{2 b} \]

Antiderivative was successfully verified.

[In]

Integrate[Sinh[b*x]*SinhIntegral[b*x],x]

[Out]

(Cosh[b*x]*SinhIntegral[b*x])/b - SinhIntegral[2*b*x]/(2*b)

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Maple [A]  time = 0.045, size = 22, normalized size = 0.9 \begin{align*}{\frac{1}{b} \left ( \cosh \left ( bx \right ){\it Shi} \left ( bx \right ) -{\frac{{\it Shi} \left ( 2\,bx \right ) }{2}} \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(Shi(b*x)*sinh(b*x),x)

[Out]

1/b*(cosh(b*x)*Shi(b*x)-1/2*Shi(2*b*x))

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\rm Shi}\left (b x\right ) \sinh \left (b x\right )\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(Shi(b*x)*sinh(b*x),x, algorithm="maxima")

[Out]

integrate(Shi(b*x)*sinh(b*x), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\sinh \left (b x\right ) \operatorname{Shi}\left (b x\right ), x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(Shi(b*x)*sinh(b*x),x, algorithm="fricas")

[Out]

integral(sinh(b*x)*sinh_integral(b*x), x)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \sinh{\left (b x \right )} \operatorname{Shi}{\left (b x \right )}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(Shi(b*x)*sinh(b*x),x)

[Out]

Integral(sinh(b*x)*Shi(b*x), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\rm Shi}\left (b x\right ) \sinh \left (b x\right )\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(Shi(b*x)*sinh(b*x),x, algorithm="giac")

[Out]

integrate(Shi(b*x)*sinh(b*x), x)