Optimal. Leaf size=370 \[ \frac{\sin \left (a-\frac{b c}{d}\right ) \text{CosIntegral}\left (\frac{c (b-d)}{d}+x (b-d)\right )}{2 b^2}-\frac{\sin \left (a-\frac{b c}{d}\right ) \text{CosIntegral}\left (\frac{c (b+d)}{d}+x (b+d)\right )}{2 b^2}+\frac{\cos \left (a-\frac{b c}{d}\right ) \text{Si}\left (x (b-d)+\frac{c (b-d)}{d}\right )}{2 b^2}+\frac{\cos (a+b x) \text{Si}(c+d x)}{b^2}-\frac{\cos \left (a-\frac{b c}{d}\right ) \text{Si}\left (x (b+d)+\frac{c (b+d)}{d}\right )}{2 b^2}+\frac{c \cos \left (a-\frac{b c}{d}\right ) \text{CosIntegral}\left (\frac{c (b-d)}{d}+x (b-d)\right )}{2 b d}-\frac{c \cos \left (a-\frac{b c}{d}\right ) \text{CosIntegral}\left (\frac{c (b+d)}{d}+x (b+d)\right )}{2 b d}-\frac{c \sin \left (a-\frac{b c}{d}\right ) \text{Si}\left (x (b-d)+\frac{c (b-d)}{d}\right )}{2 b d}+\frac{x \sin (a+b x) \text{Si}(c+d x)}{b}+\frac{c \sin \left (a-\frac{b c}{d}\right ) \text{Si}\left (x (b+d)+\frac{c (b+d)}{d}\right )}{2 b d}-\frac{\sin (a+x (b-d)-c)}{2 b (b-d)}+\frac{\sin (a+x (b+d)+c)}{2 b (b+d)} \]
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Rubi [A] time = 1.24023, antiderivative size = 370, normalized size of antiderivative = 1., number of steps used = 24, number of rules used = 9, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.643, Rules used = {6519, 4608, 6742, 2637, 3303, 3299, 3302, 6511, 4430} \[ \frac{\sin \left (a-\frac{b c}{d}\right ) \text{CosIntegral}\left (\frac{c (b-d)}{d}+x (b-d)\right )}{2 b^2}-\frac{\sin \left (a-\frac{b c}{d}\right ) \text{CosIntegral}\left (\frac{c (b+d)}{d}+x (b+d)\right )}{2 b^2}+\frac{\cos \left (a-\frac{b c}{d}\right ) \text{Si}\left (x (b-d)+\frac{c (b-d)}{d}\right )}{2 b^2}+\frac{\cos (a+b x) \text{Si}(c+d x)}{b^2}-\frac{\cos \left (a-\frac{b c}{d}\right ) \text{Si}\left (x (b+d)+\frac{c (b+d)}{d}\right )}{2 b^2}+\frac{c \cos \left (a-\frac{b c}{d}\right ) \text{CosIntegral}\left (\frac{c (b-d)}{d}+x (b-d)\right )}{2 b d}-\frac{c \cos \left (a-\frac{b c}{d}\right ) \text{CosIntegral}\left (\frac{c (b+d)}{d}+x (b+d)\right )}{2 b d}-\frac{c \sin \left (a-\frac{b c}{d}\right ) \text{Si}\left (x (b-d)+\frac{c (b-d)}{d}\right )}{2 b d}+\frac{x \sin (a+b x) \text{Si}(c+d x)}{b}+\frac{c \sin \left (a-\frac{b c}{d}\right ) \text{Si}\left (x (b+d)+\frac{c (b+d)}{d}\right )}{2 b d}-\frac{\sin (a+x (b-d)-c)}{2 b (b-d)}+\frac{\sin (a+x (b+d)+c)}{2 b (b+d)} \]
Antiderivative was successfully verified.
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Rule 6519
Rule 4608
Rule 6742
Rule 2637
Rule 3303
Rule 3299
Rule 3302
Rule 6511
Rule 4430
Rubi steps
\begin{align*} \int x \cos (a+b x) \text{Si}(c+d x) \, dx &=\frac{x \sin (a+b x) \text{Si}(c+d x)}{b}-\frac{\int \sin (a+b x) \text{Si}(c+d x) \, dx}{b}-\frac{d \int \frac{x \sin (a+b x) \sin (c+d x)}{c+d x} \, dx}{b}\\ &=\frac{\cos (a+b x) \text{Si}(c+d x)}{b^2}+\frac{x \sin (a+b x) \text{Si}(c+d x)}{b}-\frac{d \int \frac{\cos (a+b x) \sin (c+d x)}{c+d x} \, dx}{b^2}-\frac{d \int \left (\frac{x \cos (a-c+(b-d) x)}{2 (c+d x)}-\frac{x \cos (a+c+(b+d) x)}{2 (c+d x)}\right ) \, dx}{b}\\ &=\frac{\cos (a+b x) \text{Si}(c+d x)}{b^2}+\frac{x \sin (a+b x) \text{Si}(c+d x)}{b}-\frac{d \int \left (-\frac{\sin (a-c+(b-d) x)}{2 (c+d x)}+\frac{\sin (a+c+(b+d) x)}{2 (c+d x)}\right ) \, dx}{b^2}-\frac{d \int \frac{x \cos (a-c+(b-d) x)}{c+d x} \, dx}{2 b}+\frac{d \int \frac{x \cos (a+c+(b+d) x)}{c+d x} \, dx}{2 b}\\ &=\frac{\cos (a+b x) \text{Si}(c+d x)}{b^2}+\frac{x \sin (a+b x) \text{Si}(c+d x)}{b}+\frac{d \int \frac{\sin (a-c+(b-d) x)}{c+d x} \, dx}{2 b^2}-\frac{d \int \frac{\sin (a+c+(b+d) x)}{c+d x} \, dx}{2 b^2}-\frac{d \int \left (\frac{\cos (a-c+(b-d) x)}{d}-\frac{c \cos (a-c+(b-d) x)}{d (c+d x)}\right ) \, dx}{2 b}+\frac{d \int \left (\frac{\cos (a+c+(b+d) x)}{d}-\frac{c \cos (a+c+(b+d) x)}{d (c+d x)}\right ) \, dx}{2 b}\\ &=\frac{\cos (a+b x) \text{Si}(c+d x)}{b^2}+\frac{x \sin (a+b x) \text{Si}(c+d x)}{b}-\frac{\int \cos (a-c+(b-d) x) \, dx}{2 b}+\frac{\int \cos (a+c+(b+d) x) \, dx}{2 b}+\frac{c \int \frac{\cos (a-c+(b-d) x)}{c+d x} \, dx}{2 b}-\frac{c \int \frac{\cos (a+c+(b+d) x)}{c+d x} \, dx}{2 b}+\frac{\left (d \cos \left (a-\frac{b c}{d}\right )\right ) \int \frac{\sin \left (\frac{c (b-d)}{d}+(b-d) x\right )}{c+d x} \, dx}{2 b^2}-\frac{\left (d \cos \left (a-\frac{b c}{d}\right )\right ) \int \frac{\sin \left (\frac{c (b+d)}{d}+(b+d) x\right )}{c+d x} \, dx}{2 b^2}+\frac{\left (d \sin \left (a-\frac{b c}{d}\right )\right ) \int \frac{\cos \left (\frac{c (b-d)}{d}+(b-d) x\right )}{c+d x} \, dx}{2 b^2}-\frac{\left (d \sin \left (a-\frac{b c}{d}\right )\right ) \int \frac{\cos \left (\frac{c (b+d)}{d}+(b+d) x\right )}{c+d x} \, dx}{2 b^2}\\ &=\frac{\text{Ci}\left (\frac{c (b-d)}{d}+(b-d) x\right ) \sin \left (a-\frac{b c}{d}\right )}{2 b^2}-\frac{\text{Ci}\left (\frac{c (b+d)}{d}+(b+d) x\right ) \sin \left (a-\frac{b c}{d}\right )}{2 b^2}-\frac{\sin (a-c+(b-d) x)}{2 b (b-d)}+\frac{\sin (a+c+(b+d) x)}{2 b (b+d)}+\frac{\cos \left (a-\frac{b c}{d}\right ) \text{Si}\left (\frac{c (b-d)}{d}+(b-d) x\right )}{2 b^2}+\frac{\cos (a+b x) \text{Si}(c+d x)}{b^2}+\frac{x \sin (a+b x) \text{Si}(c+d x)}{b}-\frac{\cos \left (a-\frac{b c}{d}\right ) \text{Si}\left (\frac{c (b+d)}{d}+(b+d) x\right )}{2 b^2}+\frac{\left (c \cos \left (a-\frac{b c}{d}\right )\right ) \int \frac{\cos \left (\frac{c (b-d)}{d}+(b-d) x\right )}{c+d x} \, dx}{2 b}-\frac{\left (c \cos \left (a-\frac{b c}{d}\right )\right ) \int \frac{\cos \left (\frac{c (b+d)}{d}+(b+d) x\right )}{c+d x} \, dx}{2 b}-\frac{\left (c \sin \left (a-\frac{b c}{d}\right )\right ) \int \frac{\sin \left (\frac{c (b-d)}{d}+(b-d) x\right )}{c+d x} \, dx}{2 b}+\frac{\left (c \sin \left (a-\frac{b c}{d}\right )\right ) \int \frac{\sin \left (\frac{c (b+d)}{d}+(b+d) x\right )}{c+d x} \, dx}{2 b}\\ &=\frac{c \cos \left (a-\frac{b c}{d}\right ) \text{Ci}\left (\frac{c (b-d)}{d}+(b-d) x\right )}{2 b d}-\frac{c \cos \left (a-\frac{b c}{d}\right ) \text{Ci}\left (\frac{c (b+d)}{d}+(b+d) x\right )}{2 b d}+\frac{\text{Ci}\left (\frac{c (b-d)}{d}+(b-d) x\right ) \sin \left (a-\frac{b c}{d}\right )}{2 b^2}-\frac{\text{Ci}\left (\frac{c (b+d)}{d}+(b+d) x\right ) \sin \left (a-\frac{b c}{d}\right )}{2 b^2}-\frac{\sin (a-c+(b-d) x)}{2 b (b-d)}+\frac{\sin (a+c+(b+d) x)}{2 b (b+d)}+\frac{\cos \left (a-\frac{b c}{d}\right ) \text{Si}\left (\frac{c (b-d)}{d}+(b-d) x\right )}{2 b^2}-\frac{c \sin \left (a-\frac{b c}{d}\right ) \text{Si}\left (\frac{c (b-d)}{d}+(b-d) x\right )}{2 b d}+\frac{\cos (a+b x) \text{Si}(c+d x)}{b^2}+\frac{x \sin (a+b x) \text{Si}(c+d x)}{b}-\frac{\cos \left (a-\frac{b c}{d}\right ) \text{Si}\left (\frac{c (b+d)}{d}+(b+d) x\right )}{2 b^2}+\frac{c \sin \left (a-\frac{b c}{d}\right ) \text{Si}\left (\frac{c (b+d)}{d}+(b+d) x\right )}{2 b d}\\ \end{align*}
Mathematica [C] time = 4.21426, size = 393, normalized size = 1.06 \[ \frac{e^{-\frac{i (d (a-d x)+b (c+d x))}{d}} \left (-\left (b^2-d^2\right ) (b c-i d) e^{i (2 a+x (b-d))} \text{ExpIntegralEi}\left (\frac{i (b+d) (c+d x)}{d}\right )-i b d e^{\frac{i c (b+d)}{d}} \left (-d e^{2 i (a+b x)}+b e^{2 i (a+b x)}+b+d\right )+\left (b^2-d^2\right ) (b c+i d) e^{i b \left (\frac{2 c}{d}+x\right )-i d x} \text{ExpIntegralEi}\left (-\frac{i (b-d) (c+d x)}{d}\right )\right )}{4 b^2 d (b-d) (b+d)}-\frac{e^{-i (a+c)} \left ((-b c+i d) e^{\frac{i (d (2 a+c)-b c)}{d}} \text{ExpIntegralEi}\left (\frac{i (b-d) (c+d x)}{d}\right )-i b d \left (\frac{e^{i (2 a+x (b-d))}}{b-d}+\frac{e^{-i x (b+d)}}{b+d}\right )+(b c+i d) e^{\frac{i c (b+d)}{d}} \text{ExpIntegralEi}\left (-\frac{i (b+d) (c+d x)}{d}\right )\right )}{4 b^2 d}+\frac{\text{Si}(c+d x) (b x \sin (a+b x)+\cos (a+b x))}{b^2} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.107, size = 1208, normalized size = 3.3 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x{\rm Si}\left (d x + c\right ) \cos \left (b x + a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (x \cos \left (b x + a\right ) \operatorname{Si}\left (d x + c\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x \cos{\left (a + b x \right )} \operatorname{Si}{\left (c + d x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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