Optimal. Leaf size=98 \[ -\frac{\text{CosIntegral}(2 b x)}{b^3}-\frac{2 \text{Si}(b x) \sin (b x)}{b^3}+\frac{2 x \text{Si}(b x) \cos (b x)}{b^2}+\frac{\log (x)}{b^3}-\frac{5 \sin ^2(b x)}{4 b^3}+\frac{x \sin (b x) \cos (b x)}{2 b^2}+\frac{x^2 \text{Si}(b x) \sin (b x)}{b}-\frac{x^2}{4 b} \]
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Rubi [A] time = 0.122718, antiderivative size = 98, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 9, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.75, Rules used = {6519, 12, 3310, 30, 6513, 2564, 6517, 3312, 3302} \[ -\frac{\text{CosIntegral}(2 b x)}{b^3}-\frac{2 \text{Si}(b x) \sin (b x)}{b^3}+\frac{2 x \text{Si}(b x) \cos (b x)}{b^2}+\frac{\log (x)}{b^3}-\frac{5 \sin ^2(b x)}{4 b^3}+\frac{x \sin (b x) \cos (b x)}{2 b^2}+\frac{x^2 \text{Si}(b x) \sin (b x)}{b}-\frac{x^2}{4 b} \]
Antiderivative was successfully verified.
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Rule 6519
Rule 12
Rule 3310
Rule 30
Rule 6513
Rule 2564
Rule 6517
Rule 3312
Rule 3302
Rubi steps
\begin{align*} \int x^2 \cos (b x) \text{Si}(b x) \, dx &=\frac{x^2 \sin (b x) \text{Si}(b x)}{b}-\frac{2 \int x \sin (b x) \text{Si}(b x) \, dx}{b}-\int \frac{x \sin ^2(b x)}{b} \, dx\\ &=\frac{2 x \cos (b x) \text{Si}(b x)}{b^2}+\frac{x^2 \sin (b x) \text{Si}(b x)}{b}-\frac{2 \int \cos (b x) \text{Si}(b x) \, dx}{b^2}-\frac{\int x \sin ^2(b x) \, dx}{b}-\frac{2 \int \frac{\cos (b x) \sin (b x)}{b} \, dx}{b}\\ &=\frac{x \cos (b x) \sin (b x)}{2 b^2}-\frac{\sin ^2(b x)}{4 b^3}+\frac{2 x \cos (b x) \text{Si}(b x)}{b^2}-\frac{2 \sin (b x) \text{Si}(b x)}{b^3}+\frac{x^2 \sin (b x) \text{Si}(b x)}{b}-\frac{2 \int \cos (b x) \sin (b x) \, dx}{b^2}+\frac{2 \int \frac{\sin ^2(b x)}{b x} \, dx}{b^2}-\frac{\int x \, dx}{2 b}\\ &=-\frac{x^2}{4 b}+\frac{x \cos (b x) \sin (b x)}{2 b^2}-\frac{\sin ^2(b x)}{4 b^3}+\frac{2 x \cos (b x) \text{Si}(b x)}{b^2}-\frac{2 \sin (b x) \text{Si}(b x)}{b^3}+\frac{x^2 \sin (b x) \text{Si}(b x)}{b}+\frac{2 \int \frac{\sin ^2(b x)}{x} \, dx}{b^3}-\frac{2 \operatorname{Subst}(\int x \, dx,x,\sin (b x))}{b^3}\\ &=-\frac{x^2}{4 b}+\frac{x \cos (b x) \sin (b x)}{2 b^2}-\frac{5 \sin ^2(b x)}{4 b^3}+\frac{2 x \cos (b x) \text{Si}(b x)}{b^2}-\frac{2 \sin (b x) \text{Si}(b x)}{b^3}+\frac{x^2 \sin (b x) \text{Si}(b x)}{b}+\frac{2 \int \left (\frac{1}{2 x}-\frac{\cos (2 b x)}{2 x}\right ) \, dx}{b^3}\\ &=-\frac{x^2}{4 b}+\frac{\log (x)}{b^3}+\frac{x \cos (b x) \sin (b x)}{2 b^2}-\frac{5 \sin ^2(b x)}{4 b^3}+\frac{2 x \cos (b x) \text{Si}(b x)}{b^2}-\frac{2 \sin (b x) \text{Si}(b x)}{b^3}+\frac{x^2 \sin (b x) \text{Si}(b x)}{b}-\frac{\int \frac{\cos (2 b x)}{x} \, dx}{b^3}\\ &=-\frac{x^2}{4 b}-\frac{\text{Ci}(2 b x)}{b^3}+\frac{\log (x)}{b^3}+\frac{x \cos (b x) \sin (b x)}{2 b^2}-\frac{5 \sin ^2(b x)}{4 b^3}+\frac{2 x \cos (b x) \text{Si}(b x)}{b^2}-\frac{2 \sin (b x) \text{Si}(b x)}{b^3}+\frac{x^2 \sin (b x) \text{Si}(b x)}{b}\\ \end{align*}
Mathematica [A] time = 0.0967561, size = 72, normalized size = 0.73 \[ \frac{8 \text{Si}(b x) \left (\left (b^2 x^2-2\right ) \sin (b x)+2 b x \cos (b x)\right )-2 b^2 x^2-8 \text{CosIntegral}(2 b x)+2 b x \sin (2 b x)+5 \cos (2 b x)+8 \log (x)}{8 b^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.065, size = 105, normalized size = 1.1 \begin{align*}{\frac{{x}^{2}{\it Si} \left ( bx \right ) \sin \left ( bx \right ) }{b}}+2\,{\frac{x\cos \left ( bx \right ){\it Si} \left ( bx \right ) }{{b}^{2}}}-2\,{\frac{{\it Si} \left ( bx \right ) \sin \left ( bx \right ) }{{b}^{3}}}+{\frac{x\cos \left ( bx \right ) \sin \left ( bx \right ) }{2\,{b}^{2}}}-{\frac{{x}^{2}}{4\,b}}-{\frac{ \left ( \sin \left ( bx \right ) \right ) ^{2}}{4\,{b}^{3}}}+{\frac{\ln \left ( bx \right ) }{{b}^{3}}}-{\frac{{\it Ci} \left ( 2\,bx \right ) }{{b}^{3}}}+{\frac{ \left ( \cos \left ( bx \right ) \right ) ^{2}}{{b}^{3}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{2}{\rm Si}\left (b x\right ) \cos \left (b x\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (x^{2} \cos \left (b x\right ) \operatorname{Si}\left (b x\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{2} \cos{\left (b x \right )} \operatorname{Si}{\left (b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.17171, size = 88, normalized size = 0.9 \begin{align*}{\left (\frac{2 \, x \cos \left (b x\right )}{b^{2}} + \frac{{\left (b^{2} x^{2} - 2\right )} \sin \left (b x\right )}{b^{3}}\right )} \operatorname{Si}\left (b x\right ) - \frac{b^{2} x^{2} + 2 \, \operatorname{Ci}\left (2 \, b x\right ) + 2 \, \operatorname{Ci}\left (-2 \, b x\right ) - 4 \, \log \left (x\right )}{4 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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