Optimal. Leaf size=127 \[ -\frac{b S(b x) \sin \left (\frac{1}{2} \pi b^2 x^2\right )}{6 x^3}-\frac{\pi b^3 S(b x) \cos \left (\frac{1}{2} \pi b^2 x^2\right )}{6 x}-\frac{1}{12} \pi ^2 b^4 S(b x)^2+\frac{1}{12} \pi b^4 \text{Si}\left (b^2 \pi x^2\right )-\frac{b^2}{24 x^2}+\frac{b^2 \cos \left (\pi b^2 x^2\right )}{24 x^2}-\frac{S(b x)^2}{4 x^4} \]
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Rubi [A] time = 0.143154, antiderivative size = 127, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 9, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.9, Rules used = {6430, 6456, 6464, 6440, 30, 3375, 3380, 3297, 3299} \[ -\frac{b S(b x) \sin \left (\frac{1}{2} \pi b^2 x^2\right )}{6 x^3}-\frac{\pi b^3 S(b x) \cos \left (\frac{1}{2} \pi b^2 x^2\right )}{6 x}-\frac{1}{12} \pi ^2 b^4 S(b x)^2+\frac{1}{12} \pi b^4 \text{Si}\left (b^2 \pi x^2\right )-\frac{b^2}{24 x^2}+\frac{b^2 \cos \left (\pi b^2 x^2\right )}{24 x^2}-\frac{S(b x)^2}{4 x^4} \]
Antiderivative was successfully verified.
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Rule 6430
Rule 6456
Rule 6464
Rule 6440
Rule 30
Rule 3375
Rule 3380
Rule 3297
Rule 3299
Rubi steps
\begin{align*} \int \frac{S(b x)^2}{x^5} \, dx &=-\frac{S(b x)^2}{4 x^4}+\frac{1}{2} b \int \frac{S(b x) \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{x^4} \, dx\\ &=-\frac{b^2}{24 x^2}-\frac{S(b x)^2}{4 x^4}-\frac{b S(b x) \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{6 x^3}-\frac{1}{12} b^2 \int \frac{\cos \left (b^2 \pi x^2\right )}{x^3} \, dx+\frac{1}{6} \left (b^3 \pi \right ) \int \frac{\cos \left (\frac{1}{2} b^2 \pi x^2\right ) S(b x)}{x^2} \, dx\\ &=-\frac{b^2}{24 x^2}-\frac{b^3 \pi \cos \left (\frac{1}{2} b^2 \pi x^2\right ) S(b x)}{6 x}-\frac{S(b x)^2}{4 x^4}-\frac{b S(b x) \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{6 x^3}-\frac{1}{24} b^2 \operatorname{Subst}\left (\int \frac{\cos \left (b^2 \pi x\right )}{x^2} \, dx,x,x^2\right )+\frac{1}{12} \left (b^4 \pi \right ) \int \frac{\sin \left (b^2 \pi x^2\right )}{x} \, dx-\frac{1}{6} \left (b^5 \pi ^2\right ) \int S(b x) \sin \left (\frac{1}{2} b^2 \pi x^2\right ) \, dx\\ &=-\frac{b^2}{24 x^2}+\frac{b^2 \cos \left (b^2 \pi x^2\right )}{24 x^2}-\frac{b^3 \pi \cos \left (\frac{1}{2} b^2 \pi x^2\right ) S(b x)}{6 x}-\frac{S(b x)^2}{4 x^4}-\frac{b S(b x) \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{6 x^3}+\frac{1}{24} b^4 \pi \text{Si}\left (b^2 \pi x^2\right )+\frac{1}{24} \left (b^4 \pi \right ) \operatorname{Subst}\left (\int \frac{\sin \left (b^2 \pi x\right )}{x} \, dx,x,x^2\right )-\frac{1}{6} \left (b^4 \pi ^2\right ) \operatorname{Subst}(\int x \, dx,x,S(b x))\\ &=-\frac{b^2}{24 x^2}+\frac{b^2 \cos \left (b^2 \pi x^2\right )}{24 x^2}-\frac{b^3 \pi \cos \left (\frac{1}{2} b^2 \pi x^2\right ) S(b x)}{6 x}-\frac{1}{12} b^4 \pi ^2 S(b x)^2-\frac{S(b x)^2}{4 x^4}-\frac{b S(b x) \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{6 x^3}+\frac{1}{12} b^4 \pi \text{Si}\left (b^2 \pi x^2\right )\\ \end{align*}
Mathematica [A] time = 0.0060233, size = 127, normalized size = 1. \[ -\frac{b S(b x) \sin \left (\frac{1}{2} \pi b^2 x^2\right )}{6 x^3}-\frac{\pi b^3 S(b x) \cos \left (\frac{1}{2} \pi b^2 x^2\right )}{6 x}-\frac{1}{12} \pi ^2 b^4 S(b x)^2+\frac{1}{12} \pi b^4 \text{Si}\left (b^2 \pi x^2\right )-\frac{b^2}{24 x^2}+\frac{b^2 \cos \left (\pi b^2 x^2\right )}{24 x^2}-\frac{S(b x)^2}{4 x^4} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.062, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ({\it FresnelS} \left ( bx \right ) \right ) ^{2}}{{x}^{5}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\rm fresnels}\left (b x\right )^{2}}{x^{5}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\rm fresnels}\left (b x\right )^{2}}{x^{5}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{S^{2}\left (b x\right )}{x^{5}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\rm fresnels}\left (b x\right )^{2}}{x^{5}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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