3.38 \(\int S(b x)^2 \, dx\)

Optimal. Leaf size=55 \[ \frac{2 S(b x) \cos \left (\frac{1}{2} \pi b^2 x^2\right )}{\pi b}+x S(b x)^2-\frac{S\left (\sqrt{2} b x\right )}{\sqrt{2} \pi b} \]

[Out]

(2*Cos[(b^2*Pi*x^2)/2]*FresnelS[b*x])/(b*Pi) + x*FresnelS[b*x]^2 - FresnelS[Sqrt[2]*b*x]/(Sqrt[2]*b*Pi)

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Rubi [A]  time = 0.0383974, antiderivative size = 55, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 6, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.667, Rules used = {6420, 12, 6452, 3351} \[ \frac{2 S(b x) \cos \left (\frac{1}{2} \pi b^2 x^2\right )}{\pi b}+x S(b x)^2-\frac{S\left (\sqrt{2} b x\right )}{\sqrt{2} \pi b} \]

Antiderivative was successfully verified.

[In]

Int[FresnelS[b*x]^2,x]

[Out]

(2*Cos[(b^2*Pi*x^2)/2]*FresnelS[b*x])/(b*Pi) + x*FresnelS[b*x]^2 - FresnelS[Sqrt[2]*b*x]/(Sqrt[2]*b*Pi)

Rule 6420

Int[FresnelS[(a_.) + (b_.)*(x_)]^2, x_Symbol] :> Simp[((a + b*x)*FresnelS[a + b*x]^2)/b, x] - Dist[2, Int[(a +
b*x)*Sin[(Pi*(a + b*x)^2)/2]*FresnelS[a + b*x], x], x] /; FreeQ[{a, b}, x]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 6452

Int[FresnelS[(b_.)*(x_)]*(x_)*Sin[(d_.)*(x_)^2], x_Symbol] :> -Simp[(Cos[d*x^2]*FresnelS[b*x])/(2*d), x] + Dis
t[1/(2*b*Pi), Int[Sin[2*d*x^2], x], x] /; FreeQ[{b, d}, x] && EqQ[d^2, (Pi^2*b^4)/4]

Rule 3351

Int[Sin[(d_.)*((e_.) + (f_.)*(x_))^2], x_Symbol] :> Simp[(Sqrt[Pi/2]*FresnelS[Sqrt[2/Pi]*Rt[d, 2]*(e + f*x)])/
(f*Rt[d, 2]), x] /; FreeQ[{d, e, f}, x]

Rubi steps

\begin{align*} \int S(b x)^2 \, dx &=x S(b x)^2-2 \int b x S(b x) \sin \left (\frac{1}{2} b^2 \pi x^2\right ) \, dx\\ &=x S(b x)^2-(2 b) \int x S(b x) \sin \left (\frac{1}{2} b^2 \pi x^2\right ) \, dx\\ &=\frac{2 \cos \left (\frac{1}{2} b^2 \pi x^2\right ) S(b x)}{b \pi }+x S(b x)^2-\frac{\int \sin \left (b^2 \pi x^2\right ) \, dx}{\pi }\\ &=\frac{2 \cos \left (\frac{1}{2} b^2 \pi x^2\right ) S(b x)}{b \pi }+x S(b x)^2-\frac{S\left (\sqrt{2} b x\right )}{\sqrt{2} b \pi }\\ \end{align*}

Mathematica [A]  time = 0.0093133, size = 55, normalized size = 1. \[ \frac{2 S(b x) \cos \left (\frac{1}{2} \pi b^2 x^2\right )}{\pi b}+x S(b x)^2-\frac{S\left (\sqrt{2} b x\right )}{\sqrt{2} \pi b} \]

Antiderivative was successfully verified.

[In]

Integrate[FresnelS[b*x]^2,x]

[Out]

(2*Cos[(b^2*Pi*x^2)/2]*FresnelS[b*x])/(b*Pi) + x*FresnelS[b*x]^2 - FresnelS[Sqrt[2]*b*x]/(Sqrt[2]*b*Pi)

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Maple [A]  time = 0.056, size = 49, normalized size = 0.9 \begin{align*}{\frac{1}{b} \left ( bx \left ({\it FresnelS} \left ( bx \right ) \right ) ^{2}+2\,{\frac{\cos \left ( 1/2\,{b}^{2}\pi \,{x}^{2} \right ){\it FresnelS} \left ( bx \right ) }{\pi }}-{\frac{\sqrt{2}{\it FresnelS} \left ( bx\sqrt{2} \right ) }{2\,\pi }} \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(FresnelS(b*x)^2,x)

[Out]

1/b*(b*x*FresnelS(b*x)^2+2*FresnelS(b*x)/Pi*cos(1/2*b^2*Pi*x^2)-1/2/Pi*2^(1/2)*FresnelS(b*x*2^(1/2)))

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\rm fresnels}\left (b x\right )^{2}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnels(b*x)^2,x, algorithm="maxima")

[Out]

integrate(fresnels(b*x)^2, x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\rm fresnels}\left (b x\right )^{2}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnels(b*x)^2,x, algorithm="fricas")

[Out]

integral(fresnels(b*x)^2, x)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int S^{2}\left (b x\right )\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnels(b*x)**2,x)

[Out]

Integral(fresnels(b*x)**2, x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\rm fresnels}\left (b x\right )^{2}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnels(b*x)^2,x, algorithm="giac")

[Out]

integrate(fresnels(b*x)^2, x)