3.209 \(\int \frac{\text{FresnelC}(b x) \sin (\frac{1}{2} b^2 \pi x^2)}{x} \, dx\)

Optimal. Leaf size=22 \[ \text{Unintegrable}\left (\frac{\text{FresnelC}(b x) \sin \left (\frac{1}{2} \pi b^2 x^2\right )}{x},x\right ) \]

[Out]

Unintegrable[(FresnelC[b*x]*Sin[(b^2*Pi*x^2)/2])/x, x]

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Rubi [A]  time = 0.0172122, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int \frac{\text{FresnelC}(b x) \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{x} \, dx \]

Verification is Not applicable to the result.

[In]

Int[(FresnelC[b*x]*Sin[(b^2*Pi*x^2)/2])/x,x]

[Out]

Defer[Int][(FresnelC[b*x]*Sin[(b^2*Pi*x^2)/2])/x, x]

Rubi steps

\begin{align*} \int \frac{C(b x) \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{x} \, dx &=\int \frac{C(b x) \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{x} \, dx\\ \end{align*}

Mathematica [A]  time = 0.0320878, size = 0, normalized size = 0. \[ \int \frac{\text{FresnelC}(b x) \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{x} \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[(FresnelC[b*x]*Sin[(b^2*Pi*x^2)/2])/x,x]

[Out]

Integrate[(FresnelC[b*x]*Sin[(b^2*Pi*x^2)/2])/x, x]

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Maple [A]  time = 0.084, size = 0, normalized size = 0. \begin{align*} \int{\frac{{\it FresnelC} \left ( bx \right ) }{x}\sin \left ({\frac{{b}^{2}\pi \,{x}^{2}}{2}} \right ) }\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(FresnelC(b*x)*sin(1/2*b^2*Pi*x^2)/x,x)

[Out]

int(FresnelC(b*x)*sin(1/2*b^2*Pi*x^2)/x,x)

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Maxima [A]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\rm fresnelc}\left (b x\right ) \sin \left (\frac{1}{2} \, \pi b^{2} x^{2}\right )}{x}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnelc(b*x)*sin(1/2*b^2*pi*x^2)/x,x, algorithm="maxima")

[Out]

integrate(fresnelc(b*x)*sin(1/2*pi*b^2*x^2)/x, x)

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Fricas [A]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\rm fresnelc}\left (b x\right ) \sin \left (\frac{1}{2} \, \pi b^{2} x^{2}\right )}{x}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnelc(b*x)*sin(1/2*b^2*pi*x^2)/x,x, algorithm="fricas")

[Out]

integral(fresnelc(b*x)*sin(1/2*pi*b^2*x^2)/x, x)

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Sympy [A]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sin{\left (\frac{\pi b^{2} x^{2}}{2} \right )} C\left (b x\right )}{x}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnelc(b*x)*sin(1/2*b**2*pi*x**2)/x,x)

[Out]

Integral(sin(pi*b**2*x**2/2)*fresnelc(b*x)/x, x)

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Giac [A]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\rm fresnelc}\left (b x\right ) \sin \left (\frac{1}{2} \, \pi b^{2} x^{2}\right )}{x}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnelc(b*x)*sin(1/2*b^2*pi*x^2)/x,x, algorithm="giac")

[Out]

integrate(fresnelc(b*x)*sin(1/2*pi*b^2*x^2)/x, x)