Optimal. Leaf size=119 \[ \frac{1}{840} \pi ^4 b^8 S(b x)+\frac{\pi ^2 b^5 \sin \left (\frac{1}{2} \pi b^2 x^2\right )}{840 x^3}-\frac{b \sin \left (\frac{1}{2} \pi b^2 x^2\right )}{56 x^7}+\frac{\pi ^3 b^7 \cos \left (\frac{1}{2} \pi b^2 x^2\right )}{840 x}-\frac{\pi b^3 \cos \left (\frac{1}{2} \pi b^2 x^2\right )}{280 x^5}-\frac{S(b x)}{8 x^8} \]
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Rubi [A] time = 0.0810103, antiderivative size = 119, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 8, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {6426, 3387, 3388, 3351} \[ \frac{1}{840} \pi ^4 b^8 S(b x)+\frac{\pi ^2 b^5 \sin \left (\frac{1}{2} \pi b^2 x^2\right )}{840 x^3}-\frac{b \sin \left (\frac{1}{2} \pi b^2 x^2\right )}{56 x^7}+\frac{\pi ^3 b^7 \cos \left (\frac{1}{2} \pi b^2 x^2\right )}{840 x}-\frac{\pi b^3 \cos \left (\frac{1}{2} \pi b^2 x^2\right )}{280 x^5}-\frac{S(b x)}{8 x^8} \]
Antiderivative was successfully verified.
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Rule 6426
Rule 3387
Rule 3388
Rule 3351
Rubi steps
\begin{align*} \int \frac{S(b x)}{x^9} \, dx &=-\frac{S(b x)}{8 x^8}+\frac{1}{8} b \int \frac{\sin \left (\frac{1}{2} b^2 \pi x^2\right )}{x^8} \, dx\\ &=-\frac{S(b x)}{8 x^8}-\frac{b \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{56 x^7}+\frac{1}{56} \left (b^3 \pi \right ) \int \frac{\cos \left (\frac{1}{2} b^2 \pi x^2\right )}{x^6} \, dx\\ &=-\frac{b^3 \pi \cos \left (\frac{1}{2} b^2 \pi x^2\right )}{280 x^5}-\frac{S(b x)}{8 x^8}-\frac{b \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{56 x^7}-\frac{1}{280} \left (b^5 \pi ^2\right ) \int \frac{\sin \left (\frac{1}{2} b^2 \pi x^2\right )}{x^4} \, dx\\ &=-\frac{b^3 \pi \cos \left (\frac{1}{2} b^2 \pi x^2\right )}{280 x^5}-\frac{S(b x)}{8 x^8}-\frac{b \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{56 x^7}+\frac{b^5 \pi ^2 \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{840 x^3}-\frac{1}{840} \left (b^7 \pi ^3\right ) \int \frac{\cos \left (\frac{1}{2} b^2 \pi x^2\right )}{x^2} \, dx\\ &=-\frac{b^3 \pi \cos \left (\frac{1}{2} b^2 \pi x^2\right )}{280 x^5}+\frac{b^7 \pi ^3 \cos \left (\frac{1}{2} b^2 \pi x^2\right )}{840 x}-\frac{S(b x)}{8 x^8}-\frac{b \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{56 x^7}+\frac{b^5 \pi ^2 \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{840 x^3}+\frac{1}{840} \left (b^9 \pi ^4\right ) \int \sin \left (\frac{1}{2} b^2 \pi x^2\right ) \, dx\\ &=-\frac{b^3 \pi \cos \left (\frac{1}{2} b^2 \pi x^2\right )}{280 x^5}+\frac{b^7 \pi ^3 \cos \left (\frac{1}{2} b^2 \pi x^2\right )}{840 x}+\frac{1}{840} b^8 \pi ^4 S(b x)-\frac{S(b x)}{8 x^8}-\frac{b \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{56 x^7}+\frac{b^5 \pi ^2 \sin \left (\frac{1}{2} b^2 \pi x^2\right )}{840 x^3}\\ \end{align*}
Mathematica [A] time = 0.0552173, size = 84, normalized size = 0.71 \[ \frac{\left (\pi ^4 b^8 x^8-105\right ) S(b x)+b x \left (\pi ^2 b^4 x^4-15\right ) \sin \left (\frac{1}{2} \pi b^2 x^2\right )+\pi b^3 x^3 \left (\pi ^2 b^4 x^4-3\right ) \cos \left (\frac{1}{2} \pi b^2 x^2\right )}{840 x^8} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.047, size = 109, normalized size = 0.9 \begin{align*}{b}^{8} \left ( -{\frac{{\it FresnelS} \left ( bx \right ) }{8\,{b}^{8}{x}^{8}}}-{\frac{1}{56\,{b}^{7}{x}^{7}}\sin \left ({\frac{{b}^{2}\pi \,{x}^{2}}{2}} \right ) }+{\frac{\pi }{56} \left ( -{\frac{1}{5\,{b}^{5}{x}^{5}}\cos \left ({\frac{{b}^{2}\pi \,{x}^{2}}{2}} \right ) }-{\frac{\pi }{5} \left ( -{\frac{1}{3\,{x}^{3}{b}^{3}}\sin \left ({\frac{{b}^{2}\pi \,{x}^{2}}{2}} \right ) }+{\frac{\pi }{3} \left ( -{\frac{1}{bx}\cos \left ({\frac{{b}^{2}\pi \,{x}^{2}}{2}} \right ) }-\pi \,{\it FresnelS} \left ( bx \right ) \right ) } \right ) } \right ) } \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\rm fresnels}\left (b x\right )}{x^{9}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\rm fresnels}\left (b x\right )}{x^{9}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 3.70966, size = 185, normalized size = 1.55 \begin{align*} \frac{\pi ^{4} b^{8} S\left (b x\right ) \Gamma \left (- \frac{5}{4}\right )}{3584 \Gamma \left (\frac{7}{4}\right )} + \frac{\pi ^{3} b^{7} \cos{\left (\frac{\pi b^{2} x^{2}}{2} \right )} \Gamma \left (- \frac{5}{4}\right )}{3584 x \Gamma \left (\frac{7}{4}\right )} + \frac{\pi ^{2} b^{5} \sin{\left (\frac{\pi b^{2} x^{2}}{2} \right )} \Gamma \left (- \frac{5}{4}\right )}{3584 x^{3} \Gamma \left (\frac{7}{4}\right )} - \frac{3 \pi b^{3} \cos{\left (\frac{\pi b^{2} x^{2}}{2} \right )} \Gamma \left (- \frac{5}{4}\right )}{3584 x^{5} \Gamma \left (\frac{7}{4}\right )} - \frac{15 b \sin{\left (\frac{\pi b^{2} x^{2}}{2} \right )} \Gamma \left (- \frac{5}{4}\right )}{3584 x^{7} \Gamma \left (\frac{7}{4}\right )} - \frac{15 S\left (b x\right ) \Gamma \left (- \frac{5}{4}\right )}{512 x^{8} \Gamma \left (\frac{7}{4}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\rm fresnels}\left (b x\right )}{x^{9}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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