Optimal. Leaf size=122 \[ -\frac{(b c-a d)^2 \text{FresnelC}(a+b x)}{2 b^2 d}-\frac{(b c-a d) \sin \left (\frac{1}{2} \pi (a+b x)^2\right )}{\pi b^2}+\frac{d S(a+b x)}{2 \pi b^2}-\frac{d (a+b x) \sin \left (\frac{1}{2} \pi (a+b x)^2\right )}{2 \pi b^2}+\frac{(c+d x)^2 \text{FresnelC}(a+b x)}{2 d} \]
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Rubi [A] time = 0.112805, antiderivative size = 122, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.583, Rules used = {6429, 3434, 3352, 3380, 2637, 3386, 3351} \[ -\frac{(b c-a d)^2 \text{FresnelC}(a+b x)}{2 b^2 d}-\frac{(b c-a d) \sin \left (\frac{1}{2} \pi (a+b x)^2\right )}{\pi b^2}+\frac{d S(a+b x)}{2 \pi b^2}-\frac{d (a+b x) \sin \left (\frac{1}{2} \pi (a+b x)^2\right )}{2 \pi b^2}+\frac{(c+d x)^2 \text{FresnelC}(a+b x)}{2 d} \]
Antiderivative was successfully verified.
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Rule 6429
Rule 3434
Rule 3352
Rule 3380
Rule 2637
Rule 3386
Rule 3351
Rubi steps
\begin{align*} \int (c+d x) C(a+b x) \, dx &=\frac{(c+d x)^2 C(a+b x)}{2 d}-\frac{b \int (c+d x)^2 \cos \left (\frac{1}{2} \pi (a+b x)^2\right ) \, dx}{2 d}\\ &=\frac{(c+d x)^2 C(a+b x)}{2 d}-\frac{\operatorname{Subst}\left (\int \left (b^2 c^2 \left (1+\frac{a d (-2 b c+a d)}{b^2 c^2}\right ) \cos \left (\frac{\pi x^2}{2}\right )+2 b c d \left (1-\frac{a d}{b c}\right ) x \cos \left (\frac{\pi x^2}{2}\right )+d^2 x^2 \cos \left (\frac{\pi x^2}{2}\right )\right ) \, dx,x,a+b x\right )}{2 b^2 d}\\ &=\frac{(c+d x)^2 C(a+b x)}{2 d}-\frac{d \operatorname{Subst}\left (\int x^2 \cos \left (\frac{\pi x^2}{2}\right ) \, dx,x,a+b x\right )}{2 b^2}-\frac{(b c-a d) \operatorname{Subst}\left (\int x \cos \left (\frac{\pi x^2}{2}\right ) \, dx,x,a+b x\right )}{b^2}-\frac{(b c-a d)^2 \operatorname{Subst}\left (\int \cos \left (\frac{\pi x^2}{2}\right ) \, dx,x,a+b x\right )}{2 b^2 d}\\ &=-\frac{(b c-a d)^2 C(a+b x)}{2 b^2 d}+\frac{(c+d x)^2 C(a+b x)}{2 d}-\frac{d (a+b x) \sin \left (\frac{1}{2} \pi (a+b x)^2\right )}{2 b^2 \pi }-\frac{(b c-a d) \operatorname{Subst}\left (\int \cos \left (\frac{\pi x}{2}\right ) \, dx,x,(a+b x)^2\right )}{2 b^2}+\frac{d \operatorname{Subst}\left (\int \sin \left (\frac{\pi x^2}{2}\right ) \, dx,x,a+b x\right )}{2 b^2 \pi }\\ &=-\frac{(b c-a d)^2 C(a+b x)}{2 b^2 d}+\frac{(c+d x)^2 C(a+b x)}{2 d}+\frac{d S(a+b x)}{2 b^2 \pi }-\frac{(b c-a d) \sin \left (\frac{1}{2} \pi (a+b x)^2\right )}{b^2 \pi }-\frac{d (a+b x) \sin \left (\frac{1}{2} \pi (a+b x)^2\right )}{2 b^2 \pi }\\ \end{align*}
Mathematica [A] time = 0.235525, size = 74, normalized size = 0.61 \[ \frac{-\pi (a+b x) \text{FresnelC}(a+b x) (a d-b (2 c+d x))+\sin \left (\frac{1}{2} \pi (a+b x)^2\right ) (a d-2 b c-b d x)+d S(a+b x)}{2 \pi b^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.053, size = 107, normalized size = 0.9 \begin{align*}{\frac{1}{b} \left ({\frac{{\it FresnelC} \left ( bx+a \right ) }{b} \left ({\frac{d \left ( bx+a \right ) ^{2}}{2}}-ad \left ( bx+a \right ) +bc \left ( bx+a \right ) \right ) }-{\frac{1}{2\,b} \left ({\frac{d \left ( bx+a \right ) }{\pi }\sin \left ({\frac{\pi \, \left ( bx+a \right ) ^{2}}{2}} \right ) }-{\frac{d{\it FresnelS} \left ( bx+a \right ) }{\pi }}+{\frac{-2\,ad+2\,bc}{\pi }\sin \left ({\frac{\pi \, \left ( bx+a \right ) ^{2}}{2}} \right ) } \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d x + c\right )}{\rm fresnelc}\left (b x + a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (d x + c\right )}{\rm fresnelc}\left (b x + a\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (c + d x\right ) C\left (a + b x\right )\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d x + c\right )}{\rm fresnelc}\left (b x + a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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