3.167 \(\int e^{c+b^2 x^2} x^5 \text{Erfc}(b x) \, dx\)

Optimal. Leaf size=118 \[ \frac{x^4 e^{b^2 x^2+c} \text{Erfc}(b x)}{2 b^2}-\frac{x^2 e^{b^2 x^2+c} \text{Erfc}(b x)}{b^4}+\frac{e^{b^2 x^2+c} \text{Erfc}(b x)}{b^6}-\frac{2 e^c x^3}{3 \sqrt{\pi } b^3}+\frac{2 e^c x}{\sqrt{\pi } b^5}+\frac{e^c x^5}{5 \sqrt{\pi } b} \]

[Out]

(2*E^c*x)/(b^5*Sqrt[Pi]) - (2*E^c*x^3)/(3*b^3*Sqrt[Pi]) + (E^c*x^5)/(5*b*Sqrt[Pi]) + (E^(c + b^2*x^2)*Erfc[b*x
])/b^6 - (E^(c + b^2*x^2)*x^2*Erfc[b*x])/b^4 + (E^(c + b^2*x^2)*x^4*Erfc[b*x])/(2*b^2)

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Rubi [A]  time = 0.146585, antiderivative size = 118, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.263, Rules used = {6386, 6383, 8, 12, 30} \[ \frac{x^4 e^{b^2 x^2+c} \text{Erfc}(b x)}{2 b^2}-\frac{x^2 e^{b^2 x^2+c} \text{Erfc}(b x)}{b^4}+\frac{e^{b^2 x^2+c} \text{Erfc}(b x)}{b^6}-\frac{2 e^c x^3}{3 \sqrt{\pi } b^3}+\frac{2 e^c x}{\sqrt{\pi } b^5}+\frac{e^c x^5}{5 \sqrt{\pi } b} \]

Antiderivative was successfully verified.

[In]

Int[E^(c + b^2*x^2)*x^5*Erfc[b*x],x]

[Out]

(2*E^c*x)/(b^5*Sqrt[Pi]) - (2*E^c*x^3)/(3*b^3*Sqrt[Pi]) + (E^c*x^5)/(5*b*Sqrt[Pi]) + (E^(c + b^2*x^2)*Erfc[b*x
])/b^6 - (E^(c + b^2*x^2)*x^2*Erfc[b*x])/b^4 + (E^(c + b^2*x^2)*x^4*Erfc[b*x])/(2*b^2)

Rule 6386

Int[E^((c_.) + (d_.)*(x_)^2)*Erfc[(a_.) + (b_.)*(x_)]*(x_)^(m_), x_Symbol] :> Simp[(x^(m - 1)*E^(c + d*x^2)*Er
fc[a + b*x])/(2*d), x] + (-Dist[(m - 1)/(2*d), Int[x^(m - 2)*E^(c + d*x^2)*Erfc[a + b*x], x], x] + Dist[b/(d*S
qrt[Pi]), Int[x^(m - 1)*E^(-a^2 + c - 2*a*b*x - (b^2 - d)*x^2), x], x]) /; FreeQ[{a, b, c, d}, x] && IGtQ[m, 1
]

Rule 6383

Int[E^((c_.) + (d_.)*(x_)^2)*Erfc[(a_.) + (b_.)*(x_)]*(x_), x_Symbol] :> Simp[(E^(c + d*x^2)*Erfc[a + b*x])/(2
*d), x] + Dist[b/(d*Sqrt[Pi]), Int[E^(-a^2 + c - 2*a*b*x - (b^2 - d)*x^2), x], x] /; FreeQ[{a, b, c, d}, x]

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rubi steps

\begin{align*} \int e^{c+b^2 x^2} x^5 \text{erfc}(b x) \, dx &=\frac{e^{c+b^2 x^2} x^4 \text{erfc}(b x)}{2 b^2}-\frac{2 \int e^{c+b^2 x^2} x^3 \text{erfc}(b x) \, dx}{b^2}+\frac{\int e^c x^4 \, dx}{b \sqrt{\pi }}\\ &=-\frac{e^{c+b^2 x^2} x^2 \text{erfc}(b x)}{b^4}+\frac{e^{c+b^2 x^2} x^4 \text{erfc}(b x)}{2 b^2}+\frac{2 \int e^{c+b^2 x^2} x \text{erfc}(b x) \, dx}{b^4}-\frac{2 \int e^c x^2 \, dx}{b^3 \sqrt{\pi }}+\frac{e^c \int x^4 \, dx}{b \sqrt{\pi }}\\ &=\frac{e^c x^5}{5 b \sqrt{\pi }}+\frac{e^{c+b^2 x^2} \text{erfc}(b x)}{b^6}-\frac{e^{c+b^2 x^2} x^2 \text{erfc}(b x)}{b^4}+\frac{e^{c+b^2 x^2} x^4 \text{erfc}(b x)}{2 b^2}+\frac{2 \int e^c \, dx}{b^5 \sqrt{\pi }}-\frac{\left (2 e^c\right ) \int x^2 \, dx}{b^3 \sqrt{\pi }}\\ &=\frac{2 e^c x}{b^5 \sqrt{\pi }}-\frac{2 e^c x^3}{3 b^3 \sqrt{\pi }}+\frac{e^c x^5}{5 b \sqrt{\pi }}+\frac{e^{c+b^2 x^2} \text{erfc}(b x)}{b^6}-\frac{e^{c+b^2 x^2} x^2 \text{erfc}(b x)}{b^4}+\frac{e^{c+b^2 x^2} x^4 \text{erfc}(b x)}{2 b^2}\\ \end{align*}

Mathematica [A]  time = 0.0470334, size = 73, normalized size = 0.62 \[ \frac{e^c \left (15 \sqrt{\pi } e^{b^2 x^2} \left (b^4 x^4-2 b^2 x^2+2\right ) \text{Erfc}(b x)+6 b^5 x^5-20 b^3 x^3+60 b x\right )}{30 \sqrt{\pi } b^6} \]

Antiderivative was successfully verified.

[In]

Integrate[E^(c + b^2*x^2)*x^5*Erfc[b*x],x]

[Out]

(E^c*(60*b*x - 20*b^3*x^3 + 6*b^5*x^5 + 15*E^(b^2*x^2)*Sqrt[Pi]*(2 - 2*b^2*x^2 + b^4*x^4)*Erfc[b*x]))/(30*b^6*
Sqrt[Pi])

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Maple [A]  time = 0.116, size = 135, normalized size = 1.1 \begin{align*}{\frac{1}{b} \left ({\frac{{{\rm e}^{c}}}{{b}^{5}} \left ({\frac{{{\rm e}^{{b}^{2}{x}^{2}}}{b}^{4}{x}^{4}}{2}}-{b}^{2}{x}^{2}{{\rm e}^{{b}^{2}{x}^{2}}}+{{\rm e}^{{b}^{2}{x}^{2}}} \right ) }-{\frac{{\it Erf} \left ( bx \right ){{\rm e}^{c}}}{{b}^{5}} \left ({\frac{{{\rm e}^{{b}^{2}{x}^{2}}}{b}^{4}{x}^{4}}{2}}-{b}^{2}{x}^{2}{{\rm e}^{{b}^{2}{x}^{2}}}+{{\rm e}^{{b}^{2}{x}^{2}}} \right ) }+{\frac{{{\rm e}^{c}}}{\sqrt{\pi }{b}^{5}} \left ({\frac{{b}^{5}{x}^{5}}{5}}-{\frac{2\,{x}^{3}{b}^{3}}{3}}+2\,bx \right ) } \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(b^2*x^2+c)*x^5*erfc(b*x),x)

[Out]

(1/b^5*exp(c)*(1/2*exp(b^2*x^2)*b^4*x^4-b^2*x^2*exp(b^2*x^2)+exp(b^2*x^2))-erf(b*x)/b^5*exp(c)*(1/2*exp(b^2*x^
2)*b^4*x^4-b^2*x^2*exp(b^2*x^2)+exp(b^2*x^2))+1/Pi^(1/2)/b^5*exp(c)*(1/5*b^5*x^5-2/3*x^3*b^3+2*b*x))/b

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{5} \operatorname{erfc}\left (b x\right ) e^{\left (b^{2} x^{2} + c\right )}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(b^2*x^2+c)*x^5*erfc(b*x),x, algorithm="maxima")

[Out]

integrate(x^5*erfc(b*x)*e^(b^2*x^2 + c), x)

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Fricas [A]  time = 2.18223, size = 227, normalized size = 1.92 \begin{align*} \frac{2 \, \sqrt{\pi }{\left (3 \, b^{5} x^{5} - 10 \, b^{3} x^{3} + 30 \, b x\right )} e^{c} + 15 \,{\left (2 \, \pi + \pi b^{4} x^{4} - 2 \, \pi b^{2} x^{2} -{\left (2 \, \pi + \pi b^{4} x^{4} - 2 \, \pi b^{2} x^{2}\right )} \operatorname{erf}\left (b x\right )\right )} e^{\left (b^{2} x^{2} + c\right )}}{30 \, \pi b^{6}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(b^2*x^2+c)*x^5*erfc(b*x),x, algorithm="fricas")

[Out]

1/30*(2*sqrt(pi)*(3*b^5*x^5 - 10*b^3*x^3 + 30*b*x)*e^c + 15*(2*pi + pi*b^4*x^4 - 2*pi*b^2*x^2 - (2*pi + pi*b^4
*x^4 - 2*pi*b^2*x^2)*erf(b*x))*e^(b^2*x^2 + c))/(pi*b^6)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(b**2*x**2+c)*x**5*erfc(b*x),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{5} \operatorname{erfc}\left (b x\right ) e^{\left (b^{2} x^{2} + c\right )}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(b^2*x^2+c)*x^5*erfc(b*x),x, algorithm="giac")

[Out]

integrate(x^5*erfc(b*x)*e^(b^2*x^2 + c), x)