Optimal. Leaf size=35 \[ \frac{\text{PolyLog}\left (2,-\frac{1}{a+b x}\right )}{2 b}-\frac{\text{PolyLog}\left (2,\frac{1}{a+b x}\right )}{2 b} \]
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Rubi [A] time = 0.0254893, antiderivative size = 35, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {6108, 5913} \[ \frac{\text{PolyLog}\left (2,-\frac{1}{a+b x}\right )}{2 b}-\frac{\text{PolyLog}\left (2,\frac{1}{a+b x}\right )}{2 b} \]
Antiderivative was successfully verified.
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Rule 6108
Rule 5913
Rubi steps
\begin{align*} \int \frac{\coth ^{-1}(a+b x)}{a+b x} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\coth ^{-1}(x)}{x} \, dx,x,a+b x\right )}{b}\\ &=\frac{\text{Li}_2\left (-\frac{1}{a+b x}\right )}{2 b}-\frac{\text{Li}_2\left (\frac{1}{a+b x}\right )}{2 b}\\ \end{align*}
Mathematica [B] time = 0.0254113, size = 286, normalized size = 8.17 \[ -\frac{\text{PolyLog}(2,-a-b x)}{2 b}+\frac{\text{PolyLog}(2,a+b x)}{2 b}-\frac{\log ^2\left (\frac{a b-(a-1) b}{b (a+b x)}\right )}{4 b}+\frac{\log ^2\left (\frac{a b-(a+1) b}{b (a+b x)}\right )}{4 b}-\frac{\log \left (\frac{b (a+b x-1)}{(a-1) b-a b}\right ) \log \left (\frac{a b-(a-1) b}{b (a+b x)}\right )}{2 b}+\frac{\log \left (\frac{a+b x-1}{a+b x}\right ) \log \left (\frac{a b-(a-1) b}{b (a+b x)}\right )}{2 b}+\frac{\log \left (\frac{b (-a-b x-1)}{(-a-1) b+a b}\right ) \log \left (\frac{a b-(a+1) b}{b (a+b x)}\right )}{2 b}-\frac{\log \left (\frac{a b-(a+1) b}{b (a+b x)}\right ) \log \left (\frac{a+b x+1}{a+b x}\right )}{2 b} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.042, size = 59, normalized size = 1.7 \begin{align*}{\frac{\ln \left ( bx+a \right ){\rm arccoth} \left (bx+a\right )}{b}}-{\frac{{\it dilog} \left ( bx+a \right ) }{2\,b}}-{\frac{{\it dilog} \left ( bx+a+1 \right ) }{2\,b}}-{\frac{\ln \left ( bx+a \right ) \ln \left ( bx+a+1 \right ) }{2\,b}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 0.981154, size = 151, normalized size = 4.31 \begin{align*} -\frac{1}{2} \, b{\left (\frac{\log \left (b x + a\right ) \log \left (b x + a - 1\right ) +{\rm Li}_2\left (-b x - a + 1\right )}{b^{2}} - \frac{\log \left (b x + a + 1\right ) \log \left (-b x - a\right ) +{\rm Li}_2\left (b x + a + 1\right )}{b^{2}}\right )} - \frac{1}{2} \,{\left (\frac{\log \left (b x + a + 1\right )}{b} - \frac{\log \left (b x + a - 1\right )}{b}\right )} \log \left (b x + a\right ) + \frac{\operatorname{arcoth}\left (b x + a\right ) \log \left (b x + a\right )}{b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\operatorname{arcoth}\left (b x + a\right )}{b x + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{acoth}{\left (a + b x \right )}}{a + b x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{arcoth}\left (b x + a\right )}{b x + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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