Optimal. Leaf size=92 \[ \frac{1}{2} \text{PolyLog}\left (2,1-\frac{2}{a+b x+1}\right )-\frac{1}{2} \text{PolyLog}\left (2,1-\frac{2 b x}{(1-a) (a+b x+1)}\right )+\log \left (\frac{2}{a+b x+1}\right ) \left (-\coth ^{-1}(a+b x)\right )+\log \left (\frac{2 b x}{(1-a) (a+b x+1)}\right ) \coth ^{-1}(a+b x) \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.0973951, antiderivative size = 92, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {6112, 5921, 2402, 2315, 2447} \[ \frac{1}{2} \text{PolyLog}\left (2,1-\frac{2}{a+b x+1}\right )-\frac{1}{2} \text{PolyLog}\left (2,1-\frac{2 b x}{(1-a) (a+b x+1)}\right )+\log \left (\frac{2}{a+b x+1}\right ) \left (-\coth ^{-1}(a+b x)\right )+\log \left (\frac{2 b x}{(1-a) (a+b x+1)}\right ) \coth ^{-1}(a+b x) \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 6112
Rule 5921
Rule 2402
Rule 2315
Rule 2447
Rubi steps
\begin{align*} \int \frac{\coth ^{-1}(a+b x)}{x} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\coth ^{-1}(x)}{-\frac{a}{b}+\frac{x}{b}} \, dx,x,a+b x\right )}{b}\\ &=-\coth ^{-1}(a+b x) \log \left (\frac{2}{1+a+b x}\right )+\coth ^{-1}(a+b x) \log \left (\frac{2 b x}{(1-a) (1+a+b x)}\right )+\operatorname{Subst}\left (\int \frac{\log \left (\frac{2}{1+x}\right )}{1-x^2} \, dx,x,a+b x\right )-\operatorname{Subst}\left (\int \frac{\log \left (\frac{2 \left (-\frac{a}{b}+\frac{x}{b}\right )}{\left (\frac{1}{b}-\frac{a}{b}\right ) (1+x)}\right )}{1-x^2} \, dx,x,a+b x\right )\\ &=-\coth ^{-1}(a+b x) \log \left (\frac{2}{1+a+b x}\right )+\coth ^{-1}(a+b x) \log \left (\frac{2 b x}{(1-a) (1+a+b x)}\right )-\frac{1}{2} \text{Li}_2\left (1-\frac{2 b x}{(1-a) (1+a+b x)}\right )+\operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1+a+b x}\right )\\ &=-\coth ^{-1}(a+b x) \log \left (\frac{2}{1+a+b x}\right )+\coth ^{-1}(a+b x) \log \left (\frac{2 b x}{(1-a) (1+a+b x)}\right )+\frac{1}{2} \text{Li}_2\left (1-\frac{2}{1+a+b x}\right )-\frac{1}{2} \text{Li}_2\left (1-\frac{2 b x}{(1-a) (1+a+b x)}\right )\\ \end{align*}
Mathematica [C] time = 0.167891, size = 259, normalized size = 2.82 \[ \frac{1}{8} \left (-4 \text{PolyLog}\left (2,e^{2 \tanh ^{-1}(a)-2 \tanh ^{-1}(a+b x)}\right )-4 \text{PolyLog}\left (2,-e^{2 \tanh ^{-1}(a+b x)}\right )+4 \left (\tanh ^{-1}(a)-\tanh ^{-1}(a+b x)\right )^2-\left (\pi -2 i \tanh ^{-1}(a+b x)\right )^2-8 \left (\tanh ^{-1}(a)-\tanh ^{-1}(a+b x)\right ) \log \left (1-e^{2 \tanh ^{-1}(a)-2 \tanh ^{-1}(a+b x)}\right )-4 i \left (\pi -2 i \tanh ^{-1}(a+b x)\right ) \log \left (e^{2 \tanh ^{-1}(a+b x)}+1\right )+4 \log \left (\frac{2}{\sqrt{1-(a+b x)^2}}\right ) \left (2 \tanh ^{-1}(a+b x)+i \pi \right )+8 \left (\tanh ^{-1}(a)-\tanh ^{-1}(a+b x)\right ) \log \left (-2 i \sinh \left (\tanh ^{-1}(a)-\tanh ^{-1}(a+b x)\right )\right )\right )+\tanh ^{-1}(a+b x) \left (-\log \left (\frac{1}{\sqrt{1-(a+b x)^2}}\right )+\log \left (-i \sinh \left (\tanh ^{-1}(a)-\tanh ^{-1}(a+b x)\right )\right )\right )+\log (x) \left (\coth ^{-1}(a+b x)-\tanh ^{-1}(a+b x)\right ) \]
Warning: Unable to verify antiderivative.
[In]
[Out]
________________________________________________________________________________________
Maple [A] time = 0.076, size = 81, normalized size = 0.9 \begin{align*} \ln \left ( bx \right ){\rm arccoth} \left (bx+a\right )-{\frac{1}{2}{\it dilog} \left ({\frac{bx+a+1}{1+a}} \right ) }-{\frac{\ln \left ( bx \right ) }{2}\ln \left ({\frac{bx+a+1}{1+a}} \right ) }+{\frac{1}{2}{\it dilog} \left ({\frac{bx+a-1}{a-1}} \right ) }+{\frac{\ln \left ( bx \right ) }{2}\ln \left ({\frac{bx+a-1}{a-1}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [A] time = 0.971844, size = 173, normalized size = 1.88 \begin{align*} -\frac{1}{2} \, b{\left (\frac{\log \left (b x + a + 1\right )}{b} - \frac{\log \left (b x + a - 1\right )}{b}\right )} \log \left (x\right ) + \frac{1}{2} \, b{\left (\frac{\log \left (b x + a + 1\right ) \log \left (-\frac{b x + a + 1}{a + 1} + 1\right ) +{\rm Li}_2\left (\frac{b x + a + 1}{a + 1}\right )}{b} - \frac{\log \left (b x + a - 1\right ) \log \left (-\frac{b x + a - 1}{a - 1} + 1\right ) +{\rm Li}_2\left (\frac{b x + a - 1}{a - 1}\right )}{b}\right )} + \operatorname{arcoth}\left (b x + a\right ) \log \left (x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\operatorname{arcoth}\left (b x + a\right )}{x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{acoth}{\left (a + b x \right )}}{x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{arcoth}\left (b x + a\right )}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]