Optimal. Leaf size=67 \[ -\frac{3}{16 \left (1-x^2\right )}-\frac{1}{16 \left (1-x^2\right )^2}+\frac{3 x \coth ^{-1}(x)}{8 \left (1-x^2\right )}+\frac{x \coth ^{-1}(x)}{4 \left (1-x^2\right )^2}+\frac{3}{16} \coth ^{-1}(x)^2 \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.0352498, antiderivative size = 67, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {5961, 5957, 261} \[ -\frac{3}{16 \left (1-x^2\right )}-\frac{1}{16 \left (1-x^2\right )^2}+\frac{3 x \coth ^{-1}(x)}{8 \left (1-x^2\right )}+\frac{x \coth ^{-1}(x)}{4 \left (1-x^2\right )^2}+\frac{3}{16} \coth ^{-1}(x)^2 \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 5961
Rule 5957
Rule 261
Rubi steps
\begin{align*} \int \frac{\coth ^{-1}(x)}{\left (1-x^2\right )^3} \, dx &=-\frac{1}{16 \left (1-x^2\right )^2}+\frac{x \coth ^{-1}(x)}{4 \left (1-x^2\right )^2}+\frac{3}{4} \int \frac{\coth ^{-1}(x)}{\left (1-x^2\right )^2} \, dx\\ &=-\frac{1}{16 \left (1-x^2\right )^2}+\frac{x \coth ^{-1}(x)}{4 \left (1-x^2\right )^2}+\frac{3 x \coth ^{-1}(x)}{8 \left (1-x^2\right )}+\frac{3}{16} \coth ^{-1}(x)^2-\frac{3}{8} \int \frac{x}{\left (1-x^2\right )^2} \, dx\\ &=-\frac{1}{16 \left (1-x^2\right )^2}-\frac{3}{16 \left (1-x^2\right )}+\frac{x \coth ^{-1}(x)}{4 \left (1-x^2\right )^2}+\frac{3 x \coth ^{-1}(x)}{8 \left (1-x^2\right )}+\frac{3}{16} \coth ^{-1}(x)^2\\ \end{align*}
Mathematica [A] time = 0.0523017, size = 43, normalized size = 0.64 \[ -\frac{-3 x^2+2 \left (3 x^2-5\right ) x \coth ^{-1}(x)-3 \left (x^2-1\right )^2 \coth ^{-1}(x)^2+4}{16 \left (x^2-1\right )^2} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [B] time = 0.049, size = 131, normalized size = 2. \begin{align*}{\frac{{\rm arccoth} \left (x\right )}{16\, \left ( -1+x \right ) ^{2}}}-{\frac{3\,{\rm arccoth} \left (x\right )}{-16+16\,x}}-{\frac{3\,{\rm arccoth} \left (x\right )\ln \left ( -1+x \right ) }{16}}-{\frac{{\rm arccoth} \left (x\right )}{16\, \left ( 1+x \right ) ^{2}}}-{\frac{3\,{\rm arccoth} \left (x\right )}{16+16\,x}}+{\frac{3\,{\rm arccoth} \left (x\right )\ln \left ( 1+x \right ) }{16}}-{\frac{3\, \left ( \ln \left ( -1+x \right ) \right ) ^{2}}{64}}+{\frac{3\,\ln \left ( -1+x \right ) }{32}\ln \left ({\frac{1}{2}}+{\frac{x}{2}} \right ) }+{\frac{3}{32} \left ( \ln \left ( 1+x \right ) -\ln \left ({\frac{1}{2}}+{\frac{x}{2}} \right ) \right ) \ln \left ( -{\frac{x}{2}}+{\frac{1}{2}} \right ) }-{\frac{3\, \left ( \ln \left ( 1+x \right ) \right ) ^{2}}{64}}-{\frac{1}{64\, \left ( -1+x \right ) ^{2}}}+{\frac{7}{-64+64\,x}}-{\frac{1}{64\, \left ( 1+x \right ) ^{2}}}-{\frac{7}{64+64\,x}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [B] time = 0.961914, size = 159, normalized size = 2.37 \begin{align*} -\frac{1}{16} \,{\left (\frac{2 \,{\left (3 \, x^{3} - 5 \, x\right )}}{x^{4} - 2 \, x^{2} + 1} - 3 \, \log \left (x + 1\right ) + 3 \, \log \left (x - 1\right )\right )} \operatorname{arcoth}\left (x\right ) - \frac{3 \,{\left (x^{4} - 2 \, x^{2} + 1\right )} \log \left (x + 1\right )^{2} - 6 \,{\left (x^{4} - 2 \, x^{2} + 1\right )} \log \left (x + 1\right ) \log \left (x - 1\right ) + 3 \,{\left (x^{4} - 2 \, x^{2} + 1\right )} \log \left (x - 1\right )^{2} - 12 \, x^{2} + 16}{64 \,{\left (x^{4} - 2 \, x^{2} + 1\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [A] time = 1.58159, size = 165, normalized size = 2.46 \begin{align*} \frac{3 \,{\left (x^{4} - 2 \, x^{2} + 1\right )} \log \left (\frac{x + 1}{x - 1}\right )^{2} + 12 \, x^{2} - 4 \,{\left (3 \, x^{3} - 5 \, x\right )} \log \left (\frac{x + 1}{x - 1}\right ) - 16}{64 \,{\left (x^{4} - 2 \, x^{2} + 1\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - \int \frac{\operatorname{acoth}{\left (x \right )}}{x^{6} - 3 x^{4} + 3 x^{2} - 1}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{\operatorname{arcoth}\left (x\right )}{{\left (x^{2} - 1\right )}^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]