Optimal. Leaf size=79 \[ -\frac{i \text{PolyLog}\left (2,-i e^{2 i (a+b x)}\right )}{4 b}+\frac{i \text{PolyLog}\left (2,i e^{2 i (a+b x)}\right )}{4 b}+i x \tan ^{-1}\left (e^{2 i (a+b x)}\right )+x \coth ^{-1}(\tan (a+b x)) \]
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Rubi [A] time = 0.047899, antiderivative size = 79, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 7, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.571, Rules used = {6248, 4181, 2279, 2391} \[ -\frac{i \text{PolyLog}\left (2,-i e^{2 i (a+b x)}\right )}{4 b}+\frac{i \text{PolyLog}\left (2,i e^{2 i (a+b x)}\right )}{4 b}+i x \tan ^{-1}\left (e^{2 i (a+b x)}\right )+x \coth ^{-1}(\tan (a+b x)) \]
Antiderivative was successfully verified.
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Rule 6248
Rule 4181
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \coth ^{-1}(\tan (a+b x)) \, dx &=x \coth ^{-1}(\tan (a+b x))-b \int x \sec (2 a+2 b x) \, dx\\ &=x \coth ^{-1}(\tan (a+b x))+i x \tan ^{-1}\left (e^{2 i (a+b x)}\right )+\frac{1}{2} \int \log \left (1-i e^{i (2 a+2 b x)}\right ) \, dx-\frac{1}{2} \int \log \left (1+i e^{i (2 a+2 b x)}\right ) \, dx\\ &=x \coth ^{-1}(\tan (a+b x))+i x \tan ^{-1}\left (e^{2 i (a+b x)}\right )-\frac{i \operatorname{Subst}\left (\int \frac{\log (1-i x)}{x} \, dx,x,e^{i (2 a+2 b x)}\right )}{4 b}+\frac{i \operatorname{Subst}\left (\int \frac{\log (1+i x)}{x} \, dx,x,e^{i (2 a+2 b x)}\right )}{4 b}\\ &=x \coth ^{-1}(\tan (a+b x))+i x \tan ^{-1}\left (e^{2 i (a+b x)}\right )-\frac{i \text{Li}_2\left (-i e^{2 i (a+b x)}\right )}{4 b}+\frac{i \text{Li}_2\left (i e^{2 i (a+b x)}\right )}{4 b}\\ \end{align*}
Mathematica [A] time = 0.0230426, size = 78, normalized size = 0.99 \[ \frac{-i \text{PolyLog}\left (2,-i e^{2 i (a+b x)}\right )+i \text{PolyLog}\left (2,i e^{2 i (a+b x)}\right )+4 b x \left (\coth ^{-1}(\tan (a+b x))+i \tan ^{-1}\left (e^{2 i (a+b x)}\right )\right )}{4 b} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.158, size = 178, normalized size = 2.3 \begin{align*}{\frac{\arctan \left ( \tan \left ( bx+a \right ) \right ){\rm arccoth} \left (\tan \left ( bx+a \right ) \right )}{b}}+{\frac{\arctan \left ( \tan \left ( bx+a \right ) \right ) }{2\,b}\ln \left ( 1+{\frac{i \left ( 1+i\tan \left ( bx+a \right ) \right ) ^{2}}{1+ \left ( \tan \left ( bx+a \right ) \right ) ^{2}}} \right ) }-{\frac{{\frac{i}{4}}}{b}{\it polylog} \left ( 2,{\frac{-i \left ( 1+i\tan \left ( bx+a \right ) \right ) ^{2}}{1+ \left ( \tan \left ( bx+a \right ) \right ) ^{2}}} \right ) }-{\frac{\arctan \left ( \tan \left ( bx+a \right ) \right ) }{2\,b}\ln \left ( 1-{\frac{i \left ( 1+i\tan \left ( bx+a \right ) \right ) ^{2}}{1+ \left ( \tan \left ( bx+a \right ) \right ) ^{2}}} \right ) }+{\frac{{\frac{i}{4}}}{b}{\it polylog} \left ( 2,{\frac{i \left ( 1+i\tan \left ( bx+a \right ) \right ) ^{2}}{1+ \left ( \tan \left ( bx+a \right ) \right ) ^{2}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.8146, size = 246, normalized size = 3.11 \begin{align*} \frac{4 \,{\left (b x + a\right )} \operatorname{arcoth}\left (\tan \left (b x + a\right )\right ) +{\left (\arctan \left (\frac{1}{2} \, \tan \left (b x + a\right ) + \frac{1}{2}, \frac{1}{2} \, \tan \left (b x + a\right ) + \frac{1}{2}\right ) - \arctan \left (\frac{1}{2} \, \tan \left (b x + a\right ) - \frac{1}{2}, -\frac{1}{2} \, \tan \left (b x + a\right ) + \frac{1}{2}\right )\right )} \log \left (\tan \left (b x + a\right )^{2} + 1\right ) -{\left (b x + a\right )} \log \left (\frac{1}{2} \, \tan \left (b x + a\right )^{2} + \tan \left (b x + a\right ) + \frac{1}{2}\right ) +{\left (b x + a\right )} \log \left (\frac{1}{2} \, \tan \left (b x + a\right )^{2} - \tan \left (b x + a\right ) + \frac{1}{2}\right ) - i \,{\rm Li}_2\left (\left (\frac{1}{2} i + \frac{1}{2}\right ) \, \tan \left (b x + a\right ) - \frac{1}{2} i + \frac{1}{2}\right ) + i \,{\rm Li}_2\left (-\left (\frac{1}{2} i - \frac{1}{2}\right ) \, \tan \left (b x + a\right ) + \frac{1}{2} i + \frac{1}{2}\right ) + i \,{\rm Li}_2\left (\left (\frac{1}{2} i - \frac{1}{2}\right ) \, \tan \left (b x + a\right ) + \frac{1}{2} i + \frac{1}{2}\right ) - i \,{\rm Li}_2\left (-\left (\frac{1}{2} i + \frac{1}{2}\right ) \, \tan \left (b x + a\right ) - \frac{1}{2} i + \frac{1}{2}\right )}{4 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.896, size = 1493, normalized size = 18.9 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \operatorname{acoth}{\left (\tan{\left (a + b x \right )} \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \operatorname{arcoth}\left (\tan \left (b x + a\right )\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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