Optimal. Leaf size=90 \[ -\frac{a^2}{12 x^2}-\frac{1}{3} a^4 \log \left (1-a^2 x^2\right )+\frac{2}{3} a^4 \log (x)+\frac{1}{4} a^4 \coth ^{-1}(a x)^2-\frac{a^3 \coth ^{-1}(a x)}{2 x}-\frac{a \coth ^{-1}(a x)}{6 x^3}-\frac{\coth ^{-1}(a x)^2}{4 x^4} \]
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Rubi [A] time = 0.17234, antiderivative size = 90, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 8, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.8, Rules used = {5917, 5983, 266, 44, 36, 29, 31, 5949} \[ -\frac{a^2}{12 x^2}-\frac{1}{3} a^4 \log \left (1-a^2 x^2\right )+\frac{2}{3} a^4 \log (x)+\frac{1}{4} a^4 \coth ^{-1}(a x)^2-\frac{a^3 \coth ^{-1}(a x)}{2 x}-\frac{a \coth ^{-1}(a x)}{6 x^3}-\frac{\coth ^{-1}(a x)^2}{4 x^4} \]
Antiderivative was successfully verified.
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Rule 5917
Rule 5983
Rule 266
Rule 44
Rule 36
Rule 29
Rule 31
Rule 5949
Rubi steps
\begin{align*} \int \frac{\coth ^{-1}(a x)^2}{x^5} \, dx &=-\frac{\coth ^{-1}(a x)^2}{4 x^4}+\frac{1}{2} a \int \frac{\coth ^{-1}(a x)}{x^4 \left (1-a^2 x^2\right )} \, dx\\ &=-\frac{\coth ^{-1}(a x)^2}{4 x^4}+\frac{1}{2} a \int \frac{\coth ^{-1}(a x)}{x^4} \, dx+\frac{1}{2} a^3 \int \frac{\coth ^{-1}(a x)}{x^2 \left (1-a^2 x^2\right )} \, dx\\ &=-\frac{a \coth ^{-1}(a x)}{6 x^3}-\frac{\coth ^{-1}(a x)^2}{4 x^4}+\frac{1}{6} a^2 \int \frac{1}{x^3 \left (1-a^2 x^2\right )} \, dx+\frac{1}{2} a^3 \int \frac{\coth ^{-1}(a x)}{x^2} \, dx+\frac{1}{2} a^5 \int \frac{\coth ^{-1}(a x)}{1-a^2 x^2} \, dx\\ &=-\frac{a \coth ^{-1}(a x)}{6 x^3}-\frac{a^3 \coth ^{-1}(a x)}{2 x}+\frac{1}{4} a^4 \coth ^{-1}(a x)^2-\frac{\coth ^{-1}(a x)^2}{4 x^4}+\frac{1}{12} a^2 \operatorname{Subst}\left (\int \frac{1}{x^2 \left (1-a^2 x\right )} \, dx,x,x^2\right )+\frac{1}{2} a^4 \int \frac{1}{x \left (1-a^2 x^2\right )} \, dx\\ &=-\frac{a \coth ^{-1}(a x)}{6 x^3}-\frac{a^3 \coth ^{-1}(a x)}{2 x}+\frac{1}{4} a^4 \coth ^{-1}(a x)^2-\frac{\coth ^{-1}(a x)^2}{4 x^4}+\frac{1}{12} a^2 \operatorname{Subst}\left (\int \left (\frac{1}{x^2}+\frac{a^2}{x}-\frac{a^4}{-1+a^2 x}\right ) \, dx,x,x^2\right )+\frac{1}{4} a^4 \operatorname{Subst}\left (\int \frac{1}{x \left (1-a^2 x\right )} \, dx,x,x^2\right )\\ &=-\frac{a^2}{12 x^2}-\frac{a \coth ^{-1}(a x)}{6 x^3}-\frac{a^3 \coth ^{-1}(a x)}{2 x}+\frac{1}{4} a^4 \coth ^{-1}(a x)^2-\frac{\coth ^{-1}(a x)^2}{4 x^4}+\frac{1}{6} a^4 \log (x)-\frac{1}{12} a^4 \log \left (1-a^2 x^2\right )+\frac{1}{4} a^4 \operatorname{Subst}\left (\int \frac{1}{x} \, dx,x,x^2\right )+\frac{1}{4} a^6 \operatorname{Subst}\left (\int \frac{1}{1-a^2 x} \, dx,x,x^2\right )\\ &=-\frac{a^2}{12 x^2}-\frac{a \coth ^{-1}(a x)}{6 x^3}-\frac{a^3 \coth ^{-1}(a x)}{2 x}+\frac{1}{4} a^4 \coth ^{-1}(a x)^2-\frac{\coth ^{-1}(a x)^2}{4 x^4}+\frac{2}{3} a^4 \log (x)-\frac{1}{3} a^4 \log \left (1-a^2 x^2\right )\\ \end{align*}
Mathematica [A] time = 0.0216711, size = 82, normalized size = 0.91 \[ -\frac{a^2}{12 x^2}-\frac{1}{3} a^4 \log \left (1-a^2 x^2\right )-\frac{a \left (3 a^2 x^2+1\right ) \coth ^{-1}(a x)}{6 x^3}+\frac{\left (a^4 x^4-1\right ) \coth ^{-1}(a x)^2}{4 x^4}+\frac{2}{3} a^4 \log (x) \]
Antiderivative was successfully verified.
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Maple [B] time = 0.06, size = 185, normalized size = 2.1 \begin{align*} -{\frac{ \left ({\rm arccoth} \left (ax\right ) \right ) ^{2}}{4\,{x}^{4}}}-{\frac{{a}^{4}{\rm arccoth} \left (ax\right )\ln \left ( ax-1 \right ) }{4}}-{\frac{a{\rm arccoth} \left (ax\right )}{6\,{x}^{3}}}-{\frac{{a}^{3}{\rm arccoth} \left (ax\right )}{2\,x}}+{\frac{{a}^{4}{\rm arccoth} \left (ax\right )\ln \left ( ax+1 \right ) }{4}}-{\frac{{a}^{4} \left ( \ln \left ( ax-1 \right ) \right ) ^{2}}{16}}+{\frac{{a}^{4}\ln \left ( ax-1 \right ) }{8}\ln \left ({\frac{1}{2}}+{\frac{ax}{2}} \right ) }-{\frac{{a}^{4}}{8}\ln \left ( -{\frac{ax}{2}}+{\frac{1}{2}} \right ) \ln \left ({\frac{1}{2}}+{\frac{ax}{2}} \right ) }+{\frac{{a}^{4}\ln \left ( ax+1 \right ) }{8}\ln \left ( -{\frac{ax}{2}}+{\frac{1}{2}} \right ) }-{\frac{{a}^{4} \left ( \ln \left ( ax+1 \right ) \right ) ^{2}}{16}}-{\frac{{a}^{4}\ln \left ( ax-1 \right ) }{3}}-{\frac{{a}^{2}}{12\,{x}^{2}}}+{\frac{2\,{a}^{4}\ln \left ( ax \right ) }{3}}-{\frac{{a}^{4}\ln \left ( ax+1 \right ) }{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 0.98254, size = 208, normalized size = 2.31 \begin{align*} \frac{1}{48} \,{\left (32 \, a^{2} \log \left (x\right ) - \frac{3 \, a^{2} x^{2} \log \left (a x + 1\right )^{2} + 3 \, a^{2} x^{2} \log \left (a x - 1\right )^{2} + 16 \, a^{2} x^{2} \log \left (a x - 1\right ) - 2 \,{\left (3 \, a^{2} x^{2} \log \left (a x - 1\right ) - 8 \, a^{2} x^{2}\right )} \log \left (a x + 1\right ) + 4}{x^{2}}\right )} a^{2} + \frac{1}{12} \,{\left (3 \, a^{3} \log \left (a x + 1\right ) - 3 \, a^{3} \log \left (a x - 1\right ) - \frac{2 \,{\left (3 \, a^{2} x^{2} + 1\right )}}{x^{3}}\right )} a \operatorname{arcoth}\left (a x\right ) - \frac{\operatorname{arcoth}\left (a x\right )^{2}}{4 \, x^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.83772, size = 223, normalized size = 2.48 \begin{align*} -\frac{16 \, a^{4} x^{4} \log \left (a^{2} x^{2} - 1\right ) - 32 \, a^{4} x^{4} \log \left (x\right ) + 4 \, a^{2} x^{2} - 3 \,{\left (a^{4} x^{4} - 1\right )} \log \left (\frac{a x + 1}{a x - 1}\right )^{2} + 4 \,{\left (3 \, a^{3} x^{3} + a x\right )} \log \left (\frac{a x + 1}{a x - 1}\right )}{48 \, x^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 6.42276, size = 90, normalized size = 1. \begin{align*} \frac{2 a^{4} \log{\left (x \right )}}{3} - \frac{2 a^{4} \log{\left (a x + 1 \right )}}{3} + \frac{a^{4} \operatorname{acoth}^{2}{\left (a x \right )}}{4} + \frac{2 a^{4} \operatorname{acoth}{\left (a x \right )}}{3} - \frac{a^{3} \operatorname{acoth}{\left (a x \right )}}{2 x} - \frac{a^{2}}{12 x^{2}} - \frac{a \operatorname{acoth}{\left (a x \right )}}{6 x^{3}} - \frac{\operatorname{acoth}^{2}{\left (a x \right )}}{4 x^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{arcoth}\left (a x\right )^{2}}{x^{5}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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