Optimal. Leaf size=81 \[ \frac{x^2}{12 a^2}+\frac{\log \left (1-a^2 x^2\right )}{3 a^4}+\frac{x \coth ^{-1}(a x)}{2 a^3}-\frac{\coth ^{-1}(a x)^2}{4 a^4}+\frac{1}{4} x^4 \coth ^{-1}(a x)^2+\frac{x^3 \coth ^{-1}(a x)}{6 a} \]
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Rubi [A] time = 0.162949, antiderivative size = 81, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 7, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.7, Rules used = {5917, 5981, 266, 43, 5911, 260, 5949} \[ \frac{x^2}{12 a^2}+\frac{\log \left (1-a^2 x^2\right )}{3 a^4}+\frac{x \coth ^{-1}(a x)}{2 a^3}-\frac{\coth ^{-1}(a x)^2}{4 a^4}+\frac{1}{4} x^4 \coth ^{-1}(a x)^2+\frac{x^3 \coth ^{-1}(a x)}{6 a} \]
Antiderivative was successfully verified.
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Rule 5917
Rule 5981
Rule 266
Rule 43
Rule 5911
Rule 260
Rule 5949
Rubi steps
\begin{align*} \int x^3 \coth ^{-1}(a x)^2 \, dx &=\frac{1}{4} x^4 \coth ^{-1}(a x)^2-\frac{1}{2} a \int \frac{x^4 \coth ^{-1}(a x)}{1-a^2 x^2} \, dx\\ &=\frac{1}{4} x^4 \coth ^{-1}(a x)^2+\frac{\int x^2 \coth ^{-1}(a x) \, dx}{2 a}-\frac{\int \frac{x^2 \coth ^{-1}(a x)}{1-a^2 x^2} \, dx}{2 a}\\ &=\frac{x^3 \coth ^{-1}(a x)}{6 a}+\frac{1}{4} x^4 \coth ^{-1}(a x)^2-\frac{1}{6} \int \frac{x^3}{1-a^2 x^2} \, dx+\frac{\int \coth ^{-1}(a x) \, dx}{2 a^3}-\frac{\int \frac{\coth ^{-1}(a x)}{1-a^2 x^2} \, dx}{2 a^3}\\ &=\frac{x \coth ^{-1}(a x)}{2 a^3}+\frac{x^3 \coth ^{-1}(a x)}{6 a}-\frac{\coth ^{-1}(a x)^2}{4 a^4}+\frac{1}{4} x^4 \coth ^{-1}(a x)^2-\frac{1}{12} \operatorname{Subst}\left (\int \frac{x}{1-a^2 x} \, dx,x,x^2\right )-\frac{\int \frac{x}{1-a^2 x^2} \, dx}{2 a^2}\\ &=\frac{x \coth ^{-1}(a x)}{2 a^3}+\frac{x^3 \coth ^{-1}(a x)}{6 a}-\frac{\coth ^{-1}(a x)^2}{4 a^4}+\frac{1}{4} x^4 \coth ^{-1}(a x)^2+\frac{\log \left (1-a^2 x^2\right )}{4 a^4}-\frac{1}{12} \operatorname{Subst}\left (\int \left (-\frac{1}{a^2}-\frac{1}{a^2 \left (-1+a^2 x\right )}\right ) \, dx,x,x^2\right )\\ &=\frac{x^2}{12 a^2}+\frac{x \coth ^{-1}(a x)}{2 a^3}+\frac{x^3 \coth ^{-1}(a x)}{6 a}-\frac{\coth ^{-1}(a x)^2}{4 a^4}+\frac{1}{4} x^4 \coth ^{-1}(a x)^2+\frac{\log \left (1-a^2 x^2\right )}{3 a^4}\\ \end{align*}
Mathematica [A] time = 0.0167572, size = 62, normalized size = 0.77 \[ \frac{a^2 x^2+4 \log \left (1-a^2 x^2\right )+2 a x \left (a^2 x^2+3\right ) \coth ^{-1}(a x)+3 \left (a^4 x^4-1\right ) \coth ^{-1}(a x)^2}{12 a^4} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.052, size = 176, normalized size = 2.2 \begin{align*}{\frac{{x}^{4} \left ({\rm arccoth} \left (ax\right ) \right ) ^{2}}{4}}+{\frac{{x}^{3}{\rm arccoth} \left (ax\right )}{6\,a}}+{\frac{x{\rm arccoth} \left (ax\right )}{2\,{a}^{3}}}+{\frac{{\rm arccoth} \left (ax\right )\ln \left ( ax-1 \right ) }{4\,{a}^{4}}}-{\frac{{\rm arccoth} \left (ax\right )\ln \left ( ax+1 \right ) }{4\,{a}^{4}}}+{\frac{ \left ( \ln \left ( ax-1 \right ) \right ) ^{2}}{16\,{a}^{4}}}-{\frac{\ln \left ( ax-1 \right ) }{8\,{a}^{4}}\ln \left ({\frac{1}{2}}+{\frac{ax}{2}} \right ) }-{\frac{\ln \left ( ax+1 \right ) }{8\,{a}^{4}}\ln \left ( -{\frac{ax}{2}}+{\frac{1}{2}} \right ) }+{\frac{1}{8\,{a}^{4}}\ln \left ( -{\frac{ax}{2}}+{\frac{1}{2}} \right ) \ln \left ({\frac{1}{2}}+{\frac{ax}{2}} \right ) }+{\frac{ \left ( \ln \left ( ax+1 \right ) \right ) ^{2}}{16\,{a}^{4}}}+{\frac{{x}^{2}}{12\,{a}^{2}}}+{\frac{\ln \left ( ax-1 \right ) }{3\,{a}^{4}}}+{\frac{\ln \left ( ax+1 \right ) }{3\,{a}^{4}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.955027, size = 159, normalized size = 1.96 \begin{align*} \frac{1}{4} \, x^{4} \operatorname{arcoth}\left (a x\right )^{2} + \frac{1}{12} \, a{\left (\frac{2 \,{\left (a^{2} x^{3} + 3 \, x\right )}}{a^{4}} - \frac{3 \, \log \left (a x + 1\right )}{a^{5}} + \frac{3 \, \log \left (a x - 1\right )}{a^{5}}\right )} \operatorname{arcoth}\left (a x\right ) + \frac{4 \, a^{2} x^{2} - 2 \,{\left (3 \, \log \left (a x - 1\right ) - 8\right )} \log \left (a x + 1\right ) + 3 \, \log \left (a x + 1\right )^{2} + 3 \, \log \left (a x - 1\right )^{2} + 16 \, \log \left (a x - 1\right )}{48 \, a^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.59719, size = 184, normalized size = 2.27 \begin{align*} \frac{4 \, a^{2} x^{2} + 3 \,{\left (a^{4} x^{4} - 1\right )} \log \left (\frac{a x + 1}{a x - 1}\right )^{2} + 4 \,{\left (a^{3} x^{3} + 3 \, a x\right )} \log \left (\frac{a x + 1}{a x - 1}\right ) + 16 \, \log \left (a^{2} x^{2} - 1\right )}{48 \, a^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 5.10093, size = 90, normalized size = 1.11 \begin{align*} \begin{cases} \frac{x^{4} \operatorname{acoth}^{2}{\left (a x \right )}}{4} + \frac{x^{3} \operatorname{acoth}{\left (a x \right )}}{6 a} + \frac{x^{2}}{12 a^{2}} + \frac{x \operatorname{acoth}{\left (a x \right )}}{2 a^{3}} + \frac{2 \log{\left (a x + 1 \right )}}{3 a^{4}} - \frac{\operatorname{acoth}^{2}{\left (a x \right )}}{4 a^{4}} - \frac{2 \operatorname{acoth}{\left (a x \right )}}{3 a^{4}} & \text{for}\: a \neq 0 \\- \frac{\pi ^{2} x^{4}}{16} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{3} \operatorname{arcoth}\left (a x\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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