Optimal. Leaf size=546 \[ -\frac{b^2 \left (\left (3 c^2+1\right ) f^2-6 c d e f+3 d^2 e^2\right ) \text{PolyLog}\left (2,1-\frac{2}{-c-d x+1}\right ) \left (a+b \coth ^{-1}(c+d x)\right )}{d^3}+\frac{b^3 \left (\left (3 c^2+1\right ) f^2-6 c d e f+3 d^2 e^2\right ) \text{PolyLog}\left (3,1-\frac{2}{-c-d x+1}\right )}{2 d^3}-\frac{3 b^3 f (d e-c f) \text{PolyLog}\left (2,-\frac{c+d x+1}{-c-d x+1}\right )}{d^3}-\frac{6 b^2 f (d e-c f) \log \left (\frac{2}{-c-d x+1}\right ) \left (a+b \coth ^{-1}(c+d x)\right )}{d^3}+\frac{a b^2 f^2 x}{d^2}-\frac{(d e-c f) \left (\left (c^2+3\right ) f^2-2 c d e f+d^2 e^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 d^3 f}+\frac{\left (\left (3 c^2+1\right ) f^2-6 c d e f+3 d^2 e^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 d^3}-\frac{b \left (\left (3 c^2+1\right ) f^2-6 c d e f+3 d^2 e^2\right ) \log \left (\frac{2}{-c-d x+1}\right ) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{3 b f (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{3 b f (c+d x) (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}-\frac{b f^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}+\frac{b f^2 (c+d x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}+\frac{(e+f x)^3 \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 f}+\frac{b^3 f^2 \log \left (1-(c+d x)^2\right )}{2 d^3}+\frac{b^3 f^2 (c+d x) \coth ^{-1}(c+d x)}{d^3} \]
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Rubi [A] time = 1.04283, antiderivative size = 546, normalized size of antiderivative = 1., number of steps used = 21, number of rules used = 14, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.7, Rules used = {6112, 5929, 5911, 5985, 5919, 2402, 2315, 5917, 5981, 260, 5949, 6049, 6059, 6610} \[ -\frac{b^2 \left (\left (3 c^2+1\right ) f^2-6 c d e f+3 d^2 e^2\right ) \text{PolyLog}\left (2,1-\frac{2}{-c-d x+1}\right ) \left (a+b \coth ^{-1}(c+d x)\right )}{d^3}+\frac{b^3 \left (\left (3 c^2+1\right ) f^2-6 c d e f+3 d^2 e^2\right ) \text{PolyLog}\left (3,1-\frac{2}{-c-d x+1}\right )}{2 d^3}-\frac{3 b^3 f (d e-c f) \text{PolyLog}\left (2,-\frac{c+d x+1}{-c-d x+1}\right )}{d^3}-\frac{6 b^2 f (d e-c f) \log \left (\frac{2}{-c-d x+1}\right ) \left (a+b \coth ^{-1}(c+d x)\right )}{d^3}+\frac{a b^2 f^2 x}{d^2}-\frac{(d e-c f) \left (\left (c^2+3\right ) f^2-2 c d e f+d^2 e^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 d^3 f}+\frac{\left (\left (3 c^2+1\right ) f^2-6 c d e f+3 d^2 e^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 d^3}-\frac{b \left (\left (3 c^2+1\right ) f^2-6 c d e f+3 d^2 e^2\right ) \log \left (\frac{2}{-c-d x+1}\right ) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{3 b f (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{3 b f (c+d x) (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}-\frac{b f^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}+\frac{b f^2 (c+d x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}+\frac{(e+f x)^3 \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 f}+\frac{b^3 f^2 \log \left (1-(c+d x)^2\right )}{2 d^3}+\frac{b^3 f^2 (c+d x) \coth ^{-1}(c+d x)}{d^3} \]
Antiderivative was successfully verified.
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Rule 6112
Rule 5929
Rule 5911
Rule 5985
Rule 5919
Rule 2402
Rule 2315
Rule 5917
Rule 5981
Rule 260
Rule 5949
Rule 6049
Rule 6059
Rule 6610
Rubi steps
\begin{align*} \int (e+f x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^3 \, dx &=\frac{\operatorname{Subst}\left (\int \left (\frac{d e-c f}{d}+\frac{f x}{d}\right )^2 \left (a+b \coth ^{-1}(x)\right )^3 \, dx,x,c+d x\right )}{d}\\ &=\frac{(e+f x)^3 \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 f}-\frac{b \operatorname{Subst}\left (\int \left (-\frac{3 f^2 (d e-c f) \left (a+b \coth ^{-1}(x)\right )^2}{d^3}-\frac{f^3 x \left (a+b \coth ^{-1}(x)\right )^2}{d^3}+\frac{\left ((d e-c f) \left (d^2 e^2-2 c d e f+3 f^2+c^2 f^2\right )+f \left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right ) x\right ) \left (a+b \coth ^{-1}(x)\right )^2}{d^3 \left (1-x^2\right )}\right ) \, dx,x,c+d x\right )}{f}\\ &=\frac{(e+f x)^3 \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 f}-\frac{b \operatorname{Subst}\left (\int \frac{\left ((d e-c f) \left (d^2 e^2-2 c d e f+3 f^2+c^2 f^2\right )+f \left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right ) x\right ) \left (a+b \coth ^{-1}(x)\right )^2}{1-x^2} \, dx,x,c+d x\right )}{d^3 f}+\frac{\left (b f^2\right ) \operatorname{Subst}\left (\int x \left (a+b \coth ^{-1}(x)\right )^2 \, dx,x,c+d x\right )}{d^3}+\frac{(3 b f (d e-c f)) \operatorname{Subst}\left (\int \left (a+b \coth ^{-1}(x)\right )^2 \, dx,x,c+d x\right )}{d^3}\\ &=\frac{3 b f (d e-c f) (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{b f^2 (c+d x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}+\frac{(e+f x)^3 \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 f}-\frac{b \operatorname{Subst}\left (\int \left (\frac{(d e-c f) \left (d^2 e^2-2 c d e f+\left (3+c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(x)\right )^2}{1-x^2}+\frac{f \left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right ) x \left (a+b \coth ^{-1}(x)\right )^2}{1-x^2}\right ) \, dx,x,c+d x\right )}{d^3 f}-\frac{\left (b^2 f^2\right ) \operatorname{Subst}\left (\int \frac{x^2 \left (a+b \coth ^{-1}(x)\right )}{1-x^2} \, dx,x,c+d x\right )}{d^3}-\frac{\left (6 b^2 f (d e-c f)\right ) \operatorname{Subst}\left (\int \frac{x \left (a+b \coth ^{-1}(x)\right )}{1-x^2} \, dx,x,c+d x\right )}{d^3}\\ &=\frac{3 b f (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{3 b f (d e-c f) (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{b f^2 (c+d x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}+\frac{(e+f x)^3 \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 f}+\frac{\left (b^2 f^2\right ) \operatorname{Subst}\left (\int \left (a+b \coth ^{-1}(x)\right ) \, dx,x,c+d x\right )}{d^3}-\frac{\left (b^2 f^2\right ) \operatorname{Subst}\left (\int \frac{a+b \coth ^{-1}(x)}{1-x^2} \, dx,x,c+d x\right )}{d^3}-\frac{\left (6 b^2 f (d e-c f)\right ) \operatorname{Subst}\left (\int \frac{a+b \coth ^{-1}(x)}{1-x} \, dx,x,c+d x\right )}{d^3}-\frac{\left (b (d e-c f) \left (d^2 e^2-2 c d e f+\left (3+c^2\right ) f^2\right )\right ) \operatorname{Subst}\left (\int \frac{\left (a+b \coth ^{-1}(x)\right )^2}{1-x^2} \, dx,x,c+d x\right )}{d^3 f}-\frac{\left (b \left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right )\right ) \operatorname{Subst}\left (\int \frac{x \left (a+b \coth ^{-1}(x)\right )^2}{1-x^2} \, dx,x,c+d x\right )}{d^3}\\ &=\frac{a b^2 f^2 x}{d^2}-\frac{b f^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}+\frac{3 b f (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{3 b f (d e-c f) (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{b f^2 (c+d x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}-\frac{(d e-c f) \left (d^2 e^2-2 c d e f+\left (3+c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 d^3 f}+\frac{\left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 d^3}+\frac{(e+f x)^3 \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 f}-\frac{6 b^2 f (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right ) \log \left (\frac{2}{1-c-d x}\right )}{d^3}+\frac{\left (b^3 f^2\right ) \operatorname{Subst}\left (\int \coth ^{-1}(x) \, dx,x,c+d x\right )}{d^3}+\frac{\left (6 b^3 f (d e-c f)\right ) \operatorname{Subst}\left (\int \frac{\log \left (\frac{2}{1-x}\right )}{1-x^2} \, dx,x,c+d x\right )}{d^3}-\frac{\left (b \left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right )\right ) \operatorname{Subst}\left (\int \frac{\left (a+b \coth ^{-1}(x)\right )^2}{1-x} \, dx,x,c+d x\right )}{d^3}\\ &=\frac{a b^2 f^2 x}{d^2}+\frac{b^3 f^2 (c+d x) \coth ^{-1}(c+d x)}{d^3}-\frac{b f^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}+\frac{3 b f (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{3 b f (d e-c f) (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{b f^2 (c+d x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}-\frac{(d e-c f) \left (d^2 e^2-2 c d e f+\left (3+c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 d^3 f}+\frac{\left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 d^3}+\frac{(e+f x)^3 \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 f}-\frac{6 b^2 f (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right ) \log \left (\frac{2}{1-c-d x}\right )}{d^3}-\frac{b \left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^2 \log \left (\frac{2}{1-c-d x}\right )}{d^3}-\frac{\left (b^3 f^2\right ) \operatorname{Subst}\left (\int \frac{x}{1-x^2} \, dx,x,c+d x\right )}{d^3}-\frac{\left (6 b^3 f (d e-c f)\right ) \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1-c-d x}\right )}{d^3}+\frac{\left (2 b^2 \left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right )\right ) \operatorname{Subst}\left (\int \frac{\left (a+b \coth ^{-1}(x)\right ) \log \left (\frac{2}{1-x}\right )}{1-x^2} \, dx,x,c+d x\right )}{d^3}\\ &=\frac{a b^2 f^2 x}{d^2}+\frac{b^3 f^2 (c+d x) \coth ^{-1}(c+d x)}{d^3}-\frac{b f^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}+\frac{3 b f (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{3 b f (d e-c f) (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{b f^2 (c+d x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}-\frac{(d e-c f) \left (d^2 e^2-2 c d e f+\left (3+c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 d^3 f}+\frac{\left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 d^3}+\frac{(e+f x)^3 \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 f}-\frac{6 b^2 f (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right ) \log \left (\frac{2}{1-c-d x}\right )}{d^3}-\frac{b \left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^2 \log \left (\frac{2}{1-c-d x}\right )}{d^3}+\frac{b^3 f^2 \log \left (1-(c+d x)^2\right )}{2 d^3}-\frac{3 b^3 f (d e-c f) \text{Li}_2\left (1-\frac{2}{1-c-d x}\right )}{d^3}-\frac{b^2 \left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right ) \text{Li}_2\left (1-\frac{2}{1-c-d x}\right )}{d^3}+\frac{\left (b^3 \left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right )\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2\left (1-\frac{2}{1-x}\right )}{1-x^2} \, dx,x,c+d x\right )}{d^3}\\ &=\frac{a b^2 f^2 x}{d^2}+\frac{b^3 f^2 (c+d x) \coth ^{-1}(c+d x)}{d^3}-\frac{b f^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}+\frac{3 b f (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{3 b f (d e-c f) (c+d x) \left (a+b \coth ^{-1}(c+d x)\right )^2}{d^3}+\frac{b f^2 (c+d x)^2 \left (a+b \coth ^{-1}(c+d x)\right )^2}{2 d^3}-\frac{(d e-c f) \left (d^2 e^2-2 c d e f+\left (3+c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 d^3 f}+\frac{\left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 d^3}+\frac{(e+f x)^3 \left (a+b \coth ^{-1}(c+d x)\right )^3}{3 f}-\frac{6 b^2 f (d e-c f) \left (a+b \coth ^{-1}(c+d x)\right ) \log \left (\frac{2}{1-c-d x}\right )}{d^3}-\frac{b \left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right )^2 \log \left (\frac{2}{1-c-d x}\right )}{d^3}+\frac{b^3 f^2 \log \left (1-(c+d x)^2\right )}{2 d^3}-\frac{3 b^3 f (d e-c f) \text{Li}_2\left (1-\frac{2}{1-c-d x}\right )}{d^3}-\frac{b^2 \left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right ) \left (a+b \coth ^{-1}(c+d x)\right ) \text{Li}_2\left (1-\frac{2}{1-c-d x}\right )}{d^3}+\frac{b^3 \left (3 d^2 e^2-6 c d e f+\left (1+3 c^2\right ) f^2\right ) \text{Li}_3\left (1-\frac{2}{1-c-d x}\right )}{2 d^3}\\ \end{align*}
Mathematica [C] time = 10.423, size = 2594, normalized size = 4.75 \[ \text{Result too large to show} \]
Warning: Unable to verify antiderivative.
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Maple [C] time = 3.685, size = 10477, normalized size = 19.2 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (a^{3} f^{2} x^{2} + 2 \, a^{3} e f x + a^{3} e^{2} +{\left (b^{3} f^{2} x^{2} + 2 \, b^{3} e f x + b^{3} e^{2}\right )} \operatorname{arcoth}\left (d x + c\right )^{3} + 3 \,{\left (a b^{2} f^{2} x^{2} + 2 \, a b^{2} e f x + a b^{2} e^{2}\right )} \operatorname{arcoth}\left (d x + c\right )^{2} + 3 \,{\left (a^{2} b f^{2} x^{2} + 2 \, a^{2} b e f x + a^{2} b e^{2}\right )} \operatorname{arcoth}\left (d x + c\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (f x + e\right )}^{2}{\left (b \operatorname{arcoth}\left (d x + c\right ) + a\right )}^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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