Optimal. Leaf size=34 \[ \frac{x \tanh ^{-1}(\tanh (a+b x))^7}{7 b}-\frac{\tanh ^{-1}(\tanh (a+b x))^8}{56 b^2} \]
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Rubi [A] time = 0.0137937, antiderivative size = 34, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 11, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.273, Rules used = {2168, 2157, 30} \[ \frac{x \tanh ^{-1}(\tanh (a+b x))^7}{7 b}-\frac{\tanh ^{-1}(\tanh (a+b x))^8}{56 b^2} \]
Antiderivative was successfully verified.
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Rule 2168
Rule 2157
Rule 30
Rubi steps
\begin{align*} \int x \tanh ^{-1}(\tanh (a+b x))^6 \, dx &=\frac{x \tanh ^{-1}(\tanh (a+b x))^7}{7 b}-\frac{\int \tanh ^{-1}(\tanh (a+b x))^7 \, dx}{7 b}\\ &=\frac{x \tanh ^{-1}(\tanh (a+b x))^7}{7 b}-\frac{\operatorname{Subst}\left (\int x^7 \, dx,x,\tanh ^{-1}(\tanh (a+b x))\right )}{7 b^2}\\ &=\frac{x \tanh ^{-1}(\tanh (a+b x))^7}{7 b}-\frac{\tanh ^{-1}(\tanh (a+b x))^8}{56 b^2}\\ \end{align*}
Mathematica [B] time = 0.1182, size = 177, normalized size = 5.21 \[ -\frac{(a+b x) \left (-56 \left (2 a^2+a b x-b^2 x^2\right ) \tanh ^{-1}(\tanh (a+b x))^5+(7 a-b x) (a+b x)^6-8 (6 a-b x) (a+b x)^5 \tanh ^{-1}(\tanh (a+b x))+28 (5 a-b x) (a+b x)^4 \tanh ^{-1}(\tanh (a+b x))^2-56 (4 a-b x) (a+b x)^3 \tanh ^{-1}(\tanh (a+b x))^3+70 (3 a-b x) (a+b x)^2 \tanh ^{-1}(\tanh (a+b x))^4+28 (a-b x) \tanh ^{-1}(\tanh (a+b x))^6\right )}{56 b^2} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.048, size = 110, normalized size = 3.2 \begin{align*}{\frac{{x}^{2} \left ({\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) \right ) ^{6}}{2}}-3\,b \left ( 1/3\,{x}^{3} \left ({\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) \right ) ^{5}-5/3\,b \left ( 1/4\,{x}^{4} \left ({\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) \right ) ^{4}-b \left ( 1/5\,{x}^{5} \left ({\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) \right ) ^{3}-3/5\,b \left ( 1/6\,{x}^{6} \left ({\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) \right ) ^{2}-1/3\,b \left ( 1/7\,{x}^{7}{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) -{\frac{{x}^{8}b}{56}} \right ) \right ) \right ) \right ) \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 2.14864, size = 149, normalized size = 4.38 \begin{align*} -b x^{3} \operatorname{artanh}\left (\tanh \left (b x + a\right )\right )^{5} + \frac{1}{2} \, x^{2} \operatorname{artanh}\left (\tanh \left (b x + a\right )\right )^{6} + \frac{1}{56} \,{\left (70 \, b x^{4} \operatorname{artanh}\left (\tanh \left (b x + a\right )\right )^{4} -{\left (56 \, b x^{5} \operatorname{artanh}\left (\tanh \left (b x + a\right )\right )^{3} -{\left (28 \, b x^{6} \operatorname{artanh}\left (\tanh \left (b x + a\right )\right )^{2} +{\left (b^{2} x^{8} - 8 \, b x^{7} \operatorname{artanh}\left (\tanh \left (b x + a\right )\right )\right )} b\right )} b\right )} b\right )} b \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.45888, size = 149, normalized size = 4.38 \begin{align*} \frac{1}{8} \, b^{6} x^{8} + \frac{6}{7} \, a b^{5} x^{7} + \frac{5}{2} \, a^{2} b^{4} x^{6} + 4 \, a^{3} b^{3} x^{5} + \frac{15}{4} \, a^{4} b^{2} x^{4} + 2 \, a^{5} b x^{3} + \frac{1}{2} \, a^{6} x^{2} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 11.7372, size = 41, normalized size = 1.21 \begin{align*} \begin{cases} \frac{x \operatorname{atanh}^{7}{\left (\tanh{\left (a + b x \right )} \right )}}{7 b} - \frac{\operatorname{atanh}^{8}{\left (\tanh{\left (a + b x \right )} \right )}}{56 b^{2}} & \text{for}\: b \neq 0 \\\frac{x^{2} \operatorname{atanh}^{6}{\left (\tanh{\left (a \right )} \right )}}{2} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.13139, size = 92, normalized size = 2.71 \begin{align*} \frac{1}{8} \, b^{6} x^{8} + \frac{6}{7} \, a b^{5} x^{7} + \frac{5}{2} \, a^{2} b^{4} x^{6} + 4 \, a^{3} b^{3} x^{5} + \frac{15}{4} \, a^{4} b^{2} x^{4} + 2 \, a^{5} b x^{3} + \frac{1}{2} \, a^{6} x^{2} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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