Optimal. Leaf size=128 \[ \frac{5 x^{3/2} \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{2 b^2}+\frac{15 \sqrt{x} \left (b x-\tanh ^{-1}(\tanh (a+b x))\right ) \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{4 b^3}+\frac{15 \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{x}}{\sqrt{\tanh ^{-1}(\tanh (a+b x))}}\right ) \left (b x-\tanh ^{-1}(\tanh (a+b x))\right )^2}{4 b^{7/2}}-\frac{2 x^{5/2}}{b \sqrt{\tanh ^{-1}(\tanh (a+b x))}} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.076284, antiderivative size = 128, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.176, Rules used = {2168, 2169, 2165} \[ \frac{5 x^{3/2} \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{2 b^2}+\frac{15 \sqrt{x} \left (b x-\tanh ^{-1}(\tanh (a+b x))\right ) \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{4 b^3}+\frac{15 \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{x}}{\sqrt{\tanh ^{-1}(\tanh (a+b x))}}\right ) \left (b x-\tanh ^{-1}(\tanh (a+b x))\right )^2}{4 b^{7/2}}-\frac{2 x^{5/2}}{b \sqrt{\tanh ^{-1}(\tanh (a+b x))}} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 2168
Rule 2169
Rule 2165
Rubi steps
\begin{align*} \int \frac{x^{5/2}}{\tanh ^{-1}(\tanh (a+b x))^{3/2}} \, dx &=-\frac{2 x^{5/2}}{b \sqrt{\tanh ^{-1}(\tanh (a+b x))}}+\frac{5 \int \frac{x^{3/2}}{\sqrt{\tanh ^{-1}(\tanh (a+b x))}} \, dx}{b}\\ &=-\frac{2 x^{5/2}}{b \sqrt{\tanh ^{-1}(\tanh (a+b x))}}+\frac{5 x^{3/2} \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{2 b^2}-\frac{\left (15 \left (-b x+\tanh ^{-1}(\tanh (a+b x))\right )\right ) \int \frac{\sqrt{x}}{\sqrt{\tanh ^{-1}(\tanh (a+b x))}} \, dx}{4 b^2}\\ &=-\frac{2 x^{5/2}}{b \sqrt{\tanh ^{-1}(\tanh (a+b x))}}+\frac{5 x^{3/2} \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{2 b^2}+\frac{15 \sqrt{x} \left (b x-\tanh ^{-1}(\tanh (a+b x))\right ) \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{4 b^3}+\frac{\left (15 \left (-b x+\tanh ^{-1}(\tanh (a+b x))\right )^2\right ) \int \frac{1}{\sqrt{x} \sqrt{\tanh ^{-1}(\tanh (a+b x))}} \, dx}{8 b^3}\\ &=\frac{15 \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{x}}{\sqrt{\tanh ^{-1}(\tanh (a+b x))}}\right ) \left (b x-\tanh ^{-1}(\tanh (a+b x))\right )^2}{4 b^{7/2}}-\frac{2 x^{5/2}}{b \sqrt{\tanh ^{-1}(\tanh (a+b x))}}+\frac{5 x^{3/2} \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{2 b^2}+\frac{15 \sqrt{x} \left (b x-\tanh ^{-1}(\tanh (a+b x))\right ) \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{4 b^3}\\ \end{align*}
Mathematica [A] time = 0.0935498, size = 104, normalized size = 0.81 \[ \frac{15 \left (\tanh ^{-1}(\tanh (a+b x))-b x\right )^2 \log \left (\sqrt{b} \sqrt{\tanh ^{-1}(\tanh (a+b x))}+b \sqrt{x}\right )}{4 b^{7/2}}-\frac{\sqrt{x} \left (-25 b x \tanh ^{-1}(\tanh (a+b x))+15 \tanh ^{-1}(\tanh (a+b x))^2+8 b^2 x^2\right )}{4 b^3 \sqrt{\tanh ^{-1}(\tanh (a+b x))}} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [B] time = 0.119, size = 261, normalized size = 2. \begin{align*}{\frac{1}{2\,b}{x}^{{\frac{5}{2}}}{\frac{1}{\sqrt{{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) }}}}-{\frac{5\,a}{4\,{b}^{2}}{x}^{{\frac{3}{2}}}{\frac{1}{\sqrt{{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) }}}}-{\frac{15\,{a}^{2}}{4\,{b}^{3}}\sqrt{x}{\frac{1}{\sqrt{{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) }}}}+{\frac{15\,{a}^{2}}{4}\ln \left ( \sqrt{b}\sqrt{x}+\sqrt{{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) } \right ){b}^{-{\frac{7}{2}}}}-{\frac{15\,a \left ({\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) -bx-a \right ) }{2\,{b}^{3}}\sqrt{x}{\frac{1}{\sqrt{{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) }}}}+{\frac{15\,a \left ({\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) -bx-a \right ) }{2}\ln \left ( \sqrt{b}\sqrt{x}+\sqrt{{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) } \right ){b}^{-{\frac{7}{2}}}}-{\frac{5\,{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) -5\,bx-5\,a}{4\,{b}^{2}}{x}^{{\frac{3}{2}}}{\frac{1}{\sqrt{{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) }}}}-{\frac{15\, \left ({\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) -bx-a \right ) ^{2}}{4\,{b}^{3}}\sqrt{x}{\frac{1}{\sqrt{{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) }}}}+{\frac{15\, \left ({\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) -bx-a \right ) ^{2}}{4}\ln \left ( \sqrt{b}\sqrt{x}+\sqrt{{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) } \right ){b}^{-{\frac{7}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{\frac{5}{2}}}{\operatorname{artanh}\left (\tanh \left (b x + a\right )\right )^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [A] time = 2.22357, size = 429, normalized size = 3.35 \begin{align*} \left [\frac{15 \,{\left (a^{2} b x + a^{3}\right )} \sqrt{b} \log \left (2 \, b x + 2 \, \sqrt{b x + a} \sqrt{b} \sqrt{x} + a\right ) + 2 \,{\left (2 \, b^{3} x^{2} - 5 \, a b^{2} x - 15 \, a^{2} b\right )} \sqrt{b x + a} \sqrt{x}}{8 \,{\left (b^{5} x + a b^{4}\right )}}, -\frac{15 \,{\left (a^{2} b x + a^{3}\right )} \sqrt{-b} \arctan \left (\frac{\sqrt{b x + a} \sqrt{-b}}{b \sqrt{x}}\right ) -{\left (2 \, b^{3} x^{2} - 5 \, a b^{2} x - 15 \, a^{2} b\right )} \sqrt{b x + a} \sqrt{x}}{4 \,{\left (b^{5} x + a b^{4}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [A] time = 1.20362, size = 85, normalized size = 0.66 \begin{align*} \frac{{\left (x{\left (\frac{2 \, x}{b} - \frac{5 \, a}{b^{2}}\right )} - \frac{15 \, a^{2}}{b^{3}}\right )} \sqrt{x}}{4 \, \sqrt{b x + a}} - \frac{15 \, a^{2} \log \left ({\left | -\sqrt{b} \sqrt{x} + \sqrt{b x + a} \right |}\right )}{4 \, b^{\frac{7}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]