Optimal. Leaf size=55 \[ \frac{8 x \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{b^2}-\frac{16 \tanh ^{-1}(\tanh (a+b x))^{3/2}}{3 b^3}-\frac{2 x^2}{b \sqrt{\tanh ^{-1}(\tanh (a+b x))}} \]
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Rubi [A] time = 0.0300588, antiderivative size = 55, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {2168, 2157, 30} \[ \frac{8 x \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{b^2}-\frac{16 \tanh ^{-1}(\tanh (a+b x))^{3/2}}{3 b^3}-\frac{2 x^2}{b \sqrt{\tanh ^{-1}(\tanh (a+b x))}} \]
Antiderivative was successfully verified.
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Rule 2168
Rule 2157
Rule 30
Rubi steps
\begin{align*} \int \frac{x^2}{\tanh ^{-1}(\tanh (a+b x))^{3/2}} \, dx &=-\frac{2 x^2}{b \sqrt{\tanh ^{-1}(\tanh (a+b x))}}+\frac{4 \int \frac{x}{\sqrt{\tanh ^{-1}(\tanh (a+b x))}} \, dx}{b}\\ &=-\frac{2 x^2}{b \sqrt{\tanh ^{-1}(\tanh (a+b x))}}+\frac{8 x \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{b^2}-\frac{8 \int \sqrt{\tanh ^{-1}(\tanh (a+b x))} \, dx}{b^2}\\ &=-\frac{2 x^2}{b \sqrt{\tanh ^{-1}(\tanh (a+b x))}}+\frac{8 x \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{b^2}-\frac{8 \operatorname{Subst}\left (\int \sqrt{x} \, dx,x,\tanh ^{-1}(\tanh (a+b x))\right )}{b^3}\\ &=-\frac{2 x^2}{b \sqrt{\tanh ^{-1}(\tanh (a+b x))}}+\frac{8 x \sqrt{\tanh ^{-1}(\tanh (a+b x))}}{b^2}-\frac{16 \tanh ^{-1}(\tanh (a+b x))^{3/2}}{3 b^3}\\ \end{align*}
Mathematica [A] time = 0.0320327, size = 49, normalized size = 0.89 \[ -\frac{2 \left (-12 b x \tanh ^{-1}(\tanh (a+b x))+8 \tanh ^{-1}(\tanh (a+b x))^2+3 b^2 x^2\right )}{3 b^3 \sqrt{\tanh ^{-1}(\tanh (a+b x))}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.04, size = 106, normalized size = 1.9 \begin{align*} 2\,{\frac{1}{{b}^{3}} \left ( 1/3\, \left ({\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) \right ) ^{3/2}-2\,a\sqrt{{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) }-2\, \left ({\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) -bx-a \right ) \sqrt{{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) }-{\frac{{a}^{2}+2\,a \left ({\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) -bx-a \right ) + \left ({\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) -bx-a \right ) ^{2}}{\sqrt{{\it Artanh} \left ( \tanh \left ( bx+a \right ) \right ) }}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.78539, size = 55, normalized size = 1. \begin{align*} \frac{2 \,{\left (b^{3} x^{3} - 3 \, a b^{2} x^{2} - 12 \, a^{2} b x - 8 \, a^{3}\right )}}{3 \,{\left (b x + a\right )}^{\frac{3}{2}} b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.26811, size = 85, normalized size = 1.55 \begin{align*} \frac{2 \,{\left (b^{2} x^{2} - 4 \, a b x - 8 \, a^{2}\right )} \sqrt{b x + a}}{3 \,{\left (b^{4} x + a b^{3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2}}{\operatorname{atanh}^{\frac{3}{2}}{\left (\tanh{\left (a + b x \right )} \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.15513, size = 62, normalized size = 1.13 \begin{align*} -\frac{2 \, a^{2}}{\sqrt{b x + a} b^{3}} + \frac{2 \,{\left ({\left (b x + a\right )}^{\frac{3}{2}} b^{6} - 6 \, \sqrt{b x + a} a b^{6}\right )}}{3 \, b^{9}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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