Optimal. Leaf size=127 \[ -\frac{5 d^2 x \sqrt{d+e x^2}}{96 e^{5/2}}+\frac{5 d^3 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )}{96 e^3}+\frac{5 d x^3 \sqrt{d+e x^2}}{144 e^{3/2}}-\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{e}}+\frac{1}{6} x^6 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right ) \]
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Rubi [A] time = 0.0524512, antiderivative size = 127, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.174, Rules used = {6221, 321, 217, 206} \[ -\frac{5 d^2 x \sqrt{d+e x^2}}{96 e^{5/2}}+\frac{5 d^3 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )}{96 e^3}+\frac{5 d x^3 \sqrt{d+e x^2}}{144 e^{3/2}}-\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{e}}+\frac{1}{6} x^6 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right ) \]
Antiderivative was successfully verified.
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Rule 6221
Rule 321
Rule 217
Rule 206
Rubi steps
\begin{align*} \int x^5 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right ) \, dx &=\frac{1}{6} x^6 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )-\frac{1}{6} \sqrt{e} \int \frac{x^6}{\sqrt{d+e x^2}} \, dx\\ &=-\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{e}}+\frac{1}{6} x^6 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )+\frac{(5 d) \int \frac{x^4}{\sqrt{d+e x^2}} \, dx}{36 \sqrt{e}}\\ &=\frac{5 d x^3 \sqrt{d+e x^2}}{144 e^{3/2}}-\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{e}}+\frac{1}{6} x^6 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )-\frac{\left (5 d^2\right ) \int \frac{x^2}{\sqrt{d+e x^2}} \, dx}{48 e^{3/2}}\\ &=-\frac{5 d^2 x \sqrt{d+e x^2}}{96 e^{5/2}}+\frac{5 d x^3 \sqrt{d+e x^2}}{144 e^{3/2}}-\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{e}}+\frac{1}{6} x^6 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )+\frac{\left (5 d^3\right ) \int \frac{1}{\sqrt{d+e x^2}} \, dx}{96 e^{5/2}}\\ &=-\frac{5 d^2 x \sqrt{d+e x^2}}{96 e^{5/2}}+\frac{5 d x^3 \sqrt{d+e x^2}}{144 e^{3/2}}-\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{e}}+\frac{1}{6} x^6 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )+\frac{\left (5 d^3\right ) \operatorname{Subst}\left (\int \frac{1}{1-e x^2} \, dx,x,\frac{x}{\sqrt{d+e x^2}}\right )}{96 e^{5/2}}\\ &=-\frac{5 d^2 x \sqrt{d+e x^2}}{96 e^{5/2}}+\frac{5 d x^3 \sqrt{d+e x^2}}{144 e^{3/2}}-\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{e}}+\frac{5 d^3 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )}{96 e^3}+\frac{1}{6} x^6 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )\\ \end{align*}
Mathematica [A] time = 0.0719379, size = 99, normalized size = 0.78 \[ \frac{\sqrt{e} x \sqrt{d+e x^2} \left (-15 d^2+10 d e x^2-8 e^2 x^4\right )+15 d^3 \log \left (\sqrt{d+e x^2}+\sqrt{e} x\right )+48 e^3 x^6 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )}{288 e^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.036, size = 172, normalized size = 1.4 \begin{align*}{\frac{{x}^{6}}{6}{\it Artanh} \left ({x\sqrt{e}{\frac{1}{\sqrt{e{x}^{2}+d}}}} \right ) }+{\frac{{x}^{7}}{48\,d}\sqrt{e}\sqrt{e{x}^{2}+d}}-{\frac{7\,{x}^{5}}{288}\sqrt{e{x}^{2}+d}{\frac{1}{\sqrt{e}}}}+{\frac{35\,d{x}^{3}}{1152}\sqrt{e{x}^{2}+d}{e}^{-{\frac{3}{2}}}}-{\frac{5\,{d}^{2}x}{128}\sqrt{e{x}^{2}+d}{e}^{-{\frac{5}{2}}}}+{\frac{5\,{d}^{3}}{96\,{e}^{3}}\ln \left ( x\sqrt{e}+\sqrt{e{x}^{2}+d} \right ) }-{\frac{{x}^{5}}{48\,d} \left ( e{x}^{2}+d \right ) ^{{\frac{3}{2}}}{\frac{1}{\sqrt{e}}}}+{\frac{5\,{x}^{3}}{288} \left ( e{x}^{2}+d \right ) ^{{\frac{3}{2}}}{e}^{-{\frac{3}{2}}}}-{\frac{5\,dx}{384} \left ( e{x}^{2}+d \right ) ^{{\frac{3}{2}}}{e}^{-{\frac{5}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{12} \, x^{6} \log \left (\sqrt{e} x + \sqrt{e x^{2} + d}\right ) - \frac{1}{12} \, x^{6} \log \left (-\sqrt{e} x + \sqrt{e x^{2} + d}\right ) - \frac{1}{2} \, d \sqrt{e} \int -\frac{\sqrt{e x^{2} + d} x^{6}}{3 \,{\left (e^{2} x^{4} + d e x^{2} -{\left (e x^{2} + d\right )}^{2}\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.20834, size = 205, normalized size = 1.61 \begin{align*} -\frac{2 \,{\left (8 \, e^{2} x^{5} - 10 \, d e x^{3} + 15 \, d^{2} x\right )} \sqrt{e x^{2} + d} \sqrt{e} - 3 \,{\left (16 \, e^{3} x^{6} + 5 \, d^{3}\right )} \log \left (\frac{2 \, e x^{2} + 2 \, \sqrt{e x^{2} + d} \sqrt{e} x + d}{d}\right )}{576 \, e^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 11.8099, size = 121, normalized size = 0.95 \begin{align*} \begin{cases} \frac{5 d^{3} \operatorname{atanh}{\left (\frac{\sqrt{e} x}{\sqrt{d + e x^{2}}} \right )}}{96 e^{3}} - \frac{5 d^{2} x \sqrt{d + e x^{2}}}{96 e^{\frac{5}{2}}} + \frac{5 d x^{3} \sqrt{d + e x^{2}}}{144 e^{\frac{3}{2}}} + \frac{x^{6} \operatorname{atanh}{\left (\frac{\sqrt{e} x}{\sqrt{d + e x^{2}}} \right )}}{6} - \frac{x^{5} \sqrt{d + e x^{2}}}{36 \sqrt{e}} & \text{for}\: e \neq 0 \\0 & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \left [\mathit{undef}, \mathit{undef}, \mathit{undef}, \mathit{undef}, \mathit{undef}, -\frac{1}{2} \, d e^{\frac{1}{2}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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