Optimal. Leaf size=107 \[ -\frac{2 (a+1)^2 \tanh ^{-1}\left (\frac{\sqrt{1-a} \sqrt{a+b x+1}}{\sqrt{a+1} \sqrt{-a-b x+1}}\right )}{(1-a) \sqrt{1-a^2}}+\frac{4 \sqrt{a+b x+1}}{(1-a) \sqrt{-a-b x+1}}-\sin ^{-1}(a+b x) \]
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Rubi [A] time = 0.0908619, antiderivative size = 107, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.571, Rules used = {6163, 98, 157, 53, 619, 216, 93, 208} \[ -\frac{2 (a+1)^2 \tanh ^{-1}\left (\frac{\sqrt{1-a} \sqrt{a+b x+1}}{\sqrt{a+1} \sqrt{-a-b x+1}}\right )}{(1-a) \sqrt{1-a^2}}+\frac{4 \sqrt{a+b x+1}}{(1-a) \sqrt{-a-b x+1}}-\sin ^{-1}(a+b x) \]
Antiderivative was successfully verified.
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Rule 6163
Rule 98
Rule 157
Rule 53
Rule 619
Rule 216
Rule 93
Rule 208
Rubi steps
\begin{align*} \int \frac{e^{3 \tanh ^{-1}(a+b x)}}{x} \, dx &=\int \frac{(1+a+b x)^{3/2}}{x (1-a-b x)^{3/2}} \, dx\\ &=\frac{4 \sqrt{1+a+b x}}{(1-a) \sqrt{1-a-b x}}-\frac{2 \int \frac{-\frac{1}{2} (1+a)^2 b+\frac{1}{2} (1-a) b^2 x}{x \sqrt{1-a-b x} \sqrt{1+a+b x}} \, dx}{(1-a) b}\\ &=\frac{4 \sqrt{1+a+b x}}{(1-a) \sqrt{1-a-b x}}+\frac{(1+a)^2 \int \frac{1}{x \sqrt{1-a-b x} \sqrt{1+a+b x}} \, dx}{1-a}-b \int \frac{1}{\sqrt{1-a-b x} \sqrt{1+a+b x}} \, dx\\ &=\frac{4 \sqrt{1+a+b x}}{(1-a) \sqrt{1-a-b x}}+\frac{\left (2 (1+a)^2\right ) \operatorname{Subst}\left (\int \frac{1}{-1-a-(-1+a) x^2} \, dx,x,\frac{\sqrt{1+a+b x}}{\sqrt{1-a-b x}}\right )}{1-a}-b \int \frac{1}{\sqrt{(1-a) (1+a)-2 a b x-b^2 x^2}} \, dx\\ &=\frac{4 \sqrt{1+a+b x}}{(1-a) \sqrt{1-a-b x}}-\frac{2 (1+a)^2 \tanh ^{-1}\left (\frac{\sqrt{1-a} \sqrt{1+a+b x}}{\sqrt{1+a} \sqrt{1-a-b x}}\right )}{(1-a) \sqrt{1-a^2}}+\frac{\operatorname{Subst}\left (\int \frac{1}{\sqrt{1-\frac{x^2}{4 b^2}}} \, dx,x,-2 a b-2 b^2 x\right )}{2 b}\\ &=\frac{4 \sqrt{1+a+b x}}{(1-a) \sqrt{1-a-b x}}-\sin ^{-1}(a+b x)-\frac{2 (1+a)^2 \tanh ^{-1}\left (\frac{\sqrt{1-a} \sqrt{1+a+b x}}{\sqrt{1+a} \sqrt{1-a-b x}}\right )}{(1-a) \sqrt{1-a^2}}\\ \end{align*}
Mathematica [A] time = 0.486515, size = 160, normalized size = 1.5 \[ \frac{2 \sqrt{b} \sinh ^{-1}\left (\frac{\sqrt{-b} \sqrt{-a-b x+1}}{\sqrt{2} \sqrt{b}}\right )}{\sqrt{-b}}-\frac{2 \left (2 \sqrt{a-1} \sqrt{a+1} \sqrt{a+b x+1}+(a+1)^2 \sqrt{-a-b x+1} \tan ^{-1}\left (\frac{\sqrt{-a-b x+1}}{\sqrt{\frac{a-1}{a+1}} \sqrt{a+b x+1}}\right )\right )}{(a-1)^{3/2} \sqrt{a+1} \sqrt{-a-b x+1}} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.042, size = 1019, normalized size = 9.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.14404, size = 1058, normalized size = 9.89 \begin{align*} \left [\frac{{\left ({\left (a + 1\right )} b x + a^{2} - 1\right )} \sqrt{-\frac{a + 1}{a - 1}} \log \left (\frac{{\left (2 \, a^{2} - 1\right )} b^{2} x^{2} + 2 \, a^{4} + 4 \,{\left (a^{3} - a\right )} b x - 4 \, a^{2} + 2 \, \sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}{\left (a^{3} +{\left (a^{2} - a\right )} b x - a^{2} - a + 1\right )} \sqrt{-\frac{a + 1}{a - 1}} + 2}{x^{2}}\right ) + 2 \,{\left ({\left (a - 1\right )} b x + a^{2} - 2 \, a + 1\right )} \arctan \left (\frac{\sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}{\left (b x + a\right )}}{b^{2} x^{2} + 2 \, a b x + a^{2} - 1}\right ) + 8 \, \sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}}{2 \,{\left ({\left (a - 1\right )} b x + a^{2} - 2 \, a + 1\right )}}, -\frac{{\left ({\left (a + 1\right )} b x + a^{2} - 1\right )} \sqrt{\frac{a + 1}{a - 1}} \arctan \left (\frac{\sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}{\left (a b x + a^{2} - 1\right )} \sqrt{\frac{a + 1}{a - 1}}}{{\left (a + 1\right )} b^{2} x^{2} + a^{3} + 2 \,{\left (a^{2} + a\right )} b x + a^{2} - a - 1}\right ) -{\left ({\left (a - 1\right )} b x + a^{2} - 2 \, a + 1\right )} \arctan \left (\frac{\sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}{\left (b x + a\right )}}{b^{2} x^{2} + 2 \, a b x + a^{2} - 1}\right ) - 4 \, \sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}}{{\left (a - 1\right )} b x + a^{2} - 2 \, a + 1}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + b x + 1\right )^{3}}{x \left (- \left (a + b x - 1\right ) \left (a + b x + 1\right )\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.25198, size = 188, normalized size = 1.76 \begin{align*} \frac{b \arcsin \left (-b x - a\right ) \mathrm{sgn}\left (b\right )}{{\left | b \right |}} - \frac{2 \,{\left (a^{2} b + 2 \, a b + b\right )} \arctan \left (\frac{\frac{{\left (\sqrt{-{\left (b x + a\right )}^{2} + 1}{\left | b \right |} + b\right )} a}{b^{2} x + a b} - 1}{\sqrt{a^{2} - 1}}\right )}{\sqrt{a^{2} - 1}{\left (a{\left | b \right |} -{\left | b \right |}\right )}} - \frac{8 \, b}{{\left (a{\left | b \right |} -{\left | b \right |}\right )}{\left (\frac{\sqrt{-{\left (b x + a\right )}^{2} + 1}{\left | b \right |} + b}{b^{2} x + a b} - 1\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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