Optimal. Leaf size=335 \[ -4 \sqrt{2 \pi } \sin (1) \text{FresnelC}\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+\frac{15}{2} \sqrt{\frac{\pi }{2}} \sin (1) \text{FresnelC}\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )-4 \sqrt{2 \pi } \cos (1) \text{FresnelC}\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+\frac{15}{4} \sqrt{\frac{\pi }{2}} \cos (1) \text{FresnelC}\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )-4 \sqrt{2 \pi } \sin (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+\frac{15}{4} \sqrt{\frac{\pi }{2}} \sin (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+4 \sqrt{2 \pi } \cos (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )-\frac{15}{2} \sqrt{\frac{\pi }{2}} \cos (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+\frac{5}{2} (1-x)^{3/2} \sin (x)-\frac{15}{2} \sqrt{1-x} \sin (x)+(1-x)^{5/2} \cos (x)-5 (1-x)^{3/2} \cos (x)+\frac{17}{4} \sqrt{1-x} \cos (x) \]
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Rubi [A] time = 0.475661, antiderivative size = 335, normalized size of antiderivative = 1., number of steps used = 22, number of rules used = 8, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.533, Rules used = {6129, 6742, 3353, 3352, 3351, 3385, 3354, 3386} \[ -4 \sqrt{2 \pi } \sin (1) \text{FresnelC}\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+\frac{15}{2} \sqrt{\frac{\pi }{2}} \sin (1) \text{FresnelC}\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )-4 \sqrt{2 \pi } \cos (1) \text{FresnelC}\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+\frac{15}{4} \sqrt{\frac{\pi }{2}} \cos (1) \text{FresnelC}\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )-4 \sqrt{2 \pi } \sin (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+\frac{15}{4} \sqrt{\frac{\pi }{2}} \sin (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+4 \sqrt{2 \pi } \cos (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )-\frac{15}{2} \sqrt{\frac{\pi }{2}} \cos (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+\frac{5}{2} (1-x)^{3/2} \sin (x)-\frac{15}{2} \sqrt{1-x} \sin (x)+(1-x)^{5/2} \cos (x)-5 (1-x)^{3/2} \cos (x)+\frac{17}{4} \sqrt{1-x} \cos (x) \]
Antiderivative was successfully verified.
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Rule 6129
Rule 6742
Rule 3353
Rule 3352
Rule 3351
Rule 3385
Rule 3354
Rule 3386
Rubi steps
\begin{align*} \int e^{\tanh ^{-1}(x)} x (1+x)^{3/2} \sin (x) \, dx &=\int \frac{x (1+x)^2 \sin (x)}{\sqrt{1-x}} \, dx\\ &=2 \operatorname{Subst}\left (\int \left (-2+x^2\right )^2 \left (-1+x^2\right ) \sin \left (1-x^2\right ) \, dx,x,\sqrt{1-x}\right )\\ &=2 \operatorname{Subst}\left (\int \left (-4 \sin \left (1-x^2\right )+8 x^2 \sin \left (1-x^2\right )-5 x^4 \sin \left (1-x^2\right )+x^6 \sin \left (1-x^2\right )\right ) \, dx,x,\sqrt{1-x}\right )\\ &=2 \operatorname{Subst}\left (\int x^6 \sin \left (1-x^2\right ) \, dx,x,\sqrt{1-x}\right )-8 \operatorname{Subst}\left (\int \sin \left (1-x^2\right ) \, dx,x,\sqrt{1-x}\right )-10 \operatorname{Subst}\left (\int x^4 \sin \left (1-x^2\right ) \, dx,x,\sqrt{1-x}\right )+16 \operatorname{Subst}\left (\int x^2 \sin \left (1-x^2\right ) \, dx,x,\sqrt{1-x}\right )\\ &=8 \sqrt{1-x} \cos (x)-5 (1-x)^{3/2} \cos (x)+(1-x)^{5/2} \cos (x)-5 \operatorname{Subst}\left (\int x^4 \cos \left (1-x^2\right ) \, dx,x,\sqrt{1-x}\right )-8 \operatorname{Subst}\left (\int \cos \left (1-x^2\right ) \, dx,x,\sqrt{1-x}\right )+15 \operatorname{Subst}\left (\int x^2 \cos \left (1-x^2\right ) \, dx,x,\sqrt{1-x}\right )+(8 \cos (1)) \operatorname{Subst}\left (\int \sin \left (x^2\right ) \, dx,x,\sqrt{1-x}\right )-(8 \sin (1)) \operatorname{Subst}\left (\int \cos \left (x^2\right ) \, dx,x,\sqrt{1-x}\right )\\ &=8 \sqrt{1-x} \cos (x)-5 (1-x)^{3/2} \cos (x)+(1-x)^{5/2} \cos (x)+4 \sqrt{2 \pi } \cos (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )-4 \sqrt{2 \pi } C\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right ) \sin (1)-\frac{15}{2} \sqrt{1-x} \sin (x)+\frac{5}{2} (1-x)^{3/2} \sin (x)+\frac{15}{2} \operatorname{Subst}\left (\int \sin \left (1-x^2\right ) \, dx,x,\sqrt{1-x}\right )-\frac{15}{2} \operatorname{Subst}\left (\int x^2 \sin \left (1-x^2\right ) \, dx,x,\sqrt{1-x}\right )-(8 \cos (1)) \operatorname{Subst}\left (\int \cos \left (x^2\right ) \, dx,x,\sqrt{1-x}\right )-(8 \sin (1)) \operatorname{Subst}\left (\int \sin \left (x^2\right ) \, dx,x,\sqrt{1-x}\right )\\ &=\frac{17}{4} \sqrt{1-x} \cos (x)-5 (1-x)^{3/2} \cos (x)+(1-x)^{5/2} \cos (x)-4 \sqrt{2 \pi } \cos (1) C\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+4 \sqrt{2 \pi } \cos (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )-4 \sqrt{2 \pi } C\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right ) \sin (1)-4 \sqrt{2 \pi } S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right ) \sin (1)-\frac{15}{2} \sqrt{1-x} \sin (x)+\frac{5}{2} (1-x)^{3/2} \sin (x)+\frac{15}{4} \operatorname{Subst}\left (\int \cos \left (1-x^2\right ) \, dx,x,\sqrt{1-x}\right )-\frac{1}{2} (15 \cos (1)) \operatorname{Subst}\left (\int \sin \left (x^2\right ) \, dx,x,\sqrt{1-x}\right )+\frac{1}{2} (15 \sin (1)) \operatorname{Subst}\left (\int \cos \left (x^2\right ) \, dx,x,\sqrt{1-x}\right )\\ &=\frac{17}{4} \sqrt{1-x} \cos (x)-5 (1-x)^{3/2} \cos (x)+(1-x)^{5/2} \cos (x)-4 \sqrt{2 \pi } \cos (1) C\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )-\frac{15}{2} \sqrt{\frac{\pi }{2}} \cos (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+4 \sqrt{2 \pi } \cos (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+\frac{15}{2} \sqrt{\frac{\pi }{2}} C\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right ) \sin (1)-4 \sqrt{2 \pi } C\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right ) \sin (1)-4 \sqrt{2 \pi } S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right ) \sin (1)-\frac{15}{2} \sqrt{1-x} \sin (x)+\frac{5}{2} (1-x)^{3/2} \sin (x)+\frac{1}{4} (15 \cos (1)) \operatorname{Subst}\left (\int \cos \left (x^2\right ) \, dx,x,\sqrt{1-x}\right )+\frac{1}{4} (15 \sin (1)) \operatorname{Subst}\left (\int \sin \left (x^2\right ) \, dx,x,\sqrt{1-x}\right )\\ &=\frac{17}{4} \sqrt{1-x} \cos (x)-5 (1-x)^{3/2} \cos (x)+(1-x)^{5/2} \cos (x)+\frac{15}{4} \sqrt{\frac{\pi }{2}} \cos (1) C\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )-4 \sqrt{2 \pi } \cos (1) C\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )-\frac{15}{2} \sqrt{\frac{\pi }{2}} \cos (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+4 \sqrt{2 \pi } \cos (1) S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right )+\frac{15}{2} \sqrt{\frac{\pi }{2}} C\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right ) \sin (1)-4 \sqrt{2 \pi } C\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right ) \sin (1)+\frac{15}{4} \sqrt{\frac{\pi }{2}} S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right ) \sin (1)-4 \sqrt{2 \pi } S\left (\sqrt{\frac{2}{\pi }} \sqrt{1-x}\right ) \sin (1)-\frac{15}{2} \sqrt{1-x} \sin (x)+\frac{5}{2} (1-x)^{3/2} \sin (x)\\ \end{align*}
Mathematica [C] time = 9.47678, size = 200, normalized size = 0.6 \[ \frac{\left (\frac{1}{32}+\frac{i}{32}\right ) \sqrt{x+1} \left ((\cos (x+1)-i \sin (x+1)) \left ((17+2 i) \sqrt{2 \pi } \sqrt{x-1} \text{Erf}\left (\frac{(1+i) \sqrt{x-1}}{\sqrt{2}}\right ) (\sin (x)-i \cos (x))+(2+2 i) \left (4 i x^3+(10+8 i) x^2+(10-11 i) x-(20+i)\right ) (\cos (1)+i \sin (1))\right )+(-2-17 i) \sqrt{2 \pi } \sqrt{x-1} \text{Erfi}\left (\frac{(1+i) \sqrt{x-1}}{\sqrt{2}}\right ) (\cos (1)+i \sin (1))-(2-2 i) \left (4 x^3+(8+10 i) x^2-(11-10 i) x-(1+20 i)\right ) (\cos (x)+i \sin (x))\right )}{\sqrt{1-x^2}} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.28, size = 0, normalized size = 0. \begin{align*} \int{x\sin \left ( x \right ) \left ( 1+x \right ) ^{{\frac{5}{2}}}{\frac{1}{\sqrt{-{x}^{2}+1}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [C] time = 1.40317, size = 1364, normalized size = 4.07 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{{\left (x^{2} + x\right )} \sqrt{-x^{2} + 1} \sqrt{x + 1} \sin \left (x\right )}{x - 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [C] time = 1.28932, size = 273, normalized size = 0.81 \begin{align*} -\left (\frac{19}{32} i - \frac{15}{32}\right ) \, \sqrt{2} \sqrt{\pi } \operatorname{erf}\left (-\left (\frac{1}{2} i + \frac{1}{2}\right ) \, \sqrt{2} \sqrt{-x + 1}\right ) e^{i} + \left (\frac{19}{32} i + \frac{15}{32}\right ) \, \sqrt{2} \sqrt{\pi } \operatorname{erf}\left (\left (\frac{1}{2} i - \frac{1}{2}\right ) \, \sqrt{2} \sqrt{-x + 1}\right ) e^{\left (-i\right )} - \frac{1}{8} i \,{\left (4 i \,{\left (x - 1\right )}^{2} \sqrt{-x + 1} - \left (12 i - 10\right ) \,{\left (-x + 1\right )}^{\frac{3}{2}} - \left (3 i + 18\right ) \, \sqrt{-x + 1}\right )} e^{\left (i \, x\right )} - \frac{1}{2} i \,{\left (-2 i \,{\left (-x + 1\right )}^{\frac{3}{2}} + \left (4 i - 3\right ) \, \sqrt{-x + 1}\right )} e^{\left (i \, x\right )} - \frac{1}{8} i \,{\left (4 i \,{\left (x - 1\right )}^{2} \sqrt{-x + 1} - \left (12 i + 10\right ) \,{\left (-x + 1\right )}^{\frac{3}{2}} - \left (3 i - 18\right ) \, \sqrt{-x + 1}\right )} e^{\left (-i \, x\right )} - \frac{1}{2} i \,{\left (-2 i \,{\left (-x + 1\right )}^{\frac{3}{2}} + \left (4 i + 3\right ) \, \sqrt{-x + 1}\right )} e^{\left (-i \, x\right )} + \frac{1}{2} \, \sqrt{-x + 1} e^{\left (i \, x\right )} + \frac{1}{2} \, \sqrt{-x + 1} e^{\left (-i \, x\right )} + 3.25954715712 \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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