3.748 \(\int e^{2 \tanh ^{-1}(a x)} \sqrt{c-\frac{c}{a^2 x^2}} x^2 \, dx\)

Optimal. Leaf size=123 \[ -\frac{x (a x+1)^2 \sqrt{c-\frac{c}{a^2 x^2}}}{3 a^2}-\frac{x (a x+1) \sqrt{c-\frac{c}{a^2 x^2}}}{3 a^2}-\frac{x \sqrt{c-\frac{c}{a^2 x^2}}}{a^2}+\frac{x \sqrt{c-\frac{c}{a^2 x^2}} \sin ^{-1}(a x)}{a^2 \sqrt{1-a x} \sqrt{a x+1}} \]

[Out]

-((Sqrt[c - c/(a^2*x^2)]*x)/a^2) - (Sqrt[c - c/(a^2*x^2)]*x*(1 + a*x))/(3*a^2) - (Sqrt[c - c/(a^2*x^2)]*x*(1 +
a*x)^2)/(3*a^2) + (Sqrt[c - c/(a^2*x^2)]*x*ArcSin[a*x])/(a^2*Sqrt[1 - a*x]*Sqrt[1 + a*x])

________________________________________________________________________________________

Rubi [A]  time = 0.330686, antiderivative size = 123, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.222, Rules used = {6159, 6129, 80, 50, 41, 216} \[ -\frac{x (a x+1)^2 \sqrt{c-\frac{c}{a^2 x^2}}}{3 a^2}-\frac{x (a x+1) \sqrt{c-\frac{c}{a^2 x^2}}}{3 a^2}-\frac{x \sqrt{c-\frac{c}{a^2 x^2}}}{a^2}+\frac{x \sqrt{c-\frac{c}{a^2 x^2}} \sin ^{-1}(a x)}{a^2 \sqrt{1-a x} \sqrt{a x+1}} \]

Antiderivative was successfully verified.

[In]

Int[E^(2*ArcTanh[a*x])*Sqrt[c - c/(a^2*x^2)]*x^2,x]

[Out]

-((Sqrt[c - c/(a^2*x^2)]*x)/a^2) - (Sqrt[c - c/(a^2*x^2)]*x*(1 + a*x))/(3*a^2) - (Sqrt[c - c/(a^2*x^2)]*x*(1 +
a*x)^2)/(3*a^2) + (Sqrt[c - c/(a^2*x^2)]*x*ArcSin[a*x])/(a^2*Sqrt[1 - a*x]*Sqrt[1 + a*x])

Rule 6159

Int[E^(ArcTanh[(a_.)*(x_)]*(n_))*(u_.)*((c_) + (d_.)/(x_)^2)^(p_), x_Symbol] :> Dist[(x^(2*p)*(c + d/x^2)^p)/(
(1 - a*x)^p*(1 + a*x)^p), Int[(u*(1 - a*x)^p*(1 + a*x)^p*E^(n*ArcTanh[a*x]))/x^(2*p), x], x] /; FreeQ[{a, c, d
, n, p}, x] && EqQ[c + a^2*d, 0] &&  !IntegerQ[p] && IntegerQ[n/2] &&  !GtQ[c, 0]

Rule 6129

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)*(x_))^(p_.), x_Symbol] :> Dist[c^p, Int[(u*(1 + (d*x)/c)
^p*(1 + a*x)^(n/2))/(1 - a*x)^(n/2), x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[a^2*c^2 - d^2, 0] && (IntegerQ
[p] || GtQ[c, 0])

Rule 80

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(c + d*x)
^(n + 1)*(e + f*x)^(p + 1))/(d*f*(n + p + 2)), x] + Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p + 1)))/(
d*f*(n + p + 2)), Int[(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 2,
0]

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 41

Int[((a_) + (b_.)*(x_))^(m_.)*((c_) + (d_.)*(x_))^(m_.), x_Symbol] :> Int[(a*c + b*d*x^2)^m, x] /; FreeQ[{a, b
, c, d, m}, x] && EqQ[b*c + a*d, 0] && (IntegerQ[m] || (GtQ[a, 0] && GtQ[c, 0]))

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rubi steps

\begin{align*} \int e^{2 \tanh ^{-1}(a x)} \sqrt{c-\frac{c}{a^2 x^2}} x^2 \, dx &=\frac{\left (\sqrt{c-\frac{c}{a^2 x^2}} x\right ) \int e^{2 \tanh ^{-1}(a x)} x \sqrt{1-a x} \sqrt{1+a x} \, dx}{\sqrt{1-a x} \sqrt{1+a x}}\\ &=\frac{\left (\sqrt{c-\frac{c}{a^2 x^2}} x\right ) \int \frac{x (1+a x)^{3/2}}{\sqrt{1-a x}} \, dx}{\sqrt{1-a x} \sqrt{1+a x}}\\ &=-\frac{\sqrt{c-\frac{c}{a^2 x^2}} x (1+a x)^2}{3 a^2}+\frac{\left (2 \sqrt{c-\frac{c}{a^2 x^2}} x\right ) \int \frac{(1+a x)^{3/2}}{\sqrt{1-a x}} \, dx}{3 a \sqrt{1-a x} \sqrt{1+a x}}\\ &=-\frac{\sqrt{c-\frac{c}{a^2 x^2}} x (1+a x)}{3 a^2}-\frac{\sqrt{c-\frac{c}{a^2 x^2}} x (1+a x)^2}{3 a^2}+\frac{\left (\sqrt{c-\frac{c}{a^2 x^2}} x\right ) \int \frac{\sqrt{1+a x}}{\sqrt{1-a x}} \, dx}{a \sqrt{1-a x} \sqrt{1+a x}}\\ &=-\frac{\sqrt{c-\frac{c}{a^2 x^2}} x}{a^2}-\frac{\sqrt{c-\frac{c}{a^2 x^2}} x (1+a x)}{3 a^2}-\frac{\sqrt{c-\frac{c}{a^2 x^2}} x (1+a x)^2}{3 a^2}+\frac{\left (\sqrt{c-\frac{c}{a^2 x^2}} x\right ) \int \frac{1}{\sqrt{1-a x} \sqrt{1+a x}} \, dx}{a \sqrt{1-a x} \sqrt{1+a x}}\\ &=-\frac{\sqrt{c-\frac{c}{a^2 x^2}} x}{a^2}-\frac{\sqrt{c-\frac{c}{a^2 x^2}} x (1+a x)}{3 a^2}-\frac{\sqrt{c-\frac{c}{a^2 x^2}} x (1+a x)^2}{3 a^2}+\frac{\left (\sqrt{c-\frac{c}{a^2 x^2}} x\right ) \int \frac{1}{\sqrt{1-a^2 x^2}} \, dx}{a \sqrt{1-a x} \sqrt{1+a x}}\\ &=-\frac{\sqrt{c-\frac{c}{a^2 x^2}} x}{a^2}-\frac{\sqrt{c-\frac{c}{a^2 x^2}} x (1+a x)}{3 a^2}-\frac{\sqrt{c-\frac{c}{a^2 x^2}} x (1+a x)^2}{3 a^2}+\frac{\sqrt{c-\frac{c}{a^2 x^2}} x \sin ^{-1}(a x)}{a^2 \sqrt{1-a x} \sqrt{1+a x}}\\ \end{align*}

Mathematica [A]  time = 0.0626633, size = 84, normalized size = 0.68 \[ -\frac{x \sqrt{c-\frac{c}{a^2 x^2}} \left (\sqrt{a^2 x^2-1} \left (a^2 x^2+3 a x+5\right )+3 \log \left (\sqrt{a^2 x^2-1}+a x\right )\right )}{3 a^2 \sqrt{a^2 x^2-1}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[E^(2*ArcTanh[a*x])*Sqrt[c - c/(a^2*x^2)]*x^2,x]

[Out]

-(Sqrt[c - c/(a^2*x^2)]*x*(Sqrt[-1 + a^2*x^2]*(5 + 3*a*x + a^2*x^2) + 3*Log[a*x + Sqrt[-1 + a^2*x^2]]))/(3*a^2
*Sqrt[-1 + a^2*x^2])

________________________________________________________________________________________

Maple [A]  time = 0.124, size = 174, normalized size = 1.4 \begin{align*}{\frac{x}{3\,{a}^{3}c}\sqrt{{\frac{c \left ({a}^{2}{x}^{2}-1 \right ) }{{a}^{2}{x}^{2}}}} \left ( - \left ({\frac{c \left ({a}^{2}{x}^{2}-1 \right ) }{{a}^{2}}} \right ) ^{{\frac{3}{2}}}{a}^{3}-3\,\sqrt{{\frac{c \left ({a}^{2}{x}^{2}-1 \right ) }{{a}^{2}}}}x{a}^{2}c+3\,{c}^{3/2}\ln \left ( x\sqrt{c}+\sqrt{{\frac{c \left ({a}^{2}{x}^{2}-1 \right ) }{{a}^{2}}}} \right ) -6\,{c}^{3/2}\ln \left ({\frac{1}{\sqrt{c}} \left ( \sqrt{{\frac{ \left ( ax-1 \right ) \left ( ax+1 \right ) c}{{a}^{2}}}}\sqrt{c}+cx \right ) } \right ) -6\,\sqrt{{\frac{ \left ( ax-1 \right ) \left ( ax+1 \right ) c}{{a}^{2}}}}ac \right ){\frac{1}{\sqrt{{\frac{c \left ({a}^{2}{x}^{2}-1 \right ) }{{a}^{2}}}}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+1)^2/(-a^2*x^2+1)*x^2*(c-c/a^2/x^2)^(1/2),x)

[Out]

1/3*(c*(a^2*x^2-1)/a^2/x^2)^(1/2)*x*(-(c*(a^2*x^2-1)/a^2)^(3/2)*a^3-3*(c*(a^2*x^2-1)/a^2)^(1/2)*x*a^2*c+3*c^(3
/2)*ln(x*c^(1/2)+(c*(a^2*x^2-1)/a^2)^(1/2))-6*c^(3/2)*ln((((a*x-1)*(a*x+1)*c/a^2)^(1/2)*c^(1/2)+c*x)/c^(1/2))-
6*((a*x-1)*(a*x+1)*c/a^2)^(1/2)*a*c)/(c*(a^2*x^2-1)/a^2)^(1/2)/a^3/c

________________________________________________________________________________________

Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} -\int \frac{{\left (a x + 1\right )}^{2} \sqrt{c - \frac{c}{a^{2} x^{2}}} x^{2}}{a^{2} x^{2} - 1}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*x^2*(c-c/a^2/x^2)^(1/2),x, algorithm="maxima")

[Out]

-integrate((a*x + 1)^2*sqrt(c - c/(a^2*x^2))*x^2/(a^2*x^2 - 1), x)

________________________________________________________________________________________

Fricas [A]  time = 1.905, size = 439, normalized size = 3.57 \begin{align*} \left [-\frac{2 \,{\left (a^{3} x^{3} + 3 \, a^{2} x^{2} + 5 \, a x\right )} \sqrt{\frac{a^{2} c x^{2} - c}{a^{2} x^{2}}} - 3 \, \sqrt{c} \log \left (2 \, a^{2} c x^{2} - 2 \, a^{2} \sqrt{c} x^{2} \sqrt{\frac{a^{2} c x^{2} - c}{a^{2} x^{2}}} - c\right )}{6 \, a^{3}}, -\frac{{\left (a^{3} x^{3} + 3 \, a^{2} x^{2} + 5 \, a x\right )} \sqrt{\frac{a^{2} c x^{2} - c}{a^{2} x^{2}}} - 3 \, \sqrt{-c} \arctan \left (\frac{a^{2} \sqrt{-c} x^{2} \sqrt{\frac{a^{2} c x^{2} - c}{a^{2} x^{2}}}}{a^{2} c x^{2} - c}\right )}{3 \, a^{3}}\right ] \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*x^2*(c-c/a^2/x^2)^(1/2),x, algorithm="fricas")

[Out]

[-1/6*(2*(a^3*x^3 + 3*a^2*x^2 + 5*a*x)*sqrt((a^2*c*x^2 - c)/(a^2*x^2)) - 3*sqrt(c)*log(2*a^2*c*x^2 - 2*a^2*sqr
t(c)*x^2*sqrt((a^2*c*x^2 - c)/(a^2*x^2)) - c))/a^3, -1/3*((a^3*x^3 + 3*a^2*x^2 + 5*a*x)*sqrt((a^2*c*x^2 - c)/(
a^2*x^2)) - 3*sqrt(-c)*arctan(a^2*sqrt(-c)*x^2*sqrt((a^2*c*x^2 - c)/(a^2*x^2))/(a^2*c*x^2 - c)))/a^3]

________________________________________________________________________________________

Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} - \int \frac{x^{2} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a x - 1}\, dx - \int \frac{a x^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a x - 1}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)**2/(-a**2*x**2+1)*x**2*(c-c/a**2/x**2)**(1/2),x)

[Out]

-Integral(x**2*sqrt(c - c/(a**2*x**2))/(a*x - 1), x) - Integral(a*x**3*sqrt(c - c/(a**2*x**2))/(a*x - 1), x)

________________________________________________________________________________________

Giac [A]  time = 1.26156, size = 157, normalized size = 1.28 \begin{align*} -\frac{1}{6} \,{\left (2 \, \sqrt{a^{2} c x^{2} - c}{\left (x{\left (\frac{x \mathrm{sgn}\left (x\right )}{a^{2}} + \frac{3 \, \mathrm{sgn}\left (x\right )}{a^{3}}\right )} + \frac{5 \, \mathrm{sgn}\left (x\right )}{a^{4}}\right )} - \frac{6 \, \sqrt{c} \log \left ({\left | -\sqrt{a^{2} c} x + \sqrt{a^{2} c x^{2} - c} \right |}\right ) \mathrm{sgn}\left (x\right )}{a^{3}{\left | a \right |}} + \frac{{\left (3 \, a \sqrt{c} \log \left ({\left | c \right |}\right ) - 10 \, \sqrt{-c}{\left | a \right |}\right )} \mathrm{sgn}\left (x\right )}{a^{4}{\left | a \right |}}\right )}{\left | a \right |} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*x^2*(c-c/a^2/x^2)^(1/2),x, algorithm="giac")

[Out]

-1/6*(2*sqrt(a^2*c*x^2 - c)*(x*(x*sgn(x)/a^2 + 3*sgn(x)/a^3) + 5*sgn(x)/a^4) - 6*sqrt(c)*log(abs(-sqrt(a^2*c)*
x + sqrt(a^2*c*x^2 - c)))*sgn(x)/(a^3*abs(a)) + (3*a*sqrt(c)*log(abs(c)) - 10*sqrt(-c)*abs(a))*sgn(x)/(a^4*abs
(a)))*abs(a)