3.722 \(\int \frac{e^{-\tanh ^{-1}(a x)}}{(c-\frac{c}{a^2 x^2})^{7/2}} \, dx\)

Optimal. Leaf size=361 \[ -\frac{5 \left (1-a^2 x^2\right )^{7/2}}{16 a^8 x^7 (1-a x) \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{3 \left (1-a^2 x^2\right )^{7/2}}{2 a^8 x^7 (a x+1) \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{\left (1-a^2 x^2\right )^{7/2}}{32 a^8 x^7 (1-a x)^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}-\frac{11 \left (1-a^2 x^2\right )^{7/2}}{32 a^8 x^7 (a x+1)^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{\left (1-a^2 x^2\right )^{7/2}}{24 a^8 x^7 (a x+1)^3 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}-\frac{\left (1-a^2 x^2\right )^{7/2}}{a^7 x^6 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}-\frac{19 \left (1-a^2 x^2\right )^{7/2} \log (1-a x)}{32 a^8 x^7 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{51 \left (1-a^2 x^2\right )^{7/2} \log (a x+1)}{32 a^8 x^7 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}} \]

[Out]

-((1 - a^2*x^2)^(7/2)/(a^7*(c - c/(a^2*x^2))^(7/2)*x^6)) + (1 - a^2*x^2)^(7/2)/(32*a^8*(c - c/(a^2*x^2))^(7/2)
*x^7*(1 - a*x)^2) - (5*(1 - a^2*x^2)^(7/2))/(16*a^8*(c - c/(a^2*x^2))^(7/2)*x^7*(1 - a*x)) + (1 - a^2*x^2)^(7/
2)/(24*a^8*(c - c/(a^2*x^2))^(7/2)*x^7*(1 + a*x)^3) - (11*(1 - a^2*x^2)^(7/2))/(32*a^8*(c - c/(a^2*x^2))^(7/2)
*x^7*(1 + a*x)^2) + (3*(1 - a^2*x^2)^(7/2))/(2*a^8*(c - c/(a^2*x^2))^(7/2)*x^7*(1 + a*x)) - (19*(1 - a^2*x^2)^
(7/2)*Log[1 - a*x])/(32*a^8*(c - c/(a^2*x^2))^(7/2)*x^7) + (51*(1 - a^2*x^2)^(7/2)*Log[1 + a*x])/(32*a^8*(c -
c/(a^2*x^2))^(7/2)*x^7)

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Rubi [A]  time = 0.240329, antiderivative size = 361, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125, Rules used = {6160, 6150, 88} \[ -\frac{5 \left (1-a^2 x^2\right )^{7/2}}{16 a^8 x^7 (1-a x) \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{3 \left (1-a^2 x^2\right )^{7/2}}{2 a^8 x^7 (a x+1) \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{\left (1-a^2 x^2\right )^{7/2}}{32 a^8 x^7 (1-a x)^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}-\frac{11 \left (1-a^2 x^2\right )^{7/2}}{32 a^8 x^7 (a x+1)^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{\left (1-a^2 x^2\right )^{7/2}}{24 a^8 x^7 (a x+1)^3 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}-\frac{\left (1-a^2 x^2\right )^{7/2}}{a^7 x^6 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}-\frac{19 \left (1-a^2 x^2\right )^{7/2} \log (1-a x)}{32 a^8 x^7 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{51 \left (1-a^2 x^2\right )^{7/2} \log (a x+1)}{32 a^8 x^7 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}} \]

Antiderivative was successfully verified.

[In]

Int[1/(E^ArcTanh[a*x]*(c - c/(a^2*x^2))^(7/2)),x]

[Out]

-((1 - a^2*x^2)^(7/2)/(a^7*(c - c/(a^2*x^2))^(7/2)*x^6)) + (1 - a^2*x^2)^(7/2)/(32*a^8*(c - c/(a^2*x^2))^(7/2)
*x^7*(1 - a*x)^2) - (5*(1 - a^2*x^2)^(7/2))/(16*a^8*(c - c/(a^2*x^2))^(7/2)*x^7*(1 - a*x)) + (1 - a^2*x^2)^(7/
2)/(24*a^8*(c - c/(a^2*x^2))^(7/2)*x^7*(1 + a*x)^3) - (11*(1 - a^2*x^2)^(7/2))/(32*a^8*(c - c/(a^2*x^2))^(7/2)
*x^7*(1 + a*x)^2) + (3*(1 - a^2*x^2)^(7/2))/(2*a^8*(c - c/(a^2*x^2))^(7/2)*x^7*(1 + a*x)) - (19*(1 - a^2*x^2)^
(7/2)*Log[1 - a*x])/(32*a^8*(c - c/(a^2*x^2))^(7/2)*x^7) + (51*(1 - a^2*x^2)^(7/2)*Log[1 + a*x])/(32*a^8*(c -
c/(a^2*x^2))^(7/2)*x^7)

Rule 6160

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)/(x_)^2)^(p_), x_Symbol] :> Dist[(x^(2*p)*(c + d/x^2)^p)/
(1 + (c*x^2)/d)^p, Int[(u*(1 + (c*x^2)/d)^p*E^(n*ArcTanh[a*x]))/x^(2*p), x], x] /; FreeQ[{a, c, d, n, p}, x] &
& EqQ[c + a^2*d, 0] &&  !IntegerQ[p] &&  !IntegerQ[n/2]

Rule 6150

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[c^p, Int[x^m*(1 -
a*x)^(p - n/2)*(1 + a*x)^(p + n/2), x], x] /; FreeQ[{a, c, d, m, n, p}, x] && EqQ[a^2*c + d, 0] && (IntegerQ[p
] || GtQ[c, 0])

Rule 88

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandI
ntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] &&
(IntegerQ[p] || (GtQ[m, 0] && GeQ[n, -1]))

Rubi steps

\begin{align*} \int \frac{e^{-\tanh ^{-1}(a x)}}{\left (c-\frac{c}{a^2 x^2}\right )^{7/2}} \, dx &=\frac{\left (1-a^2 x^2\right )^{7/2} \int \frac{e^{-\tanh ^{-1}(a x)} x^7}{\left (1-a^2 x^2\right )^{7/2}} \, dx}{\left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ &=\frac{\left (1-a^2 x^2\right )^{7/2} \int \frac{x^7}{(1-a x)^3 (1+a x)^4} \, dx}{\left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ &=\frac{\left (1-a^2 x^2\right )^{7/2} \int \left (-\frac{1}{a^7}-\frac{1}{16 a^7 (-1+a x)^3}-\frac{5}{16 a^7 (-1+a x)^2}-\frac{19}{32 a^7 (-1+a x)}-\frac{1}{8 a^7 (1+a x)^4}+\frac{11}{16 a^7 (1+a x)^3}-\frac{3}{2 a^7 (1+a x)^2}+\frac{51}{32 a^7 (1+a x)}\right ) \, dx}{\left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ &=-\frac{\left (1-a^2 x^2\right )^{7/2}}{a^7 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^6}+\frac{\left (1-a^2 x^2\right )^{7/2}}{32 a^8 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7 (1-a x)^2}-\frac{5 \left (1-a^2 x^2\right )^{7/2}}{16 a^8 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7 (1-a x)}+\frac{\left (1-a^2 x^2\right )^{7/2}}{24 a^8 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7 (1+a x)^3}-\frac{11 \left (1-a^2 x^2\right )^{7/2}}{32 a^8 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7 (1+a x)^2}+\frac{3 \left (1-a^2 x^2\right )^{7/2}}{2 a^8 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7 (1+a x)}-\frac{19 \left (1-a^2 x^2\right )^{7/2} \log (1-a x)}{32 a^8 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}+\frac{51 \left (1-a^2 x^2\right )^{7/2} \log (1+a x)}{32 a^8 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ \end{align*}

Mathematica [A]  time = 0.117548, size = 145, normalized size = 0.4 \[ \frac{\sqrt{1-a^2 x^2} \left (96 a^6 x^6+96 a^5 x^5-366 a^4 x^4-222 a^3 x^3+338 a^2 x^2+122 a x+57 (a x-1)^2 (a x+1)^3 \log (1-a x)-153 (a x-1)^2 (a x+1)^3 \log (a x+1)-88\right )}{96 a^2 x (a x-1)^2 \sqrt{c-\frac{c}{a^2 x^2}} (a c x+c)^3} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(E^ArcTanh[a*x]*(c - c/(a^2*x^2))^(7/2)),x]

[Out]

(Sqrt[1 - a^2*x^2]*(-88 + 122*a*x + 338*a^2*x^2 - 222*a^3*x^3 - 366*a^4*x^4 + 96*a^5*x^5 + 96*a^6*x^6 + 57*(-1
+ a*x)^2*(1 + a*x)^3*Log[1 - a*x] - 153*(-1 + a*x)^2*(1 + a*x)^3*Log[1 + a*x]))/(96*a^2*Sqrt[c - c/(a^2*x^2)]
*x*(-1 + a*x)^2*(c + a*c*x)^3)

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Maple [A]  time = 0.168, size = 239, normalized size = 0.7 \begin{align*} -{\frac{ \left ( ax-1 \right ) \left ( -96\,{x}^{6}{a}^{6}+153\,\ln \left ( ax+1 \right ){x}^{5}{a}^{5}-57\,\ln \left ( ax-1 \right ){x}^{5}{a}^{5}-96\,{x}^{5}{a}^{5}+153\,\ln \left ( ax+1 \right ){a}^{4}{x}^{4}-57\,\ln \left ( ax-1 \right ){a}^{4}{x}^{4}+366\,{x}^{4}{a}^{4}-306\,{a}^{3}{x}^{3}\ln \left ( ax+1 \right ) +114\,\ln \left ( ax-1 \right ){x}^{3}{a}^{3}+222\,{x}^{3}{a}^{3}-306\,\ln \left ( ax+1 \right ){a}^{2}{x}^{2}+114\,\ln \left ( ax-1 \right ){a}^{2}{x}^{2}-338\,{a}^{2}{x}^{2}+153\,ax\ln \left ( ax+1 \right ) -57\,\ln \left ( ax-1 \right ) xa-122\,ax+153\,\ln \left ( ax+1 \right ) -57\,\ln \left ( ax-1 \right ) +88 \right ) }{96\,{a}^{8}{x}^{7}}\sqrt{-{a}^{2}{x}^{2}+1} \left ({\frac{c \left ({a}^{2}{x}^{2}-1 \right ) }{{a}^{2}{x}^{2}}} \right ) ^{-{\frac{7}{2}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(a*x+1)*(-a^2*x^2+1)^(1/2)/(c-c/a^2/x^2)^(7/2),x)

[Out]

-1/96*(-a^2*x^2+1)^(1/2)*(a*x-1)*(-96*x^6*a^6+153*ln(a*x+1)*x^5*a^5-57*ln(a*x-1)*x^5*a^5-96*x^5*a^5+153*ln(a*x
+1)*a^4*x^4-57*ln(a*x-1)*a^4*x^4+366*x^4*a^4-306*a^3*x^3*ln(a*x+1)+114*ln(a*x-1)*x^3*a^3+222*x^3*a^3-306*ln(a*
x+1)*a^2*x^2+114*ln(a*x-1)*a^2*x^2-338*a^2*x^2+153*a*x*ln(a*x+1)-57*ln(a*x-1)*x*a-122*a*x+153*ln(a*x+1)-57*ln(
a*x-1)+88)/a^8/x^7/(c*(a^2*x^2-1)/a^2/x^2)^(7/2)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{-a^{2} x^{2} + 1}}{{\left (a x + 1\right )}{\left (c - \frac{c}{a^{2} x^{2}}\right )}^{\frac{7}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*x+1)*(-a^2*x^2+1)^(1/2)/(c-c/a^2/x^2)^(7/2),x, algorithm="maxima")

[Out]

integrate(sqrt(-a^2*x^2 + 1)/((a*x + 1)*(c - c/(a^2*x^2))^(7/2)), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{-a^{2} x^{2} + 1} a^{8} x^{8} \sqrt{\frac{a^{2} c x^{2} - c}{a^{2} x^{2}}}}{a^{9} c^{4} x^{9} + a^{8} c^{4} x^{8} - 4 \, a^{7} c^{4} x^{7} - 4 \, a^{6} c^{4} x^{6} + 6 \, a^{5} c^{4} x^{5} + 6 \, a^{4} c^{4} x^{4} - 4 \, a^{3} c^{4} x^{3} - 4 \, a^{2} c^{4} x^{2} + a c^{4} x + c^{4}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*x+1)*(-a^2*x^2+1)^(1/2)/(c-c/a^2/x^2)^(7/2),x, algorithm="fricas")

[Out]

integral(sqrt(-a^2*x^2 + 1)*a^8*x^8*sqrt((a^2*c*x^2 - c)/(a^2*x^2))/(a^9*c^4*x^9 + a^8*c^4*x^8 - 4*a^7*c^4*x^7
- 4*a^6*c^4*x^6 + 6*a^5*c^4*x^5 + 6*a^4*c^4*x^4 - 4*a^3*c^4*x^3 - 4*a^2*c^4*x^2 + a*c^4*x + c^4), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*x+1)*(-a**2*x**2+1)**(1/2)/(c-c/a**2/x**2)**(7/2),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{-a^{2} x^{2} + 1}}{{\left (a x + 1\right )}{\left (c - \frac{c}{a^{2} x^{2}}\right )}^{\frac{7}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*x+1)*(-a^2*x^2+1)^(1/2)/(c-c/a^2/x^2)^(7/2),x, algorithm="giac")

[Out]

integrate(sqrt(-a^2*x^2 + 1)/((a*x + 1)*(c - c/(a^2*x^2))^(7/2)), x)