3.705 \(\int e^{3 \tanh ^{-1}(a x)} (c-\frac{c}{a^2 x^2})^{9/2} \, dx\)

Optimal. Leaf size=300 \[ -\frac{a^9 x^{10} \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{\left (1-a^2 x^2\right )^{9/2}}-\frac{4 a^6 x^7 \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{\left (1-a^2 x^2\right )^{9/2}}-\frac{2 a^5 x^6 \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{\left (1-a^2 x^2\right )^{9/2}}+\frac{3 a^4 x^5 \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{2 \left (1-a^2 x^2\right )^{9/2}}+\frac{8 a^3 x^4 \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{5 \left (1-a^2 x^2\right )^{9/2}}-\frac{3 a x^2 \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{7 \left (1-a^2 x^2\right )^{9/2}}-\frac{x \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{8 \left (1-a^2 x^2\right )^{9/2}}-\frac{3 a^8 x^9 \log (x) \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{\left (1-a^2 x^2\right )^{9/2}} \]

[Out]

-((c - c/(a^2*x^2))^(9/2)*x)/(8*(1 - a^2*x^2)^(9/2)) - (3*a*(c - c/(a^2*x^2))^(9/2)*x^2)/(7*(1 - a^2*x^2)^(9/2
)) + (8*a^3*(c - c/(a^2*x^2))^(9/2)*x^4)/(5*(1 - a^2*x^2)^(9/2)) + (3*a^4*(c - c/(a^2*x^2))^(9/2)*x^5)/(2*(1 -
a^2*x^2)^(9/2)) - (2*a^5*(c - c/(a^2*x^2))^(9/2)*x^6)/(1 - a^2*x^2)^(9/2) - (4*a^6*(c - c/(a^2*x^2))^(9/2)*x^
7)/(1 - a^2*x^2)^(9/2) - (a^9*(c - c/(a^2*x^2))^(9/2)*x^10)/(1 - a^2*x^2)^(9/2) - (3*a^8*(c - c/(a^2*x^2))^(9/
2)*x^9*Log[x])/(1 - a^2*x^2)^(9/2)

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Rubi [A]  time = 0.194142, antiderivative size = 300, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125, Rules used = {6160, 6150, 88} \[ -\frac{a^9 x^{10} \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{\left (1-a^2 x^2\right )^{9/2}}-\frac{4 a^6 x^7 \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{\left (1-a^2 x^2\right )^{9/2}}-\frac{2 a^5 x^6 \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{\left (1-a^2 x^2\right )^{9/2}}+\frac{3 a^4 x^5 \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{2 \left (1-a^2 x^2\right )^{9/2}}+\frac{8 a^3 x^4 \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{5 \left (1-a^2 x^2\right )^{9/2}}-\frac{3 a x^2 \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{7 \left (1-a^2 x^2\right )^{9/2}}-\frac{x \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{8 \left (1-a^2 x^2\right )^{9/2}}-\frac{3 a^8 x^9 \log (x) \left (c-\frac{c}{a^2 x^2}\right )^{9/2}}{\left (1-a^2 x^2\right )^{9/2}} \]

Antiderivative was successfully verified.

[In]

Int[E^(3*ArcTanh[a*x])*(c - c/(a^2*x^2))^(9/2),x]

[Out]

-((c - c/(a^2*x^2))^(9/2)*x)/(8*(1 - a^2*x^2)^(9/2)) - (3*a*(c - c/(a^2*x^2))^(9/2)*x^2)/(7*(1 - a^2*x^2)^(9/2
)) + (8*a^3*(c - c/(a^2*x^2))^(9/2)*x^4)/(5*(1 - a^2*x^2)^(9/2)) + (3*a^4*(c - c/(a^2*x^2))^(9/2)*x^5)/(2*(1 -
a^2*x^2)^(9/2)) - (2*a^5*(c - c/(a^2*x^2))^(9/2)*x^6)/(1 - a^2*x^2)^(9/2) - (4*a^6*(c - c/(a^2*x^2))^(9/2)*x^
7)/(1 - a^2*x^2)^(9/2) - (a^9*(c - c/(a^2*x^2))^(9/2)*x^10)/(1 - a^2*x^2)^(9/2) - (3*a^8*(c - c/(a^2*x^2))^(9/
2)*x^9*Log[x])/(1 - a^2*x^2)^(9/2)

Rule 6160

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)/(x_)^2)^(p_), x_Symbol] :> Dist[(x^(2*p)*(c + d/x^2)^p)/
(1 + (c*x^2)/d)^p, Int[(u*(1 + (c*x^2)/d)^p*E^(n*ArcTanh[a*x]))/x^(2*p), x], x] /; FreeQ[{a, c, d, n, p}, x] &
& EqQ[c + a^2*d, 0] &&  !IntegerQ[p] &&  !IntegerQ[n/2]

Rule 6150

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[c^p, Int[x^m*(1 -
a*x)^(p - n/2)*(1 + a*x)^(p + n/2), x], x] /; FreeQ[{a, c, d, m, n, p}, x] && EqQ[a^2*c + d, 0] && (IntegerQ[p
] || GtQ[c, 0])

Rule 88

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandI
ntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] &&
(IntegerQ[p] || (GtQ[m, 0] && GeQ[n, -1]))

Rubi steps

\begin{align*} \int e^{3 \tanh ^{-1}(a x)} \left (c-\frac{c}{a^2 x^2}\right )^{9/2} \, dx &=\frac{\left (\left (c-\frac{c}{a^2 x^2}\right )^{9/2} x^9\right ) \int \frac{e^{3 \tanh ^{-1}(a x)} \left (1-a^2 x^2\right )^{9/2}}{x^9} \, dx}{\left (1-a^2 x^2\right )^{9/2}}\\ &=\frac{\left (\left (c-\frac{c}{a^2 x^2}\right )^{9/2} x^9\right ) \int \frac{(1-a x)^3 (1+a x)^6}{x^9} \, dx}{\left (1-a^2 x^2\right )^{9/2}}\\ &=\frac{\left (\left (c-\frac{c}{a^2 x^2}\right )^{9/2} x^9\right ) \int \left (-a^9+\frac{1}{x^9}+\frac{3 a}{x^8}-\frac{8 a^3}{x^6}-\frac{6 a^4}{x^5}+\frac{6 a^5}{x^4}+\frac{8 a^6}{x^3}-\frac{3 a^8}{x}\right ) \, dx}{\left (1-a^2 x^2\right )^{9/2}}\\ &=-\frac{\left (c-\frac{c}{a^2 x^2}\right )^{9/2} x}{8 \left (1-a^2 x^2\right )^{9/2}}-\frac{3 a \left (c-\frac{c}{a^2 x^2}\right )^{9/2} x^2}{7 \left (1-a^2 x^2\right )^{9/2}}+\frac{8 a^3 \left (c-\frac{c}{a^2 x^2}\right )^{9/2} x^4}{5 \left (1-a^2 x^2\right )^{9/2}}+\frac{3 a^4 \left (c-\frac{c}{a^2 x^2}\right )^{9/2} x^5}{2 \left (1-a^2 x^2\right )^{9/2}}-\frac{2 a^5 \left (c-\frac{c}{a^2 x^2}\right )^{9/2} x^6}{\left (1-a^2 x^2\right )^{9/2}}-\frac{4 a^6 \left (c-\frac{c}{a^2 x^2}\right )^{9/2} x^7}{\left (1-a^2 x^2\right )^{9/2}}-\frac{a^9 \left (c-\frac{c}{a^2 x^2}\right )^{9/2} x^{10}}{\left (1-a^2 x^2\right )^{9/2}}-\frac{3 a^8 \left (c-\frac{c}{a^2 x^2}\right )^{9/2} x^9 \log (x)}{\left (1-a^2 x^2\right )^{9/2}}\\ \end{align*}

Mathematica [A]  time = 0.0653958, size = 98, normalized size = 0.33 \[ -\frac{c^4 \sqrt{c-\frac{c}{a^2 x^2}} \left (280 a^9 x^9+1120 a^6 x^6+560 a^5 x^5-420 a^4 x^4-448 a^3 x^3+840 a^8 x^8 \log (x)+120 a x+35\right )}{280 a^8 x^7 \sqrt{1-a^2 x^2}} \]

Antiderivative was successfully verified.

[In]

Integrate[E^(3*ArcTanh[a*x])*(c - c/(a^2*x^2))^(9/2),x]

[Out]

-(c^4*Sqrt[c - c/(a^2*x^2)]*(35 + 120*a*x - 448*a^3*x^3 - 420*a^4*x^4 + 560*a^5*x^5 + 1120*a^6*x^6 + 280*a^9*x
^9 + 840*a^8*x^8*Log[x]))/(280*a^8*x^7*Sqrt[1 - a^2*x^2])

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Maple [A]  time = 0.16, size = 102, normalized size = 0.3 \begin{align*}{\frac{x \left ( 280\,{a}^{9}{x}^{9}+840\,{a}^{8}\ln \left ( x \right ){x}^{8}+1120\,{x}^{6}{a}^{6}+560\,{x}^{5}{a}^{5}-420\,{x}^{4}{a}^{4}-448\,{x}^{3}{a}^{3}+120\,ax+35 \right ) }{280\, \left ({a}^{2}{x}^{2}-1 \right ) ^{5}} \left ({\frac{c \left ({a}^{2}{x}^{2}-1 \right ) }{{a}^{2}{x}^{2}}} \right ) ^{{\frac{9}{2}}}\sqrt{-{a}^{2}{x}^{2}+1}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+1)^3/(-a^2*x^2+1)^(3/2)*(c-c/a^2/x^2)^(9/2),x)

[Out]

1/280*(c*(a^2*x^2-1)/a^2/x^2)^(9/2)*x/(a^2*x^2-1)^5*(-a^2*x^2+1)^(1/2)*(280*a^9*x^9+840*a^8*ln(x)*x^8+1120*x^6
*a^6+560*x^5*a^5-420*x^4*a^4-448*x^3*a^3+120*a*x+35)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a x + 1\right )}^{3}{\left (c - \frac{c}{a^{2} x^{2}}\right )}^{\frac{9}{2}}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac{3}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^3/(-a^2*x^2+1)^(3/2)*(c-c/a^2/x^2)^(9/2),x, algorithm="maxima")

[Out]

integrate((a*x + 1)^3*(c - c/(a^2*x^2))^(9/2)/(-a^2*x^2 + 1)^(3/2), x)

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Fricas [A]  time = 2.3707, size = 1181, normalized size = 3.94 \begin{align*} \left [\frac{420 \,{\left (a^{9} c^{4} x^{9} - a^{7} c^{4} x^{7}\right )} \sqrt{-c} \log \left (\frac{a^{2} c x^{6} + a^{2} c x^{2} - c x^{4} -{\left (a x^{5} - a x\right )} \sqrt{-a^{2} x^{2} + 1} \sqrt{-c} \sqrt{\frac{a^{2} c x^{2} - c}{a^{2} x^{2}}} - c}{a^{2} x^{4} - x^{2}}\right ) +{\left (280 \, a^{9} c^{4} x^{9} + 1120 \, a^{6} c^{4} x^{6} + 560 \, a^{5} c^{4} x^{5} -{\left (280 \, a^{9} + 1120 \, a^{6} + 560 \, a^{5} - 420 \, a^{4} - 448 \, a^{3} + 120 \, a + 35\right )} c^{4} x^{8} - 420 \, a^{4} c^{4} x^{4} - 448 \, a^{3} c^{4} x^{3} + 120 \, a c^{4} x + 35 \, c^{4}\right )} \sqrt{-a^{2} x^{2} + 1} \sqrt{\frac{a^{2} c x^{2} - c}{a^{2} x^{2}}}}{280 \,{\left (a^{10} x^{9} - a^{8} x^{7}\right )}}, \frac{840 \,{\left (a^{9} c^{4} x^{9} - a^{7} c^{4} x^{7}\right )} \sqrt{c} \arctan \left (\frac{\sqrt{-a^{2} x^{2} + 1}{\left (a x^{3} + a x\right )} \sqrt{c} \sqrt{\frac{a^{2} c x^{2} - c}{a^{2} x^{2}}}}{a^{2} c x^{4} -{\left (a^{2} + 1\right )} c x^{2} + c}\right ) +{\left (280 \, a^{9} c^{4} x^{9} + 1120 \, a^{6} c^{4} x^{6} + 560 \, a^{5} c^{4} x^{5} -{\left (280 \, a^{9} + 1120 \, a^{6} + 560 \, a^{5} - 420 \, a^{4} - 448 \, a^{3} + 120 \, a + 35\right )} c^{4} x^{8} - 420 \, a^{4} c^{4} x^{4} - 448 \, a^{3} c^{4} x^{3} + 120 \, a c^{4} x + 35 \, c^{4}\right )} \sqrt{-a^{2} x^{2} + 1} \sqrt{\frac{a^{2} c x^{2} - c}{a^{2} x^{2}}}}{280 \,{\left (a^{10} x^{9} - a^{8} x^{7}\right )}}\right ] \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^3/(-a^2*x^2+1)^(3/2)*(c-c/a^2/x^2)^(9/2),x, algorithm="fricas")

[Out]

[1/280*(420*(a^9*c^4*x^9 - a^7*c^4*x^7)*sqrt(-c)*log((a^2*c*x^6 + a^2*c*x^2 - c*x^4 - (a*x^5 - a*x)*sqrt(-a^2*
x^2 + 1)*sqrt(-c)*sqrt((a^2*c*x^2 - c)/(a^2*x^2)) - c)/(a^2*x^4 - x^2)) + (280*a^9*c^4*x^9 + 1120*a^6*c^4*x^6
+ 560*a^5*c^4*x^5 - (280*a^9 + 1120*a^6 + 560*a^5 - 420*a^4 - 448*a^3 + 120*a + 35)*c^4*x^8 - 420*a^4*c^4*x^4
- 448*a^3*c^4*x^3 + 120*a*c^4*x + 35*c^4)*sqrt(-a^2*x^2 + 1)*sqrt((a^2*c*x^2 - c)/(a^2*x^2)))/(a^10*x^9 - a^8*
x^7), 1/280*(840*(a^9*c^4*x^9 - a^7*c^4*x^7)*sqrt(c)*arctan(sqrt(-a^2*x^2 + 1)*(a*x^3 + a*x)*sqrt(c)*sqrt((a^2
*c*x^2 - c)/(a^2*x^2))/(a^2*c*x^4 - (a^2 + 1)*c*x^2 + c)) + (280*a^9*c^4*x^9 + 1120*a^6*c^4*x^6 + 560*a^5*c^4*
x^5 - (280*a^9 + 1120*a^6 + 560*a^5 - 420*a^4 - 448*a^3 + 120*a + 35)*c^4*x^8 - 420*a^4*c^4*x^4 - 448*a^3*c^4*
x^3 + 120*a*c^4*x + 35*c^4)*sqrt(-a^2*x^2 + 1)*sqrt((a^2*c*x^2 - c)/(a^2*x^2)))/(a^10*x^9 - a^8*x^7)]

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)**3/(-a**2*x**2+1)**(3/2)*(c-c/a**2/x**2)**(9/2),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a x + 1\right )}^{3}{\left (c - \frac{c}{a^{2} x^{2}}\right )}^{\frac{9}{2}}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac{3}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^3/(-a^2*x^2+1)^(3/2)*(c-c/a^2/x^2)^(9/2),x, algorithm="giac")

[Out]

integrate((a*x + 1)^3*(c - c/(a^2*x^2))^(9/2)/(-a^2*x^2 + 1)^(3/2), x)