3.703 \(\int \frac{e^{2 \tanh ^{-1}(a x)}}{(c-\frac{c}{a^2 x^2})^{7/2}} \, dx\)

Optimal. Leaf size=283 \[ -\frac{142 (a x+1)^2 (1-a x)^4}{35 a^6 x^5 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}-\frac{2 (a x+1)^3 (107 a x+72) (1-a x)^4}{35 a^8 x^7 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}-\frac{782 (a x+1)^2 (1-a x)^3}{105 a^5 x^4 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{124 (a x+1)^2 (1-a x)^2}{105 a^4 x^3 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}-\frac{2 (a x+1)^2 (1-a x)}{5 a^3 x^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{(a x+1)^2}{7 a^2 x \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{2 (a x+1)^{7/2} (1-a x)^{7/2} \sin ^{-1}(a x)}{a^8 x^7 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}} \]

[Out]

(1 + a*x)^2/(7*a^2*(c - c/(a^2*x^2))^(7/2)*x) - (2*(1 - a*x)*(1 + a*x)^2)/(5*a^3*(c - c/(a^2*x^2))^(7/2)*x^2)
+ (124*(1 - a*x)^2*(1 + a*x)^2)/(105*a^4*(c - c/(a^2*x^2))^(7/2)*x^3) - (782*(1 - a*x)^3*(1 + a*x)^2)/(105*a^5
*(c - c/(a^2*x^2))^(7/2)*x^4) - (142*(1 - a*x)^4*(1 + a*x)^2)/(35*a^6*(c - c/(a^2*x^2))^(7/2)*x^5) - (2*(1 - a
*x)^4*(1 + a*x)^3*(72 + 107*a*x))/(35*a^8*(c - c/(a^2*x^2))^(7/2)*x^7) + (2*(1 - a*x)^(7/2)*(1 + a*x)^(7/2)*Ar
cSin[a*x])/(a^8*(c - c/(a^2*x^2))^(7/2)*x^7)

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Rubi [A]  time = 0.427405, antiderivative size = 283, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 7, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.292, Rules used = {6159, 6129, 98, 150, 143, 41, 216} \[ -\frac{142 (a x+1)^2 (1-a x)^4}{35 a^6 x^5 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}-\frac{2 (a x+1)^3 (107 a x+72) (1-a x)^4}{35 a^8 x^7 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}-\frac{782 (a x+1)^2 (1-a x)^3}{105 a^5 x^4 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{124 (a x+1)^2 (1-a x)^2}{105 a^4 x^3 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}-\frac{2 (a x+1)^2 (1-a x)}{5 a^3 x^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{(a x+1)^2}{7 a^2 x \left (c-\frac{c}{a^2 x^2}\right )^{7/2}}+\frac{2 (a x+1)^{7/2} (1-a x)^{7/2} \sin ^{-1}(a x)}{a^8 x^7 \left (c-\frac{c}{a^2 x^2}\right )^{7/2}} \]

Antiderivative was successfully verified.

[In]

Int[E^(2*ArcTanh[a*x])/(c - c/(a^2*x^2))^(7/2),x]

[Out]

(1 + a*x)^2/(7*a^2*(c - c/(a^2*x^2))^(7/2)*x) - (2*(1 - a*x)*(1 + a*x)^2)/(5*a^3*(c - c/(a^2*x^2))^(7/2)*x^2)
+ (124*(1 - a*x)^2*(1 + a*x)^2)/(105*a^4*(c - c/(a^2*x^2))^(7/2)*x^3) - (782*(1 - a*x)^3*(1 + a*x)^2)/(105*a^5
*(c - c/(a^2*x^2))^(7/2)*x^4) - (142*(1 - a*x)^4*(1 + a*x)^2)/(35*a^6*(c - c/(a^2*x^2))^(7/2)*x^5) - (2*(1 - a
*x)^4*(1 + a*x)^3*(72 + 107*a*x))/(35*a^8*(c - c/(a^2*x^2))^(7/2)*x^7) + (2*(1 - a*x)^(7/2)*(1 + a*x)^(7/2)*Ar
cSin[a*x])/(a^8*(c - c/(a^2*x^2))^(7/2)*x^7)

Rule 6159

Int[E^(ArcTanh[(a_.)*(x_)]*(n_))*(u_.)*((c_) + (d_.)/(x_)^2)^(p_), x_Symbol] :> Dist[(x^(2*p)*(c + d/x^2)^p)/(
(1 - a*x)^p*(1 + a*x)^p), Int[(u*(1 - a*x)^p*(1 + a*x)^p*E^(n*ArcTanh[a*x]))/x^(2*p), x], x] /; FreeQ[{a, c, d
, n, p}, x] && EqQ[c + a^2*d, 0] &&  !IntegerQ[p] && IntegerQ[n/2] &&  !GtQ[c, 0]

Rule 6129

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)*(x_))^(p_.), x_Symbol] :> Dist[c^p, Int[(u*(1 + (d*x)/c)
^p*(1 + a*x)^(n/2))/(1 - a*x)^(n/2), x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[a^2*c^2 - d^2, 0] && (IntegerQ
[p] || GtQ[c, 0])

Rule 98

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((b*c -
a*d)*(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] + Dist[1/(b*(b*e - a*
f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 2)*(e + f*x)^p*Simp[a*d*(d*e*(n - 1) + c*f*(p + 1)) + b*c*(d
*e*(m - n + 2) - c*f*(m + p + 2)) + d*(a*d*f*(n + p) + b*(d*e*(m + 1) - c*f*(m + n + p + 1)))*x, x], x], x] /;
FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 1] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p
] || IntegersQ[p, m + n])

Rule 150

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] - Dist[1
/(b*(b*e - a*f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b*c*(f*g - e*h)*(m + 1) + (
b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h)*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; Free
Q[{a, b, c, d, e, f, g, h, p}, x] && LtQ[m, -1] && GtQ[n, 0] && IntegersQ[2*m, 2*n, 2*p]

Rule 143

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_) + (f_.)*(x_))*((g_.) + (h_.)*(x_)), x_Symbol] :
> Simp[((b^2*d*e*g - a^2*d*f*h*m - a*b*(d*(f*g + e*h) - c*f*h*(m + 1)) + b*f*h*(b*c - a*d)*(m + 1)*x)*(a + b*x
)^(m + 1)*(c + d*x)^(n + 1))/(b^2*d*(b*c - a*d)*(m + 1)), x] + Dist[(a*d*f*h*m + b*(d*(f*g + e*h) - c*f*h*(m +
2)))/(b^2*d), Int[(a + b*x)^(m + 1)*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, m, n}, x] && EqQ[m
+ n + 2, 0] && NeQ[m, -1] &&  !(SumSimplerQ[n, 1] &&  !SumSimplerQ[m, 1])

Rule 41

Int[((a_) + (b_.)*(x_))^(m_.)*((c_) + (d_.)*(x_))^(m_.), x_Symbol] :> Int[(a*c + b*d*x^2)^m, x] /; FreeQ[{a, b
, c, d, m}, x] && EqQ[b*c + a*d, 0] && (IntegerQ[m] || (GtQ[a, 0] && GtQ[c, 0]))

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rubi steps

\begin{align*} \int \frac{e^{2 \tanh ^{-1}(a x)}}{\left (c-\frac{c}{a^2 x^2}\right )^{7/2}} \, dx &=\frac{\left ((1-a x)^{7/2} (1+a x)^{7/2}\right ) \int \frac{e^{2 \tanh ^{-1}(a x)} x^7}{(1-a x)^{7/2} (1+a x)^{7/2}} \, dx}{\left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ &=\frac{\left ((1-a x)^{7/2} (1+a x)^{7/2}\right ) \int \frac{x^7}{(1-a x)^{9/2} (1+a x)^{5/2}} \, dx}{\left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ &=\frac{(1+a x)^2}{7 a^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x}-\frac{\left ((1-a x)^{7/2} (1+a x)^{7/2}\right ) \int \frac{x^5 (6+8 a x)}{(1-a x)^{7/2} (1+a x)^{5/2}} \, dx}{7 a^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ &=\frac{(1+a x)^2}{7 a^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x}-\frac{2 (1-a x) (1+a x)^2}{5 a^3 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^2}-\frac{\left ((1-a x)^{7/2} (1+a x)^{7/2}\right ) \int \frac{x^4 \left (-70 a-54 a^2 x\right )}{(1-a x)^{5/2} (1+a x)^{5/2}} \, dx}{35 a^4 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ &=\frac{(1+a x)^2}{7 a^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x}-\frac{2 (1-a x) (1+a x)^2}{5 a^3 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^2}+\frac{124 (1-a x)^2 (1+a x)^2}{105 a^4 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^3}-\frac{\left ((1-a x)^{7/2} (1+a x)^{7/2}\right ) \int \frac{x^3 \left (496 a^2+286 a^3 x\right )}{(1-a x)^{3/2} (1+a x)^{5/2}} \, dx}{105 a^6 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ &=\frac{(1+a x)^2}{7 a^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x}-\frac{2 (1-a x) (1+a x)^2}{5 a^3 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^2}+\frac{124 (1-a x)^2 (1+a x)^2}{105 a^4 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^3}-\frac{782 (1-a x)^3 (1+a x)^2}{105 a^5 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^4}-\frac{\left ((1-a x)^{7/2} (1+a x)^{7/2}\right ) \int \frac{x^2 \left (-2346 a^3-1068 a^4 x\right )}{\sqrt{1-a x} (1+a x)^{5/2}} \, dx}{105 a^8 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ &=\frac{(1+a x)^2}{7 a^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x}-\frac{2 (1-a x) (1+a x)^2}{5 a^3 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^2}+\frac{124 (1-a x)^2 (1+a x)^2}{105 a^4 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^3}-\frac{782 (1-a x)^3 (1+a x)^2}{105 a^5 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^4}-\frac{142 (1-a x)^4 (1+a x)^2}{35 a^6 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^5}-\frac{\left ((1-a x)^{7/2} (1+a x)^{7/2}\right ) \int \frac{x \left (-2556 a^4-1926 a^5 x\right )}{\sqrt{1-a x} (1+a x)^{3/2}} \, dx}{315 a^{10} \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ &=\frac{(1+a x)^2}{7 a^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x}-\frac{2 (1-a x) (1+a x)^2}{5 a^3 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^2}+\frac{124 (1-a x)^2 (1+a x)^2}{105 a^4 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^3}-\frac{782 (1-a x)^3 (1+a x)^2}{105 a^5 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^4}-\frac{142 (1-a x)^4 (1+a x)^2}{35 a^6 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^5}-\frac{2 (1-a x)^4 (1+a x)^3 (72+107 a x)}{35 a^8 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}+\frac{\left (2 (1-a x)^{7/2} (1+a x)^{7/2}\right ) \int \frac{1}{\sqrt{1-a x} \sqrt{1+a x}} \, dx}{a^7 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ &=\frac{(1+a x)^2}{7 a^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x}-\frac{2 (1-a x) (1+a x)^2}{5 a^3 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^2}+\frac{124 (1-a x)^2 (1+a x)^2}{105 a^4 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^3}-\frac{782 (1-a x)^3 (1+a x)^2}{105 a^5 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^4}-\frac{142 (1-a x)^4 (1+a x)^2}{35 a^6 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^5}-\frac{2 (1-a x)^4 (1+a x)^3 (72+107 a x)}{35 a^8 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}+\frac{\left (2 (1-a x)^{7/2} (1+a x)^{7/2}\right ) \int \frac{1}{\sqrt{1-a^2 x^2}} \, dx}{a^7 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ &=\frac{(1+a x)^2}{7 a^2 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x}-\frac{2 (1-a x) (1+a x)^2}{5 a^3 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^2}+\frac{124 (1-a x)^2 (1+a x)^2}{105 a^4 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^3}-\frac{782 (1-a x)^3 (1+a x)^2}{105 a^5 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^4}-\frac{142 (1-a x)^4 (1+a x)^2}{35 a^6 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^5}-\frac{2 (1-a x)^4 (1+a x)^3 (72+107 a x)}{35 a^8 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}+\frac{2 (1-a x)^{7/2} (1+a x)^{7/2} \sin ^{-1}(a x)}{a^8 \left (c-\frac{c}{a^2 x^2}\right )^{7/2} x^7}\\ \end{align*}

Mathematica [A]  time = 0.115456, size = 133, normalized size = 0.47 \[ \frac{-105 a^6 x^6+562 a^5 x^5-74 a^4 x^4-1226 a^3 x^3+636 a^2 x^2-210 (a x-1)^3 (a x+1) \sqrt{a^2 x^2-1} \log \left (\sqrt{a^2 x^2-1}+a x\right )+654 a x-432}{105 a^2 c^3 x (a x-1)^3 (a x+1) \sqrt{c-\frac{c}{a^2 x^2}}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[E^(2*ArcTanh[a*x])/(c - c/(a^2*x^2))^(7/2),x]

[Out]

(-432 + 654*a*x + 636*a^2*x^2 - 1226*a^3*x^3 - 74*a^4*x^4 + 562*a^5*x^5 - 105*a^6*x^6 - 210*(-1 + a*x)^3*(1 +
a*x)*Sqrt[-1 + a^2*x^2]*Log[a*x + Sqrt[-1 + a^2*x^2]])/(105*a^2*c^3*Sqrt[c - c/(a^2*x^2)]*x*(-1 + a*x)^3*(1 +
a*x))

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Maple [B]  time = 0.151, size = 572, normalized size = 2. \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+1)^2/(-a^2*x^2+1)/(c-c/a^2/x^2)^(7/2),x)

[Out]

-1/105*(105*c^(7/2)*((a*x-1)*(a*x+1)*c/a^2)^(5/2)*x^7*a^7-553*x^6*c^(7/2)*a^6*((a*x-1)*(a*x+1)*c/a^2)^(5/2)+96
*c^(7/2)*(c*(a^2*x^2-1)/a^2)^(5/2)*x^6*a^6-392*c^(7/2)*((a*x-1)*(a*x+1)*c/a^2)^(5/2)*x^5*a^5-96*c^(7/2)*(c*(a^
2*x^2-1)/a^2)^(5/2)*x^5*a^5+1540*c^(7/2)*((a*x-1)*(a*x+1)*c/a^2)^(5/2)*x^4*a^4-240*c^(7/2)*(c*(a^2*x^2-1)/a^2)
^(5/2)*x^4*a^4+210*ln(x*c^(1/2)+(c*(a^2*x^2-1)/a^2)^(1/2))*((a*x-1)*(a*x+1)*c/a^2)^(5/2)*(c*(a^2*x^2-1)/a^2)^(
5/2)*x*a^6*c+350*c^(7/2)*((a*x-1)*(a*x+1)*c/a^2)^(5/2)*x^3*a^3+240*c^(7/2)*(c*(a^2*x^2-1)/a^2)^(5/2)*x^3*a^3-2
10*ln(x*c^(1/2)+(c*(a^2*x^2-1)/a^2)^(1/2))*((a*x-1)*(a*x+1)*c/a^2)^(5/2)*(c*(a^2*x^2-1)/a^2)^(5/2)*a^5*c-1470*
c^(7/2)*((a*x-1)*(a*x+1)*c/a^2)^(5/2)*x^2*a^2+180*c^(7/2)*(c*(a^2*x^2-1)/a^2)^(5/2)*x^2*a^2-42*c^(7/2)*((a*x-1
)*(a*x+1)*c/a^2)^(5/2)*x*a-180*c^(7/2)*(c*(a^2*x^2-1)/a^2)^(5/2)*x*a+462*c^(7/2)*((a*x-1)*(a*x+1)*c/a^2)^(5/2)
-30*c^(7/2)*(c*(a^2*x^2-1)/a^2)^(5/2))*(a*x+1)/((a*x-1)*(a*x+1)*c/a^2)^(5/2)/x^7/(c*(a^2*x^2-1)/a^2/x^2)^(7/2)
/a^8/c^(7/2)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} -\int \frac{{\left (a x + 1\right )}^{2}}{{\left (a^{2} x^{2} - 1\right )}{\left (c - \frac{c}{a^{2} x^{2}}\right )}^{\frac{7}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)/(c-c/a^2/x^2)^(7/2),x, algorithm="maxima")

[Out]

-integrate((a*x + 1)^2/((a^2*x^2 - 1)*(c - c/(a^2*x^2))^(7/2)), x)

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Fricas [A]  time = 3.0785, size = 1044, normalized size = 3.69 \begin{align*} \left [\frac{105 \,{\left (a^{6} x^{6} - 2 \, a^{5} x^{5} - a^{4} x^{4} + 4 \, a^{3} x^{3} - a^{2} x^{2} - 2 \, a x + 1\right )} \sqrt{c} \log \left (2 \, a^{2} c x^{2} - 2 \, a^{2} \sqrt{c} x^{2} \sqrt{\frac{a^{2} c x^{2} - c}{a^{2} x^{2}}} - c\right ) -{\left (105 \, a^{7} x^{7} - 562 \, a^{6} x^{6} + 74 \, a^{5} x^{5} + 1226 \, a^{4} x^{4} - 636 \, a^{3} x^{3} - 654 \, a^{2} x^{2} + 432 \, a x\right )} \sqrt{\frac{a^{2} c x^{2} - c}{a^{2} x^{2}}}}{105 \,{\left (a^{7} c^{4} x^{6} - 2 \, a^{6} c^{4} x^{5} - a^{5} c^{4} x^{4} + 4 \, a^{4} c^{4} x^{3} - a^{3} c^{4} x^{2} - 2 \, a^{2} c^{4} x + a c^{4}\right )}}, \frac{210 \,{\left (a^{6} x^{6} - 2 \, a^{5} x^{5} - a^{4} x^{4} + 4 \, a^{3} x^{3} - a^{2} x^{2} - 2 \, a x + 1\right )} \sqrt{-c} \arctan \left (\frac{a^{2} \sqrt{-c} x^{2} \sqrt{\frac{a^{2} c x^{2} - c}{a^{2} x^{2}}}}{a^{2} c x^{2} - c}\right ) -{\left (105 \, a^{7} x^{7} - 562 \, a^{6} x^{6} + 74 \, a^{5} x^{5} + 1226 \, a^{4} x^{4} - 636 \, a^{3} x^{3} - 654 \, a^{2} x^{2} + 432 \, a x\right )} \sqrt{\frac{a^{2} c x^{2} - c}{a^{2} x^{2}}}}{105 \,{\left (a^{7} c^{4} x^{6} - 2 \, a^{6} c^{4} x^{5} - a^{5} c^{4} x^{4} + 4 \, a^{4} c^{4} x^{3} - a^{3} c^{4} x^{2} - 2 \, a^{2} c^{4} x + a c^{4}\right )}}\right ] \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)/(c-c/a^2/x^2)^(7/2),x, algorithm="fricas")

[Out]

[1/105*(105*(a^6*x^6 - 2*a^5*x^5 - a^4*x^4 + 4*a^3*x^3 - a^2*x^2 - 2*a*x + 1)*sqrt(c)*log(2*a^2*c*x^2 - 2*a^2*
sqrt(c)*x^2*sqrt((a^2*c*x^2 - c)/(a^2*x^2)) - c) - (105*a^7*x^7 - 562*a^6*x^6 + 74*a^5*x^5 + 1226*a^4*x^4 - 63
6*a^3*x^3 - 654*a^2*x^2 + 432*a*x)*sqrt((a^2*c*x^2 - c)/(a^2*x^2)))/(a^7*c^4*x^6 - 2*a^6*c^4*x^5 - a^5*c^4*x^4
+ 4*a^4*c^4*x^3 - a^3*c^4*x^2 - 2*a^2*c^4*x + a*c^4), 1/105*(210*(a^6*x^6 - 2*a^5*x^5 - a^4*x^4 + 4*a^3*x^3 -
a^2*x^2 - 2*a*x + 1)*sqrt(-c)*arctan(a^2*sqrt(-c)*x^2*sqrt((a^2*c*x^2 - c)/(a^2*x^2))/(a^2*c*x^2 - c)) - (105
*a^7*x^7 - 562*a^6*x^6 + 74*a^5*x^5 + 1226*a^4*x^4 - 636*a^3*x^3 - 654*a^2*x^2 + 432*a*x)*sqrt((a^2*c*x^2 - c)
/(a^2*x^2)))/(a^7*c^4*x^6 - 2*a^6*c^4*x^5 - a^5*c^4*x^4 + 4*a^4*c^4*x^3 - a^3*c^4*x^2 - 2*a^2*c^4*x + a*c^4)]

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} - \int \frac{a x}{a c^{3} x \sqrt{c - \frac{c}{a^{2} x^{2}}} - c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}} - \frac{3 c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a x} + \frac{3 c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a^{2} x^{2}} + \frac{3 c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a^{3} x^{3}} - \frac{3 c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a^{4} x^{4}} - \frac{c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a^{5} x^{5}} + \frac{c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a^{6} x^{6}}}\, dx - \int \frac{1}{a c^{3} x \sqrt{c - \frac{c}{a^{2} x^{2}}} - c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}} - \frac{3 c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a x} + \frac{3 c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a^{2} x^{2}} + \frac{3 c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a^{3} x^{3}} - \frac{3 c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a^{4} x^{4}} - \frac{c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a^{5} x^{5}} + \frac{c^{3} \sqrt{c - \frac{c}{a^{2} x^{2}}}}{a^{6} x^{6}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)**2/(-a**2*x**2+1)/(c-c/a**2/x**2)**(7/2),x)

[Out]

-Integral(a*x/(a*c**3*x*sqrt(c - c/(a**2*x**2)) - c**3*sqrt(c - c/(a**2*x**2)) - 3*c**3*sqrt(c - c/(a**2*x**2)
)/(a*x) + 3*c**3*sqrt(c - c/(a**2*x**2))/(a**2*x**2) + 3*c**3*sqrt(c - c/(a**2*x**2))/(a**3*x**3) - 3*c**3*sqr
t(c - c/(a**2*x**2))/(a**4*x**4) - c**3*sqrt(c - c/(a**2*x**2))/(a**5*x**5) + c**3*sqrt(c - c/(a**2*x**2))/(a*
*6*x**6)), x) - Integral(1/(a*c**3*x*sqrt(c - c/(a**2*x**2)) - c**3*sqrt(c - c/(a**2*x**2)) - 3*c**3*sqrt(c -
c/(a**2*x**2))/(a*x) + 3*c**3*sqrt(c - c/(a**2*x**2))/(a**2*x**2) + 3*c**3*sqrt(c - c/(a**2*x**2))/(a**3*x**3)
- 3*c**3*sqrt(c - c/(a**2*x**2))/(a**4*x**4) - c**3*sqrt(c - c/(a**2*x**2))/(a**5*x**5) + c**3*sqrt(c - c/(a*
*2*x**2))/(a**6*x**6)), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{{\left (a x + 1\right )}^{2}}{{\left (a^{2} x^{2} - 1\right )}{\left (c - \frac{c}{a^{2} x^{2}}\right )}^{\frac{7}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)/(c-c/a^2/x^2)^(7/2),x, algorithm="giac")

[Out]

integrate(-(a*x + 1)^2/((a^2*x^2 - 1)*(c - c/(a^2*x^2))^(7/2)), x)