3.592 \(\int e^{-\tanh ^{-1}(a x)} \sqrt{c-\frac{c}{a x}} x^2 \, dx\)

Optimal. Leaf size=182 \[ -\frac{x^3 \sqrt{1-a^2 x^2} \sqrt{c-\frac{c}{a x}}}{3 (1-a x)}-\frac{11 x \sqrt{a x+1} \sqrt{c-\frac{c}{a x}}}{8 a^2 \sqrt{1-a x}}+\frac{11 \sqrt{x} \sqrt{c-\frac{c}{a x}} \sinh ^{-1}\left (\sqrt{a} \sqrt{x}\right )}{8 a^{5/2} \sqrt{1-a x}}+\frac{11 x^2 \sqrt{a x+1} \sqrt{c-\frac{c}{a x}}}{12 a \sqrt{1-a x}} \]

[Out]

(-11*Sqrt[c - c/(a*x)]*x*Sqrt[1 + a*x])/(8*a^2*Sqrt[1 - a*x]) + (11*Sqrt[c - c/(a*x)]*x^2*Sqrt[1 + a*x])/(12*a
*Sqrt[1 - a*x]) - (Sqrt[c - c/(a*x)]*x^3*Sqrt[1 - a^2*x^2])/(3*(1 - a*x)) + (11*Sqrt[c - c/(a*x)]*Sqrt[x]*ArcS
inh[Sqrt[a]*Sqrt[x]])/(8*a^(5/2)*Sqrt[1 - a*x])

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Rubi [A]  time = 0.307973, antiderivative size = 182, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.259, Rules used = {6134, 6128, 881, 848, 50, 54, 215} \[ -\frac{x^3 \sqrt{1-a^2 x^2} \sqrt{c-\frac{c}{a x}}}{3 (1-a x)}-\frac{11 x \sqrt{a x+1} \sqrt{c-\frac{c}{a x}}}{8 a^2 \sqrt{1-a x}}+\frac{11 \sqrt{x} \sqrt{c-\frac{c}{a x}} \sinh ^{-1}\left (\sqrt{a} \sqrt{x}\right )}{8 a^{5/2} \sqrt{1-a x}}+\frac{11 x^2 \sqrt{a x+1} \sqrt{c-\frac{c}{a x}}}{12 a \sqrt{1-a x}} \]

Antiderivative was successfully verified.

[In]

Int[(Sqrt[c - c/(a*x)]*x^2)/E^ArcTanh[a*x],x]

[Out]

(-11*Sqrt[c - c/(a*x)]*x*Sqrt[1 + a*x])/(8*a^2*Sqrt[1 - a*x]) + (11*Sqrt[c - c/(a*x)]*x^2*Sqrt[1 + a*x])/(12*a
*Sqrt[1 - a*x]) - (Sqrt[c - c/(a*x)]*x^3*Sqrt[1 - a^2*x^2])/(3*(1 - a*x)) + (11*Sqrt[c - c/(a*x)]*Sqrt[x]*ArcS
inh[Sqrt[a]*Sqrt[x]])/(8*a^(5/2)*Sqrt[1 - a*x])

Rule 6134

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)/(x_))^(p_), x_Symbol] :> Dist[(x^p*(c + d/x)^p)/(1 + (c*
x)/d)^p, Int[(u*(1 + (c*x)/d)^p*E^(n*ArcTanh[a*x]))/x^p, x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[c^2 - a^2*
d^2, 0] &&  !IntegerQ[p]

Rule 6128

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_))^(p_.)*((e_.) + (f_.)*(x_))^(m_.), x_Symbol] :> Dist[c^n,
Int[(e + f*x)^m*(c + d*x)^(p - n)*(1 - a^2*x^2)^(n/2), x], x] /; FreeQ[{a, c, d, e, f, m, p}, x] && EqQ[a*c +
d, 0] && IntegerQ[(n - 1)/2] && (IntegerQ[p] || EqQ[p, n/2] || EqQ[p - n/2 - 1, 0]) && IntegerQ[2*p]

Rule 881

Int[((d_) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))^(n_)*((a_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(e^2*(d +
e*x)^(m - 2)*(f + g*x)^(n + 1)*(a + c*x^2)^(p + 1))/(c*g*(n + p + 2)), x] - Dist[(e*f*(p + 1) - d*g*(2*n + p
+ 3))/(g*(n + p + 2)), Int[(d + e*x)^(m - 1)*(f + g*x)^n*(a + c*x^2)^p, x], x] /; FreeQ[{a, c, d, e, f, g, m,
n, p}, x] && NeQ[e*f - d*g, 0] && EqQ[c*d^2 + a*e^2, 0] &&  !IntegerQ[p] && EqQ[m + p - 1, 0] &&  !LtQ[n, -1]
&& IntegerQ[2*p]

Rule 848

Int[((d_) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))^(n_)*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[(d + e*x)
^(m + p)*(f + g*x)^n*(a/d + (c*x)/e)^p, x] /; FreeQ[{a, c, d, e, f, g, m, n}, x] && NeQ[e*f - d*g, 0] && EqQ[c
*d^2 + a*e^2, 0] && (IntegerQ[p] || (GtQ[a, 0] && GtQ[d, 0] && EqQ[m + p, 0]))

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 54

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 215

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSinh[(Rt[b, 2]*x)/Sqrt[a]]/Rt[b, 2], x] /; FreeQ[{a, b},
x] && GtQ[a, 0] && PosQ[b]

Rubi steps

\begin{align*} \int e^{-\tanh ^{-1}(a x)} \sqrt{c-\frac{c}{a x}} x^2 \, dx &=\frac{\left (\sqrt{c-\frac{c}{a x}} \sqrt{x}\right ) \int e^{-\tanh ^{-1}(a x)} x^{3/2} \sqrt{1-a x} \, dx}{\sqrt{1-a x}}\\ &=\frac{\left (\sqrt{c-\frac{c}{a x}} \sqrt{x}\right ) \int \frac{x^{3/2} (1-a x)^{3/2}}{\sqrt{1-a^2 x^2}} \, dx}{\sqrt{1-a x}}\\ &=-\frac{\sqrt{c-\frac{c}{a x}} x^3 \sqrt{1-a^2 x^2}}{3 (1-a x)}+\frac{\left (11 \sqrt{c-\frac{c}{a x}} \sqrt{x}\right ) \int \frac{x^{3/2} \sqrt{1-a x}}{\sqrt{1-a^2 x^2}} \, dx}{6 \sqrt{1-a x}}\\ &=-\frac{\sqrt{c-\frac{c}{a x}} x^3 \sqrt{1-a^2 x^2}}{3 (1-a x)}+\frac{\left (11 \sqrt{c-\frac{c}{a x}} \sqrt{x}\right ) \int \frac{x^{3/2}}{\sqrt{1+a x}} \, dx}{6 \sqrt{1-a x}}\\ &=\frac{11 \sqrt{c-\frac{c}{a x}} x^2 \sqrt{1+a x}}{12 a \sqrt{1-a x}}-\frac{\sqrt{c-\frac{c}{a x}} x^3 \sqrt{1-a^2 x^2}}{3 (1-a x)}-\frac{\left (11 \sqrt{c-\frac{c}{a x}} \sqrt{x}\right ) \int \frac{\sqrt{x}}{\sqrt{1+a x}} \, dx}{8 a \sqrt{1-a x}}\\ &=-\frac{11 \sqrt{c-\frac{c}{a x}} x \sqrt{1+a x}}{8 a^2 \sqrt{1-a x}}+\frac{11 \sqrt{c-\frac{c}{a x}} x^2 \sqrt{1+a x}}{12 a \sqrt{1-a x}}-\frac{\sqrt{c-\frac{c}{a x}} x^3 \sqrt{1-a^2 x^2}}{3 (1-a x)}+\frac{\left (11 \sqrt{c-\frac{c}{a x}} \sqrt{x}\right ) \int \frac{1}{\sqrt{x} \sqrt{1+a x}} \, dx}{16 a^2 \sqrt{1-a x}}\\ &=-\frac{11 \sqrt{c-\frac{c}{a x}} x \sqrt{1+a x}}{8 a^2 \sqrt{1-a x}}+\frac{11 \sqrt{c-\frac{c}{a x}} x^2 \sqrt{1+a x}}{12 a \sqrt{1-a x}}-\frac{\sqrt{c-\frac{c}{a x}} x^3 \sqrt{1-a^2 x^2}}{3 (1-a x)}+\frac{\left (11 \sqrt{c-\frac{c}{a x}} \sqrt{x}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1+a x^2}} \, dx,x,\sqrt{x}\right )}{8 a^2 \sqrt{1-a x}}\\ &=-\frac{11 \sqrt{c-\frac{c}{a x}} x \sqrt{1+a x}}{8 a^2 \sqrt{1-a x}}+\frac{11 \sqrt{c-\frac{c}{a x}} x^2 \sqrt{1+a x}}{12 a \sqrt{1-a x}}-\frac{\sqrt{c-\frac{c}{a x}} x^3 \sqrt{1-a^2 x^2}}{3 (1-a x)}+\frac{11 \sqrt{c-\frac{c}{a x}} \sqrt{x} \sinh ^{-1}\left (\sqrt{a} \sqrt{x}\right )}{8 a^{5/2} \sqrt{1-a x}}\\ \end{align*}

Mathematica [A]  time = 0.0844775, size = 88, normalized size = 0.48 \[ \frac{\sqrt{x} \sqrt{c-\frac{c}{a x}} \left (\sqrt{a} \sqrt{x} \sqrt{a x+1} \left (-8 a^2 x^2+22 a x-33\right )+33 \sinh ^{-1}\left (\sqrt{a} \sqrt{x}\right )\right )}{24 a^{5/2} \sqrt{1-a x}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(Sqrt[c - c/(a*x)]*x^2)/E^ArcTanh[a*x],x]

[Out]

(Sqrt[c - c/(a*x)]*Sqrt[x]*(Sqrt[a]*Sqrt[x]*Sqrt[1 + a*x]*(-33 + 22*a*x - 8*a^2*x^2) + 33*ArcSinh[Sqrt[a]*Sqrt
[x]]))/(24*a^(5/2)*Sqrt[1 - a*x])

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Maple [A]  time = 0.132, size = 125, normalized size = 0.7 \begin{align*}{\frac{x}{48\,ax-48}\sqrt{{\frac{c \left ( ax-1 \right ) }{ax}}}\sqrt{-{a}^{2}{x}^{2}+1} \left ( 16\,{a}^{5/2}{x}^{2}\sqrt{- \left ( ax+1 \right ) x}-44\,{a}^{3/2}x\sqrt{- \left ( ax+1 \right ) x}+66\,\sqrt{a}\sqrt{- \left ( ax+1 \right ) x}+33\,\arctan \left ( 1/2\,{\frac{2\,ax+1}{\sqrt{a}\sqrt{- \left ( ax+1 \right ) x}}} \right ) \right ){a}^{-{\frac{5}{2}}}{\frac{1}{\sqrt{- \left ( ax+1 \right ) x}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(c-c/a/x)^(1/2)/(a*x+1)*(-a^2*x^2+1)^(1/2),x)

[Out]

1/48*(c*(a*x-1)/a/x)^(1/2)*x*(-a^2*x^2+1)^(1/2)/a^(5/2)*(16*a^(5/2)*x^2*(-(a*x+1)*x)^(1/2)-44*a^(3/2)*x*(-(a*x
+1)*x)^(1/2)+66*a^(1/2)*(-(a*x+1)*x)^(1/2)+33*arctan(1/2/a^(1/2)*(2*a*x+1)/(-(a*x+1)*x)^(1/2)))/(a*x-1)/(-(a*x
+1)*x)^(1/2)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{-a^{2} x^{2} + 1} \sqrt{c - \frac{c}{a x}} x^{2}}{a x + 1}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(c-c/a/x)^(1/2)/(a*x+1)*(-a^2*x^2+1)^(1/2),x, algorithm="maxima")

[Out]

integrate(sqrt(-a^2*x^2 + 1)*sqrt(c - c/(a*x))*x^2/(a*x + 1), x)

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Fricas [A]  time = 3.23785, size = 625, normalized size = 3.43 \begin{align*} \left [\frac{33 \,{\left (a x - 1\right )} \sqrt{-c} \log \left (-\frac{8 \, a^{3} c x^{3} - 7 \, a c x + 4 \,{\left (2 \, a^{2} x^{2} + a x\right )} \sqrt{-a^{2} x^{2} + 1} \sqrt{-c} \sqrt{\frac{a c x - c}{a x}} - c}{a x - 1}\right ) + 4 \,{\left (8 \, a^{3} x^{3} - 22 \, a^{2} x^{2} + 33 \, a x\right )} \sqrt{-a^{2} x^{2} + 1} \sqrt{\frac{a c x - c}{a x}}}{96 \,{\left (a^{4} x - a^{3}\right )}}, -\frac{33 \,{\left (a x - 1\right )} \sqrt{c} \arctan \left (\frac{2 \, \sqrt{-a^{2} x^{2} + 1} a \sqrt{c} x \sqrt{\frac{a c x - c}{a x}}}{2 \, a^{2} c x^{2} - a c x - c}\right ) - 2 \,{\left (8 \, a^{3} x^{3} - 22 \, a^{2} x^{2} + 33 \, a x\right )} \sqrt{-a^{2} x^{2} + 1} \sqrt{\frac{a c x - c}{a x}}}{48 \,{\left (a^{4} x - a^{3}\right )}}\right ] \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(c-c/a/x)^(1/2)/(a*x+1)*(-a^2*x^2+1)^(1/2),x, algorithm="fricas")

[Out]

[1/96*(33*(a*x - 1)*sqrt(-c)*log(-(8*a^3*c*x^3 - 7*a*c*x + 4*(2*a^2*x^2 + a*x)*sqrt(-a^2*x^2 + 1)*sqrt(-c)*sqr
t((a*c*x - c)/(a*x)) - c)/(a*x - 1)) + 4*(8*a^3*x^3 - 22*a^2*x^2 + 33*a*x)*sqrt(-a^2*x^2 + 1)*sqrt((a*c*x - c)
/(a*x)))/(a^4*x - a^3), -1/48*(33*(a*x - 1)*sqrt(c)*arctan(2*sqrt(-a^2*x^2 + 1)*a*sqrt(c)*x*sqrt((a*c*x - c)/(
a*x))/(2*a^2*c*x^2 - a*c*x - c)) - 2*(8*a^3*x^3 - 22*a^2*x^2 + 33*a*x)*sqrt(-a^2*x^2 + 1)*sqrt((a*c*x - c)/(a*
x)))/(a^4*x - a^3)]

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2} \sqrt{- c \left (-1 + \frac{1}{a x}\right )} \sqrt{- \left (a x - 1\right ) \left (a x + 1\right )}}{a x + 1}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*(c-c/a/x)**(1/2)/(a*x+1)*(-a**2*x**2+1)**(1/2),x)

[Out]

Integral(x**2*sqrt(-c*(-1 + 1/(a*x)))*sqrt(-(a*x - 1)*(a*x + 1))/(a*x + 1), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{-a^{2} x^{2} + 1} \sqrt{c - \frac{c}{a x}} x^{2}}{a x + 1}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(c-c/a/x)^(1/2)/(a*x+1)*(-a^2*x^2+1)^(1/2),x, algorithm="giac")

[Out]

integrate(sqrt(-a^2*x^2 + 1)*sqrt(c - c/(a*x))*x^2/(a*x + 1), x)