3.502 \(\int e^{-3 \tanh ^{-1}(a x)} (c-\frac{c}{a x})^3 \, dx\)

Optimal. Leaf size=140 \[ -\frac{c^3 \sqrt{1-a^2 x^2}}{a}-\frac{6 c^3 \sqrt{1-a^2 x^2}}{a^2 x}+\frac{c^3 \sqrt{1-a^2 x^2}}{2 a^3 x^2}-\frac{32 c^3 (1-a x)}{a \sqrt{1-a^2 x^2}}+\frac{33 c^3 \tanh ^{-1}\left (\sqrt{1-a^2 x^2}\right )}{2 a}-\frac{6 c^3 \sin ^{-1}(a x)}{a} \]

[Out]

(-32*c^3*(1 - a*x))/(a*Sqrt[1 - a^2*x^2]) - (c^3*Sqrt[1 - a^2*x^2])/a + (c^3*Sqrt[1 - a^2*x^2])/(2*a^3*x^2) -
(6*c^3*Sqrt[1 - a^2*x^2])/(a^2*x) - (6*c^3*ArcSin[a*x])/a + (33*c^3*ArcTanh[Sqrt[1 - a^2*x^2]])/(2*a)

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Rubi [A]  time = 0.367923, antiderivative size = 140, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 10, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.454, Rules used = {6131, 6128, 1805, 1807, 1809, 844, 216, 266, 63, 208} \[ -\frac{c^3 \sqrt{1-a^2 x^2}}{a}-\frac{6 c^3 \sqrt{1-a^2 x^2}}{a^2 x}+\frac{c^3 \sqrt{1-a^2 x^2}}{2 a^3 x^2}-\frac{32 c^3 (1-a x)}{a \sqrt{1-a^2 x^2}}+\frac{33 c^3 \tanh ^{-1}\left (\sqrt{1-a^2 x^2}\right )}{2 a}-\frac{6 c^3 \sin ^{-1}(a x)}{a} \]

Antiderivative was successfully verified.

[In]

Int[(c - c/(a*x))^3/E^(3*ArcTanh[a*x]),x]

[Out]

(-32*c^3*(1 - a*x))/(a*Sqrt[1 - a^2*x^2]) - (c^3*Sqrt[1 - a^2*x^2])/a + (c^3*Sqrt[1 - a^2*x^2])/(2*a^3*x^2) -
(6*c^3*Sqrt[1 - a^2*x^2])/(a^2*x) - (6*c^3*ArcSin[a*x])/a + (33*c^3*ArcTanh[Sqrt[1 - a^2*x^2]])/(2*a)

Rule 6131

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)/(x_))^(p_.), x_Symbol] :> Dist[d^p, Int[(u*(1 + (c*x)/d)
^p*E^(n*ArcTanh[a*x]))/x^p, x], x] /; FreeQ[{a, c, d, n}, x] && EqQ[c^2 - a^2*d^2, 0] && IntegerQ[p]

Rule 6128

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_))^(p_.)*((e_.) + (f_.)*(x_))^(m_.), x_Symbol] :> Dist[c^n,
Int[(e + f*x)^m*(c + d*x)^(p - n)*(1 - a^2*x^2)^(n/2), x], x] /; FreeQ[{a, c, d, e, f, m, p}, x] && EqQ[a*c +
d, 0] && IntegerQ[(n - 1)/2] && (IntegerQ[p] || EqQ[p, n/2] || EqQ[p - n/2 - 1, 0]) && IntegerQ[2*p]

Rule 1805

Int[(Pq_)*((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{Q = PolynomialQuotient[(c*x)^m*Pq,
a + b*x^2, x], f = Coeff[PolynomialRemainder[(c*x)^m*Pq, a + b*x^2, x], x, 0], g = Coeff[PolynomialRemainder[
(c*x)^m*Pq, a + b*x^2, x], x, 1]}, Simp[((a*g - b*f*x)*(a + b*x^2)^(p + 1))/(2*a*b*(p + 1)), x] + Dist[1/(2*a*
(p + 1)), Int[(c*x)^m*(a + b*x^2)^(p + 1)*ExpandToSum[(2*a*(p + 1)*Q)/(c*x)^m + (f*(2*p + 3))/(c*x)^m, x], x],
x]] /; FreeQ[{a, b, c}, x] && PolyQ[Pq, x] && LtQ[p, -1] && ILtQ[m, 0]

Rule 1807

Int[(Pq_)*((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{Q = PolynomialQuotient[Pq, c*x, x],
R = PolynomialRemainder[Pq, c*x, x]}, Simp[(R*(c*x)^(m + 1)*(a + b*x^2)^(p + 1))/(a*c*(m + 1)), x] + Dist[1/(
a*c*(m + 1)), Int[(c*x)^(m + 1)*(a + b*x^2)^p*ExpandToSum[a*c*(m + 1)*Q - b*R*(m + 2*p + 3)*x, x], x], x]] /;
FreeQ[{a, b, c, p}, x] && PolyQ[Pq, x] && LtQ[m, -1] && (IntegerQ[2*p] || NeQ[Expon[Pq, x], 1])

Rule 1809

Int[(Pq_)*((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{q = Expon[Pq, x], f = Coeff[Pq, x,
Expon[Pq, x]]}, Simp[(f*(c*x)^(m + q - 1)*(a + b*x^2)^(p + 1))/(b*c^(q - 1)*(m + q + 2*p + 1)), x] + Dist[1/(
b*(m + q + 2*p + 1)), Int[(c*x)^m*(a + b*x^2)^p*ExpandToSum[b*(m + q + 2*p + 1)*Pq - b*f*(m + q + 2*p + 1)*x^q
- a*f*(m + q - 1)*x^(q - 2), x], x], x] /; GtQ[q, 1] && NeQ[m + q + 2*p + 1, 0]] /; FreeQ[{a, b, c, m, p}, x]
&& PolyQ[Pq, x] && ( !IGtQ[m, 0] || IGtQ[p + 1/2, -1])

Rule 844

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[g/e, Int[(d
+ e*x)^(m + 1)*(a + c*x^2)^p, x], x] + Dist[(e*f - d*g)/e, Int[(d + e*x)^m*(a + c*x^2)^p, x], x] /; FreeQ[{a,
c, d, e, f, g, m, p}, x] && NeQ[c*d^2 + a*e^2, 0] &&  !IGtQ[m, 0]

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rubi steps

\begin{align*} \int e^{-3 \tanh ^{-1}(a x)} \left (c-\frac{c}{a x}\right )^3 \, dx &=-\frac{c^3 \int \frac{e^{-3 \tanh ^{-1}(a x)} (1-a x)^3}{x^3} \, dx}{a^3}\\ &=-\frac{c^3 \int \frac{(1-a x)^6}{x^3 \left (1-a^2 x^2\right )^{3/2}} \, dx}{a^3}\\ &=-\frac{32 c^3 (1-a x)}{a \sqrt{1-a^2 x^2}}+\frac{c^3 \int \frac{-1+6 a x-16 a^2 x^2-6 a^3 x^3+a^4 x^4}{x^3 \sqrt{1-a^2 x^2}} \, dx}{a^3}\\ &=-\frac{32 c^3 (1-a x)}{a \sqrt{1-a^2 x^2}}+\frac{c^3 \sqrt{1-a^2 x^2}}{2 a^3 x^2}-\frac{c^3 \int \frac{-12 a+33 a^2 x+12 a^3 x^2-2 a^4 x^3}{x^2 \sqrt{1-a^2 x^2}} \, dx}{2 a^3}\\ &=-\frac{32 c^3 (1-a x)}{a \sqrt{1-a^2 x^2}}+\frac{c^3 \sqrt{1-a^2 x^2}}{2 a^3 x^2}-\frac{6 c^3 \sqrt{1-a^2 x^2}}{a^2 x}+\frac{c^3 \int \frac{-33 a^2-12 a^3 x+2 a^4 x^2}{x \sqrt{1-a^2 x^2}} \, dx}{2 a^3}\\ &=-\frac{32 c^3 (1-a x)}{a \sqrt{1-a^2 x^2}}-\frac{c^3 \sqrt{1-a^2 x^2}}{a}+\frac{c^3 \sqrt{1-a^2 x^2}}{2 a^3 x^2}-\frac{6 c^3 \sqrt{1-a^2 x^2}}{a^2 x}-\frac{c^3 \int \frac{33 a^4+12 a^5 x}{x \sqrt{1-a^2 x^2}} \, dx}{2 a^5}\\ &=-\frac{32 c^3 (1-a x)}{a \sqrt{1-a^2 x^2}}-\frac{c^3 \sqrt{1-a^2 x^2}}{a}+\frac{c^3 \sqrt{1-a^2 x^2}}{2 a^3 x^2}-\frac{6 c^3 \sqrt{1-a^2 x^2}}{a^2 x}-\left (6 c^3\right ) \int \frac{1}{\sqrt{1-a^2 x^2}} \, dx-\frac{\left (33 c^3\right ) \int \frac{1}{x \sqrt{1-a^2 x^2}} \, dx}{2 a}\\ &=-\frac{32 c^3 (1-a x)}{a \sqrt{1-a^2 x^2}}-\frac{c^3 \sqrt{1-a^2 x^2}}{a}+\frac{c^3 \sqrt{1-a^2 x^2}}{2 a^3 x^2}-\frac{6 c^3 \sqrt{1-a^2 x^2}}{a^2 x}-\frac{6 c^3 \sin ^{-1}(a x)}{a}-\frac{\left (33 c^3\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{1-a^2 x}} \, dx,x,x^2\right )}{4 a}\\ &=-\frac{32 c^3 (1-a x)}{a \sqrt{1-a^2 x^2}}-\frac{c^3 \sqrt{1-a^2 x^2}}{a}+\frac{c^3 \sqrt{1-a^2 x^2}}{2 a^3 x^2}-\frac{6 c^3 \sqrt{1-a^2 x^2}}{a^2 x}-\frac{6 c^3 \sin ^{-1}(a x)}{a}+\frac{\left (33 c^3\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{1}{a^2}-\frac{x^2}{a^2}} \, dx,x,\sqrt{1-a^2 x^2}\right )}{2 a^3}\\ &=-\frac{32 c^3 (1-a x)}{a \sqrt{1-a^2 x^2}}-\frac{c^3 \sqrt{1-a^2 x^2}}{a}+\frac{c^3 \sqrt{1-a^2 x^2}}{2 a^3 x^2}-\frac{6 c^3 \sqrt{1-a^2 x^2}}{a^2 x}-\frac{6 c^3 \sin ^{-1}(a x)}{a}+\frac{33 c^3 \tanh ^{-1}\left (\sqrt{1-a^2 x^2}\right )}{2 a}\\ \end{align*}

Mathematica [A]  time = 0.281584, size = 93, normalized size = 0.66 \[ \frac{c^3 \left (-\frac{\sqrt{1-a^2 x^2} \left (2 a^3 x^3+78 a^2 x^2+11 a x-1\right )}{a^2 x^2 (a x+1)}+33 \log \left (\sqrt{1-a^2 x^2}+1\right )-33 \log (a x)-12 \sin ^{-1}(a x)\right )}{2 a} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(c - c/(a*x))^3/E^(3*ArcTanh[a*x]),x]

[Out]

(c^3*(-((Sqrt[1 - a^2*x^2]*(-1 + 11*a*x + 78*a^2*x^2 + 2*a^3*x^3))/(a^2*x^2*(1 + a*x))) - 12*ArcSin[a*x] - 33*
Log[a*x] + 33*Log[1 + Sqrt[1 - a^2*x^2]]))/(2*a)

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Maple [B]  time = 0.063, size = 352, normalized size = 2.5 \begin{align*} -8\,{\frac{{c}^{3} \left ( -{a}^{2} \left ( x+{a}^{-1} \right ) ^{2}+2\,a \left ( x+{a}^{-1} \right ) \right ) ^{5/2}}{{a}^{4} \left ( x+{a}^{-1} \right ) ^{3}}}-4\,{\frac{{c}^{3} \left ( -{a}^{2} \left ( x+{a}^{-1} \right ) ^{2}+2\,a \left ( x+{a}^{-1} \right ) \right ) ^{5/2}}{{a}^{3} \left ( x+{a}^{-1} \right ) ^{2}}}+2\,{\frac{{c}^{3} \left ( -{a}^{2} \left ( x+{a}^{-1} \right ) ^{2}+2\,a \left ( x+{a}^{-1} \right ) \right ) ^{3/2}}{a}}+3\,{c}^{3}\sqrt{-{a}^{2} \left ( x+{a}^{-1} \right ) ^{2}+2\,a \left ( x+{a}^{-1} \right ) }x+3\,{\frac{{c}^{3}}{\sqrt{{a}^{2}}}\arctan \left ({\frac{\sqrt{{a}^{2}}x}{\sqrt{-{a}^{2} \left ( x+{a}^{-1} \right ) ^{2}+2\,a \left ( x+{a}^{-1} \right ) }}} \right ) }-6\,{\frac{{c}^{3} \left ( -{a}^{2}{x}^{2}+1 \right ) ^{5/2}}{{a}^{2}x}}-6\,{c}^{3}x \left ( -{a}^{2}{x}^{2}+1 \right ) ^{3/2}-9\,{c}^{3}x\sqrt{-{a}^{2}{x}^{2}+1}-9\,{\frac{{c}^{3}}{\sqrt{{a}^{2}}}\arctan \left ({\frac{\sqrt{{a}^{2}}x}{\sqrt{-{a}^{2}{x}^{2}+1}}} \right ) }-{\frac{11\,{c}^{3}}{2\,a} \left ( -{a}^{2}{x}^{2}+1 \right ) ^{{\frac{3}{2}}}}-{\frac{33\,{c}^{3}}{2\,a}\sqrt{-{a}^{2}{x}^{2}+1}}+{\frac{33\,{c}^{3}}{2\,a}{\it Artanh} \left ({\frac{1}{\sqrt{-{a}^{2}{x}^{2}+1}}} \right ) }+{\frac{{c}^{3}}{2\,{x}^{2}{a}^{3}} \left ( -{a}^{2}{x}^{2}+1 \right ) ^{{\frac{5}{2}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c-c/a/x)^3/(a*x+1)^3*(-a^2*x^2+1)^(3/2),x)

[Out]

-8*c^3/a^4/(x+1/a)^3*(-a^2*(x+1/a)^2+2*a*(x+1/a))^(5/2)-4*c^3/a^3/(x+1/a)^2*(-a^2*(x+1/a)^2+2*a*(x+1/a))^(5/2)
+2*c^3/a*(-a^2*(x+1/a)^2+2*a*(x+1/a))^(3/2)+3*c^3*(-a^2*(x+1/a)^2+2*a*(x+1/a))^(1/2)*x+3*c^3/(a^2)^(1/2)*arcta
n((a^2)^(1/2)*x/(-a^2*(x+1/a)^2+2*a*(x+1/a))^(1/2))-6*c^3/a^2/x*(-a^2*x^2+1)^(5/2)-6*c^3*x*(-a^2*x^2+1)^(3/2)-
9*c^3*x*(-a^2*x^2+1)^(1/2)-9*c^3/(a^2)^(1/2)*arctan((a^2)^(1/2)*x/(-a^2*x^2+1)^(1/2))-11/2*c^3*(-a^2*x^2+1)^(3
/2)/a-33/2*c^3*(-a^2*x^2+1)^(1/2)/a+33/2*c^3/a*arctanh(1/(-a^2*x^2+1)^(1/2))+1/2*c^3/a^3/x^2*(-a^2*x^2+1)^(5/2
)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (-a^{2} x^{2} + 1\right )}^{\frac{3}{2}}{\left (c - \frac{c}{a x}\right )}^{3}}{{\left (a x + 1\right )}^{3}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c-c/a/x)^3/(a*x+1)^3*(-a^2*x^2+1)^(3/2),x, algorithm="maxima")

[Out]

integrate((-a^2*x^2 + 1)^(3/2)*(c - c/(a*x))^3/(a*x + 1)^3, x)

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Fricas [A]  time = 2.51443, size = 365, normalized size = 2.61 \begin{align*} -\frac{66 \, a^{3} c^{3} x^{3} + 66 \, a^{2} c^{3} x^{2} - 24 \,{\left (a^{3} c^{3} x^{3} + a^{2} c^{3} x^{2}\right )} \arctan \left (\frac{\sqrt{-a^{2} x^{2} + 1} - 1}{a x}\right ) + 33 \,{\left (a^{3} c^{3} x^{3} + a^{2} c^{3} x^{2}\right )} \log \left (\frac{\sqrt{-a^{2} x^{2} + 1} - 1}{x}\right ) +{\left (2 \, a^{3} c^{3} x^{3} + 78 \, a^{2} c^{3} x^{2} + 11 \, a c^{3} x - c^{3}\right )} \sqrt{-a^{2} x^{2} + 1}}{2 \,{\left (a^{4} x^{3} + a^{3} x^{2}\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c-c/a/x)^3/(a*x+1)^3*(-a^2*x^2+1)^(3/2),x, algorithm="fricas")

[Out]

-1/2*(66*a^3*c^3*x^3 + 66*a^2*c^3*x^2 - 24*(a^3*c^3*x^3 + a^2*c^3*x^2)*arctan((sqrt(-a^2*x^2 + 1) - 1)/(a*x))
+ 33*(a^3*c^3*x^3 + a^2*c^3*x^2)*log((sqrt(-a^2*x^2 + 1) - 1)/x) + (2*a^3*c^3*x^3 + 78*a^2*c^3*x^2 + 11*a*c^3*
x - c^3)*sqrt(-a^2*x^2 + 1))/(a^4*x^3 + a^3*x^2)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \frac{c^{3} \left (\int - \frac{\sqrt{- a^{2} x^{2} + 1}}{a^{3} x^{6} + 3 a^{2} x^{5} + 3 a x^{4} + x^{3}}\, dx + \int \frac{3 a x \sqrt{- a^{2} x^{2} + 1}}{a^{3} x^{6} + 3 a^{2} x^{5} + 3 a x^{4} + x^{3}}\, dx + \int - \frac{2 a^{2} x^{2} \sqrt{- a^{2} x^{2} + 1}}{a^{3} x^{6} + 3 a^{2} x^{5} + 3 a x^{4} + x^{3}}\, dx + \int - \frac{2 a^{3} x^{3} \sqrt{- a^{2} x^{2} + 1}}{a^{3} x^{6} + 3 a^{2} x^{5} + 3 a x^{4} + x^{3}}\, dx + \int \frac{3 a^{4} x^{4} \sqrt{- a^{2} x^{2} + 1}}{a^{3} x^{6} + 3 a^{2} x^{5} + 3 a x^{4} + x^{3}}\, dx + \int - \frac{a^{5} x^{5} \sqrt{- a^{2} x^{2} + 1}}{a^{3} x^{6} + 3 a^{2} x^{5} + 3 a x^{4} + x^{3}}\, dx\right )}{a^{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c-c/a/x)**3/(a*x+1)**3*(-a**2*x**2+1)**(3/2),x)

[Out]

c**3*(Integral(-sqrt(-a**2*x**2 + 1)/(a**3*x**6 + 3*a**2*x**5 + 3*a*x**4 + x**3), x) + Integral(3*a*x*sqrt(-a*
*2*x**2 + 1)/(a**3*x**6 + 3*a**2*x**5 + 3*a*x**4 + x**3), x) + Integral(-2*a**2*x**2*sqrt(-a**2*x**2 + 1)/(a**
3*x**6 + 3*a**2*x**5 + 3*a*x**4 + x**3), x) + Integral(-2*a**3*x**3*sqrt(-a**2*x**2 + 1)/(a**3*x**6 + 3*a**2*x
**5 + 3*a*x**4 + x**3), x) + Integral(3*a**4*x**4*sqrt(-a**2*x**2 + 1)/(a**3*x**6 + 3*a**2*x**5 + 3*a*x**4 + x
**3), x) + Integral(-a**5*x**5*sqrt(-a**2*x**2 + 1)/(a**3*x**6 + 3*a**2*x**5 + 3*a*x**4 + x**3), x))/a**3

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Giac [B]  time = 1.17329, size = 358, normalized size = 2.56 \begin{align*} -\frac{6 \, c^{3} \arcsin \left (a x\right ) \mathrm{sgn}\left (a\right )}{{\left | a \right |}} - \frac{{\left (c^{3} - \frac{23 \,{\left (\sqrt{-a^{2} x^{2} + 1}{\left | a \right |} + a\right )} c^{3}}{a^{2} x} - \frac{536 \,{\left (\sqrt{-a^{2} x^{2} + 1}{\left | a \right |} + a\right )}^{2} c^{3}}{a^{4} x^{2}}\right )} a^{4} x^{2}}{8 \,{\left (\sqrt{-a^{2} x^{2} + 1}{\left | a \right |} + a\right )}^{2}{\left (\frac{\sqrt{-a^{2} x^{2} + 1}{\left | a \right |} + a}{a^{2} x} + 1\right )}{\left | a \right |}} + \frac{33 \, c^{3} \log \left (\frac{{\left | -2 \, \sqrt{-a^{2} x^{2} + 1}{\left | a \right |} - 2 \, a \right |}}{2 \, a^{2}{\left | x \right |}}\right )}{2 \,{\left | a \right |}} - \frac{\sqrt{-a^{2} x^{2} + 1} c^{3}}{a} - \frac{\frac{24 \,{\left (\sqrt{-a^{2} x^{2} + 1}{\left | a \right |} + a\right )} c^{3}{\left | a \right |}}{a^{2} x} - \frac{{\left (\sqrt{-a^{2} x^{2} + 1}{\left | a \right |} + a\right )}^{2} c^{3}{\left | a \right |}}{a^{4} x^{2}}}{8 \, a^{2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c-c/a/x)^3/(a*x+1)^3*(-a^2*x^2+1)^(3/2),x, algorithm="giac")

[Out]

-6*c^3*arcsin(a*x)*sgn(a)/abs(a) - 1/8*(c^3 - 23*(sqrt(-a^2*x^2 + 1)*abs(a) + a)*c^3/(a^2*x) - 536*(sqrt(-a^2*
x^2 + 1)*abs(a) + a)^2*c^3/(a^4*x^2))*a^4*x^2/((sqrt(-a^2*x^2 + 1)*abs(a) + a)^2*((sqrt(-a^2*x^2 + 1)*abs(a) +
a)/(a^2*x) + 1)*abs(a)) + 33/2*c^3*log(1/2*abs(-2*sqrt(-a^2*x^2 + 1)*abs(a) - 2*a)/(a^2*abs(x)))/abs(a) - sqr
t(-a^2*x^2 + 1)*c^3/a - 1/8*(24*(sqrt(-a^2*x^2 + 1)*abs(a) + a)*c^3*abs(a)/(a^2*x) - (sqrt(-a^2*x^2 + 1)*abs(a
) + a)^2*c^3*abs(a)/(a^4*x^2))/a^2