Optimal. Leaf size=104 \[ \frac{1}{4 a c^4 \sqrt{c-a c x}}+\frac{1}{6 a c^3 (c-a c x)^{3/2}}+\frac{1}{5 a c^2 (c-a c x)^{5/2}}-\frac{\tanh ^{-1}\left (\frac{\sqrt{c-a c x}}{\sqrt{2} \sqrt{c}}\right )}{4 \sqrt{2} a c^{9/2}} \]
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Rubi [A] time = 0.0817663, antiderivative size = 104, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {6130, 21, 51, 63, 206} \[ \frac{1}{4 a c^4 \sqrt{c-a c x}}+\frac{1}{6 a c^3 (c-a c x)^{3/2}}+\frac{1}{5 a c^2 (c-a c x)^{5/2}}-\frac{\tanh ^{-1}\left (\frac{\sqrt{c-a c x}}{\sqrt{2} \sqrt{c}}\right )}{4 \sqrt{2} a c^{9/2}} \]
Antiderivative was successfully verified.
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Rule 6130
Rule 21
Rule 51
Rule 63
Rule 206
Rubi steps
\begin{align*} \int \frac{e^{-2 \tanh ^{-1}(a x)}}{(c-a c x)^{9/2}} \, dx &=\int \frac{1-a x}{(1+a x) (c-a c x)^{9/2}} \, dx\\ &=\frac{\int \frac{1}{(1+a x) (c-a c x)^{7/2}} \, dx}{c}\\ &=\frac{1}{5 a c^2 (c-a c x)^{5/2}}+\frac{\int \frac{1}{(1+a x) (c-a c x)^{5/2}} \, dx}{2 c^2}\\ &=\frac{1}{5 a c^2 (c-a c x)^{5/2}}+\frac{1}{6 a c^3 (c-a c x)^{3/2}}+\frac{\int \frac{1}{(1+a x) (c-a c x)^{3/2}} \, dx}{4 c^3}\\ &=\frac{1}{5 a c^2 (c-a c x)^{5/2}}+\frac{1}{6 a c^3 (c-a c x)^{3/2}}+\frac{1}{4 a c^4 \sqrt{c-a c x}}+\frac{\int \frac{1}{(1+a x) \sqrt{c-a c x}} \, dx}{8 c^4}\\ &=\frac{1}{5 a c^2 (c-a c x)^{5/2}}+\frac{1}{6 a c^3 (c-a c x)^{3/2}}+\frac{1}{4 a c^4 \sqrt{c-a c x}}-\frac{\operatorname{Subst}\left (\int \frac{1}{2-\frac{x^2}{c}} \, dx,x,\sqrt{c-a c x}\right )}{4 a c^5}\\ &=\frac{1}{5 a c^2 (c-a c x)^{5/2}}+\frac{1}{6 a c^3 (c-a c x)^{3/2}}+\frac{1}{4 a c^4 \sqrt{c-a c x}}-\frac{\tanh ^{-1}\left (\frac{\sqrt{c-a c x}}{\sqrt{2} \sqrt{c}}\right )}{4 \sqrt{2} a c^{9/2}}\\ \end{align*}
Mathematica [C] time = 0.0299514, size = 39, normalized size = 0.38 \[ \frac{\text{Hypergeometric2F1}\left (-\frac{5}{2},1,-\frac{3}{2},\frac{1}{2} (1-a x)\right )}{5 a c^2 (c-a c x)^{5/2}} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.044, size = 78, normalized size = 0.8 \begin{align*} 2\,{\frac{1}{ac} \left ( -1/16\,{\frac{\sqrt{2}}{{c}^{7/2}}{\it Artanh} \left ( 1/2\,{\frac{\sqrt{-acx+c}\sqrt{2}}{\sqrt{c}}} \right ) }+1/8\,{\frac{1}{{c}^{3}\sqrt{-acx+c}}}+1/12\,{\frac{1}{{c}^{2} \left ( -acx+c \right ) ^{3/2}}}+1/10\,{\frac{1}{c \left ( -acx+c \right ) ^{5/2}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.32154, size = 598, normalized size = 5.75 \begin{align*} \left [\frac{15 \, \sqrt{2}{\left (a^{3} x^{3} - 3 \, a^{2} x^{2} + 3 \, a x - 1\right )} \sqrt{c} \log \left (\frac{a c x + 2 \, \sqrt{2} \sqrt{-a c x + c} \sqrt{c} - 3 \, c}{a x + 1}\right ) - 4 \,{\left (15 \, a^{2} x^{2} - 40 \, a x + 37\right )} \sqrt{-a c x + c}}{240 \,{\left (a^{4} c^{5} x^{3} - 3 \, a^{3} c^{5} x^{2} + 3 \, a^{2} c^{5} x - a c^{5}\right )}}, \frac{15 \, \sqrt{2}{\left (a^{3} x^{3} - 3 \, a^{2} x^{2} + 3 \, a x - 1\right )} \sqrt{-c} \arctan \left (\frac{\sqrt{2} \sqrt{-a c x + c} \sqrt{-c}}{2 \, c}\right ) - 2 \,{\left (15 \, a^{2} x^{2} - 40 \, a x + 37\right )} \sqrt{-a c x + c}}{120 \,{\left (a^{4} c^{5} x^{3} - 3 \, a^{3} c^{5} x^{2} + 3 \, a^{2} c^{5} x - a c^{5}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.15584, size = 126, normalized size = 1.21 \begin{align*} \frac{\sqrt{2} \arctan \left (\frac{\sqrt{2} \sqrt{-a c x + c}}{2 \, \sqrt{-c}}\right )}{8 \, a \sqrt{-c} c^{4}} + \frac{15 \,{\left (a c x - c\right )}^{2} - 10 \,{\left (a c x - c\right )} c + 12 \, c^{2}}{60 \,{\left (a c x - c\right )}^{2} \sqrt{-a c x + c} a c^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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