Optimal. Leaf size=222 \[ \frac{(2 p+11) x^3 \left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p \text{Hypergeometric2F1}\left (\frac{3}{2},\frac{3}{2}-p,\frac{5}{2},a^2 x^2\right )}{6 (p+1)}-\frac{\left (1-a^2 x^2\right )^{3/2} \left (c-a^2 c x^2\right )^p}{a^3 (2 p+3)}+\frac{5 \sqrt{1-a^2 x^2} \left (c-a^2 c x^2\right )^p}{a^3 (2 p+1)}-\frac{3 x^3 \left (c-a^2 c x^2\right )^p}{2 (p+1) \sqrt{1-a^2 x^2}}+\frac{4 \left (c-a^2 c x^2\right )^p}{a^3 (1-2 p) \sqrt{1-a^2 x^2}} \]
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Rubi [A] time = 0.339021, antiderivative size = 222, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.28, Rules used = {6153, 6148, 1652, 459, 364, 446, 77} \[ \frac{(2 p+11) x^3 \left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p \, _2F_1\left (\frac{3}{2},\frac{3}{2}-p;\frac{5}{2};a^2 x^2\right )}{6 (p+1)}-\frac{\left (1-a^2 x^2\right )^{3/2} \left (c-a^2 c x^2\right )^p}{a^3 (2 p+3)}+\frac{5 \sqrt{1-a^2 x^2} \left (c-a^2 c x^2\right )^p}{a^3 (2 p+1)}-\frac{3 x^3 \left (c-a^2 c x^2\right )^p}{2 (p+1) \sqrt{1-a^2 x^2}}+\frac{4 \left (c-a^2 c x^2\right )^p}{a^3 (1-2 p) \sqrt{1-a^2 x^2}} \]
Antiderivative was successfully verified.
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Rule 6153
Rule 6148
Rule 1652
Rule 459
Rule 364
Rule 446
Rule 77
Rubi steps
\begin{align*} \int e^{3 \tanh ^{-1}(a x)} x^2 \left (c-a^2 c x^2\right )^p \, dx &=\left (\left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p\right ) \int e^{3 \tanh ^{-1}(a x)} x^2 \left (1-a^2 x^2\right )^p \, dx\\ &=\left (\left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p\right ) \int x^2 (1+a x)^3 \left (1-a^2 x^2\right )^{-\frac{3}{2}+p} \, dx\\ &=\left (\left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p\right ) \int x^2 \left (1-a^2 x^2\right )^{-\frac{3}{2}+p} \left (1+3 a^2 x^2\right ) \, dx+\left (\left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p\right ) \int x^3 \left (1-a^2 x^2\right )^{-\frac{3}{2}+p} \left (3 a+a^3 x^2\right ) \, dx\\ &=-\frac{3 x^3 \left (c-a^2 c x^2\right )^p}{2 (1+p) \sqrt{1-a^2 x^2}}+\frac{1}{2} \left (\left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p\right ) \operatorname{Subst}\left (\int x \left (1-a^2 x\right )^{-\frac{3}{2}+p} \left (3 a+a^3 x\right ) \, dx,x,x^2\right )+\frac{\left ((11+2 p) \left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p\right ) \int x^2 \left (1-a^2 x^2\right )^{-\frac{3}{2}+p} \, dx}{2 (1+p)}\\ &=-\frac{3 x^3 \left (c-a^2 c x^2\right )^p}{2 (1+p) \sqrt{1-a^2 x^2}}+\frac{(11+2 p) x^3 \left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p \, _2F_1\left (\frac{3}{2},\frac{3}{2}-p;\frac{5}{2};a^2 x^2\right )}{6 (1+p)}+\frac{1}{2} \left (\left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p\right ) \operatorname{Subst}\left (\int \left (\frac{4 \left (1-a^2 x\right )^{-\frac{3}{2}+p}}{a}-\frac{5 \left (1-a^2 x\right )^{-\frac{1}{2}+p}}{a}+\frac{\left (1-a^2 x\right )^{\frac{1}{2}+p}}{a}\right ) \, dx,x,x^2\right )\\ &=\frac{4 \left (c-a^2 c x^2\right )^p}{a^3 (1-2 p) \sqrt{1-a^2 x^2}}-\frac{3 x^3 \left (c-a^2 c x^2\right )^p}{2 (1+p) \sqrt{1-a^2 x^2}}+\frac{5 \sqrt{1-a^2 x^2} \left (c-a^2 c x^2\right )^p}{a^3 (1+2 p)}-\frac{\left (1-a^2 x^2\right )^{3/2} \left (c-a^2 c x^2\right )^p}{a^3 (3+2 p)}+\frac{(11+2 p) x^3 \left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p \, _2F_1\left (\frac{3}{2},\frac{3}{2}-p;\frac{5}{2};a^2 x^2\right )}{6 (1+p)}\\ \end{align*}
Mathematica [A] time = 0.230338, size = 179, normalized size = 0.81 \[ \left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p \left (\frac{1}{3} x^3 \text{Hypergeometric2F1}\left (\frac{3}{2},\frac{3}{2}-p,\frac{5}{2},a^2 x^2\right )+\frac{3}{5} a^2 x^5 \text{Hypergeometric2F1}\left (\frac{5}{2},\frac{3}{2}-p,\frac{7}{2},a^2 x^2\right )+\frac{\left (-4 a^2 p^2 x^2 \left (a^2 x^2+3\right )-4 p \left (5 a^2 x^2+3\right )+a^4 x^4+13 a^2 x^2-26\right ) \left (1-a^2 x^2\right )^{p-\frac{1}{2}}}{a^3 (2 p-1) (2 p+1) (2 p+3)}\right ) \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.404, size = 0, normalized size = 0. \begin{align*} \int{ \left ( ax+1 \right ) ^{3}{x}^{2} \left ( -{a}^{2}c{x}^{2}+c \right ) ^{p} \left ( -{a}^{2}{x}^{2}+1 \right ) ^{-{\frac{3}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a x + 1\right )}^{3}{\left (-a^{2} c x^{2} + c\right )}^{p} x^{2}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{-a^{2} x^{2} + 1}{\left (a x^{3} + x^{2}\right )}{\left (-a^{2} c x^{2} + c\right )}^{p}}{a^{2} x^{2} - 2 \, a x + 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2} \left (- c \left (a x - 1\right ) \left (a x + 1\right )\right )^{p} \left (a x + 1\right )^{3}}{\left (- \left (a x - 1\right ) \left (a x + 1\right )\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a x + 1\right )}^{3}{\left (-a^{2} c x^{2} + c\right )}^{p} x^{2}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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