3.1043 \(\int e^{2 \tanh ^{-1}(a x)} (c-a^2 c x^2)^3 \, dx\)

Optimal. Leaf size=52 \[ \frac{c^3 (a x+1)^7}{7 a}-\frac{2 c^3 (a x+1)^6}{3 a}+\frac{4 c^3 (a x+1)^5}{5 a} \]

[Out]

(4*c^3*(1 + a*x)^5)/(5*a) - (2*c^3*(1 + a*x)^6)/(3*a) + (c^3*(1 + a*x)^7)/(7*a)

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Rubi [A]  time = 0.0499648, antiderivative size = 52, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.091, Rules used = {6140, 43} \[ \frac{c^3 (a x+1)^7}{7 a}-\frac{2 c^3 (a x+1)^6}{3 a}+\frac{4 c^3 (a x+1)^5}{5 a} \]

Antiderivative was successfully verified.

[In]

Int[E^(2*ArcTanh[a*x])*(c - a^2*c*x^2)^3,x]

[Out]

(4*c^3*(1 + a*x)^5)/(5*a) - (2*c^3*(1 + a*x)^6)/(3*a) + (c^3*(1 + a*x)^7)/(7*a)

Rule 6140

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[c^p, Int[(1 - a*x)^(p - n/2)*
(1 + a*x)^(p + n/2), x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[a^2*c + d, 0] && (IntegerQ[p] || GtQ[c, 0])

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin{align*} \int e^{2 \tanh ^{-1}(a x)} \left (c-a^2 c x^2\right )^3 \, dx &=c^3 \int (1-a x)^2 (1+a x)^4 \, dx\\ &=c^3 \int \left (4 (1+a x)^4-4 (1+a x)^5+(1+a x)^6\right ) \, dx\\ &=\frac{4 c^3 (1+a x)^5}{5 a}-\frac{2 c^3 (1+a x)^6}{3 a}+\frac{c^3 (1+a x)^7}{7 a}\\ \end{align*}

Mathematica [A]  time = 0.0211414, size = 31, normalized size = 0.6 \[ \frac{c^3 (a x+1)^5 \left (15 a^2 x^2-40 a x+29\right )}{105 a} \]

Antiderivative was successfully verified.

[In]

Integrate[E^(2*ArcTanh[a*x])*(c - a^2*c*x^2)^3,x]

[Out]

(c^3*(1 + a*x)^5*(29 - 40*a*x + 15*a^2*x^2))/(105*a)

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Maple [A]  time = 0.025, size = 52, normalized size = 1. \begin{align*}{c}^{3} \left ({\frac{{x}^{7}{a}^{6}}{7}}+{\frac{{x}^{6}{a}^{5}}{3}}-{\frac{{x}^{5}{a}^{4}}{5}}-{x}^{4}{a}^{3}-{\frac{{x}^{3}{a}^{2}}{3}}+a{x}^{2}+x \right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^3,x)

[Out]

c^3*(1/7*x^7*a^6+1/3*x^6*a^5-1/5*x^5*a^4-x^4*a^3-1/3*x^3*a^2+a*x^2+x)

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Maxima [A]  time = 0.963406, size = 93, normalized size = 1.79 \begin{align*} \frac{1}{7} \, a^{6} c^{3} x^{7} + \frac{1}{3} \, a^{5} c^{3} x^{6} - \frac{1}{5} \, a^{4} c^{3} x^{5} - a^{3} c^{3} x^{4} - \frac{1}{3} \, a^{2} c^{3} x^{3} + a c^{3} x^{2} + c^{3} x \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^3,x, algorithm="maxima")

[Out]

1/7*a^6*c^3*x^7 + 1/3*a^5*c^3*x^6 - 1/5*a^4*c^3*x^5 - a^3*c^3*x^4 - 1/3*a^2*c^3*x^3 + a*c^3*x^2 + c^3*x

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Fricas [A]  time = 1.68886, size = 142, normalized size = 2.73 \begin{align*} \frac{1}{7} \, a^{6} c^{3} x^{7} + \frac{1}{3} \, a^{5} c^{3} x^{6} - \frac{1}{5} \, a^{4} c^{3} x^{5} - a^{3} c^{3} x^{4} - \frac{1}{3} \, a^{2} c^{3} x^{3} + a c^{3} x^{2} + c^{3} x \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^3,x, algorithm="fricas")

[Out]

1/7*a^6*c^3*x^7 + 1/3*a^5*c^3*x^6 - 1/5*a^4*c^3*x^5 - a^3*c^3*x^4 - 1/3*a^2*c^3*x^3 + a*c^3*x^2 + c^3*x

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Sympy [A]  time = 0.108122, size = 70, normalized size = 1.35 \begin{align*} \frac{a^{6} c^{3} x^{7}}{7} + \frac{a^{5} c^{3} x^{6}}{3} - \frac{a^{4} c^{3} x^{5}}{5} - a^{3} c^{3} x^{4} - \frac{a^{2} c^{3} x^{3}}{3} + a c^{3} x^{2} + c^{3} x \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)**2/(-a**2*x**2+1)*(-a**2*c*x**2+c)**3,x)

[Out]

a**6*c**3*x**7/7 + a**5*c**3*x**6/3 - a**4*c**3*x**5/5 - a**3*c**3*x**4 - a**2*c**3*x**3/3 + a*c**3*x**2 + c**
3*x

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Giac [A]  time = 1.12947, size = 93, normalized size = 1.79 \begin{align*} \frac{1}{7} \, a^{6} c^{3} x^{7} + \frac{1}{3} \, a^{5} c^{3} x^{6} - \frac{1}{5} \, a^{4} c^{3} x^{5} - a^{3} c^{3} x^{4} - \frac{1}{3} \, a^{2} c^{3} x^{3} + a c^{3} x^{2} + c^{3} x \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^3,x, algorithm="giac")

[Out]

1/7*a^6*c^3*x^7 + 1/3*a^5*c^3*x^6 - 1/5*a^4*c^3*x^5 - a^3*c^3*x^4 - 1/3*a^2*c^3*x^3 + a*c^3*x^2 + c^3*x