Optimal. Leaf size=113 \[ -\frac{\left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p \text{Hypergeometric2F1}\left (-\frac{1}{2},\frac{1}{2}-p,\frac{1}{2},a^2 x^2\right )}{x}-\frac{a \sqrt{1-a^2 x^2} \left (c-a^2 c x^2\right )^p \text{Hypergeometric2F1}\left (1,p+\frac{1}{2},p+\frac{3}{2},1-a^2 x^2\right )}{2 p+1} \]
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Rubi [A] time = 0.166599, antiderivative size = 113, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.261, Rules used = {6153, 6148, 764, 364, 266, 65} \[ -\frac{\left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p \, _2F_1\left (-\frac{1}{2},\frac{1}{2}-p;\frac{1}{2};a^2 x^2\right )}{x}-\frac{a \sqrt{1-a^2 x^2} \left (c-a^2 c x^2\right )^p \, _2F_1\left (1,p+\frac{1}{2};p+\frac{3}{2};1-a^2 x^2\right )}{2 p+1} \]
Antiderivative was successfully verified.
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Rule 6153
Rule 6148
Rule 764
Rule 364
Rule 266
Rule 65
Rubi steps
\begin{align*} \int \frac{e^{\tanh ^{-1}(a x)} \left (c-a^2 c x^2\right )^p}{x^2} \, dx &=\left (\left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p\right ) \int \frac{e^{\tanh ^{-1}(a x)} \left (1-a^2 x^2\right )^p}{x^2} \, dx\\ &=\left (\left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p\right ) \int \frac{(1+a x) \left (1-a^2 x^2\right )^{-\frac{1}{2}+p}}{x^2} \, dx\\ &=\left (\left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p\right ) \int \frac{\left (1-a^2 x^2\right )^{-\frac{1}{2}+p}}{x^2} \, dx+\left (a \left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p\right ) \int \frac{\left (1-a^2 x^2\right )^{-\frac{1}{2}+p}}{x} \, dx\\ &=-\frac{\left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p \, _2F_1\left (-\frac{1}{2},\frac{1}{2}-p;\frac{1}{2};a^2 x^2\right )}{x}+\frac{1}{2} \left (a \left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p\right ) \operatorname{Subst}\left (\int \frac{\left (1-a^2 x\right )^{-\frac{1}{2}+p}}{x} \, dx,x,x^2\right )\\ &=-\frac{\left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p \, _2F_1\left (-\frac{1}{2},\frac{1}{2}-p;\frac{1}{2};a^2 x^2\right )}{x}-\frac{a \sqrt{1-a^2 x^2} \left (c-a^2 c x^2\right )^p \, _2F_1\left (1,\frac{1}{2}+p;\frac{3}{2}+p;1-a^2 x^2\right )}{1+2 p}\\ \end{align*}
Mathematica [A] time = 0.0361945, size = 105, normalized size = 0.93 \[ \left (1-a^2 x^2\right )^{-p} \left (c-a^2 c x^2\right )^p \left (-\frac{a \left (1-a^2 x^2\right )^{p+\frac{1}{2}} \text{Hypergeometric2F1}\left (1,p+\frac{1}{2},p+\frac{3}{2},1-a^2 x^2\right )}{2 \left (p+\frac{1}{2}\right )}-\frac{\text{Hypergeometric2F1}\left (-\frac{1}{2},\frac{1}{2}-p,\frac{1}{2},a^2 x^2\right )}{x}\right ) \]
Antiderivative was successfully verified.
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Maple [F] time = 0.328, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( ax+1 \right ) \left ( -{a}^{2}c{x}^{2}+c \right ) ^{p}}{{x}^{2}}{\frac{1}{\sqrt{-{a}^{2}{x}^{2}+1}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a x + 1\right )}{\left (-a^{2} c x^{2} + c\right )}^{p}}{\sqrt{-a^{2} x^{2} + 1} x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{\sqrt{-a^{2} x^{2} + 1}{\left (-a^{2} c x^{2} + c\right )}^{p}}{a x^{3} - x^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 16.23, size = 294, normalized size = 2.6 \begin{align*} - \frac{a a^{2 p} c^{p} x^{2 p} e^{i \pi p} \Gamma \left (- p\right ) \Gamma \left (p + \frac{1}{2}\right ){{}_{3}F_{2}\left (\begin{matrix} \frac{1}{2}, 1, p \\ p + 1, p + 1 \end{matrix}\middle |{a^{2} x^{2} e^{2 i \pi }} \right )}}{2 \sqrt{\pi } \Gamma \left (1 - p\right ) \Gamma \left (p + 1\right )} - \frac{a a^{2 p} c^{p} x^{2 p} e^{i \pi p} \Gamma \left (- p\right ) \Gamma \left (p + \frac{1}{2}\right ){{}_{3}F_{2}\left (\begin{matrix} 1, - p, - p \\ \frac{1}{2}, 1 - p \end{matrix}\middle |{\frac{1}{a^{2} x^{2}}} \right )}}{2 \sqrt{\pi } \Gamma \left (1 - p\right ) \Gamma \left (p + 1\right )} - \frac{a^{2 p} c^{p} x^{2 p} e^{i \pi p} \Gamma \left (\frac{1}{2} - p\right ) \Gamma \left (p + \frac{1}{2}\right ){{}_{3}F_{2}\left (\begin{matrix} \frac{1}{2}, 1, p - \frac{1}{2} \\ p + \frac{1}{2}, p + 1 \end{matrix}\middle |{a^{2} x^{2} e^{2 i \pi }} \right )}}{2 \sqrt{\pi } x \Gamma \left (\frac{3}{2} - p\right ) \Gamma \left (p + 1\right )} - \frac{a^{2 p} c^{p} x^{2 p} e^{i \pi p} \Gamma \left (\frac{1}{2} - p\right ) \Gamma \left (p + \frac{1}{2}\right ){{}_{3}F_{2}\left (\begin{matrix} 1, - p, \frac{1}{2} - p \\ \frac{1}{2}, \frac{3}{2} - p \end{matrix}\middle |{\frac{1}{a^{2} x^{2}}} \right )}}{2 \sqrt{\pi } x \Gamma \left (\frac{3}{2} - p\right ) \Gamma \left (p + 1\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a x + 1\right )}{\left (-a^{2} c x^{2} + c\right )}^{p}}{\sqrt{-a^{2} x^{2} + 1} x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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