Optimal. Leaf size=58 \[ \frac{1}{3} a x^3 \text{Hypergeometric2F1}\left (\frac{3}{2},\frac{1}{2}-p,\frac{5}{2},a^2 x^2\right )-\frac{\left (1-a^2 x^2\right )^{p+\frac{1}{2}}}{a^2 (2 p+1)} \]
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Rubi [A] time = 0.0613426, antiderivative size = 58, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {6148, 764, 261, 364} \[ \frac{1}{3} a x^3 \, _2F_1\left (\frac{3}{2},\frac{1}{2}-p;\frac{5}{2};a^2 x^2\right )-\frac{\left (1-a^2 x^2\right )^{p+\frac{1}{2}}}{a^2 (2 p+1)} \]
Antiderivative was successfully verified.
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Rule 6148
Rule 764
Rule 261
Rule 364
Rubi steps
\begin{align*} \int e^{\tanh ^{-1}(a x)} x \left (1-a^2 x^2\right )^p \, dx &=\int x (1+a x) \left (1-a^2 x^2\right )^{-\frac{1}{2}+p} \, dx\\ &=a \int x^2 \left (1-a^2 x^2\right )^{-\frac{1}{2}+p} \, dx+\int x \left (1-a^2 x^2\right )^{-\frac{1}{2}+p} \, dx\\ &=-\frac{\left (1-a^2 x^2\right )^{\frac{1}{2}+p}}{a^2 (1+2 p)}+\frac{1}{3} a x^3 \, _2F_1\left (\frac{3}{2},\frac{1}{2}-p;\frac{5}{2};a^2 x^2\right )\\ \end{align*}
Mathematica [A] time = 0.0238248, size = 60, normalized size = 1.03 \[ \frac{1}{3} a x^3 \text{Hypergeometric2F1}\left (\frac{3}{2},\frac{1}{2}-p,\frac{5}{2},a^2 x^2\right )-\frac{\left (1-a^2 x^2\right )^{p+\frac{1}{2}}}{2 a^2 \left (p+\frac{1}{2}\right )} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.342, size = 47, normalized size = 0.8 \begin{align*}{\frac{{x}^{3}a}{3}{\mbox{$_2$F$_1$}({\frac{3}{2}},{\frac{1}{2}}-p;\,{\frac{5}{2}};\,{a}^{2}{x}^{2})}}+{\frac{{x}^{2}}{2}{\mbox{$_2$F$_1$}(1,{\frac{1}{2}}-p;\,2;\,{a}^{2}{x}^{2})}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{\sqrt{-a^{2} x^{2} + 1}{\left (-a^{2} x^{2} + 1\right )}^{p} x}{a x - 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 13.3856, size = 301, normalized size = 5.19 \begin{align*} - \frac{a a^{2 p} x^{3} x^{2 p} e^{i \pi p} \Gamma \left (- p - \frac{3}{2}\right ) \Gamma \left (p + \frac{1}{2}\right ){{}_{3}F_{2}\left (\begin{matrix} \frac{1}{2}, 1, p + \frac{3}{2} \\ p + 1, p + \frac{5}{2} \end{matrix}\middle |{a^{2} x^{2} e^{2 i \pi }} \right )}}{2 \sqrt{\pi } \Gamma \left (- p - \frac{1}{2}\right ) \Gamma \left (p + 1\right )} - \frac{a a^{2 p} x^{3} x^{2 p} e^{i \pi p} \Gamma \left (- p - \frac{3}{2}\right ) \Gamma \left (p + \frac{1}{2}\right ){{}_{3}F_{2}\left (\begin{matrix} 1, - p, - p - \frac{3}{2} \\ \frac{1}{2}, - p - \frac{1}{2} \end{matrix}\middle |{\frac{1}{a^{2} x^{2}}} \right )}}{2 \sqrt{\pi } \Gamma \left (- p - \frac{1}{2}\right ) \Gamma \left (p + 1\right )} - \frac{a^{2 p} x^{2} x^{2 p} e^{i \pi p} \Gamma \left (- p - 1\right ) \Gamma \left (p + \frac{1}{2}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{1}{2}, 1 \\ p + 2 \end{matrix}\middle |{a^{2} x^{2} e^{2 i \pi }} \right )}}{2 \sqrt{\pi } \Gamma \left (- p\right ) \Gamma \left (p + 1\right )} - \frac{a^{2 p} x^{2} x^{2 p} e^{i \pi p} \Gamma \left (- p - 1\right ) \Gamma \left (p + \frac{1}{2}\right ){{}_{2}F_{1}\left (\begin{matrix} 1, - p - 1 \\ \frac{1}{2} \end{matrix}\middle |{\frac{1}{a^{2} x^{2}}} \right )}}{2 \sqrt{\pi } \Gamma \left (- p\right ) \Gamma \left (p + 1\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a x + 1\right )}{\left (-a^{2} x^{2} + 1\right )}^{p} x}{\sqrt{-a^{2} x^{2} + 1}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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