Optimal. Leaf size=153 \[ -\frac{16 b^2 (e (c+d x))^{7/2} \text{HypergeometricPFQ}\left (\left \{1,\frac{7}{4},\frac{7}{4}\right \},\left \{\frac{9}{4},\frac{11}{4}\right \},(c+d x)^2\right )}{105 d e^3}-\frac{8 b \sqrt{-c-d x+1} (e (c+d x))^{5/2} \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{5}{4},\frac{9}{4},(c+d x)^2\right ) \left (a+b \cosh ^{-1}(c+d x)\right )}{15 d e^2 \sqrt{c+d x-1}}+\frac{2 (e (c+d x))^{3/2} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{3 d e} \]
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Rubi [A] time = 0.315728, antiderivative size = 165, normalized size of antiderivative = 1.08, number of steps used = 3, number of rules used = 3, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.12, Rules used = {5866, 5662, 5763} \[ -\frac{16 b^2 (e (c+d x))^{7/2} \, _3F_2\left (1,\frac{7}{4},\frac{7}{4};\frac{9}{4},\frac{11}{4};(c+d x)^2\right )}{105 d e^3}-\frac{8 b \sqrt{1-(c+d x)^2} (e (c+d x))^{5/2} \, _2F_1\left (\frac{1}{2},\frac{5}{4};\frac{9}{4};(c+d x)^2\right ) \left (a+b \cosh ^{-1}(c+d x)\right )}{15 d e^2 \sqrt{c+d x-1} \sqrt{c+d x+1}}+\frac{2 (e (c+d x))^{3/2} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{3 d e} \]
Antiderivative was successfully verified.
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Rule 5866
Rule 5662
Rule 5763
Rubi steps
\begin{align*} \int \sqrt{c e+d e x} \left (a+b \cosh ^{-1}(c+d x)\right )^2 \, dx &=\frac{\operatorname{Subst}\left (\int \sqrt{e x} \left (a+b \cosh ^{-1}(x)\right )^2 \, dx,x,c+d x\right )}{d}\\ &=\frac{2 (e (c+d x))^{3/2} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{3 d e}-\frac{(4 b) \operatorname{Subst}\left (\int \frac{(e x)^{3/2} \left (a+b \cosh ^{-1}(x)\right )}{\sqrt{-1+x} \sqrt{1+x}} \, dx,x,c+d x\right )}{3 d e}\\ &=\frac{2 (e (c+d x))^{3/2} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{3 d e}-\frac{8 b (e (c+d x))^{5/2} \sqrt{1-(c+d x)^2} \left (a+b \cosh ^{-1}(c+d x)\right ) \, _2F_1\left (\frac{1}{2},\frac{5}{4};\frac{9}{4};(c+d x)^2\right )}{15 d e^2 \sqrt{-1+c+d x} \sqrt{1+c+d x}}-\frac{16 b^2 (e (c+d x))^{7/2} \, _3F_2\left (1,\frac{7}{4},\frac{7}{4};\frac{9}{4},\frac{11}{4};(c+d x)^2\right )}{105 d e^3}\\ \end{align*}
Mathematica [A] time = 0.435795, size = 140, normalized size = 0.92 \[ \frac{2 (e (c+d x))^{3/2} \left (35 \left (a+b \cosh ^{-1}(c+d x)\right )^2-4 b (c+d x) \left (2 b (c+d x) \text{HypergeometricPFQ}\left (\left \{1,\frac{7}{4},\frac{7}{4}\right \},\left \{\frac{9}{4},\frac{11}{4}\right \},(c+d x)^2\right )+\frac{7 \sqrt{1-(c+d x)^2} \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{5}{4},\frac{9}{4},(c+d x)^2\right ) \left (a+b \cosh ^{-1}(c+d x)\right )}{\sqrt{c+d x-1} \sqrt{c+d x+1}}\right )\right )}{105 d e} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.37, size = 0, normalized size = 0. \begin{align*} \int \left ( a+b{\rm arccosh} \left (dx+c\right ) \right ) ^{2}\sqrt{dex+ce}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (b^{2} \operatorname{arcosh}\left (d x + c\right )^{2} + 2 \, a b \operatorname{arcosh}\left (d x + c\right ) + a^{2}\right )} \sqrt{d e x + c e}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{e \left (c + d x\right )} \left (a + b \operatorname{acosh}{\left (c + d x \right )}\right )^{2}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{d e x + c e}{\left (b \operatorname{arcosh}\left (d x + c\right ) + a\right )}^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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