Optimal. Leaf size=264 \[ \frac{24 i b^3 \text{PolyLog}\left (3,-i e^{\cosh ^{-1}(c+d x)}\right ) \left (a+b \cosh ^{-1}(c+d x)\right )}{d e^2}-\frac{24 i b^3 \text{PolyLog}\left (3,i e^{\cosh ^{-1}(c+d x)}\right ) \left (a+b \cosh ^{-1}(c+d x)\right )}{d e^2}-\frac{12 i b^2 \text{PolyLog}\left (2,-i e^{\cosh ^{-1}(c+d x)}\right ) \left (a+b \cosh ^{-1}(c+d x)\right )^2}{d e^2}+\frac{12 i b^2 \text{PolyLog}\left (2,i e^{\cosh ^{-1}(c+d x)}\right ) \left (a+b \cosh ^{-1}(c+d x)\right )^2}{d e^2}-\frac{24 i b^4 \text{PolyLog}\left (4,-i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}+\frac{24 i b^4 \text{PolyLog}\left (4,i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}-\frac{\left (a+b \cosh ^{-1}(c+d x)\right )^4}{d e^2 (c+d x)}+\frac{8 b \tan ^{-1}\left (e^{\cosh ^{-1}(c+d x)}\right ) \left (a+b \cosh ^{-1}(c+d x)\right )^3}{d e^2} \]
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Rubi [A] time = 0.412514, antiderivative size = 264, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 9, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.391, Rules used = {5866, 12, 5662, 5761, 4180, 2531, 6609, 2282, 6589} \[ \frac{24 i b^3 \text{PolyLog}\left (3,-i e^{\cosh ^{-1}(c+d x)}\right ) \left (a+b \cosh ^{-1}(c+d x)\right )}{d e^2}-\frac{24 i b^3 \text{PolyLog}\left (3,i e^{\cosh ^{-1}(c+d x)}\right ) \left (a+b \cosh ^{-1}(c+d x)\right )}{d e^2}-\frac{12 i b^2 \text{PolyLog}\left (2,-i e^{\cosh ^{-1}(c+d x)}\right ) \left (a+b \cosh ^{-1}(c+d x)\right )^2}{d e^2}+\frac{12 i b^2 \text{PolyLog}\left (2,i e^{\cosh ^{-1}(c+d x)}\right ) \left (a+b \cosh ^{-1}(c+d x)\right )^2}{d e^2}-\frac{24 i b^4 \text{PolyLog}\left (4,-i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}+\frac{24 i b^4 \text{PolyLog}\left (4,i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}-\frac{\left (a+b \cosh ^{-1}(c+d x)\right )^4}{d e^2 (c+d x)}+\frac{8 b \tan ^{-1}\left (e^{\cosh ^{-1}(c+d x)}\right ) \left (a+b \cosh ^{-1}(c+d x)\right )^3}{d e^2} \]
Antiderivative was successfully verified.
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Rule 5866
Rule 12
Rule 5662
Rule 5761
Rule 4180
Rule 2531
Rule 6609
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int \frac{\left (a+b \cosh ^{-1}(c+d x)\right )^4}{(c e+d e x)^2} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (a+b \cosh ^{-1}(x)\right )^4}{e^2 x^2} \, dx,x,c+d x\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \frac{\left (a+b \cosh ^{-1}(x)\right )^4}{x^2} \, dx,x,c+d x\right )}{d e^2}\\ &=-\frac{\left (a+b \cosh ^{-1}(c+d x)\right )^4}{d e^2 (c+d x)}+\frac{(4 b) \operatorname{Subst}\left (\int \frac{\left (a+b \cosh ^{-1}(x)\right )^3}{\sqrt{-1+x} x \sqrt{1+x}} \, dx,x,c+d x\right )}{d e^2}\\ &=-\frac{\left (a+b \cosh ^{-1}(c+d x)\right )^4}{d e^2 (c+d x)}+\frac{(4 b) \operatorname{Subst}\left (\int (a+b x)^3 \text{sech}(x) \, dx,x,\cosh ^{-1}(c+d x)\right )}{d e^2}\\ &=-\frac{\left (a+b \cosh ^{-1}(c+d x)\right )^4}{d e^2 (c+d x)}+\frac{8 b \left (a+b \cosh ^{-1}(c+d x)\right )^3 \tan ^{-1}\left (e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}-\frac{\left (12 i b^2\right ) \operatorname{Subst}\left (\int (a+b x)^2 \log \left (1-i e^x\right ) \, dx,x,\cosh ^{-1}(c+d x)\right )}{d e^2}+\frac{\left (12 i b^2\right ) \operatorname{Subst}\left (\int (a+b x)^2 \log \left (1+i e^x\right ) \, dx,x,\cosh ^{-1}(c+d x)\right )}{d e^2}\\ &=-\frac{\left (a+b \cosh ^{-1}(c+d x)\right )^4}{d e^2 (c+d x)}+\frac{8 b \left (a+b \cosh ^{-1}(c+d x)\right )^3 \tan ^{-1}\left (e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}-\frac{12 i b^2 \left (a+b \cosh ^{-1}(c+d x)\right )^2 \text{Li}_2\left (-i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}+\frac{12 i b^2 \left (a+b \cosh ^{-1}(c+d x)\right )^2 \text{Li}_2\left (i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}+\frac{\left (24 i b^3\right ) \operatorname{Subst}\left (\int (a+b x) \text{Li}_2\left (-i e^x\right ) \, dx,x,\cosh ^{-1}(c+d x)\right )}{d e^2}-\frac{\left (24 i b^3\right ) \operatorname{Subst}\left (\int (a+b x) \text{Li}_2\left (i e^x\right ) \, dx,x,\cosh ^{-1}(c+d x)\right )}{d e^2}\\ &=-\frac{\left (a+b \cosh ^{-1}(c+d x)\right )^4}{d e^2 (c+d x)}+\frac{8 b \left (a+b \cosh ^{-1}(c+d x)\right )^3 \tan ^{-1}\left (e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}-\frac{12 i b^2 \left (a+b \cosh ^{-1}(c+d x)\right )^2 \text{Li}_2\left (-i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}+\frac{12 i b^2 \left (a+b \cosh ^{-1}(c+d x)\right )^2 \text{Li}_2\left (i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}+\frac{24 i b^3 \left (a+b \cosh ^{-1}(c+d x)\right ) \text{Li}_3\left (-i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}-\frac{24 i b^3 \left (a+b \cosh ^{-1}(c+d x)\right ) \text{Li}_3\left (i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}-\frac{\left (24 i b^4\right ) \operatorname{Subst}\left (\int \text{Li}_3\left (-i e^x\right ) \, dx,x,\cosh ^{-1}(c+d x)\right )}{d e^2}+\frac{\left (24 i b^4\right ) \operatorname{Subst}\left (\int \text{Li}_3\left (i e^x\right ) \, dx,x,\cosh ^{-1}(c+d x)\right )}{d e^2}\\ &=-\frac{\left (a+b \cosh ^{-1}(c+d x)\right )^4}{d e^2 (c+d x)}+\frac{8 b \left (a+b \cosh ^{-1}(c+d x)\right )^3 \tan ^{-1}\left (e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}-\frac{12 i b^2 \left (a+b \cosh ^{-1}(c+d x)\right )^2 \text{Li}_2\left (-i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}+\frac{12 i b^2 \left (a+b \cosh ^{-1}(c+d x)\right )^2 \text{Li}_2\left (i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}+\frac{24 i b^3 \left (a+b \cosh ^{-1}(c+d x)\right ) \text{Li}_3\left (-i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}-\frac{24 i b^3 \left (a+b \cosh ^{-1}(c+d x)\right ) \text{Li}_3\left (i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}-\frac{\left (24 i b^4\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_3(-i x)}{x} \, dx,x,e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}+\frac{\left (24 i b^4\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_3(i x)}{x} \, dx,x,e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}\\ &=-\frac{\left (a+b \cosh ^{-1}(c+d x)\right )^4}{d e^2 (c+d x)}+\frac{8 b \left (a+b \cosh ^{-1}(c+d x)\right )^3 \tan ^{-1}\left (e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}-\frac{12 i b^2 \left (a+b \cosh ^{-1}(c+d x)\right )^2 \text{Li}_2\left (-i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}+\frac{12 i b^2 \left (a+b \cosh ^{-1}(c+d x)\right )^2 \text{Li}_2\left (i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}+\frac{24 i b^3 \left (a+b \cosh ^{-1}(c+d x)\right ) \text{Li}_3\left (-i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}-\frac{24 i b^3 \left (a+b \cosh ^{-1}(c+d x)\right ) \text{Li}_3\left (i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}-\frac{24 i b^4 \text{Li}_4\left (-i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}+\frac{24 i b^4 \text{Li}_4\left (i e^{\cosh ^{-1}(c+d x)}\right )}{d e^2}\\ \end{align*}
Mathematica [B] time = 2.34485, size = 872, normalized size = 3.3 \[ \frac{-\frac{a^4}{c+d x}+4 b \left (2 \tan ^{-1}\left (\tanh \left (\frac{1}{2} \cosh ^{-1}(c+d x)\right )\right )-\frac{\cosh ^{-1}(c+d x)}{c+d x}\right ) a^3-6 i b^2 \left (\cosh ^{-1}(c+d x) \left (-\frac{i \cosh ^{-1}(c+d x)}{c+d x}+2 \log \left (1-i e^{-\cosh ^{-1}(c+d x)}\right )-2 \log \left (1+i e^{-\cosh ^{-1}(c+d x)}\right )\right )+2 \text{PolyLog}\left (2,-i e^{-\cosh ^{-1}(c+d x)}\right )-2 \text{PolyLog}\left (2,i e^{-\cosh ^{-1}(c+d x)}\right )\right ) a^2+4 b^3 \left (3 i \left (-\left (\log \left (1-i e^{-\cosh ^{-1}(c+d x)}\right )-\log \left (1+i e^{-\cosh ^{-1}(c+d x)}\right )\right ) \cosh ^{-1}(c+d x)^2-2 \left (\text{PolyLog}\left (2,-i e^{-\cosh ^{-1}(c+d x)}\right )-\text{PolyLog}\left (2,i e^{-\cosh ^{-1}(c+d x)}\right )\right ) \cosh ^{-1}(c+d x)-2 \text{PolyLog}\left (3,-i e^{-\cosh ^{-1}(c+d x)}\right )+2 \text{PolyLog}\left (3,i e^{-\cosh ^{-1}(c+d x)}\right )\right )-\frac{\cosh ^{-1}(c+d x)^3}{c+d x}\right ) a+b^4 \left (-\frac{\cosh ^{-1}(c+d x)^4}{c+d x}+i \cosh ^{-1}(c+d x)^4+4 i \log \left (1+i e^{-\cosh ^{-1}(c+d x)}\right ) \cosh ^{-1}(c+d x)^3-4 i \log \left (1+i e^{\cosh ^{-1}(c+d x)}\right ) \cosh ^{-1}(c+d x)^3-2 \pi \cosh ^{-1}(c+d x)^3-6 \pi \log \left (1+i e^{-\cosh ^{-1}(c+d x)}\right ) \cosh ^{-1}(c+d x)^2+6 \pi \log \left (1-i e^{\cosh ^{-1}(c+d x)}\right ) \cosh ^{-1}(c+d x)^2-12 i \text{PolyLog}\left (2,-i e^{\cosh ^{-1}(c+d x)}\right ) \cosh ^{-1}(c+d x)^2-\frac{3}{2} i \pi ^2 \cosh ^{-1}(c+d x)^2-3 i \pi ^2 \log \left (1+i e^{-\cosh ^{-1}(c+d x)}\right ) \cosh ^{-1}(c+d x)+3 i \pi ^2 \log \left (1-i e^{\cosh ^{-1}(c+d x)}\right ) \cosh ^{-1}(c+d x)+12 \pi \text{PolyLog}\left (2,i e^{\cosh ^{-1}(c+d x)}\right ) \cosh ^{-1}(c+d x)-24 i \text{PolyLog}\left (3,-i e^{-\cosh ^{-1}(c+d x)}\right ) \cosh ^{-1}(c+d x)+24 i \text{PolyLog}\left (3,-i e^{\cosh ^{-1}(c+d x)}\right ) \cosh ^{-1}(c+d x)+\frac{1}{2} \pi ^3 \cosh ^{-1}(c+d x)+\frac{1}{2} \pi ^3 \log \left (1+i e^{-\cosh ^{-1}(c+d x)}\right )-\frac{1}{2} \pi ^3 \log \left (1+i e^{\cosh ^{-1}(c+d x)}\right )+\frac{1}{2} \pi ^3 \log \left (\tan \left (\frac{1}{4} \left (2 i \cosh ^{-1}(c+d x)+\pi \right )\right )\right )+3 i \left (\pi -2 i \cosh ^{-1}(c+d x)\right )^2 \text{PolyLog}\left (2,-i e^{-\cosh ^{-1}(c+d x)}\right )+3 i \pi ^2 \text{PolyLog}\left (2,i e^{\cosh ^{-1}(c+d x)}\right )+12 \pi \text{PolyLog}\left (3,-i e^{-\cosh ^{-1}(c+d x)}\right )-12 \pi \text{PolyLog}\left (3,i e^{\cosh ^{-1}(c+d x)}\right )-24 i \text{PolyLog}\left (4,-i e^{-\cosh ^{-1}(c+d x)}\right )-24 i \text{PolyLog}\left (4,-i e^{\cosh ^{-1}(c+d x)}\right )-\frac{7 i \pi ^4}{16}\right )}{d e^2} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.086, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( a+b{\rm arccosh} \left (dx+c\right ) \right ) ^{4}}{ \left ( dex+ce \right ) ^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b^{4} \operatorname{arcosh}\left (d x + c\right )^{4} + 4 \, a b^{3} \operatorname{arcosh}\left (d x + c\right )^{3} + 6 \, a^{2} b^{2} \operatorname{arcosh}\left (d x + c\right )^{2} + 4 \, a^{3} b \operatorname{arcosh}\left (d x + c\right ) + a^{4}}{d^{2} e^{2} x^{2} + 2 \, c d e^{2} x + c^{2} e^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{a^{4}}{c^{2} + 2 c d x + d^{2} x^{2}}\, dx + \int \frac{b^{4} \operatorname{acosh}^{4}{\left (c + d x \right )}}{c^{2} + 2 c d x + d^{2} x^{2}}\, dx + \int \frac{4 a b^{3} \operatorname{acosh}^{3}{\left (c + d x \right )}}{c^{2} + 2 c d x + d^{2} x^{2}}\, dx + \int \frac{6 a^{2} b^{2} \operatorname{acosh}^{2}{\left (c + d x \right )}}{c^{2} + 2 c d x + d^{2} x^{2}}\, dx + \int \frac{4 a^{3} b \operatorname{acosh}{\left (c + d x \right )}}{c^{2} + 2 c d x + d^{2} x^{2}}\, dx}{e^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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