Optimal. Leaf size=175 \[ \frac{3 b^2 e (c+d x)^2 \left (a+b \cosh ^{-1}(c+d x)\right )}{4 d}-\frac{3 b e \sqrt{c+d x-1} (c+d x) \sqrt{c+d x+1} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{4 d}+\frac{e (c+d x)^2 \left (a+b \cosh ^{-1}(c+d x)\right )^3}{2 d}-\frac{e \left (a+b \cosh ^{-1}(c+d x)\right )^3}{4 d}-\frac{3 b^3 e \sqrt{c+d x-1} (c+d x) \sqrt{c+d x+1}}{8 d}-\frac{3 b^3 e \cosh ^{-1}(c+d x)}{8 d} \]
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Rubi [A] time = 0.358665, antiderivative size = 175, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {5866, 12, 5662, 5759, 5676, 90, 52} \[ \frac{3 b^2 e (c+d x)^2 \left (a+b \cosh ^{-1}(c+d x)\right )}{4 d}-\frac{3 b e \sqrt{c+d x-1} (c+d x) \sqrt{c+d x+1} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{4 d}+\frac{e (c+d x)^2 \left (a+b \cosh ^{-1}(c+d x)\right )^3}{2 d}-\frac{e \left (a+b \cosh ^{-1}(c+d x)\right )^3}{4 d}-\frac{3 b^3 e \sqrt{c+d x-1} (c+d x) \sqrt{c+d x+1}}{8 d}-\frac{3 b^3 e \cosh ^{-1}(c+d x)}{8 d} \]
Antiderivative was successfully verified.
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Rule 5866
Rule 12
Rule 5662
Rule 5759
Rule 5676
Rule 90
Rule 52
Rubi steps
\begin{align*} \int (c e+d e x) \left (a+b \cosh ^{-1}(c+d x)\right )^3 \, dx &=\frac{\operatorname{Subst}\left (\int e x \left (a+b \cosh ^{-1}(x)\right )^3 \, dx,x,c+d x\right )}{d}\\ &=\frac{e \operatorname{Subst}\left (\int x \left (a+b \cosh ^{-1}(x)\right )^3 \, dx,x,c+d x\right )}{d}\\ &=\frac{e (c+d x)^2 \left (a+b \cosh ^{-1}(c+d x)\right )^3}{2 d}-\frac{(3 b e) \operatorname{Subst}\left (\int \frac{x^2 \left (a+b \cosh ^{-1}(x)\right )^2}{\sqrt{-1+x} \sqrt{1+x}} \, dx,x,c+d x\right )}{2 d}\\ &=-\frac{3 b e \sqrt{-1+c+d x} (c+d x) \sqrt{1+c+d x} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{4 d}+\frac{e (c+d x)^2 \left (a+b \cosh ^{-1}(c+d x)\right )^3}{2 d}-\frac{(3 b e) \operatorname{Subst}\left (\int \frac{\left (a+b \cosh ^{-1}(x)\right )^2}{\sqrt{-1+x} \sqrt{1+x}} \, dx,x,c+d x\right )}{4 d}+\frac{\left (3 b^2 e\right ) \operatorname{Subst}\left (\int x \left (a+b \cosh ^{-1}(x)\right ) \, dx,x,c+d x\right )}{2 d}\\ &=\frac{3 b^2 e (c+d x)^2 \left (a+b \cosh ^{-1}(c+d x)\right )}{4 d}-\frac{3 b e \sqrt{-1+c+d x} (c+d x) \sqrt{1+c+d x} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{4 d}-\frac{e \left (a+b \cosh ^{-1}(c+d x)\right )^3}{4 d}+\frac{e (c+d x)^2 \left (a+b \cosh ^{-1}(c+d x)\right )^3}{2 d}-\frac{\left (3 b^3 e\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{-1+x} \sqrt{1+x}} \, dx,x,c+d x\right )}{4 d}\\ &=-\frac{3 b^3 e \sqrt{-1+c+d x} (c+d x) \sqrt{1+c+d x}}{8 d}+\frac{3 b^2 e (c+d x)^2 \left (a+b \cosh ^{-1}(c+d x)\right )}{4 d}-\frac{3 b e \sqrt{-1+c+d x} (c+d x) \sqrt{1+c+d x} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{4 d}-\frac{e \left (a+b \cosh ^{-1}(c+d x)\right )^3}{4 d}+\frac{e (c+d x)^2 \left (a+b \cosh ^{-1}(c+d x)\right )^3}{2 d}-\frac{\left (3 b^3 e\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{-1+x} \sqrt{1+x}} \, dx,x,c+d x\right )}{8 d}\\ &=-\frac{3 b^3 e \sqrt{-1+c+d x} (c+d x) \sqrt{1+c+d x}}{8 d}-\frac{3 b^3 e \cosh ^{-1}(c+d x)}{8 d}+\frac{3 b^2 e (c+d x)^2 \left (a+b \cosh ^{-1}(c+d x)\right )}{4 d}-\frac{3 b e \sqrt{-1+c+d x} (c+d x) \sqrt{1+c+d x} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{4 d}-\frac{e \left (a+b \cosh ^{-1}(c+d x)\right )^3}{4 d}+\frac{e (c+d x)^2 \left (a+b \cosh ^{-1}(c+d x)\right )^3}{2 d}\\ \end{align*}
Mathematica [A] time = 0.301525, size = 244, normalized size = 1.39 \[ \frac{e \left (2 a \left (2 a^2+3 b^2\right ) (c+d x)^2-3 b \left (2 a^2+b^2\right ) \sqrt{c+d x-1} (c+d x) \sqrt{c+d x+1}-3 b \left (2 a^2+b^2\right ) \log \left (\sqrt{c+d x-1} \sqrt{c+d x+1}+c+d x\right )-6 b (c+d x) \cosh ^{-1}(c+d x) \left (-2 a^2 (c+d x)+2 a b \sqrt{c+d x-1} \sqrt{c+d x+1}-b^2 (c+d x)\right )+6 b^2 \cosh ^{-1}(c+d x)^2 \left (2 a (c+d x)^2-a-b \sqrt{c+d x-1} \sqrt{c+d x+1} (c+d x)\right )+2 b^3 \left (2 (c+d x)^2-1\right ) \cosh ^{-1}(c+d x)^3\right )}{8 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.036, size = 605, normalized size = 3.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.51384, size = 891, normalized size = 5.09 \begin{align*} \frac{2 \,{\left (2 \, a^{3} + 3 \, a b^{2}\right )} d^{2} e x^{2} + 4 \,{\left (2 \, a^{3} + 3 \, a b^{2}\right )} c d e x + 2 \,{\left (2 \, b^{3} d^{2} e x^{2} + 4 \, b^{3} c d e x +{\left (2 \, b^{3} c^{2} - b^{3}\right )} e\right )} \log \left (d x + c + \sqrt{d^{2} x^{2} + 2 \, c d x + c^{2} - 1}\right )^{3} + 6 \,{\left (2 \, a b^{2} d^{2} e x^{2} + 4 \, a b^{2} c d e x +{\left (2 \, a b^{2} c^{2} - a b^{2}\right )} e -{\left (b^{3} d e x + b^{3} c e\right )} \sqrt{d^{2} x^{2} + 2 \, c d x + c^{2} - 1}\right )} \log \left (d x + c + \sqrt{d^{2} x^{2} + 2 \, c d x + c^{2} - 1}\right )^{2} + 3 \,{\left (2 \,{\left (2 \, a^{2} b + b^{3}\right )} d^{2} e x^{2} + 4 \,{\left (2 \, a^{2} b + b^{3}\right )} c d e x -{\left (2 \, a^{2} b + b^{3} - 2 \,{\left (2 \, a^{2} b + b^{3}\right )} c^{2}\right )} e - 4 \,{\left (a b^{2} d e x + a b^{2} c e\right )} \sqrt{d^{2} x^{2} + 2 \, c d x + c^{2} - 1}\right )} \log \left (d x + c + \sqrt{d^{2} x^{2} + 2 \, c d x + c^{2} - 1}\right ) - 3 \,{\left ({\left (2 \, a^{2} b + b^{3}\right )} d e x +{\left (2 \, a^{2} b + b^{3}\right )} c e\right )} \sqrt{d^{2} x^{2} + 2 \, c d x + c^{2} - 1}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 2.93132, size = 685, normalized size = 3.91 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d e x + c e\right )}{\left (b \operatorname{arcosh}\left (d x + c\right ) + a\right )}^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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