Optimal. Leaf size=267 \[ \frac{2^{-n-3} e^{-\frac{2 a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \text{Gamma}\left (n+1,-\frac{2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )}{d^2}-\frac{c e^{-\frac{a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \text{Gamma}\left (n+1,-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )}{2 d^2}+\frac{c e^{a/b} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \text{Gamma}\left (n+1,\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )}{2 d^2}+\frac{2^{-n-3} e^{\frac{2 a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \text{Gamma}\left (n+1,\frac{2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )}{d^2} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.483293, antiderivative size = 267, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 9, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.643, Rules used = {5865, 5805, 6741, 12, 6742, 3307, 2181, 5448, 3308} \[ \frac{2^{-n-3} e^{-\frac{2 a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \text{Gamma}\left (n+1,-\frac{2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )}{d^2}-\frac{c e^{-\frac{a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \text{Gamma}\left (n+1,-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )}{2 d^2}+\frac{c e^{a/b} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \text{Gamma}\left (n+1,\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )}{2 d^2}+\frac{2^{-n-3} e^{\frac{2 a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \text{Gamma}\left (n+1,\frac{2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )}{d^2} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 5865
Rule 5805
Rule 6741
Rule 12
Rule 6742
Rule 3307
Rule 2181
Rule 5448
Rule 3308
Rubi steps
\begin{align*} \int x \left (a+b \sinh ^{-1}(c+d x)\right )^n \, dx &=\frac{\operatorname{Subst}\left (\int \left (-\frac{c}{d}+\frac{x}{d}\right ) \left (a+b \sinh ^{-1}(x)\right )^n \, dx,x,c+d x\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int (a+b x)^n \cosh (x) \left (-\frac{c}{d}+\frac{\sinh (x)}{d}\right ) \, dx,x,\sinh ^{-1}(c+d x)\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \frac{(a+b x)^n \cosh (x) (-c+\sinh (x))}{d} \, dx,x,\sinh ^{-1}(c+d x)\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int (a+b x)^n \cosh (x) (-c+\sinh (x)) \, dx,x,\sinh ^{-1}(c+d x)\right )}{d^2}\\ &=\frac{\operatorname{Subst}\left (\int \left (-c (a+b x)^n \cosh (x)+(a+b x)^n \cosh (x) \sinh (x)\right ) \, dx,x,\sinh ^{-1}(c+d x)\right )}{d^2}\\ &=\frac{\operatorname{Subst}\left (\int (a+b x)^n \cosh (x) \sinh (x) \, dx,x,\sinh ^{-1}(c+d x)\right )}{d^2}-\frac{c \operatorname{Subst}\left (\int (a+b x)^n \cosh (x) \, dx,x,\sinh ^{-1}(c+d x)\right )}{d^2}\\ &=\frac{\operatorname{Subst}\left (\int \frac{1}{2} (a+b x)^n \sinh (2 x) \, dx,x,\sinh ^{-1}(c+d x)\right )}{d^2}-\frac{c \operatorname{Subst}\left (\int e^{-x} (a+b x)^n \, dx,x,\sinh ^{-1}(c+d x)\right )}{2 d^2}-\frac{c \operatorname{Subst}\left (\int e^x (a+b x)^n \, dx,x,\sinh ^{-1}(c+d x)\right )}{2 d^2}\\ &=-\frac{c e^{-\frac{a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \Gamma \left (1+n,-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )}{2 d^2}+\frac{c e^{a/b} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \Gamma \left (1+n,\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )}{2 d^2}+\frac{\operatorname{Subst}\left (\int (a+b x)^n \sinh (2 x) \, dx,x,\sinh ^{-1}(c+d x)\right )}{2 d^2}\\ &=-\frac{c e^{-\frac{a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \Gamma \left (1+n,-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )}{2 d^2}+\frac{c e^{a/b} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \Gamma \left (1+n,\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )}{2 d^2}-\frac{\operatorname{Subst}\left (\int e^{-2 x} (a+b x)^n \, dx,x,\sinh ^{-1}(c+d x)\right )}{4 d^2}+\frac{\operatorname{Subst}\left (\int e^{2 x} (a+b x)^n \, dx,x,\sinh ^{-1}(c+d x)\right )}{4 d^2}\\ &=\frac{2^{-3-n} e^{-\frac{2 a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \Gamma \left (1+n,-\frac{2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )}{d^2}-\frac{c e^{-\frac{a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \Gamma \left (1+n,-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )}{2 d^2}+\frac{c e^{a/b} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \Gamma \left (1+n,\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )}{2 d^2}+\frac{2^{-3-n} e^{\frac{2 a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^{-n} \Gamma \left (1+n,\frac{2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )}{d^2}\\ \end{align*}
Mathematica [A] time = 0.179955, size = 228, normalized size = 0.85 \[ \frac{2^{-n-3} e^{-\frac{2 a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right )^n \left (-\frac{\left (a+b \sinh ^{-1}(c+d x)\right )^2}{b^2}\right )^{-n} \left (\left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )^n \text{Gamma}\left (n+1,-\frac{2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )-c 2^{n+2} e^{a/b} \left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )^n \text{Gamma}\left (n+1,-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )+c 2^{n+2} e^{\frac{3 a}{b}} \left (-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^n \text{Gamma}\left (n+1,\frac{a}{b}+\sinh ^{-1}(c+d x)\right )+e^{\frac{4 a}{b}} \left (-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )^n \text{Gamma}\left (n+1,\frac{2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )\right )}{d^2} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [F] time = 0.151, size = 0, normalized size = 0. \begin{align*} \int x \left ( a+b{\it Arcsinh} \left ( dx+c \right ) \right ) ^{n}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \operatorname{arsinh}\left (d x + c\right ) + a\right )}^{n} x\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (b \operatorname{arsinh}\left (d x + c\right ) + a\right )}^{n} x, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x \left (a + b \operatorname{asinh}{\left (c + d x \right )}\right )^{n}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \operatorname{arsinh}\left (d x + c\right ) + a\right )}^{n} x\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]