Optimal. Leaf size=178 \[ -\frac{2 b \text{PolyLog}\left (2,\frac{e^{\sinh ^{-1}(a+b x)}}{a-\sqrt{a^2+1}}\right )}{\sqrt{a^2+1}}+\frac{2 b \text{PolyLog}\left (2,\frac{e^{\sinh ^{-1}(a+b x)}}{\sqrt{a^2+1}+a}\right )}{\sqrt{a^2+1}}-\frac{2 b \sinh ^{-1}(a+b x) \log \left (1-\frac{e^{\sinh ^{-1}(a+b x)}}{a-\sqrt{a^2+1}}\right )}{\sqrt{a^2+1}}+\frac{2 b \sinh ^{-1}(a+b x) \log \left (1-\frac{e^{\sinh ^{-1}(a+b x)}}{\sqrt{a^2+1}+a}\right )}{\sqrt{a^2+1}}-\frac{\sinh ^{-1}(a+b x)^2}{x} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.382659, antiderivative size = 178, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 8, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.667, Rules used = {5865, 5801, 5831, 3322, 2264, 2190, 2279, 2391} \[ -\frac{2 b \text{PolyLog}\left (2,\frac{e^{\sinh ^{-1}(a+b x)}}{a-\sqrt{a^2+1}}\right )}{\sqrt{a^2+1}}+\frac{2 b \text{PolyLog}\left (2,\frac{e^{\sinh ^{-1}(a+b x)}}{\sqrt{a^2+1}+a}\right )}{\sqrt{a^2+1}}-\frac{2 b \sinh ^{-1}(a+b x) \log \left (1-\frac{e^{\sinh ^{-1}(a+b x)}}{a-\sqrt{a^2+1}}\right )}{\sqrt{a^2+1}}+\frac{2 b \sinh ^{-1}(a+b x) \log \left (1-\frac{e^{\sinh ^{-1}(a+b x)}}{\sqrt{a^2+1}+a}\right )}{\sqrt{a^2+1}}-\frac{\sinh ^{-1}(a+b x)^2}{x} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 5865
Rule 5801
Rule 5831
Rule 3322
Rule 2264
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \frac{\sinh ^{-1}(a+b x)^2}{x^2} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\sinh ^{-1}(x)^2}{\left (-\frac{a}{b}+\frac{x}{b}\right )^2} \, dx,x,a+b x\right )}{b}\\ &=-\frac{\sinh ^{-1}(a+b x)^2}{x}+2 \operatorname{Subst}\left (\int \frac{\sinh ^{-1}(x)}{\left (-\frac{a}{b}+\frac{x}{b}\right ) \sqrt{1+x^2}} \, dx,x,a+b x\right )\\ &=-\frac{\sinh ^{-1}(a+b x)^2}{x}+2 \operatorname{Subst}\left (\int \frac{x}{-\frac{a}{b}+\frac{\sinh (x)}{b}} \, dx,x,\sinh ^{-1}(a+b x)\right )\\ &=-\frac{\sinh ^{-1}(a+b x)^2}{x}+4 \operatorname{Subst}\left (\int \frac{e^x x}{-\frac{1}{b}-\frac{2 a e^x}{b}+\frac{e^{2 x}}{b}} \, dx,x,\sinh ^{-1}(a+b x)\right )\\ &=-\frac{\sinh ^{-1}(a+b x)^2}{x}+\frac{4 \operatorname{Subst}\left (\int \frac{e^x x}{-\frac{2 a}{b}-\frac{2 \sqrt{1+a^2}}{b}+\frac{2 e^x}{b}} \, dx,x,\sinh ^{-1}(a+b x)\right )}{\sqrt{1+a^2}}-\frac{4 \operatorname{Subst}\left (\int \frac{e^x x}{-\frac{2 a}{b}+\frac{2 \sqrt{1+a^2}}{b}+\frac{2 e^x}{b}} \, dx,x,\sinh ^{-1}(a+b x)\right )}{\sqrt{1+a^2}}\\ &=-\frac{\sinh ^{-1}(a+b x)^2}{x}-\frac{2 b \sinh ^{-1}(a+b x) \log \left (1-\frac{e^{\sinh ^{-1}(a+b x)}}{a-\sqrt{1+a^2}}\right )}{\sqrt{1+a^2}}+\frac{2 b \sinh ^{-1}(a+b x) \log \left (1-\frac{e^{\sinh ^{-1}(a+b x)}}{a+\sqrt{1+a^2}}\right )}{\sqrt{1+a^2}}-\frac{(2 b) \operatorname{Subst}\left (\int \log \left (1+\frac{2 e^x}{\left (-\frac{2 a}{b}-\frac{2 \sqrt{1+a^2}}{b}\right ) b}\right ) \, dx,x,\sinh ^{-1}(a+b x)\right )}{\sqrt{1+a^2}}+\frac{(2 b) \operatorname{Subst}\left (\int \log \left (1+\frac{2 e^x}{\left (-\frac{2 a}{b}+\frac{2 \sqrt{1+a^2}}{b}\right ) b}\right ) \, dx,x,\sinh ^{-1}(a+b x)\right )}{\sqrt{1+a^2}}\\ &=-\frac{\sinh ^{-1}(a+b x)^2}{x}-\frac{2 b \sinh ^{-1}(a+b x) \log \left (1-\frac{e^{\sinh ^{-1}(a+b x)}}{a-\sqrt{1+a^2}}\right )}{\sqrt{1+a^2}}+\frac{2 b \sinh ^{-1}(a+b x) \log \left (1-\frac{e^{\sinh ^{-1}(a+b x)}}{a+\sqrt{1+a^2}}\right )}{\sqrt{1+a^2}}-\frac{(2 b) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{2 x}{\left (-\frac{2 a}{b}-\frac{2 \sqrt{1+a^2}}{b}\right ) b}\right )}{x} \, dx,x,e^{\sinh ^{-1}(a+b x)}\right )}{\sqrt{1+a^2}}+\frac{(2 b) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{2 x}{\left (-\frac{2 a}{b}+\frac{2 \sqrt{1+a^2}}{b}\right ) b}\right )}{x} \, dx,x,e^{\sinh ^{-1}(a+b x)}\right )}{\sqrt{1+a^2}}\\ &=-\frac{\sinh ^{-1}(a+b x)^2}{x}-\frac{2 b \sinh ^{-1}(a+b x) \log \left (1-\frac{e^{\sinh ^{-1}(a+b x)}}{a-\sqrt{1+a^2}}\right )}{\sqrt{1+a^2}}+\frac{2 b \sinh ^{-1}(a+b x) \log \left (1-\frac{e^{\sinh ^{-1}(a+b x)}}{a+\sqrt{1+a^2}}\right )}{\sqrt{1+a^2}}-\frac{2 b \text{Li}_2\left (\frac{e^{\sinh ^{-1}(a+b x)}}{a-\sqrt{1+a^2}}\right )}{\sqrt{1+a^2}}+\frac{2 b \text{Li}_2\left (\frac{e^{\sinh ^{-1}(a+b x)}}{a+\sqrt{1+a^2}}\right )}{\sqrt{1+a^2}}\\ \end{align*}
Mathematica [A] time = 0.112402, size = 178, normalized size = 1. \[ \frac{-2 b x \text{PolyLog}\left (2,\frac{e^{\sinh ^{-1}(a+b x)}}{a-\sqrt{a^2+1}}\right )+2 b x \text{PolyLog}\left (2,\frac{e^{\sinh ^{-1}(a+b x)}}{\sqrt{a^2+1}+a}\right )-\sinh ^{-1}(a+b x) \left (\sqrt{a^2+1} \sinh ^{-1}(a+b x)+2 b x \left (\log \left (\frac{\sqrt{a^2+1}+e^{\sinh ^{-1}(a+b x)}-a}{\sqrt{a^2+1}-a}\right )-\log \left (\frac{\sqrt{a^2+1}-e^{\sinh ^{-1}(a+b x)}+a}{\sqrt{a^2+1}+a}\right )\right )\right )}{\sqrt{a^2+1} x} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [A] time = 0.136, size = 217, normalized size = 1.2 \begin{align*} -{\frac{ \left ({\it Arcsinh} \left ( bx+a \right ) \right ) ^{2}}{x}}+2\,{\frac{b{\it Arcsinh} \left ( bx+a \right ) }{\sqrt{{a}^{2}+1}}\ln \left ({\frac{\sqrt{{a}^{2}+1}-bx-\sqrt{1+ \left ( bx+a \right ) ^{2}}}{a+\sqrt{{a}^{2}+1}}} \right ) }-2\,{\frac{b{\it Arcsinh} \left ( bx+a \right ) }{\sqrt{{a}^{2}+1}}\ln \left ({\frac{\sqrt{{a}^{2}+1}+bx+\sqrt{1+ \left ( bx+a \right ) ^{2}}}{-a+\sqrt{{a}^{2}+1}}} \right ) }+2\,{\frac{b}{\sqrt{{a}^{2}+1}}{\it dilog} \left ({\frac{\sqrt{{a}^{2}+1}-bx-\sqrt{1+ \left ( bx+a \right ) ^{2}}}{a+\sqrt{{a}^{2}+1}}} \right ) }-2\,{\frac{b}{\sqrt{{a}^{2}+1}}{\it dilog} \left ({\frac{\sqrt{{a}^{2}+1}+bx+\sqrt{1+ \left ( bx+a \right ) ^{2}}}{-a+\sqrt{{a}^{2}+1}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\operatorname{arsinh}\left (b x + a\right )^{2}}{x^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{asinh}^{2}{\left (a + b x \right )}}{x^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{arsinh}\left (b x + a\right )^{2}}{x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]