Optimal. Leaf size=244 \[ \frac{x \left (\cosh \left (\frac{a}{2 b}\right )+i \sinh \left (\frac{a}{2 b}\right )\right ) \text{CosIntegral}\left (\frac{i \left (a-i b \sin ^{-1}\left (1+i d x^2\right )\right )}{2 b}\right )}{4 b^2 \left (\cos \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )-\sin \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )\right )}-\frac{x \left (\sinh \left (\frac{a}{2 b}\right )+i \cosh \left (\frac{a}{2 b}\right )\right ) \text{Shi}\left (\frac{a-i b \sin ^{-1}\left (i d x^2+1\right )}{2 b}\right )}{4 b^2 \left (\cos \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )-\sin \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )\right )}-\frac{\sqrt{d^2 x^4-2 i d x^2}}{2 b d x \left (a-i b \sin ^{-1}\left (1+i d x^2\right )\right )} \]
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Rubi [A] time = 0.0286216, antiderivative size = 244, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.05, Rules used = {4825} \[ \frac{x \left (\cosh \left (\frac{a}{2 b}\right )+i \sinh \left (\frac{a}{2 b}\right )\right ) \text{CosIntegral}\left (\frac{i \left (a-i b \sin ^{-1}\left (1+i d x^2\right )\right )}{2 b}\right )}{4 b^2 \left (\cos \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )-\sin \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )\right )}-\frac{x \left (\sinh \left (\frac{a}{2 b}\right )+i \cosh \left (\frac{a}{2 b}\right )\right ) \text{Shi}\left (\frac{a-i b \sin ^{-1}\left (i d x^2+1\right )}{2 b}\right )}{4 b^2 \left (\cos \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )-\sin \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )\right )}-\frac{\sqrt{d^2 x^4-2 i d x^2}}{2 b d x \left (a-i b \sin ^{-1}\left (1+i d x^2\right )\right )} \]
Antiderivative was successfully verified.
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Rule 4825
Rubi steps
\begin{align*} \int \frac{1}{\left (a-i b \sin ^{-1}\left (1+i d x^2\right )\right )^2} \, dx &=-\frac{\sqrt{-2 i d x^2+d^2 x^4}}{2 b d x \left (a-i b \sin ^{-1}\left (1+i d x^2\right )\right )}+\frac{x \text{Ci}\left (\frac{i \left (a-i b \sin ^{-1}\left (1+i d x^2\right )\right )}{2 b}\right ) \left (\cosh \left (\frac{a}{2 b}\right )+i \sinh \left (\frac{a}{2 b}\right )\right )}{4 b^2 \left (\cos \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )-\sin \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )\right )}-\frac{x \left (i \cosh \left (\frac{a}{2 b}\right )+\sinh \left (\frac{a}{2 b}\right )\right ) \text{Shi}\left (\frac{a-i b \sin ^{-1}\left (1+i d x^2\right )}{2 b}\right )}{4 b^2 \left (\cos \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )-\sin \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )\right )}\\ \end{align*}
Mathematica [A] time = 1.36747, size = 196, normalized size = 0.8 \[ \frac{\frac{x^2 \left (\left (\cosh \left (\frac{a}{2 b}\right )+i \sinh \left (\frac{a}{2 b}\right )\right ) \text{CosIntegral}\left (\frac{1}{2} \left (\frac{i a}{b}+\sin ^{-1}\left (1+i d x^2\right )\right )\right )-\left (\cosh \left (\frac{a}{2 b}\right )-i \sinh \left (\frac{a}{2 b}\right )\right ) \text{Si}\left (\frac{1}{2} \left (\frac{i a}{b}+\sin ^{-1}\left (i d x^2+1\right )\right )\right )\right )}{\cos \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )-\sin \left (\frac{1}{2} \sin ^{-1}\left (1+i d x^2\right )\right )}-\frac{2 b \sqrt{d x^2 \left (d x^2-2 i\right )}}{d \left (a-i b \sin ^{-1}\left (1+i d x^2\right )\right )}}{4 b^2 x} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.068, size = 0, normalized size = 0. \begin{align*} \int \left ( a+b{\it Arcsinh} \left ( -i+d{x}^{2} \right ) \right ) ^{-2}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{d^{2} x^{4} - 3 i \, d x^{2} +{\left (d^{\frac{3}{2}} x^{3} - 2 i \, \sqrt{d} x\right )} \sqrt{d x^{2} - 2 i} - 2}{2 \, a b d^{2} x^{3} - 4 i \, a b d x +{\left (2 \, b^{2} d^{2} x^{3} - 4 i \, b^{2} d x +{\left (2 \, b^{2} d^{\frac{3}{2}} x^{2} - 2 i \, b^{2} \sqrt{d}\right )} \sqrt{d x^{2} - 2 i}\right )} \log \left (d x^{2} + \sqrt{d x^{2} - 2 i} \sqrt{d} x - i\right ) +{\left (2 \, a b d^{\frac{3}{2}} x^{2} - 2 i \, a b \sqrt{d}\right )} \sqrt{d x^{2} - 2 i}} + \int \frac{2 \, d^{3} x^{6} - 6 i \, d^{2} x^{4} +{\left (2 \, d^{2} x^{4} - 2 i \, d x^{2} - 4\right )}{\left (d x^{2} - 2 i\right )} + 2 \,{\left (2 \, d^{\frac{5}{2}} x^{5} - 4 i \, d^{\frac{3}{2}} x^{3} - \sqrt{d} x\right )} \sqrt{d x^{2} - 2 i} - 8 i}{4 \, a b d^{3} x^{6} - 16 i \, a b d^{2} x^{4} - 16 \, a b d x^{2} +{\left (4 \, a b d^{2} x^{4} - 8 i \, a b d x^{2} - 4 \, a b\right )}{\left (d x^{2} - 2 i\right )} +{\left (4 \, b^{2} d^{3} x^{6} - 16 i \, b^{2} d^{2} x^{4} - 16 \, b^{2} d x^{2} + 4 \,{\left (b^{2} d^{2} x^{4} - 2 i \, b^{2} d x^{2} - b^{2}\right )}{\left (d x^{2} - 2 i\right )} +{\left (8 \, b^{2} d^{\frac{5}{2}} x^{5} - 24 i \, b^{2} d^{\frac{3}{2}} x^{3} - 16 \, b^{2} \sqrt{d} x\right )} \sqrt{d x^{2} - 2 i}\right )} \log \left (d x^{2} + \sqrt{d x^{2} - 2 i} \sqrt{d} x - i\right ) +{\left (8 \, a b d^{\frac{5}{2}} x^{5} - 24 i \, a b d^{\frac{3}{2}} x^{3} - 16 \, a b \sqrt{d} x\right )} \sqrt{d x^{2} - 2 i}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{2 \,{\left (b^{2} d x \log \left (d x^{2} + \sqrt{d^{2} x^{4} - 2 i \, d x^{2}} - i\right ) + a b d x\right )}{\rm integral}\left (\frac{\sqrt{d^{2} x^{4} - 2 i \, d x^{2}}}{2 \, a b d x^{2} - 4 i \, a b +{\left (2 \, b^{2} d x^{2} - 4 i \, b^{2}\right )} \log \left (d x^{2} + \sqrt{d^{2} x^{4} - 2 i \, d x^{2}} - i\right )}, x\right ) - \sqrt{d^{2} x^{4} - 2 i \, d x^{2}}}{2 \,{\left (b^{2} d x \log \left (d x^{2} + \sqrt{d^{2} x^{4} - 2 i \, d x^{2}} - i\right ) + a b d x\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b \operatorname{arsinh}\left (d x^{2} - i\right ) + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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