Optimal. Leaf size=86 \[ -\frac{\text{PolyLog}\left (2,-e^{2 \sinh ^{-1}(a+b x)}\right )}{b}+\frac{(a+b x) \sinh ^{-1}(a+b x)^2}{b \sqrt{(a+b x)^2+1}}+\frac{\sinh ^{-1}(a+b x)^2}{b}-\frac{2 \sinh ^{-1}(a+b x) \log \left (e^{2 \sinh ^{-1}(a+b x)}+1\right )}{b} \]
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Rubi [A] time = 0.160093, antiderivative size = 86, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 30, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.233, Rules used = {5867, 5687, 5714, 3718, 2190, 2279, 2391} \[ -\frac{\text{PolyLog}\left (2,-e^{2 \sinh ^{-1}(a+b x)}\right )}{b}+\frac{(a+b x) \sinh ^{-1}(a+b x)^2}{b \sqrt{(a+b x)^2+1}}+\frac{\sinh ^{-1}(a+b x)^2}{b}-\frac{2 \sinh ^{-1}(a+b x) \log \left (e^{2 \sinh ^{-1}(a+b x)}+1\right )}{b} \]
Antiderivative was successfully verified.
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Rule 5867
Rule 5687
Rule 5714
Rule 3718
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \frac{\sinh ^{-1}(a+b x)^2}{\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\sinh ^{-1}(x)^2}{\left (1+x^2\right )^{3/2}} \, dx,x,a+b x\right )}{b}\\ &=\frac{(a+b x) \sinh ^{-1}(a+b x)^2}{b \sqrt{1+(a+b x)^2}}-\frac{2 \operatorname{Subst}\left (\int \frac{x \sinh ^{-1}(x)}{1+x^2} \, dx,x,a+b x\right )}{b}\\ &=\frac{(a+b x) \sinh ^{-1}(a+b x)^2}{b \sqrt{1+(a+b x)^2}}-\frac{2 \operatorname{Subst}\left (\int x \tanh (x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{b}\\ &=\frac{\sinh ^{-1}(a+b x)^2}{b}+\frac{(a+b x) \sinh ^{-1}(a+b x)^2}{b \sqrt{1+(a+b x)^2}}-\frac{4 \operatorname{Subst}\left (\int \frac{e^{2 x} x}{1+e^{2 x}} \, dx,x,\sinh ^{-1}(a+b x)\right )}{b}\\ &=\frac{\sinh ^{-1}(a+b x)^2}{b}+\frac{(a+b x) \sinh ^{-1}(a+b x)^2}{b \sqrt{1+(a+b x)^2}}-\frac{2 \sinh ^{-1}(a+b x) \log \left (1+e^{2 \sinh ^{-1}(a+b x)}\right )}{b}+\frac{2 \operatorname{Subst}\left (\int \log \left (1+e^{2 x}\right ) \, dx,x,\sinh ^{-1}(a+b x)\right )}{b}\\ &=\frac{\sinh ^{-1}(a+b x)^2}{b}+\frac{(a+b x) \sinh ^{-1}(a+b x)^2}{b \sqrt{1+(a+b x)^2}}-\frac{2 \sinh ^{-1}(a+b x) \log \left (1+e^{2 \sinh ^{-1}(a+b x)}\right )}{b}+\frac{\operatorname{Subst}\left (\int \frac{\log (1+x)}{x} \, dx,x,e^{2 \sinh ^{-1}(a+b x)}\right )}{b}\\ &=\frac{\sinh ^{-1}(a+b x)^2}{b}+\frac{(a+b x) \sinh ^{-1}(a+b x)^2}{b \sqrt{1+(a+b x)^2}}-\frac{2 \sinh ^{-1}(a+b x) \log \left (1+e^{2 \sinh ^{-1}(a+b x)}\right )}{b}-\frac{\text{Li}_2\left (-e^{2 \sinh ^{-1}(a+b x)}\right )}{b}\\ \end{align*}
Mathematica [A] time = 0.381727, size = 98, normalized size = 1.14 \[ \frac{\text{PolyLog}\left (2,-e^{-2 \sinh ^{-1}(a+b x)}\right )+\sinh ^{-1}(a+b x) \left (\frac{\left (-\sqrt{a^2+2 a b x+b^2 x^2+1}+a+b x\right ) \sinh ^{-1}(a+b x)}{\sqrt{a^2+2 a b x+b^2 x^2+1}}-2 \log \left (e^{-2 \sinh ^{-1}(a+b x)}+1\right )\right )}{b} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.096, size = 168, normalized size = 2. \begin{align*} -{\frac{ \left ({\it Arcsinh} \left ( bx+a \right ) \right ) ^{2}}{b \left ({b}^{2}{x}^{2}+2\,xab+{a}^{2}+1 \right ) } \left ({b}^{2}{x}^{2}-\sqrt{{b}^{2}{x}^{2}+2\,xab+{a}^{2}+1}xb+2\,xab-\sqrt{{b}^{2}{x}^{2}+2\,xab+{a}^{2}+1}a+{a}^{2}+1 \right ) }+2\,{\frac{ \left ({\it Arcsinh} \left ( bx+a \right ) \right ) ^{2}}{b}}-2\,{\frac{{\it Arcsinh} \left ( bx+a \right ) \ln \left ( 1+ \left ( bx+a+\sqrt{1+ \left ( bx+a \right ) ^{2}} \right ) ^{2} \right ) }{b}}-{\frac{1}{b}{\it polylog} \left ( 2,- \left ( bx+a+\sqrt{1+ \left ( bx+a \right ) ^{2}} \right ) ^{2} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1} \operatorname{arsinh}\left (b x + a\right )^{2}}{b^{4} x^{4} + 4 \, a b^{3} x^{3} + 2 \,{\left (3 \, a^{2} + 1\right )} b^{2} x^{2} + a^{4} + 4 \,{\left (a^{3} + a\right )} b x + 2 \, a^{2} + 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{asinh}^{2}{\left (a + b x \right )}}{\left (a^{2} + 2 a b x + b^{2} x^{2} + 1\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{arsinh}\left (b x + a\right )^{2}}{{\left (b^{2} x^{2} + 2 \, a b x + a^{2} + 1\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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