Optimal. Leaf size=142 \[ \frac{2 b \sqrt{e} (c+d x+1) \sqrt{\frac{(c+d x)^2+1}{(c+d x+1)^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt{e (c+d x)}}{\sqrt{e}}\right ),\frac{1}{2}\right )}{9 d \sqrt{(c+d x)^2+1}}+\frac{2 (e (c+d x))^{3/2} \left (a+b \sinh ^{-1}(c+d x)\right )}{3 d e}-\frac{4 b \sqrt{(c+d x)^2+1} \sqrt{e (c+d x)}}{9 d} \]
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Rubi [A] time = 0.12639, antiderivative size = 142, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.217, Rules used = {5865, 5661, 321, 329, 220} \[ \frac{2 (e (c+d x))^{3/2} \left (a+b \sinh ^{-1}(c+d x)\right )}{3 d e}-\frac{4 b \sqrt{(c+d x)^2+1} \sqrt{e (c+d x)}}{9 d}+\frac{2 b \sqrt{e} (c+d x+1) \sqrt{\frac{(c+d x)^2+1}{(c+d x+1)^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt{e (c+d x)}}{\sqrt{e}}\right )|\frac{1}{2}\right )}{9 d \sqrt{(c+d x)^2+1}} \]
Antiderivative was successfully verified.
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Rule 5865
Rule 5661
Rule 321
Rule 329
Rule 220
Rubi steps
\begin{align*} \int \sqrt{c e+d e x} \left (a+b \sinh ^{-1}(c+d x)\right ) \, dx &=\frac{\operatorname{Subst}\left (\int \sqrt{e x} \left (a+b \sinh ^{-1}(x)\right ) \, dx,x,c+d x\right )}{d}\\ &=\frac{2 (e (c+d x))^{3/2} \left (a+b \sinh ^{-1}(c+d x)\right )}{3 d e}-\frac{(2 b) \operatorname{Subst}\left (\int \frac{(e x)^{3/2}}{\sqrt{1+x^2}} \, dx,x,c+d x\right )}{3 d e}\\ &=-\frac{4 b \sqrt{e (c+d x)} \sqrt{1+(c+d x)^2}}{9 d}+\frac{2 (e (c+d x))^{3/2} \left (a+b \sinh ^{-1}(c+d x)\right )}{3 d e}+\frac{(2 b e) \operatorname{Subst}\left (\int \frac{1}{\sqrt{e x} \sqrt{1+x^2}} \, dx,x,c+d x\right )}{9 d}\\ &=-\frac{4 b \sqrt{e (c+d x)} \sqrt{1+(c+d x)^2}}{9 d}+\frac{2 (e (c+d x))^{3/2} \left (a+b \sinh ^{-1}(c+d x)\right )}{3 d e}+\frac{(4 b) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1+\frac{x^4}{e^2}}} \, dx,x,\sqrt{e (c+d x)}\right )}{9 d}\\ &=-\frac{4 b \sqrt{e (c+d x)} \sqrt{1+(c+d x)^2}}{9 d}+\frac{2 (e (c+d x))^{3/2} \left (a+b \sinh ^{-1}(c+d x)\right )}{3 d e}+\frac{2 b \sqrt{e} (1+c+d x) \sqrt{\frac{1+(c+d x)^2}{(1+c+d x)^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt{e (c+d x)}}{\sqrt{e}}\right )|\frac{1}{2}\right )}{9 d \sqrt{1+(c+d x)^2}}\\ \end{align*}
Mathematica [C] time = 0.0310172, size = 87, normalized size = 0.61 \[ \frac{2 \sqrt{e (c+d x)} \left (2 b \text{Hypergeometric2F1}\left (\frac{1}{4},\frac{1}{2},\frac{5}{4},-(c+d x)^2\right )+3 a c+3 a d x-2 b \sqrt{(c+d x)^2+1}+3 b c \sinh ^{-1}(c+d x)+3 b d x \sinh ^{-1}(c+d x)\right )}{9 d} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.01, size = 179, normalized size = 1.3 \begin{align*} 2\,{\frac{1}{de} \left ( 1/3\, \left ( dex+ce \right ) ^{3/2}a+b \left ( 1/3\, \left ( dex+ce \right ) ^{3/2}{\it Arcsinh} \left ({\frac{dex+ce}{e}} \right ) -2/3\,{\frac{1}{e} \left ( 1/3\,{e}^{2}\sqrt{dex+ce}\sqrt{{\frac{ \left ( dex+ce \right ) ^{2}}{{e}^{2}}}+1}-1/3\,{{e}^{2}\sqrt{1-{\frac{i \left ( dex+ce \right ) }{e}}}\sqrt{1+{\frac{i \left ( dex+ce \right ) }{e}}}{\it EllipticF} \left ( \sqrt{dex+ce}\sqrt{{\frac{i}{e}}},i \right ){\frac{1}{\sqrt{{\frac{i}{e}}}}}{\frac{1}{\sqrt{{\frac{ \left ( dex+ce \right ) ^{2}}{{e}^{2}}}+1}}}} \right ) } \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\sqrt{d e x + c e}{\left (b \operatorname{arsinh}\left (d x + c\right ) + a\right )}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{e \left (c + d x\right )} \left (a + b \operatorname{asinh}{\left (c + d x \right )}\right )\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{d e x + c e}{\left (b \operatorname{arsinh}\left (d x + c\right ) + a\right )}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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