Optimal. Leaf size=205 \[ -\frac{3 \sqrt{\frac{\pi }{2}} b^{3/2} e e^{\frac{2 a}{b}} \text{Erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{64 d}+\frac{3 \sqrt{\frac{\pi }{2}} b^{3/2} e e^{-\frac{2 a}{b}} \text{Erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{64 d}+\frac{e (c+d x)^2 \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{2 d}-\frac{3 b e \sqrt{(c+d x)^2+1} (c+d x) \sqrt{a+b \sinh ^{-1}(c+d x)}}{8 d}+\frac{e \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{4 d} \]
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Rubi [A] time = 0.482889, antiderivative size = 205, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 11, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.478, Rules used = {5865, 12, 5663, 5758, 5675, 5669, 5448, 3308, 2180, 2204, 2205} \[ -\frac{3 \sqrt{\frac{\pi }{2}} b^{3/2} e e^{\frac{2 a}{b}} \text{Erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{64 d}+\frac{3 \sqrt{\frac{\pi }{2}} b^{3/2} e e^{-\frac{2 a}{b}} \text{Erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{64 d}+\frac{e (c+d x)^2 \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{2 d}-\frac{3 b e \sqrt{(c+d x)^2+1} (c+d x) \sqrt{a+b \sinh ^{-1}(c+d x)}}{8 d}+\frac{e \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{4 d} \]
Antiderivative was successfully verified.
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Rule 5865
Rule 12
Rule 5663
Rule 5758
Rule 5675
Rule 5669
Rule 5448
Rule 3308
Rule 2180
Rule 2204
Rule 2205
Rubi steps
\begin{align*} \int (c e+d e x) \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2} \, dx &=\frac{\operatorname{Subst}\left (\int e x \left (a+b \sinh ^{-1}(x)\right )^{3/2} \, dx,x,c+d x\right )}{d}\\ &=\frac{e \operatorname{Subst}\left (\int x \left (a+b \sinh ^{-1}(x)\right )^{3/2} \, dx,x,c+d x\right )}{d}\\ &=\frac{e (c+d x)^2 \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{2 d}-\frac{(3 b e) \operatorname{Subst}\left (\int \frac{x^2 \sqrt{a+b \sinh ^{-1}(x)}}{\sqrt{1+x^2}} \, dx,x,c+d x\right )}{4 d}\\ &=-\frac{3 b e (c+d x) \sqrt{1+(c+d x)^2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{8 d}+\frac{e (c+d x)^2 \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{2 d}+\frac{(3 b e) \operatorname{Subst}\left (\int \frac{\sqrt{a+b \sinh ^{-1}(x)}}{\sqrt{1+x^2}} \, dx,x,c+d x\right )}{8 d}+\frac{\left (3 b^2 e\right ) \operatorname{Subst}\left (\int \frac{x}{\sqrt{a+b \sinh ^{-1}(x)}} \, dx,x,c+d x\right )}{16 d}\\ &=-\frac{3 b e (c+d x) \sqrt{1+(c+d x)^2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{8 d}+\frac{e \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{4 d}+\frac{e (c+d x)^2 \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{2 d}+\frac{\left (3 b^2 e\right ) \operatorname{Subst}\left (\int \frac{\cosh (x) \sinh (x)}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{16 d}\\ &=-\frac{3 b e (c+d x) \sqrt{1+(c+d x)^2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{8 d}+\frac{e \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{4 d}+\frac{e (c+d x)^2 \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{2 d}+\frac{\left (3 b^2 e\right ) \operatorname{Subst}\left (\int \frac{\sinh (2 x)}{2 \sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{16 d}\\ &=-\frac{3 b e (c+d x) \sqrt{1+(c+d x)^2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{8 d}+\frac{e \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{4 d}+\frac{e (c+d x)^2 \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{2 d}+\frac{\left (3 b^2 e\right ) \operatorname{Subst}\left (\int \frac{\sinh (2 x)}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{32 d}\\ &=-\frac{3 b e (c+d x) \sqrt{1+(c+d x)^2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{8 d}+\frac{e \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{4 d}+\frac{e (c+d x)^2 \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{2 d}-\frac{\left (3 b^2 e\right ) \operatorname{Subst}\left (\int \frac{e^{-2 x}}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{64 d}+\frac{\left (3 b^2 e\right ) \operatorname{Subst}\left (\int \frac{e^{2 x}}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{64 d}\\ &=-\frac{3 b e (c+d x) \sqrt{1+(c+d x)^2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{8 d}+\frac{e \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{4 d}+\frac{e (c+d x)^2 \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{2 d}-\frac{(3 b e) \operatorname{Subst}\left (\int e^{\frac{2 a}{b}-\frac{2 x^2}{b}} \, dx,x,\sqrt{a+b \sinh ^{-1}(c+d x)}\right )}{32 d}+\frac{(3 b e) \operatorname{Subst}\left (\int e^{-\frac{2 a}{b}+\frac{2 x^2}{b}} \, dx,x,\sqrt{a+b \sinh ^{-1}(c+d x)}\right )}{32 d}\\ &=-\frac{3 b e (c+d x) \sqrt{1+(c+d x)^2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{8 d}+\frac{e \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{4 d}+\frac{e (c+d x)^2 \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}{2 d}-\frac{3 b^{3/2} e e^{\frac{2 a}{b}} \sqrt{\frac{\pi }{2}} \text{erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{64 d}+\frac{3 b^{3/2} e e^{-\frac{2 a}{b}} \sqrt{\frac{\pi }{2}} \text{erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{64 d}\\ \end{align*}
Mathematica [A] time = 0.104699, size = 142, normalized size = 0.69 \[ \frac{b e e^{-\frac{2 a}{b}} \sqrt{a+b \sinh ^{-1}(c+d x)} \left (e^{\frac{4 a}{b}} \sqrt{-\frac{a+b \sinh ^{-1}(c+d x)}{b}} \text{Gamma}\left (\frac{5}{2},\frac{2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )-\sqrt{\frac{a}{b}+\sinh ^{-1}(c+d x)} \text{Gamma}\left (\frac{5}{2},-\frac{2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )\right )}{16 \sqrt{2} d \sqrt{-\frac{\left (a+b \sinh ^{-1}(c+d x)\right )^2}{b^2}}} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.137, size = 0, normalized size = 0. \begin{align*} \int \left ( dex+ce \right ) \left ( a+b{\it Arcsinh} \left ( dx+c \right ) \right ) ^{{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d e x + c e\right )}{\left (b \operatorname{arsinh}\left (d x + c\right ) + a\right )}^{\frac{3}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} e \left (\int a c \sqrt{a + b \operatorname{asinh}{\left (c + d x \right )}}\, dx + \int a d x \sqrt{a + b \operatorname{asinh}{\left (c + d x \right )}}\, dx + \int b c \sqrt{a + b \operatorname{asinh}{\left (c + d x \right )}} \operatorname{asinh}{\left (c + d x \right )}\, dx + \int b d x \sqrt{a + b \operatorname{asinh}{\left (c + d x \right )}} \operatorname{asinh}{\left (c + d x \right )}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d e x + c e\right )}{\left (b \operatorname{arsinh}\left (d x + c\right ) + a\right )}^{\frac{3}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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