Optimal. Leaf size=410 \[ -\frac{e^4 \sinh \left (\frac{a}{b}\right ) \text{Chi}\left (\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )}{48 b^4 d}+\frac{27 e^4 \sinh \left (\frac{3 a}{b}\right ) \text{Chi}\left (\frac{3 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )}{32 b^4 d}-\frac{125 e^4 \sinh \left (\frac{5 a}{b}\right ) \text{Chi}\left (\frac{5 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )}{96 b^4 d}+\frac{e^4 \cosh \left (\frac{a}{b}\right ) \text{Shi}\left (\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )}{48 b^4 d}-\frac{27 e^4 \cosh \left (\frac{3 a}{b}\right ) \text{Shi}\left (\frac{3 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )}{32 b^4 d}+\frac{125 e^4 \cosh \left (\frac{5 a}{b}\right ) \text{Shi}\left (\frac{5 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )}{96 b^4 d}-\frac{5 e^4 (c+d x)^5}{6 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac{25 e^4 \sqrt{(c+d x)^2+1} (c+d x)^4}{6 b^3 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac{2 e^4 (c+d x)^3}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac{2 e^4 \sqrt{(c+d x)^2+1} (c+d x)^2}{b^3 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac{e^4 \sqrt{(c+d x)^2+1} (c+d x)^4}{3 b d \left (a+b \sinh ^{-1}(c+d x)\right )^3} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.877848, antiderivative size = 406, normalized size of antiderivative = 0.99, number of steps used = 24, number of rules used = 8, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.348, Rules used = {5865, 12, 5667, 5774, 5665, 3303, 3298, 3301} \[ -\frac{e^4 \sinh \left (\frac{a}{b}\right ) \text{Chi}\left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )}{48 b^4 d}+\frac{27 e^4 \sinh \left (\frac{3 a}{b}\right ) \text{Chi}\left (\frac{3 a}{b}+3 \sinh ^{-1}(c+d x)\right )}{32 b^4 d}-\frac{125 e^4 \sinh \left (\frac{5 a}{b}\right ) \text{Chi}\left (\frac{5 a}{b}+5 \sinh ^{-1}(c+d x)\right )}{96 b^4 d}+\frac{e^4 \cosh \left (\frac{a}{b}\right ) \text{Shi}\left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )}{48 b^4 d}-\frac{27 e^4 \cosh \left (\frac{3 a}{b}\right ) \text{Shi}\left (\frac{3 a}{b}+3 \sinh ^{-1}(c+d x)\right )}{32 b^4 d}+\frac{125 e^4 \cosh \left (\frac{5 a}{b}\right ) \text{Shi}\left (\frac{5 a}{b}+5 \sinh ^{-1}(c+d x)\right )}{96 b^4 d}-\frac{5 e^4 (c+d x)^5}{6 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac{25 e^4 \sqrt{(c+d x)^2+1} (c+d x)^4}{6 b^3 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac{2 e^4 (c+d x)^3}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac{2 e^4 \sqrt{(c+d x)^2+1} (c+d x)^2}{b^3 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac{e^4 \sqrt{(c+d x)^2+1} (c+d x)^4}{3 b d \left (a+b \sinh ^{-1}(c+d x)\right )^3} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 5865
Rule 12
Rule 5667
Rule 5774
Rule 5665
Rule 3303
Rule 3298
Rule 3301
Rubi steps
\begin{align*} \int \frac{(c e+d e x)^4}{\left (a+b \sinh ^{-1}(c+d x)\right )^4} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{e^4 x^4}{\left (a+b \sinh ^{-1}(x)\right )^4} \, dx,x,c+d x\right )}{d}\\ &=\frac{e^4 \operatorname{Subst}\left (\int \frac{x^4}{\left (a+b \sinh ^{-1}(x)\right )^4} \, dx,x,c+d x\right )}{d}\\ &=-\frac{e^4 (c+d x)^4 \sqrt{1+(c+d x)^2}}{3 b d \left (a+b \sinh ^{-1}(c+d x)\right )^3}+\frac{\left (4 e^4\right ) \operatorname{Subst}\left (\int \frac{x^3}{\sqrt{1+x^2} \left (a+b \sinh ^{-1}(x)\right )^3} \, dx,x,c+d x\right )}{3 b d}+\frac{\left (5 e^4\right ) \operatorname{Subst}\left (\int \frac{x^5}{\sqrt{1+x^2} \left (a+b \sinh ^{-1}(x)\right )^3} \, dx,x,c+d x\right )}{3 b d}\\ &=-\frac{e^4 (c+d x)^4 \sqrt{1+(c+d x)^2}}{3 b d \left (a+b \sinh ^{-1}(c+d x)\right )^3}-\frac{2 e^4 (c+d x)^3}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac{5 e^4 (c+d x)^5}{6 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}+\frac{\left (2 e^4\right ) \operatorname{Subst}\left (\int \frac{x^2}{\left (a+b \sinh ^{-1}(x)\right )^2} \, dx,x,c+d x\right )}{b^2 d}+\frac{\left (25 e^4\right ) \operatorname{Subst}\left (\int \frac{x^4}{\left (a+b \sinh ^{-1}(x)\right )^2} \, dx,x,c+d x\right )}{6 b^2 d}\\ &=-\frac{e^4 (c+d x)^4 \sqrt{1+(c+d x)^2}}{3 b d \left (a+b \sinh ^{-1}(c+d x)\right )^3}-\frac{2 e^4 (c+d x)^3}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac{5 e^4 (c+d x)^5}{6 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac{2 e^4 (c+d x)^2 \sqrt{1+(c+d x)^2}}{b^3 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac{25 e^4 (c+d x)^4 \sqrt{1+(c+d x)^2}}{6 b^3 d \left (a+b \sinh ^{-1}(c+d x)\right )}+\frac{\left (2 e^4\right ) \operatorname{Subst}\left (\int \left (-\frac{\sinh (x)}{4 (a+b x)}+\frac{3 \sinh (3 x)}{4 (a+b x)}\right ) \, dx,x,\sinh ^{-1}(c+d x)\right )}{b^3 d}+\frac{\left (25 e^4\right ) \operatorname{Subst}\left (\int \left (\frac{\sinh (x)}{8 (a+b x)}-\frac{9 \sinh (3 x)}{16 (a+b x)}+\frac{5 \sinh (5 x)}{16 (a+b x)}\right ) \, dx,x,\sinh ^{-1}(c+d x)\right )}{6 b^3 d}\\ &=-\frac{e^4 (c+d x)^4 \sqrt{1+(c+d x)^2}}{3 b d \left (a+b \sinh ^{-1}(c+d x)\right )^3}-\frac{2 e^4 (c+d x)^3}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac{5 e^4 (c+d x)^5}{6 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac{2 e^4 (c+d x)^2 \sqrt{1+(c+d x)^2}}{b^3 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac{25 e^4 (c+d x)^4 \sqrt{1+(c+d x)^2}}{6 b^3 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac{e^4 \operatorname{Subst}\left (\int \frac{\sinh (x)}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{2 b^3 d}+\frac{\left (25 e^4\right ) \operatorname{Subst}\left (\int \frac{\sinh (x)}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{48 b^3 d}+\frac{\left (125 e^4\right ) \operatorname{Subst}\left (\int \frac{\sinh (5 x)}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{96 b^3 d}+\frac{\left (3 e^4\right ) \operatorname{Subst}\left (\int \frac{\sinh (3 x)}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{2 b^3 d}-\frac{\left (75 e^4\right ) \operatorname{Subst}\left (\int \frac{\sinh (3 x)}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{32 b^3 d}\\ &=-\frac{e^4 (c+d x)^4 \sqrt{1+(c+d x)^2}}{3 b d \left (a+b \sinh ^{-1}(c+d x)\right )^3}-\frac{2 e^4 (c+d x)^3}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac{5 e^4 (c+d x)^5}{6 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac{2 e^4 (c+d x)^2 \sqrt{1+(c+d x)^2}}{b^3 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac{25 e^4 (c+d x)^4 \sqrt{1+(c+d x)^2}}{6 b^3 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac{\left (e^4 \cosh \left (\frac{a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\sinh \left (\frac{a}{b}+x\right )}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{2 b^3 d}+\frac{\left (25 e^4 \cosh \left (\frac{a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\sinh \left (\frac{a}{b}+x\right )}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{48 b^3 d}+\frac{\left (3 e^4 \cosh \left (\frac{3 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\sinh \left (\frac{3 a}{b}+3 x\right )}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{2 b^3 d}-\frac{\left (75 e^4 \cosh \left (\frac{3 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\sinh \left (\frac{3 a}{b}+3 x\right )}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{32 b^3 d}+\frac{\left (125 e^4 \cosh \left (\frac{5 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\sinh \left (\frac{5 a}{b}+5 x\right )}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{96 b^3 d}+\frac{\left (e^4 \sinh \left (\frac{a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\cosh \left (\frac{a}{b}+x\right )}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{2 b^3 d}-\frac{\left (25 e^4 \sinh \left (\frac{a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\cosh \left (\frac{a}{b}+x\right )}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{48 b^3 d}-\frac{\left (3 e^4 \sinh \left (\frac{3 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\cosh \left (\frac{3 a}{b}+3 x\right )}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{2 b^3 d}+\frac{\left (75 e^4 \sinh \left (\frac{3 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\cosh \left (\frac{3 a}{b}+3 x\right )}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{32 b^3 d}-\frac{\left (125 e^4 \sinh \left (\frac{5 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\cosh \left (\frac{5 a}{b}+5 x\right )}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{96 b^3 d}\\ &=-\frac{e^4 (c+d x)^4 \sqrt{1+(c+d x)^2}}{3 b d \left (a+b \sinh ^{-1}(c+d x)\right )^3}-\frac{2 e^4 (c+d x)^3}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac{5 e^4 (c+d x)^5}{6 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac{2 e^4 (c+d x)^2 \sqrt{1+(c+d x)^2}}{b^3 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac{25 e^4 (c+d x)^4 \sqrt{1+(c+d x)^2}}{6 b^3 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac{e^4 \text{Chi}\left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right ) \sinh \left (\frac{a}{b}\right )}{48 b^4 d}+\frac{27 e^4 \text{Chi}\left (\frac{3 a}{b}+3 \sinh ^{-1}(c+d x)\right ) \sinh \left (\frac{3 a}{b}\right )}{32 b^4 d}-\frac{125 e^4 \text{Chi}\left (\frac{5 a}{b}+5 \sinh ^{-1}(c+d x)\right ) \sinh \left (\frac{5 a}{b}\right )}{96 b^4 d}+\frac{e^4 \cosh \left (\frac{a}{b}\right ) \text{Shi}\left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )}{48 b^4 d}-\frac{27 e^4 \cosh \left (\frac{3 a}{b}\right ) \text{Shi}\left (\frac{3 a}{b}+3 \sinh ^{-1}(c+d x)\right )}{32 b^4 d}+\frac{125 e^4 \cosh \left (\frac{5 a}{b}\right ) \text{Shi}\left (\frac{5 a}{b}+5 \sinh ^{-1}(c+d x)\right )}{96 b^4 d}\\ \end{align*}
Mathematica [A] time = 1.91378, size = 410, normalized size = 1. \[ -\frac{e^4 \left (\frac{32 b^3 \sqrt{(c+d x)^2+1} (c+d x)^4}{\left (a+b \sinh ^{-1}(c+d x)\right )^3}-\frac{16 b^2 \left (-5 (c+d x)^5-4 (c+d x)^3\right )}{\left (a+b \sinh ^{-1}(c+d x)\right )^2}+384 \left (\sinh \left (\frac{a}{b}\right ) \text{Chi}\left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )-\cosh \left (\frac{a}{b}\right ) \text{Shi}\left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )\right )+544 \left (-3 \sinh \left (\frac{a}{b}\right ) \text{Chi}\left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )+\sinh \left (\frac{3 a}{b}\right ) \text{Chi}\left (3 \left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )\right )+3 \cosh \left (\frac{a}{b}\right ) \text{Shi}\left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )-\cosh \left (\frac{3 a}{b}\right ) \text{Shi}\left (3 \left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )\right )\right )+125 \left (10 \sinh \left (\frac{a}{b}\right ) \text{Chi}\left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )-5 \sinh \left (\frac{3 a}{b}\right ) \text{Chi}\left (3 \left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )\right )+\sinh \left (\frac{5 a}{b}\right ) \text{Chi}\left (5 \left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )\right )-10 \cosh \left (\frac{a}{b}\right ) \text{Shi}\left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )+5 \cosh \left (\frac{3 a}{b}\right ) \text{Shi}\left (3 \left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )\right )-\cosh \left (\frac{5 a}{b}\right ) \text{Shi}\left (5 \left (\frac{a}{b}+\sinh ^{-1}(c+d x)\right )\right )\right )+\frac{16 b \sqrt{(c+d x)^2+1} \left (25 (c+d x)^4+12 (c+d x)^2\right )}{a+b \sinh ^{-1}(c+d x)}\right )}{96 b^4 d} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [B] time = 0.258, size = 1244, normalized size = 3. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{d^{4} e^{4} x^{4} + 4 \, c d^{3} e^{4} x^{3} + 6 \, c^{2} d^{2} e^{4} x^{2} + 4 \, c^{3} d e^{4} x + c^{4} e^{4}}{b^{4} \operatorname{arsinh}\left (d x + c\right )^{4} + 4 \, a b^{3} \operatorname{arsinh}\left (d x + c\right )^{3} + 6 \, a^{2} b^{2} \operatorname{arsinh}\left (d x + c\right )^{2} + 4 \, a^{3} b \operatorname{arsinh}\left (d x + c\right ) + a^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (d e x + c e\right )}^{4}}{{\left (b \operatorname{arsinh}\left (d x + c\right ) + a\right )}^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]