Optimal. Leaf size=105 \[ \frac{e^3 (c+d x)^4 \left (a+b \sinh ^{-1}(c+d x)\right )}{4 d}-\frac{b e^3 \sqrt{(c+d x)^2+1} (c+d x)^3}{16 d}+\frac{3 b e^3 \sqrt{(c+d x)^2+1} (c+d x)}{32 d}-\frac{3 b e^3 \sinh ^{-1}(c+d x)}{32 d} \]
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Rubi [A] time = 0.0699616, antiderivative size = 105, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.238, Rules used = {5865, 12, 5661, 321, 215} \[ \frac{e^3 (c+d x)^4 \left (a+b \sinh ^{-1}(c+d x)\right )}{4 d}-\frac{b e^3 \sqrt{(c+d x)^2+1} (c+d x)^3}{16 d}+\frac{3 b e^3 \sqrt{(c+d x)^2+1} (c+d x)}{32 d}-\frac{3 b e^3 \sinh ^{-1}(c+d x)}{32 d} \]
Antiderivative was successfully verified.
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Rule 5865
Rule 12
Rule 5661
Rule 321
Rule 215
Rubi steps
\begin{align*} \int (c e+d e x)^3 \left (a+b \sinh ^{-1}(c+d x)\right ) \, dx &=\frac{\operatorname{Subst}\left (\int e^3 x^3 \left (a+b \sinh ^{-1}(x)\right ) \, dx,x,c+d x\right )}{d}\\ &=\frac{e^3 \operatorname{Subst}\left (\int x^3 \left (a+b \sinh ^{-1}(x)\right ) \, dx,x,c+d x\right )}{d}\\ &=\frac{e^3 (c+d x)^4 \left (a+b \sinh ^{-1}(c+d x)\right )}{4 d}-\frac{\left (b e^3\right ) \operatorname{Subst}\left (\int \frac{x^4}{\sqrt{1+x^2}} \, dx,x,c+d x\right )}{4 d}\\ &=-\frac{b e^3 (c+d x)^3 \sqrt{1+(c+d x)^2}}{16 d}+\frac{e^3 (c+d x)^4 \left (a+b \sinh ^{-1}(c+d x)\right )}{4 d}+\frac{\left (3 b e^3\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{1+x^2}} \, dx,x,c+d x\right )}{16 d}\\ &=\frac{3 b e^3 (c+d x) \sqrt{1+(c+d x)^2}}{32 d}-\frac{b e^3 (c+d x)^3 \sqrt{1+(c+d x)^2}}{16 d}+\frac{e^3 (c+d x)^4 \left (a+b \sinh ^{-1}(c+d x)\right )}{4 d}-\frac{\left (3 b e^3\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1+x^2}} \, dx,x,c+d x\right )}{32 d}\\ &=\frac{3 b e^3 (c+d x) \sqrt{1+(c+d x)^2}}{32 d}-\frac{b e^3 (c+d x)^3 \sqrt{1+(c+d x)^2}}{16 d}-\frac{3 b e^3 \sinh ^{-1}(c+d x)}{32 d}+\frac{e^3 (c+d x)^4 \left (a+b \sinh ^{-1}(c+d x)\right )}{4 d}\\ \end{align*}
Mathematica [A] time = 0.0730688, size = 83, normalized size = 0.79 \[ \frac{e^3 \left (8 (c+d x)^4 \left (a+b \sinh ^{-1}(c+d x)\right )-2 b \sqrt{(c+d x)^2+1} (c+d x)^3+3 b \sqrt{(c+d x)^2+1} (c+d x)-3 b \sinh ^{-1}(c+d x)\right )}{32 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.005, size = 86, normalized size = 0.8 \begin{align*}{\frac{1}{d} \left ({\frac{ \left ( dx+c \right ) ^{4}{e}^{3}a}{4}}+{e}^{3}b \left ({\frac{ \left ( dx+c \right ) ^{4}{\it Arcsinh} \left ( dx+c \right ) }{4}}-{\frac{ \left ( dx+c \right ) ^{3}}{16}\sqrt{1+ \left ( dx+c \right ) ^{2}}}+{\frac{3\,dx+3\,c}{32}\sqrt{1+ \left ( dx+c \right ) ^{2}}}-{\frac{3\,{\it Arcsinh} \left ( dx+c \right ) }{32}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.34303, size = 495, normalized size = 4.71 \begin{align*} \frac{8 \, a d^{4} e^{3} x^{4} + 32 \, a c d^{3} e^{3} x^{3} + 48 \, a c^{2} d^{2} e^{3} x^{2} + 32 \, a c^{3} d e^{3} x +{\left (8 \, b d^{4} e^{3} x^{4} + 32 \, b c d^{3} e^{3} x^{3} + 48 \, b c^{2} d^{2} e^{3} x^{2} + 32 \, b c^{3} d e^{3} x +{\left (8 \, b c^{4} - 3 \, b\right )} e^{3}\right )} \log \left (d x + c + \sqrt{d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right ) -{\left (2 \, b d^{3} e^{3} x^{3} + 6 \, b c d^{2} e^{3} x^{2} + 3 \,{\left (2 \, b c^{2} - b\right )} d e^{3} x +{\left (2 \, b c^{3} - 3 \, b c\right )} e^{3}\right )} \sqrt{d^{2} x^{2} + 2 \, c d x + c^{2} + 1}}{32 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 2.32864, size = 394, normalized size = 3.75 \begin{align*} \begin{cases} a c^{3} e^{3} x + \frac{3 a c^{2} d e^{3} x^{2}}{2} + a c d^{2} e^{3} x^{3} + \frac{a d^{3} e^{3} x^{4}}{4} + \frac{b c^{4} e^{3} \operatorname{asinh}{\left (c + d x \right )}}{4 d} + b c^{3} e^{3} x \operatorname{asinh}{\left (c + d x \right )} - \frac{b c^{3} e^{3} \sqrt{c^{2} + 2 c d x + d^{2} x^{2} + 1}}{16 d} + \frac{3 b c^{2} d e^{3} x^{2} \operatorname{asinh}{\left (c + d x \right )}}{2} - \frac{3 b c^{2} e^{3} x \sqrt{c^{2} + 2 c d x + d^{2} x^{2} + 1}}{16} + b c d^{2} e^{3} x^{3} \operatorname{asinh}{\left (c + d x \right )} - \frac{3 b c d e^{3} x^{2} \sqrt{c^{2} + 2 c d x + d^{2} x^{2} + 1}}{16} + \frac{3 b c e^{3} \sqrt{c^{2} + 2 c d x + d^{2} x^{2} + 1}}{32 d} + \frac{b d^{3} e^{3} x^{4} \operatorname{asinh}{\left (c + d x \right )}}{4} - \frac{b d^{2} e^{3} x^{3} \sqrt{c^{2} + 2 c d x + d^{2} x^{2} + 1}}{16} + \frac{3 b e^{3} x \sqrt{c^{2} + 2 c d x + d^{2} x^{2} + 1}}{32} - \frac{3 b e^{3} \operatorname{asinh}{\left (c + d x \right )}}{32 d} & \text{for}\: d \neq 0 \\c^{3} e^{3} x \left (a + b \operatorname{asinh}{\left (c \right )}\right ) & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.72075, size = 807, normalized size = 7.69 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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