Optimal. Leaf size=269 \[ \frac{\sqrt{\pi } c e^{a/b} \text{Erf}\left (\frac{\sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}+\frac{\sqrt{\frac{\pi }{2}} e^{\frac{2 a}{b}} \text{Erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}-\frac{\sqrt{\pi } c e^{-\frac{a}{b}} \text{Erfi}\left (\frac{\sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}+\frac{\sqrt{\frac{\pi }{2}} e^{-\frac{2 a}{b}} \text{Erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}+\frac{2 c \sqrt{(c+d x)^2+1}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}}-\frac{2 (c+d x) \sqrt{(c+d x)^2+1}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}} \]
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Rubi [A] time = 0.542365, antiderivative size = 269, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 10, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.625, Rules used = {5865, 5803, 5655, 5779, 3308, 2180, 2204, 2205, 5665, 3307} \[ \frac{\sqrt{\pi } c e^{a/b} \text{Erf}\left (\frac{\sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}+\frac{\sqrt{\frac{\pi }{2}} e^{\frac{2 a}{b}} \text{Erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}-\frac{\sqrt{\pi } c e^{-\frac{a}{b}} \text{Erfi}\left (\frac{\sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}+\frac{\sqrt{\frac{\pi }{2}} e^{-\frac{2 a}{b}} \text{Erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}+\frac{2 c \sqrt{(c+d x)^2+1}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}}-\frac{2 (c+d x) \sqrt{(c+d x)^2+1}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}} \]
Antiderivative was successfully verified.
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Rule 5865
Rule 5803
Rule 5655
Rule 5779
Rule 3308
Rule 2180
Rule 2204
Rule 2205
Rule 5665
Rule 3307
Rubi steps
\begin{align*} \int \frac{x}{\left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{-\frac{c}{d}+\frac{x}{d}}{\left (a+b \sinh ^{-1}(x)\right )^{3/2}} \, dx,x,c+d x\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \left (-\frac{c}{d \left (a+b \sinh ^{-1}(x)\right )^{3/2}}+\frac{x}{d \left (a+b \sinh ^{-1}(x)\right )^{3/2}}\right ) \, dx,x,c+d x\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \frac{x}{\left (a+b \sinh ^{-1}(x)\right )^{3/2}} \, dx,x,c+d x\right )}{d^2}-\frac{c \operatorname{Subst}\left (\int \frac{1}{\left (a+b \sinh ^{-1}(x)\right )^{3/2}} \, dx,x,c+d x\right )}{d^2}\\ &=\frac{2 c \sqrt{1+(c+d x)^2}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}}-\frac{2 (c+d x) \sqrt{1+(c+d x)^2}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}}+\frac{2 \operatorname{Subst}\left (\int \frac{\cosh (2 x)}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{b d^2}-\frac{(2 c) \operatorname{Subst}\left (\int \frac{x}{\sqrt{1+x^2} \sqrt{a+b \sinh ^{-1}(x)}} \, dx,x,c+d x\right )}{b d^2}\\ &=\frac{2 c \sqrt{1+(c+d x)^2}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}}-\frac{2 (c+d x) \sqrt{1+(c+d x)^2}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}}+\frac{\operatorname{Subst}\left (\int \frac{e^{-2 x}}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{b d^2}+\frac{\operatorname{Subst}\left (\int \frac{e^{2 x}}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{b d^2}-\frac{(2 c) \operatorname{Subst}\left (\int \frac{\sinh (x)}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{b d^2}\\ &=\frac{2 c \sqrt{1+(c+d x)^2}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}}-\frac{2 (c+d x) \sqrt{1+(c+d x)^2}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}}+\frac{2 \operatorname{Subst}\left (\int e^{\frac{2 a}{b}-\frac{2 x^2}{b}} \, dx,x,\sqrt{a+b \sinh ^{-1}(c+d x)}\right )}{b^2 d^2}+\frac{2 \operatorname{Subst}\left (\int e^{-\frac{2 a}{b}+\frac{2 x^2}{b}} \, dx,x,\sqrt{a+b \sinh ^{-1}(c+d x)}\right )}{b^2 d^2}+\frac{c \operatorname{Subst}\left (\int \frac{e^{-x}}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{b d^2}-\frac{c \operatorname{Subst}\left (\int \frac{e^x}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{b d^2}\\ &=\frac{2 c \sqrt{1+(c+d x)^2}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}}-\frac{2 (c+d x) \sqrt{1+(c+d x)^2}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}}+\frac{e^{\frac{2 a}{b}} \sqrt{\frac{\pi }{2}} \text{erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}+\frac{e^{-\frac{2 a}{b}} \sqrt{\frac{\pi }{2}} \text{erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}+\frac{(2 c) \operatorname{Subst}\left (\int e^{\frac{a}{b}-\frac{x^2}{b}} \, dx,x,\sqrt{a+b \sinh ^{-1}(c+d x)}\right )}{b^2 d^2}-\frac{(2 c) \operatorname{Subst}\left (\int e^{-\frac{a}{b}+\frac{x^2}{b}} \, dx,x,\sqrt{a+b \sinh ^{-1}(c+d x)}\right )}{b^2 d^2}\\ &=\frac{2 c \sqrt{1+(c+d x)^2}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}}-\frac{2 (c+d x) \sqrt{1+(c+d x)^2}}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}}+\frac{c e^{a/b} \sqrt{\pi } \text{erf}\left (\frac{\sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}+\frac{e^{\frac{2 a}{b}} \sqrt{\frac{\pi }{2}} \text{erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}-\frac{c e^{-\frac{a}{b}} \sqrt{\pi } \text{erfi}\left (\frac{\sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}+\frac{e^{-\frac{2 a}{b}} \sqrt{\frac{\pi }{2}} \text{erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )}{b^{3/2} d^2}\\ \end{align*}
Mathematica [A] time = 2.55441, size = 301, normalized size = 1.12 \[ \frac{\sqrt{2 \pi } \left (\sinh \left (\frac{2 a}{b}\right )+\cosh \left (\frac{2 a}{b}\right )\right ) \text{Erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )+\sqrt{2 \pi } \left (\cosh \left (\frac{2 a}{b}\right )-\sinh \left (\frac{2 a}{b}\right )\right ) \text{Erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c+d x)}}{\sqrt{b}}\right )-\frac{2 \sqrt{b} \sinh \left (2 \sinh ^{-1}(c+d x)\right )}{\sqrt{a+b \sinh ^{-1}(c+d x)}}}{2 b^{3/2} d^2}-\frac{c e^{-\frac{a+b \sinh ^{-1}(c+d x)}{b}} \left (e^{\frac{2 a}{b}+\sinh ^{-1}(c+d x)} \sqrt{\frac{a}{b}+\sinh ^{-1}(c+d x)} \text{Gamma}\left (\frac{1}{2},\frac{a}{b}+\sinh ^{-1}(c+d x)\right )+e^{\sinh ^{-1}(c+d x)} \sqrt{-\frac{a+b \sinh ^{-1}(c+d x)}{b}} \text{Gamma}\left (\frac{1}{2},-\frac{a+b \sinh ^{-1}(c+d x)}{b}\right )-e^{a/b} \left (e^{2 \sinh ^{-1}(c+d x)}+1\right )\right )}{b d^2 \sqrt{a+b \sinh ^{-1}(c+d x)}} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.158, size = 0, normalized size = 0. \begin{align*} \int{x \left ( a+b{\it Arcsinh} \left ( dx+c \right ) \right ) ^{-{\frac{3}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x}{{\left (b \operatorname{arsinh}\left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x}{\left (a + b \operatorname{asinh}{\left (c + d x \right )}\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x}{{\left (b \operatorname{arsinh}\left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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