Optimal. Leaf size=151 \[ \frac{2 e^{d+e x} F^{c (a+b x)} (e-b c \log (F)) \, _2F_1\left (2,\frac{b c \log (F)}{e}+1;\frac{b c \log (F)}{e}+2;-e^{d+e x}\right )}{3 e^2 f^2}+\frac{b c \log (F) \text{sech}^2\left (\frac{d}{2}+\frac{e x}{2}\right ) F^{c (a+b x)}}{6 e^2 f^2}+\frac{\tanh \left (\frac{d}{2}+\frac{e x}{2}\right ) \text{sech}^2\left (\frac{d}{2}+\frac{e x}{2}\right ) F^{c (a+b x)}}{6 e f^2} \]
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Rubi [A] time = 0.102074, antiderivative size = 151, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.136, Rules used = {5497, 5490, 5492} \[ \frac{2 e^{d+e x} F^{c (a+b x)} (e-b c \log (F)) \, _2F_1\left (2,\frac{b c \log (F)}{e}+1;\frac{b c \log (F)}{e}+2;-e^{d+e x}\right )}{3 e^2 f^2}+\frac{b c \log (F) \text{sech}^2\left (\frac{d}{2}+\frac{e x}{2}\right ) F^{c (a+b x)}}{6 e^2 f^2}+\frac{\tanh \left (\frac{d}{2}+\frac{e x}{2}\right ) \text{sech}^2\left (\frac{d}{2}+\frac{e x}{2}\right ) F^{c (a+b x)}}{6 e f^2} \]
Antiderivative was successfully verified.
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Rule 5497
Rule 5490
Rule 5492
Rubi steps
\begin{align*} \int \frac{F^{c (a+b x)}}{(f+f \cosh (d+e x))^2} \, dx &=\frac{\int F^{c (a+b x)} \text{sech}^4\left (\frac{d}{2}+\frac{e x}{2}\right ) \, dx}{4 f^2}\\ &=\frac{b c F^{c (a+b x)} \log (F) \text{sech}^2\left (\frac{d}{2}+\frac{e x}{2}\right )}{6 e^2 f^2}+\frac{F^{c (a+b x)} \text{sech}^2\left (\frac{d}{2}+\frac{e x}{2}\right ) \tanh \left (\frac{d}{2}+\frac{e x}{2}\right )}{6 e f^2}+\frac{\left (1-\frac{b^2 c^2 \log ^2(F)}{e^2}\right ) \int F^{c (a+b x)} \text{sech}^2\left (\frac{d}{2}+\frac{e x}{2}\right ) \, dx}{6 f^2}\\ &=\frac{2 e^{d+e x} F^{c (a+b x)} \, _2F_1\left (2,1+\frac{b c \log (F)}{e};2+\frac{b c \log (F)}{e};-e^{d+e x}\right ) (e-b c \log (F))}{3 e^2 f^2}+\frac{b c F^{c (a+b x)} \log (F) \text{sech}^2\left (\frac{d}{2}+\frac{e x}{2}\right )}{6 e^2 f^2}+\frac{F^{c (a+b x)} \text{sech}^2\left (\frac{d}{2}+\frac{e x}{2}\right ) \tanh \left (\frac{d}{2}+\frac{e x}{2}\right )}{6 e f^2}\\ \end{align*}
Mathematica [A] time = 0.332149, size = 127, normalized size = 0.84 \[ \frac{2 \cosh \left (\frac{1}{2} (d+e x)\right ) F^{c (a+b x)} \left (4 e^{d+e x} \cosh ^3\left (\frac{1}{2} (d+e x)\right ) (e-b c \log (F)) \, _2F_1\left (2,\frac{b c \log (F)}{e}+1;\frac{b c \log (F)}{e}+2;-e^{d+e x}\right )+b c \log (F) \cosh \left (\frac{1}{2} (d+e x)\right )+e \sinh \left (\frac{1}{2} (d+e x)\right )\right )}{3 e^2 f^2 (\cosh (d+e x)+1)^2} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.059, size = 0, normalized size = 0. \begin{align*} \int{\frac{{F}^{c \left ( bx+a \right ) }}{ \left ( f+f\cosh \left ( ex+d \right ) \right ) ^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{F^{b c x + a c}}{f^{2} \cosh \left (e x + d\right )^{2} + 2 \, f^{2} \cosh \left (e x + d\right ) + f^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{F^{a c} F^{b c x}}{\cosh ^{2}{\left (d + e x \right )} + 2 \cosh{\left (d + e x \right )} + 1}\, dx}{f^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{F^{{\left (b x + a\right )} c}}{{\left (f \cosh \left (e x + d\right ) + f\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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