Optimal. Leaf size=117 \[ -\frac{e^{-a-b x} \, _2F_1\left (1,-\frac{b}{2 d};1-\frac{b}{2 d};e^{2 (c+d x)}\right )}{b}-\frac{e^{a+b x} \, _2F_1\left (1,\frac{b}{2 d};\frac{b}{2 d}+1;e^{2 (c+d x)}\right )}{b}+\frac{e^{-a-b x}}{2 b}+\frac{e^{a+b x}}{2 b} \]
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Rubi [A] time = 0.108786, antiderivative size = 117, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 3, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.231, Rules used = {5603, 2194, 2251} \[ -\frac{e^{-a-b x} \, _2F_1\left (1,-\frac{b}{2 d};1-\frac{b}{2 d};e^{2 (c+d x)}\right )}{b}-\frac{e^{a+b x} \, _2F_1\left (1,\frac{b}{2 d};\frac{b}{2 d}+1;e^{2 (c+d x)}\right )}{b}+\frac{e^{-a-b x}}{2 b}+\frac{e^{a+b x}}{2 b} \]
Antiderivative was successfully verified.
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Rule 5603
Rule 2194
Rule 2251
Rubi steps
\begin{align*} \int \coth (c+d x) \sinh (a+b x) \, dx &=\int \left (-\frac{1}{2} e^{-a-b x}+\frac{1}{2} e^{a+b x}+\frac{e^{-a-b x}}{1-e^{2 (c+d x)}}-\frac{e^{a+b x}}{1-e^{2 (c+d x)}}\right ) \, dx\\ &=-\left (\frac{1}{2} \int e^{-a-b x} \, dx\right )+\frac{1}{2} \int e^{a+b x} \, dx+\int \frac{e^{-a-b x}}{1-e^{2 (c+d x)}} \, dx-\int \frac{e^{a+b x}}{1-e^{2 (c+d x)}} \, dx\\ &=\frac{e^{-a-b x}}{2 b}+\frac{e^{a+b x}}{2 b}-\frac{e^{-a-b x} \, _2F_1\left (1,-\frac{b}{2 d};1-\frac{b}{2 d};e^{2 (c+d x)}\right )}{b}-\frac{e^{a+b x} \, _2F_1\left (1,\frac{b}{2 d};1+\frac{b}{2 d};e^{2 (c+d x)}\right )}{b}\\ \end{align*}
Mathematica [B] time = 6.7317, size = 240, normalized size = 2.05 \[ \frac{e^{-a-b x+2 c} \left (b e^{2 d x} \, _2F_1\left (1,1-\frac{b}{2 d};2-\frac{b}{2 d};e^{2 (c+d x)}\right )-(b-2 d) \, _2F_1\left (1,-\frac{b}{2 d};1-\frac{b}{2 d};e^{2 (c+d x)}\right )\right )}{b \left (e^{2 c}-1\right ) (b-2 d)}-\frac{e^{a+2 c} \left (\frac{e^{b x} \, _2F_1\left (1,\frac{b}{2 d};\frac{b}{2 d}+1;e^{2 (c+d x)}\right )}{b}-\frac{e^{x (b+2 d)} \, _2F_1\left (1,\frac{b}{2 d}+1;\frac{b}{2 d}+2;e^{2 (c+d x)}\right )}{b+2 d}\right )}{e^{2 c}-1}+\frac{\cosh (a) \coth (c) \cosh (b x)}{b}+\frac{\sinh (a) \coth (c) \sinh (b x)}{b} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.083, size = 0, normalized size = 0. \begin{align*} \int{\rm coth} \left (dx+c\right )\sinh \left ( bx+a \right ) \, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{{\left (e^{\left (2 \, b x + 2 \, a\right )} + 1\right )} e^{\left (-b x - a\right )}}{2 \, b} - \frac{1}{2} \, \int \frac{e^{\left (2 \, b x + 2 \, a\right )} - 1}{e^{\left (b x + d x + a + c\right )} + e^{\left (b x + a\right )}}\,{d x} + \frac{1}{2} \, \int \frac{e^{\left (2 \, b x + 2 \, a\right )} - 1}{e^{\left (b x + d x + a + c\right )} - e^{\left (b x + a\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\coth \left (d x + c\right ) \sinh \left (b x + a\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sinh{\left (a + b x \right )} \coth{\left (c + d x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \coth \left (d x + c\right ) \sinh \left (b x + a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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